Please show all work and explaining reasoning behind steps and final answer thank you! Match the reaction to its energy diagram. Assume that each reaction is an overall exothermic process (i.e. the products have lower potential energy than the starting materials) Reactions Cl ?? 1) MeOH 2) HI H20 3) 4) EtOH NaSH acetone OSO2CH3 OSO2CH3 Energy diagrams IV Solution Matching the reaction to its energy diagram. Given below are four reactions and four energy diagrams First we will identify type of mechanism occruing in each case 1) and 2) and 3) are clearly Sn1 reactions. 4) is Sn2 reactions NaSH is a better nucleophile for Sn2 than EtOH and thus we have clear Sn2 reaction in case of 4) So, for 4) -- energy diagram = II and, for 3) -- energy diagram = III (forms secondary to tertiary carbocation more stable) 1) and 3) are tertiary alkyl halides, react fast in Sn1 conditions, with 2) will be faster than in acid medium. So, for 2) -- energy diagram = I and, for 1) -- energy diagram = IV(forms tertiary to secondary carbocation and then elimination) .

1. Please show all work and explaining reasoning behind steps and final answer
thank you!
Match the reaction to its energy diagram. Assume that each reaction is an overall exothermic
process (i.e. the products have lower potential energy than the starting materials) Reactions Cl ??
1) MeOH 2) HI H20 3) 4) EtOH NaSH acetone OSO2CH3 OSO2CH3 Energy diagrams IV
Solution
Matching the reaction to its energy diagram.
Given below are four reactions and four energy diagrams
First we will identify type of mechanism occruing in each case
1) and 2) and 3) are clearly Sn1 reactions.
4) is Sn2 reactions
NaSH is a better nucleophile for Sn2 than EtOH and thus we have clear Sn2 reaction in case of
4)
So, for 4) -- energy diagram = II
and,
for 3) -- energy diagram = III (forms secondary to tertiary carbocation more stable)
1) and 3) are tertiary alkyl halides, react fast in Sn1 conditions, with 2) will be faster than in acid
medium.
So, for 2) -- energy diagram = I
and,

2. for 1) -- energy diagram = IV(forms tertiary to secondary carbocation and then
elimination)