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Force system in space Equilibrium of Concurrent Forces  in Space Statics Of rigid bodies
EQUILIBRIUM is defined as that condition when the resultant of the system of force is zero. Statics Of rigid bodies Equilibrium Equations;
Example: The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10) Neglecting the weights of the members, determine the forces in AB, AC & AD. y 1000 lb A 20 ft C 10 ft D B 10 ft x o 10 ft 5 ft 6 ft z
Example: The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10) Neglecting the weights of the members, determine the forces in AB, AC & AD. y 1000 lb A 20 ft Cz Cx C 10 ft Cy Dx D B x o 10 ft 5 ft 6 ft Dz By Dy z
y Yc 1000 lb 0 (10) (15) -Dx +(1000) = A = Dx 667 lb 20 ft x = 10 ft Cz Cx 15 ft y = 20 – 6 = 14 ft z = 5 ft C 10 ft Cy 10 ft Dx D B d = 17.916 ft x o 10 ft 6 ft 5 ft Dy = 933 lb Dz By Dy Dz = 333 lb z AD = 1192 lb T

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Force system in space

  • 1. Force system in space Equilibrium of Concurrent Forces in Space Statics Of rigid bodies
  • 2. EQUILIBRIUM is defined as that condition when the resultant of the system of force is zero. Statics Of rigid bodies Equilibrium Equations;
  • 3. Example: The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10) Neglecting the weights of the members, determine the forces in AB, AC & AD. y 1000 lb A 20 ft C 10 ft D B 10 ft x o 10 ft 5 ft 6 ft z
  • 4. Example: The framework shown is composed of three members AB, AC & AD. Points B & C are in the same horizontal plane. Points C & D are in the same vertical plane. At A a 1000lb force acts in a direction parallel to the x-axis. Point B is located at the origin, A(0,+20,0),D(-10,6,5) & C(-10,0,-10) Neglecting the weights of the members, determine the forces in AB, AC & AD. y 1000 lb A 20 ft Cz Cx C 10 ft Cy Dx D B x o 10 ft 5 ft 6 ft Dz By Dy z
  • 5. y Yc 1000 lb 0 (10) (15) -Dx +(1000) = A = Dx 667 lb 20 ft x = 10 ft Cz Cx 15 ft y = 20 – 6 = 14 ft z = 5 ft C 10 ft Cy 10 ft Dx D B d = 17.916 ft x o 10 ft 6 ft 5 ft Dy = 933 lb Dz By Dy Dz = 333 lb z AD = 1192 lb T