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International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 607
Design and optimization of wheel hub for formula ATA race car
Abhishek Dabb1, Aditya Mukati2, Yuvrajsingh Rathod3, Anujith Nair4 , Adil Radhanpura5,
Shantanu Gadekar6
1 Professor, Dept. of Mechanical Engineering, Dr. D. Y Patil Inst. of Technology, Pune, India
2,3,4,5,6 U.G Student, Dept. of Mechanical Engineering, Dr. D. Y Patil Inst. of Technology, Pune, India
---------------------------------------------------------------------***---------------------------------------------------------------------
Abstract - Formula ATA is an annual international university
level design competition organized by the Society of
Automobile Engineers. The purpose of this project is to design
and manufacture the wheel hub for Formula FSAE vehicle.
The purpose of this wheel hub is to provide a mounting to
uprights which links the suspension arms to the chassis and
wheel assembly, as well as carrying brake components. It is
a load bearing member of the upright systemandisconstantly
moving with the motion of the wheel. The design of the 2k18
upright wheel hub assemblies achieved a total weight
reduction of over 500 grams, which improves to a 50%
reduction overall. This is achieved with no loss in stiffness
according to the Finite Element Analysis in the computer.
1. INTRODUCTION
The motive of our project is to design, analyze and fabricate
the wheel hub of our team “THE INTERCEPTORS”, an FSAE
vehicle. Formula Student is one of numerous competitions
that are held for students at university level yet it is one of
the largest engineering competitions for student’s
worldwide. The aim is to supply a lighter and overall
performance oriented design of upright meeting in
evaluation with season 2017-2018 automobile and thereby
contributing in making of automobile of season 2018-2019
higher than its predecessor. Use of conventional upright
assembly will increase the overall weight of the race car.For
FSAE car, weight standards is a major factor in making of
race car and in addition, to opposition factor of view. The
intention of lighter weight upright assembly may be
achieved by less complex layout and proper material
selection. Hence the modified wheel hub is designed for the
required fatigue life. Also the proper stiffness and reliability
can be achieved by means of evaluation thedesignofupright
meeting. Wheel bearings are as vintage and critical as the
wheel itself, thanks to their ability to allow unfastened
rotation without the harmful effects of friction and put on.
We're going to also cowl the variations between "wheel
bearings" or "axle bearings" established at the wheel itself
together with "axle shaft bearings" placed in addition
inboard alongside axle shafts. Despite the fact that bearings
are available in a diffusion of shapes, they all serve the
identical basic reason. A Wheel Hub Assembly (WHA), also
known as hub assembly, wheel hub unit, wheel hub bearing,
etc., is an automotive component utilized in most vehicles,
passenger vehicles, and lightandheavyvans.The Wheel Hub
Assembly is placed among the brake drums or discs and the
force axle. A wheel is bolted on it. Relying on the
construction, the hub comes geared up with the splined
teeth. They mate the enamel at the axle shaft. The axle hub
spins alongside the wheels bolted toitandofferthepowerto
the wheels if you want to rotate. The upright connects the
control arms to the hub which connects the upright to the
wheels allowing the vehicle to move. The uprights also
connect to the steering arm, allowing the driver to steer the
vehicle, and the caliper, allowing the driver to stop the
vehicle. The hub is directly connected to the wheel, and is
connected to the upright. The upright istoremainstationary
relative to the chassis while the hub is to rotate with the
wheel. This is done by placing a bearing between the hub
and upright. Typically, a spindle is pressed into the upright
and does not rotate and a bearing is pressed into the hub,
and the spindle is pressed into the bearingsallowingthehub
to rotate about the spindle. Unsprang mass is themassofthe
wheel, hub, rotor, caliper, uprights, and brake pad.
Essentially unsprang mass is the mass that is not supported
by the shocks (for example the chassis and everything
supported by the chassis is sprung mass). In this case of the
current design, it also provides a means of adjustment tothe
suspension parameters such as camber and steering
Ackerman geometry
2. DESIGN WORK
The main objectives in this project are to reduce the mass,
both the total mass and the unsprung mass of the Wheel
Hub, with retained strength and function. Therefore, all
containing parts are analysed in the Pre-study to define the
current masses. The current parts are both measured in
experiments by a scale and measured in Catia, this due to
investigate the accuracy of the measurements madeinCatia.
The new designs are only measured in Catia.
3. MATERIAL
The hubs are designed to mate with center locking 10”
Keizer rims. The front hubs have been manufactured out of
7075 aluminum by considering weight reduction. The rear
hubs incorporate a hardened steel tripod housing
coordinated on CMM that is inserted into the hub,
eliminating wear issues with the aluminum. EN-24 is the
material chosen forrearhubsconsideringthetorqueexerted
by half shaft into the hubs.
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 608
3.1 WHEELS
A 10-inch rim is the team’s choice to lower thetorquetospin
the wheel as compared to 13 inch. Hence the time taken for
10 inch wheel to reach peak torque value and rpm for each
gear has been reduced comparison to 13 inch wheel, which
would thus accelerate the car faster.Asmallerwheel sizehas
also aggravated the weight reduction of un-sprung mass.
Fig1: Rim
4. FORCES NORMAL CONDITION
To calculate the forces on the wheels, two Free Body
Diagrams are performed in Figure the car is seen from the
front, and Figure 1 the car is seen from the left side to make
assumptions of the forces acting.A“Normal condition”-drive
is where no un-normal behavior of the car appears, and the
track is smooth with no ruts, wet or loose gravel and tarmac.
Fig2: Free Body Diagram y-z-plane
To assume and show that the forces acting on the ground is
equal or assumed to be equal at the Hub see Figure 2. By
static Equations 2 and 3the forces on the system are in
equilibrium when the forces at the ground are equal to the
forces at the Hub. This assumption will be use in this project
as a simplification; some differences will be covered by a
Safety Factor.
Fig3: Forces on Hub and wheel
4.1 ACCELERATION TORQUE
FEA was used to confirm the hub design could withstandthe
torque applied by both the wheelsandthebrakes.Amoment
of 100000 N-mm was applied on the wheel mountings
keeping the disc mounting constant. The maximum normal,
lateral, and braking force was applied to the front upright
while keeping the control arm fixed.
Fig4: Free Body Diagram Torque applied
4.2 BRAKING TORQUE
The Wheel Hub is affected through the Brake Disk Adapter
which is assembled on the Hub and fixed on the wheel nuts
with the rim. The moment acting on the Hub is interesting.
Things that has to be consider when making assumptions of
this is the Brake Balance, the speed and acc eleration of the
car. These data are collected and used in this analysis, see
Figure 4 for a plot of Speed vs. time in MATLAB® from the
collected data. The Brake Pressure, or Brake Balance is not
analysed, and the braking is only calculated related to the
total acceleration during the braking.
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 609
Fig5: Speed vs. Time
The Free Body Diagram in Figure 5 showing the torque
acting on the Wheel Hub and the forces from the ground
during the braking, assumption this is equal at all four
wheels and this calculation performed at the front, or rear
right wheel.
Fig6: Free Body Diagram Braking
By comparing the torque applied in acceleration and the
torque caused by the braking is approximate a factor of ten
larger, and therefore the most critical torque acting on the
Hub.
5. CALCULATIONS
Determining the forces acting on the Hub.
The following Forces are acting on the Hub.
a. Torque on the Brake Disk Petal : -
A 130 Nm torque is acting on the Brake Disk Petal.
The Force acting on each hole=
= = 650N
b. Torque on the Wheel Petal : -
In order to sustain this braking effect the wheel must also
provide and equal and opposite torque. Thus the magnitude
of torque is same but the direction is opposite.
The Force acting on each hole =
= 650N
c. Force due to Side Impact: -
If the vehicle is banged by other vehicle from side or if the
vehicle has a collision with the fencing from side, there are
chances that the petals might bend. Hence this side impact
force must also be considered.
Here the side Impact force is taken to be 2G = 2 × g × vehicle
mass
Impact force = 2 × 9.81 × 300 = 5409 N
Impact force on 1 petal = 8829/3 = 1352.2 N
d. Loads on Bearing: -
The load on 1 bearing is 700 N
The load on 2nd bearing is 634 N
The axial load is 1388 N
Selection of Wheel Bolt
Shear Stress on the bolts = τ= 145N/mm2
The force acting on the Wheel Bolt is given by the result
now,
τ=
145 =
Dc = 2.99mm
D = dc/0.8
D = 2.99/0.8
D = 3.74mm
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 610
Selection of Brake Disk Bolt
Shear Stress on the bolts =τ= =68.75N/mm2
The force acting on the Wheel Bolt is given by the result.
now,
τ=
68.75=650/(π/4*dc*dc)
dc=
dc=3.46
d=4.33mm
Thus selecting the bolt size of M8.
Design of Wheel Petal
Shear Failure of Petal
Allowable stress in the Hub in shear
= τ= =125.75N/mm2
Force acting on Petal as obtained from result is 880 N.
Now,
τ=
125.75 =
t × b = 3.5
Where,
t= thickness of Wheel Petal
b= distance between the hole and the end of petal
If t = 8mm b= 0.475 mm
Thus the width of the petal is taken to be 7mm
The thickness of the petal is as 8 mm.
Bending of Wheel Petal
This bending is due to the force of 880 N. The radius of
effective bending is 49.25 mm
Mb = 880 × 49.25
Mb = 43340 N-mm
Now,
By Flexural Equation:
σb= =503/2=251.5N/mm2
y= 2b/2
2b=d
I= 3
Where,
t= thickness of knuckle
b= width of knuckle
=
T*d3=1034
If t= 8mm d = 11.36 mm
Thus, the width of knuckle is 12mm.
The thickness of knuckle is 8 mm.
Total thickness = width + dia of hole =12+14 = 26 mm
Design of Brake Disk Petal
Shear Failure of Petal
Allowable stress in the Hub in shear = τ=
= =125.75N/mm2
σb= =503/2=251.5N/mm2
y= t/2
I= 3
International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056
Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072
© 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 611
Where,
t= thickness of petal
b= width of petal =27 mm
Force acting on Petal as obtained from result is 880 N.
τ=
=
t = 6.61mm
The thickness of petal is taken as 8 mm
125.75=
t × b = 1.7495
Where,
t= thickness of Wheel Petal
b= distance between the hole and the end of petal
If t = 5mm b = 0.35 mm
Thus the width of the petal is taken to be 5mm.
The thickness of the petal is taken as 6mm.
Design of Wheel petal due to Side Impact
The force is obtained from the result for 1 petal = 1962 N
The effective bending Radius = 25.25 mm
Mb = 1962 × 25.25
Mb = 49540.5 N-mm
From the above result it is clear that hub without fillet and
triangulation support were more prone to failure thanthose
with fillet and triangulation support.
Besides the stress concentrationintheoptimizeddesign was
less.
6. CONCLUSION
The observation made while working throughthisprojectis
that the possibilities to improve the Wheel Hub is large. The
design developed in this project is a big step forward to
reduce the unsprung mass of the car. The design will not
affect the geometry of the suspension and therefore the
behaviour of the car in that aspect. Theadvantagesofchange
to the re-designed Hub will increase the acceleration of the
car and improve the traction between tire and road. The
limitations set in this project makes it difficult to make the
changes needed to find the optimal design.Evenifthedesign
will improve the car by making small changes can an
advantage in changing the upright and suspensiongeometry
an even more innovative design with less unsprung mass
and advantages in suspension geometry, heat flux etc.
REFERENCES
[1] Callum W. Watson, The OtimumWeightDistributionFor
a Formula SAE Vehicle , , University of New South Wales
at the Australian Defense Force Academy
[2] Pruthviraj Vitthal Wable and Sahil Sanjog Shah, Design
Analysis & Optimization of Hub Used in FSAE Cars, , UG
Student, Department of Mechanical Engineering,Trinity
College of Engineering and Research, Pune,
Maharashtra, India.
[3] Joijode Vrushabh Umeshand YadavAbhishek,Designing
and Optimization of Wheel Assembly of a Formula
Student Car, , Mechanical Engineering Department,
Vishwakarma Institite of Technology, 666, UpperIndira
Nagar, Pune-37, India.
[4] L. Daniel Metz, William F. Miliken, Douglas L. Miliken,
Race Car Vehicle Dynamics Workbook, SAE
intenationals, 1998.
[5] Óskar Kúld Pétursson, Uprights, wheel hubs and brake
system for a new Formula Student race car, School of
Science and Engineering Tækni- og verkfræðideild,
Kennitala 110489–3239.
[6] Alejandro Diaz ,Osvaldo Fernandez, Ricardo Gonzalez,
Christian Ramos, FSAE 2015 Chassis and Suspension
Final Report, EML 4905 Senior Design Project, Florida
International University.
[7] William Kinkead, ME Connor Morette, ME Adrian
Pickering, ME Zachary Sears,DesignandOptimizationof
a Formula SAE Vehicle, Worcester Polytechnic Institute.

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  • 1. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 607 Design and optimization of wheel hub for formula ATA race car Abhishek Dabb1, Aditya Mukati2, Yuvrajsingh Rathod3, Anujith Nair4 , Adil Radhanpura5, Shantanu Gadekar6 1 Professor, Dept. of Mechanical Engineering, Dr. D. Y Patil Inst. of Technology, Pune, India 2,3,4,5,6 U.G Student, Dept. of Mechanical Engineering, Dr. D. Y Patil Inst. of Technology, Pune, India ---------------------------------------------------------------------***--------------------------------------------------------------------- Abstract - Formula ATA is an annual international university level design competition organized by the Society of Automobile Engineers. The purpose of this project is to design and manufacture the wheel hub for Formula FSAE vehicle. The purpose of this wheel hub is to provide a mounting to uprights which links the suspension arms to the chassis and wheel assembly, as well as carrying brake components. It is a load bearing member of the upright systemandisconstantly moving with the motion of the wheel. The design of the 2k18 upright wheel hub assemblies achieved a total weight reduction of over 500 grams, which improves to a 50% reduction overall. This is achieved with no loss in stiffness according to the Finite Element Analysis in the computer. 1. INTRODUCTION The motive of our project is to design, analyze and fabricate the wheel hub of our team “THE INTERCEPTORS”, an FSAE vehicle. Formula Student is one of numerous competitions that are held for students at university level yet it is one of the largest engineering competitions for student’s worldwide. The aim is to supply a lighter and overall performance oriented design of upright meeting in evaluation with season 2017-2018 automobile and thereby contributing in making of automobile of season 2018-2019 higher than its predecessor. Use of conventional upright assembly will increase the overall weight of the race car.For FSAE car, weight standards is a major factor in making of race car and in addition, to opposition factor of view. The intention of lighter weight upright assembly may be achieved by less complex layout and proper material selection. Hence the modified wheel hub is designed for the required fatigue life. Also the proper stiffness and reliability can be achieved by means of evaluation thedesignofupright meeting. Wheel bearings are as vintage and critical as the wheel itself, thanks to their ability to allow unfastened rotation without the harmful effects of friction and put on. We're going to also cowl the variations between "wheel bearings" or "axle bearings" established at the wheel itself together with "axle shaft bearings" placed in addition inboard alongside axle shafts. Despite the fact that bearings are available in a diffusion of shapes, they all serve the identical basic reason. A Wheel Hub Assembly (WHA), also known as hub assembly, wheel hub unit, wheel hub bearing, etc., is an automotive component utilized in most vehicles, passenger vehicles, and lightandheavyvans.The Wheel Hub Assembly is placed among the brake drums or discs and the force axle. A wheel is bolted on it. Relying on the construction, the hub comes geared up with the splined teeth. They mate the enamel at the axle shaft. The axle hub spins alongside the wheels bolted toitandofferthepowerto the wheels if you want to rotate. The upright connects the control arms to the hub which connects the upright to the wheels allowing the vehicle to move. The uprights also connect to the steering arm, allowing the driver to steer the vehicle, and the caliper, allowing the driver to stop the vehicle. The hub is directly connected to the wheel, and is connected to the upright. The upright istoremainstationary relative to the chassis while the hub is to rotate with the wheel. This is done by placing a bearing between the hub and upright. Typically, a spindle is pressed into the upright and does not rotate and a bearing is pressed into the hub, and the spindle is pressed into the bearingsallowingthehub to rotate about the spindle. Unsprang mass is themassofthe wheel, hub, rotor, caliper, uprights, and brake pad. Essentially unsprang mass is the mass that is not supported by the shocks (for example the chassis and everything supported by the chassis is sprung mass). In this case of the current design, it also provides a means of adjustment tothe suspension parameters such as camber and steering Ackerman geometry 2. DESIGN WORK The main objectives in this project are to reduce the mass, both the total mass and the unsprung mass of the Wheel Hub, with retained strength and function. Therefore, all containing parts are analysed in the Pre-study to define the current masses. The current parts are both measured in experiments by a scale and measured in Catia, this due to investigate the accuracy of the measurements madeinCatia. The new designs are only measured in Catia. 3. MATERIAL The hubs are designed to mate with center locking 10” Keizer rims. The front hubs have been manufactured out of 7075 aluminum by considering weight reduction. The rear hubs incorporate a hardened steel tripod housing coordinated on CMM that is inserted into the hub, eliminating wear issues with the aluminum. EN-24 is the material chosen forrearhubsconsideringthetorqueexerted by half shaft into the hubs.
  • 2. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 608 3.1 WHEELS A 10-inch rim is the team’s choice to lower thetorquetospin the wheel as compared to 13 inch. Hence the time taken for 10 inch wheel to reach peak torque value and rpm for each gear has been reduced comparison to 13 inch wheel, which would thus accelerate the car faster.Asmallerwheel sizehas also aggravated the weight reduction of un-sprung mass. Fig1: Rim 4. FORCES NORMAL CONDITION To calculate the forces on the wheels, two Free Body Diagrams are performed in Figure the car is seen from the front, and Figure 1 the car is seen from the left side to make assumptions of the forces acting.A“Normal condition”-drive is where no un-normal behavior of the car appears, and the track is smooth with no ruts, wet or loose gravel and tarmac. Fig2: Free Body Diagram y-z-plane To assume and show that the forces acting on the ground is equal or assumed to be equal at the Hub see Figure 2. By static Equations 2 and 3the forces on the system are in equilibrium when the forces at the ground are equal to the forces at the Hub. This assumption will be use in this project as a simplification; some differences will be covered by a Safety Factor. Fig3: Forces on Hub and wheel 4.1 ACCELERATION TORQUE FEA was used to confirm the hub design could withstandthe torque applied by both the wheelsandthebrakes.Amoment of 100000 N-mm was applied on the wheel mountings keeping the disc mounting constant. The maximum normal, lateral, and braking force was applied to the front upright while keeping the control arm fixed. Fig4: Free Body Diagram Torque applied 4.2 BRAKING TORQUE The Wheel Hub is affected through the Brake Disk Adapter which is assembled on the Hub and fixed on the wheel nuts with the rim. The moment acting on the Hub is interesting. Things that has to be consider when making assumptions of this is the Brake Balance, the speed and acc eleration of the car. These data are collected and used in this analysis, see Figure 4 for a plot of Speed vs. time in MATLAB® from the collected data. The Brake Pressure, or Brake Balance is not analysed, and the braking is only calculated related to the total acceleration during the braking.
  • 3. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 609 Fig5: Speed vs. Time The Free Body Diagram in Figure 5 showing the torque acting on the Wheel Hub and the forces from the ground during the braking, assumption this is equal at all four wheels and this calculation performed at the front, or rear right wheel. Fig6: Free Body Diagram Braking By comparing the torque applied in acceleration and the torque caused by the braking is approximate a factor of ten larger, and therefore the most critical torque acting on the Hub. 5. CALCULATIONS Determining the forces acting on the Hub. The following Forces are acting on the Hub. a. Torque on the Brake Disk Petal : - A 130 Nm torque is acting on the Brake Disk Petal. The Force acting on each hole= = = 650N b. Torque on the Wheel Petal : - In order to sustain this braking effect the wheel must also provide and equal and opposite torque. Thus the magnitude of torque is same but the direction is opposite. The Force acting on each hole = = 650N c. Force due to Side Impact: - If the vehicle is banged by other vehicle from side or if the vehicle has a collision with the fencing from side, there are chances that the petals might bend. Hence this side impact force must also be considered. Here the side Impact force is taken to be 2G = 2 × g × vehicle mass Impact force = 2 × 9.81 × 300 = 5409 N Impact force on 1 petal = 8829/3 = 1352.2 N d. Loads on Bearing: - The load on 1 bearing is 700 N The load on 2nd bearing is 634 N The axial load is 1388 N Selection of Wheel Bolt Shear Stress on the bolts = τ= 145N/mm2 The force acting on the Wheel Bolt is given by the result now, τ= 145 = Dc = 2.99mm D = dc/0.8 D = 2.99/0.8 D = 3.74mm
  • 4. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 610 Selection of Brake Disk Bolt Shear Stress on the bolts =τ= =68.75N/mm2 The force acting on the Wheel Bolt is given by the result. now, τ= 68.75=650/(π/4*dc*dc) dc= dc=3.46 d=4.33mm Thus selecting the bolt size of M8. Design of Wheel Petal Shear Failure of Petal Allowable stress in the Hub in shear = τ= =125.75N/mm2 Force acting on Petal as obtained from result is 880 N. Now, τ= 125.75 = t × b = 3.5 Where, t= thickness of Wheel Petal b= distance between the hole and the end of petal If t = 8mm b= 0.475 mm Thus the width of the petal is taken to be 7mm The thickness of the petal is as 8 mm. Bending of Wheel Petal This bending is due to the force of 880 N. The radius of effective bending is 49.25 mm Mb = 880 × 49.25 Mb = 43340 N-mm Now, By Flexural Equation: σb= =503/2=251.5N/mm2 y= 2b/2 2b=d I= 3 Where, t= thickness of knuckle b= width of knuckle = T*d3=1034 If t= 8mm d = 11.36 mm Thus, the width of knuckle is 12mm. The thickness of knuckle is 8 mm. Total thickness = width + dia of hole =12+14 = 26 mm Design of Brake Disk Petal Shear Failure of Petal Allowable stress in the Hub in shear = τ= = =125.75N/mm2 σb= =503/2=251.5N/mm2 y= t/2 I= 3
  • 5. International Research Journal of Engineering and Technology (IRJET) e-ISSN: 2395-0056 Volume: 06 Issue: 04 | Apr 2019 www.irjet.net p-ISSN: 2395-0072 © 2019, IRJET | Impact Factor value: 7.211 | ISO 9001:2008 Certified Journal | Page 611 Where, t= thickness of petal b= width of petal =27 mm Force acting on Petal as obtained from result is 880 N. τ= = t = 6.61mm The thickness of petal is taken as 8 mm 125.75= t × b = 1.7495 Where, t= thickness of Wheel Petal b= distance between the hole and the end of petal If t = 5mm b = 0.35 mm Thus the width of the petal is taken to be 5mm. The thickness of the petal is taken as 6mm. Design of Wheel petal due to Side Impact The force is obtained from the result for 1 petal = 1962 N The effective bending Radius = 25.25 mm Mb = 1962 × 25.25 Mb = 49540.5 N-mm From the above result it is clear that hub without fillet and triangulation support were more prone to failure thanthose with fillet and triangulation support. Besides the stress concentrationintheoptimizeddesign was less. 6. CONCLUSION The observation made while working throughthisprojectis that the possibilities to improve the Wheel Hub is large. The design developed in this project is a big step forward to reduce the unsprung mass of the car. The design will not affect the geometry of the suspension and therefore the behaviour of the car in that aspect. Theadvantagesofchange to the re-designed Hub will increase the acceleration of the car and improve the traction between tire and road. The limitations set in this project makes it difficult to make the changes needed to find the optimal design.Evenifthedesign will improve the car by making small changes can an advantage in changing the upright and suspensiongeometry an even more innovative design with less unsprung mass and advantages in suspension geometry, heat flux etc. REFERENCES [1] Callum W. Watson, The OtimumWeightDistributionFor a Formula SAE Vehicle , , University of New South Wales at the Australian Defense Force Academy [2] Pruthviraj Vitthal Wable and Sahil Sanjog Shah, Design Analysis & Optimization of Hub Used in FSAE Cars, , UG Student, Department of Mechanical Engineering,Trinity College of Engineering and Research, Pune, Maharashtra, India. [3] Joijode Vrushabh Umeshand YadavAbhishek,Designing and Optimization of Wheel Assembly of a Formula Student Car, , Mechanical Engineering Department, Vishwakarma Institite of Technology, 666, UpperIndira Nagar, Pune-37, India. [4] L. Daniel Metz, William F. Miliken, Douglas L. Miliken, Race Car Vehicle Dynamics Workbook, SAE intenationals, 1998. [5] Óskar Kúld Pétursson, Uprights, wheel hubs and brake system for a new Formula Student race car, School of Science and Engineering Tækni- og verkfræðideild, Kennitala 110489–3239. [6] Alejandro Diaz ,Osvaldo Fernandez, Ricardo Gonzalez, Christian Ramos, FSAE 2015 Chassis and Suspension Final Report, EML 4905 Senior Design Project, Florida International University. [7] William Kinkead, ME Connor Morette, ME Adrian Pickering, ME Zachary Sears,DesignandOptimizationof a Formula SAE Vehicle, Worcester Polytechnic Institute.