1. develop a C program to print the sum, the average, the product, the largest and the smallest of 3 integers that are input from the keyboard.
2. define an array x of size 5, using call-by-reference (that is, use pointer) to pass the array to a function, named summation.
In main: define array, print out the array, pass the array and show the results on screen.
In function summation: take arrays from main and sum the arrays using the formula below
sum=4summation0 xi*xi
Solution
#include <stdio.h>
#include<conio.h>
void summation(int a[],int size)
{
int i;
int sum = 0;
for(i=0;i<size;i++)
{
sum = sum+ 4*a[i]*a[i];
}
printf(\"\ Summation is %d\",sum);
}
int main(void) {
// your code goes here
int a,size;
int b[] = {1,2,3};
int i =0,max = 0,min =0 ,sum = 0 ,product = 1,average = 0 ;
for(i=0;i<3;i++)
{
printf(\"Enter the value of %d number\",i+1);
scanf(\"%d\",&a);
if(i==0)
min = a;
sum =sum+a;
product = product*a;
if(a>=max)
max = a;
if(a<=min)
min = a;
}
average = sum/3;
printf(\"Sum is %d\ Product is %d\ average is %d\ max is %d\ min is %d\ \",sum,product,average,max,min);
size = sizeof(b)/sizeof(b[1]);
printf(\"Array Content\ \");
for(i=0;i<size;i++)
{
printf (\"%d \",b[i]);
}
summation(b,size);
getch();
return 0;
}
.
1- develop a C program to print the sum- the average- the product- the.docx
1. 1. develop a C program to print the sum, the average, the product, the largest and the smallest of
3 integers that are input from the keyboard.
2. define an array x of size 5, using call-by-reference (that is, use pointer) to pass the array to a
function, named summation.
In main: define array, print out the array, pass the array and show the results on screen.
In function summation: take arrays from main and sum the arrays using the formula below
sum=4summation0 xi*xi
Solution
#include <stdio.h>
#include<conio.h>
void summation(int a[],int size)
{
int i;
int sum = 0;
for(i=0;i<size;i++)
{
sum = sum+ 4*a[i]*a[i];
}
printf(" Summation is %d",sum);
}
int main(void) {
// your code goes here
int a,size;
int b[] = {1,2,3};
int i =0,max = 0,min =0 ,sum = 0 ,product = 1,average = 0 ;
2. for(i=0;i<3;i++)
{
printf("Enter the value of %d number",i+1);
scanf("%d",&a);
if(i==0)
min = a;
sum =sum+a;
product = product*a;
if(a>=max)
max = a;
if(a<=min)
min = a;
}
average = sum/3;
printf("Sum is %d Product is %d average is %d max is %d min is %d
",sum,product,average,max,min);
size = sizeof(b)/sizeof(b[1]);
printf("Array Content ");
for(i=0;i<size;i++)
{
printf ("%d ",b[i]);
}
summation(b,size);
getch();
return 0;
}
![1. develop a C program to print the sum, the average, the product, the largest and the smallest of
3 integers that are input from the keyboard.
2. define an array x of size 5, using call-by-reference (that is, use pointer) to pass the array to a
function, named summation.
In main: define array, print out the array, pass the array and show the results on screen.
In function summation: take arrays from main and sum the arrays using the formula below
sum=4summation0 xi*xi
Solution
#include <stdio.h>
#include<conio.h>
void summation(int a[],int size)
{
int i;
int sum = 0;
for(i=0;i<size;i++)
{
sum = sum+ 4*a[i]*a[i];
}
printf(" Summation is %d",sum);
}
int main(void) {
// your code goes here
int a,size;
int b[] = {1,2,3};
int i =0,max = 0,min =0 ,sum = 0 ,product = 1,average = 0 ;](https://image.slidesharecdn.com/1-developacprogramtoprintthesum-theaverage-theproduct-the-230208161921-1b2d5168/85/1-develop-a-C-program-to-print-the-sum-the-average-the-product-the-docx-1-320.jpg)
![for(i=0;i<3;i++)
{
printf("Enter the value of %d number",i+1);
scanf("%d",&a);
if(i==0)
min = a;
sum =sum+a;
product = product*a;
if(a>=max)
max = a;
if(a<=min)
min = a;
}
average = sum/3;
printf("Sum is %d Product is %d average is %d max is %d min is %d
",sum,product,average,max,min);
size = sizeof(b)/sizeof(b[1]);
printf("Array Content ");
for(i=0;i<size;i++)
{
printf ("%d ",b[i]);
}
summation(b,size);
getch();
return 0;
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)