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Magnetic Fields and Forces
Facts about Magnetism 
Magnets have 2 poles (north and south) 
Like poles repel 
Unlike poles attract 
Magnets create a MAGNETIC FIELD around them
Magnetic Field 
A bar magnet has a magnetic field around it. This field is 3D in nature and often represented by lines LEAVING north and ENTERING south 
To define a magnetic field you need to understand the MAGNITUDE and DIRECTION 
We sometimes call the magnetic field a B-Field as the letter “B” is the SYMBOL for a magnetic field with the TESLA (T) as the unit.
Magnetic Force on a moving charge 
If a MOVING CHARGE 
moves into a magnetic 
field it will experience a 
MAGNETIC FORCE. 
This deflection is 3D in 
nature. 
N 
N 
S 
S 
- 
vo 
B 
F qvBsin 
F qv B 
B 
B 
 
  
   The conditions for the force are: 
•Must have a magnetic field present 
•Charge must be moving 
•Charge must be positive or negative 
•Charge must be moving 
PERPENDICULAR to the field.
Example 
A proton moves with a speed of 1.0x105 m/s through the Earth’s magnetic field, 
which has a value of 55mT at a particular location. When the proton moves 
eastward, the magnetic force is a maximum, and when it moves northward, no 
magnetic force acts upon it. What is the magnitude and direction of the magnetic 
force acting on the proton? 
 
 
   
  
B 
B 
B 
F 
F x x x 
F qvB 
(1.6 10 )(1.0 10 )(55 10 ) 
, 90, sin 90 1 
19 5 6 
 
8.8x10-19 N 
The direction cannot be determined precisely by the given information. Since 
no force acts on the proton when it moves northward (meaning the angle is 
equal to ZERO), we can infer that the magnetic field must either go northward 
or southward.
Direction of the magnetic force? 
Right Hand Rule To determine the DIRECTION of the 
force on a POSITIVE charge we 
use a special technique that 
helps us understand the 
3D/perpendicular nature of 
magnetic fields. 
Basically you hold your right 
hand flat with your thumb 
perpendicular to the rest of your 
fingers 
•The Fingers = Direction B-Field 
•The Thumb = Direction of velocity 
•The Palm = Direction of the Force 
For NEGATIVE charges use left hand!
Example 
Determine the direction of the unknown variable for a proton moving in the field using the coordinate axis given 
+y 
+x 
+z 
B = -x 
v = +y 
F = 
+z 
B =+Z 
v = +x 
F = 
-y 
B = -z 
v = +y 
F = 
-x
Example 
Determine the direction of the unknown variable for an electron using the coordinate axis given. 
+y 
+x 
+z 
B = +x 
v = +y 
F = 
+z 
B = v = - x F = +y 
-z 
F 
B 
B = +z 
v = 
F = +y 
+x
Magnetic Force and Circular Motion 
X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X 
v 
B 
- 
- 
FB 
FB 
FB 
FB 
- 
- 
- 
Suppose we have an electron traveling at a velocity , v, entering a magnetic field, B, directed into the page. What happens after the initial force acts on the charge?
Magnetic Force and Circular Motion 
The magnetic force is equal to the 
centripetal force and thus can be used 
to solve for the circular path. Or, if the 
radius is known, could be used to 
solve for the MASS of the ion. This 
could be used to determine the 
material of the object. 
There are many “other” types of 
forces that can be set equal to the 
magnetic force.
Example 
? 
0.5 
250 
2.5 10 
1.6 10 
26 
19 
 
 
  
 
 
 
 
r 
B T 
V V 
m x kg 
q x C 
qB 
mv 
r 
r 
mv 
F F qvB B c    
2 
  
 
 
 
 
   
 
 
26 
19 
2 
2.5 10 
2 2(250)(1.6 10 ) 
2 
1 
x 
x 
m 
Vq 
v 
q 
mv 
q 
K 
q 
W 
V 
A singly charged positive ion has a mass of 2.5 x 10-26 kg. After being 
accelerated through a potential difference of 250 V, the ion enters a 
magnetic field of 0.5 T, in a direction perpendicular to the field. 
Calculate the radius of the path of the ion in the field. 
We need to 
solve for the 
velocity! 
56,568 m/s 
   
 
(1.6 10 )(0.5) 
(2.5 10 )(56,568) 
19 
26 
x 
x 
r 0.0177 m
Charges moving in a wire 
Up to this point we have focused our attention on PARTICLES or CHARGES only. The charges could be moving together in a wire. Thus, if the wire had a CURRENT (moving charges), it too will experience a force when placed in a magnetic field. 
You simply used the RIGHT HAND ONLY and the thumb will represent the direction of the CURRENT instead of the velocity.
Charges moving in a wire 
 
 
 
sin 
( )( ) sin 
sin 
F ILB 
vt B 
t 
q 
F 
t 
t 
F qvB 
B 
B 
B 
 
 
  
At this point it is VERY important that 
you understand that the MAGNETIC 
FIELD is being produced by some 
EXTERNAL AGENT
Example 
A 36-m length wire carries a current 
of 22A running from right to left. 
Calculate the magnitude and 
direction of the magnetic force 
acting on the wire if it is placed in a 
magnetic field with a magnitude of 
0.50 x10-4 T and directed up the 
page. 
 
 
 
 
B 
B 
B 
F 
F x 
F ILB 
(22)(36)(0.50 10 ) sin 90 
sin 
4 
 
0.0396 N 
B = +y 
I = -x 
F = 
+y 
+z +x 
-z, into the page
WHY does the wire move? 
The real question is WHY does the wire move? It is easy to say the EXTERNAL field moved it. But how can an external magnetic field FORCE the wire to move in a certain direction? 
THE WIRE ITSELF MUST BE MAGNETIC!!! In other words the wire has its own INTERNAL MAGNETIC FIELD that is attracted or repulsed by the EXTERNAL FIELD. 
As it turns out, the wire’s OWN internal magnetic field makes concentric circles round the wire.
A current carrying wire’s INTERNAL 
magnetic field 
To figure out the DIRECTION of this 
INTERNAL field you use the right 
hand rule. You point your thumb in 
the direction of the current then 
CURL your fingers. Your fingers will 
point in the direction of the magnetic 
field
The MAGNITUDE of the internal field 
The magnetic field, B, is directly proportional 
to the current, I, and inversely proportional 
to the circumference. 
r 
I 
B 
A 
Tm 
x x 
r 
I 
B 
r 
B I B 
o 
o 
 
m 
m  
m 
m 
 
 
 
  
2 
4 10 (1.26 10 ) 
vacuum permeability constant 
constant of proportionality 
2 
2 
1 
internal 
7 6 
o 
o 
 
 
 
 
 
Example 
A long, straight wires carries a current of 5.00 A. At one instant, a 
proton, 4 mm from the wire travels at 1500 m/s parallel to the 
wire and in the same direction as the current. Find the 
magnitude and direction of the magnetic force acting on the 
proton due to the field caused by the current carrying wire. 
  
  
  
 
 
(1.6 10 )(1500)( ) 
2(3.14)(0.004) 
(1.26 10 )(5) 
2 
19 
6 
B wire 
IN 
o 
B EX IN 
F x B 
x 
B 
r 
I 
F qvB B 
 
m 
5A 
4mm 
+ 
v 
2.51 x 10- 4 T 
6.02 x 10- 20 N 
X X X 
X X X 
X X X 
X X X 
X X X 
X X X 
B = +z 
v = +y 
F = -x

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Lecture 8 3_n_8_4_magnetic_force

  • 2. Facts about Magnetism Magnets have 2 poles (north and south) Like poles repel Unlike poles attract Magnets create a MAGNETIC FIELD around them
  • 3. Magnetic Field A bar magnet has a magnetic field around it. This field is 3D in nature and often represented by lines LEAVING north and ENTERING south To define a magnetic field you need to understand the MAGNITUDE and DIRECTION We sometimes call the magnetic field a B-Field as the letter “B” is the SYMBOL for a magnetic field with the TESLA (T) as the unit.
  • 4. Magnetic Force on a moving charge If a MOVING CHARGE moves into a magnetic field it will experience a MAGNETIC FORCE. This deflection is 3D in nature. N N S S - vo B F qvBsin F qv B B B       The conditions for the force are: •Must have a magnetic field present •Charge must be moving •Charge must be positive or negative •Charge must be moving PERPENDICULAR to the field.
  • 5. Example A proton moves with a speed of 1.0x105 m/s through the Earth’s magnetic field, which has a value of 55mT at a particular location. When the proton moves eastward, the magnetic force is a maximum, and when it moves northward, no magnetic force acts upon it. What is the magnitude and direction of the magnetic force acting on the proton?        B B B F F x x x F qvB (1.6 10 )(1.0 10 )(55 10 ) , 90, sin 90 1 19 5 6  8.8x10-19 N The direction cannot be determined precisely by the given information. Since no force acts on the proton when it moves northward (meaning the angle is equal to ZERO), we can infer that the magnetic field must either go northward or southward.
  • 6. Direction of the magnetic force? Right Hand Rule To determine the DIRECTION of the force on a POSITIVE charge we use a special technique that helps us understand the 3D/perpendicular nature of magnetic fields. Basically you hold your right hand flat with your thumb perpendicular to the rest of your fingers •The Fingers = Direction B-Field •The Thumb = Direction of velocity •The Palm = Direction of the Force For NEGATIVE charges use left hand!
  • 7. Example Determine the direction of the unknown variable for a proton moving in the field using the coordinate axis given +y +x +z B = -x v = +y F = +z B =+Z v = +x F = -y B = -z v = +y F = -x
  • 8. Example Determine the direction of the unknown variable for an electron using the coordinate axis given. +y +x +z B = +x v = +y F = +z B = v = - x F = +y -z F B B = +z v = F = +y +x
  • 9. Magnetic Force and Circular Motion X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X X v B - - FB FB FB FB - - - Suppose we have an electron traveling at a velocity , v, entering a magnetic field, B, directed into the page. What happens after the initial force acts on the charge?
  • 10. Magnetic Force and Circular Motion The magnetic force is equal to the centripetal force and thus can be used to solve for the circular path. Or, if the radius is known, could be used to solve for the MASS of the ion. This could be used to determine the material of the object. There are many “other” types of forces that can be set equal to the magnetic force.
  • 11. Example ? 0.5 250 2.5 10 1.6 10 26 19         r B T V V m x kg q x C qB mv r r mv F F qvB B c    2            26 19 2 2.5 10 2 2(250)(1.6 10 ) 2 1 x x m Vq v q mv q K q W V A singly charged positive ion has a mass of 2.5 x 10-26 kg. After being accelerated through a potential difference of 250 V, the ion enters a magnetic field of 0.5 T, in a direction perpendicular to the field. Calculate the radius of the path of the ion in the field. We need to solve for the velocity! 56,568 m/s     (1.6 10 )(0.5) (2.5 10 )(56,568) 19 26 x x r 0.0177 m
  • 12. Charges moving in a wire Up to this point we have focused our attention on PARTICLES or CHARGES only. The charges could be moving together in a wire. Thus, if the wire had a CURRENT (moving charges), it too will experience a force when placed in a magnetic field. You simply used the RIGHT HAND ONLY and the thumb will represent the direction of the CURRENT instead of the velocity.
  • 13. Charges moving in a wire    sin ( )( ) sin sin F ILB vt B t q F t t F qvB B B B     At this point it is VERY important that you understand that the MAGNETIC FIELD is being produced by some EXTERNAL AGENT
  • 14. Example A 36-m length wire carries a current of 22A running from right to left. Calculate the magnitude and direction of the magnetic force acting on the wire if it is placed in a magnetic field with a magnitude of 0.50 x10-4 T and directed up the page.     B B B F F x F ILB (22)(36)(0.50 10 ) sin 90 sin 4  0.0396 N B = +y I = -x F = +y +z +x -z, into the page
  • 15. WHY does the wire move? The real question is WHY does the wire move? It is easy to say the EXTERNAL field moved it. But how can an external magnetic field FORCE the wire to move in a certain direction? THE WIRE ITSELF MUST BE MAGNETIC!!! In other words the wire has its own INTERNAL MAGNETIC FIELD that is attracted or repulsed by the EXTERNAL FIELD. As it turns out, the wire’s OWN internal magnetic field makes concentric circles round the wire.
  • 16. A current carrying wire’s INTERNAL magnetic field To figure out the DIRECTION of this INTERNAL field you use the right hand rule. You point your thumb in the direction of the current then CURL your fingers. Your fingers will point in the direction of the magnetic field
  • 17. The MAGNITUDE of the internal field The magnetic field, B, is directly proportional to the current, I, and inversely proportional to the circumference. r I B A Tm x x r I B r B I B o o  m m  m m      2 4 10 (1.26 10 ) vacuum permeability constant constant of proportionality 2 2 1 internal 7 6 o o      
  • 18. Example A long, straight wires carries a current of 5.00 A. At one instant, a proton, 4 mm from the wire travels at 1500 m/s parallel to the wire and in the same direction as the current. Find the magnitude and direction of the magnetic force acting on the proton due to the field caused by the current carrying wire.         (1.6 10 )(1500)( ) 2(3.14)(0.004) (1.26 10 )(5) 2 19 6 B wire IN o B EX IN F x B x B r I F qvB B  m 5A 4mm + v 2.51 x 10- 4 T 6.02 x 10- 20 N X X X X X X X X X X X X X X X X X X B = +z v = +y F = -x