Ch 9 Stoichiometry

Stoichiometry Chemistry: Chapter 9

Molar Mass of Compounds ,[object Object],[object Object],[object Object],[object Object],[object Object],20 C a 40.08 17 Cl 35.45

Flowchart Atoms or Molecules Moles Mass (grams) Divide by 6.02 X 10 23 Multiply by 6.02 X 10 23 Multiply by atomic/molar mass from periodic table Divide by atomic/molar mass from periodic table

Practice ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],Ca 3 (PO 4 ) 2 120.3 g 62.0 g 128.0 g 120.3g + 62.0g +128.0g 310.3 g/mol

[object Object],[object Object],Calculations

Chocolate Chip Cookies!! ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],How many eggs are needed to make 3 dozen cookies? How much butter is needed for the amount of chocolate chips used? How many eggs would we need to make 9 dozen cookies? How much brown sugar would I need if I had 1 ½ cups white sugar?

Cookies and Chemistry…Huh!?!? ,[object Object],[object Object],[object Object],[object Object]

Chemistry Recipes ,[object Object],[object Object],[object Object],[object Object],[object Object]

Practice ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],2 mol H 2 1 mol O 2 4 mol H 2 2 mol O 2 6 mol H 2 , 6 mol H 2 O 25 mol O 2 , 50 mol H 2 O

Mole Ratios ,[object Object],[object Object],[object Object],5 moles Na 1 mol Cl 2 2 mol Na = 2.5 moles Cl 2

Mole-Mole Conversions ,[object Object],[object Object],2.6 moles Cl 2 2 mol NaCl 1 mol Cl 2 = 5.2 moles NaCl

Mole-Mass Conversions ,[object Object],[object Object],[object Object],[object Object],5.00 moles Na 1 mol Cl 2 70.90g Cl 2 2 mol Na 1 mol Cl 2 = 177g Cl 2

Practice ,[object Object],[object Object],0.50 moles Al 3 moles I 2 253.8g I 2 2 moles Al 1 mole I 2 = 190.35 g I 2

Mass-Mole ,[object Object],[object Object],[object Object],[object Object],10.0 g H 2 O 1 mol H 2 O 2 mol C 2 H 6 18.0 g H 2 O 6 mol H 2 0 = 0.185 mol C 2 H 6

Practice ,[object Object],[object Object],10.0g Al 2 O 3 1 mol Al 2 O 3 3 mol O 2 101.96g Al 2 O 3 2 mol Al 2 O 3 = 0.147 mol O 2

Mass-Mass Conversions ,[object Object],[object Object]

Mass-Mass Conversion ,[object Object],[object Object],2.00g N 2 1 mol N 2 2 mol NH 3 17.06g NH 3 28.02g N 2 1 mol N 2 1 mol NH 3 = 2.4 g NH 3

Practice ,[object Object],[object Object],2.00g Ca 1 mol Ca 1 mol Ca 3 N 2 148.26g Ca 3 N 2 40.08g Ca 3 mol Ca 1 mol Ca 3 N 2 = 2.47 g Ca 3 N 2

Limiting Reactant: Cookies ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],If we had the specified amount of all ingredients listed, could we make 4 dozen cookies? What if we had 6 eggs and twice as much of everything else, could we make 9 dozen cookies? What if we only had one egg, could we make 3 dozen cookies?

Limiting Reactant ,[object Object],[object Object],[object Object]

Limiting Reactant ,[object Object],[object Object],[object Object],[object Object]

Limiting Reactant: Example ,[object Object],[object Object],[object Object],[object Object],10.0 g Al 1 mol Al 2 mol AlCl 3 133.5 g AlCl 3 27.0 g Al 2 mol Al 1 mol AlCl 3 = 49.4g AlCl 3 35.0g Cl 2 1 mol Cl 2 2 mol AlCl 3 133.5 g AlCl 3 71.0 g Cl 2 3 mol Cl 2 1 mol AlCl 3 = 43.9g AlCl 3 Limiting Reactant

LR Example Continued ,[object Object]

Limiting Reactant Practice ,[object Object]

Limiting Reactant Practice ,[object Object],[object Object],[object Object],[object Object],15.0g K 1 mol K 2 mol KI 166 g KI 39.1g K 2 mol K 1 mol KI = 63.7g KI 15.0 g I 2 1 mol I 2 2 mol KI 166 g KI 254 g I 2 1 mol I 2 1 mol KI = 19.6 g KI

Finding the Amount of Excess ,[object Object],[object Object]

Finding Excess Practice ,[object Object],[object Object],15.0 g I 2 1 mol I 2 2 mol K 39.1 g K 254 g I 2 1 mol I 2 1 mol K = 4.62 g K USED! 15.0 g K – 4.62 g K = 10.38 g K EXCESS Given amount of excess reactant Amount of excess reactant actually used Note that we started with the limiting reactant! Once you determine the LR, you should only start with it!

Limiting Reactant: Recap ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]

Ch 9 Stoichiometry

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Ch 9 Stoichiometry