The document describes a circuit with 3 capacitors (C1, C2, C3) connected in series and parallel configurations. It then asks two questions:
(1) Find the equivalent capacitance between points a and b.
(2) If the potential between a and b is 60V, what is the charge stored on C3?
The solution shows that the equivalent capacitance is 3.95 uF. It then uses the given potential and equivalent capacitance to calculate that the charge stored on C3 is 40.9 uC.
Consider the following figure- (a) Find the equivalent capacitance bet.docx
1. Consider the following figure.
(a) Find the equivalent capacitance between points a and b for the group of capacitors connected
as shown in the figure if
C 1 = 8.00 ? F,
C 2 = 12.00 ? F,
and
C 3 = 2.00 ? F.
? F
(b) If the potential between points a and b is 60.0 V, what charge is stored on C 3 ?
? C
Min ??? == =
Solution
here,
a)
C2 and C2 are in parallel , their equivallent capacitance , C4 = C2/2 = 6 uF
(C1 and C2) are in series ,their equivalent capacitance , C5 = C1 * C2 /( C1 + C2)
C5 = 8 * 12 /( 8 + 12) = 4.8 uF
C5 , C5 and C3 are in parallel, their equivalent capacitance , C6 = C5 + C5 + C3
C6 = 11.6 uF
2. C6 and C4 are series , the equivalent capacitance , Ceq = C6 * C4 /( C6 + C4)
Ceq = 11.6 * 6 /( 11.6 + 6) uF
Ceq = 3.95 uF
b)
V = 60 V
the potential across C3 , V3 = ( V - Ceq * V /C4)
V3 = ( 60 - 3.95 * 60 /6) V
V3 = 20.5 V
the charge stored in C3 , Q3 = C3 * V3
Q3 = 40.9 uC