Let X be normally distributed with mean = 12 and standard deviatio.pdf

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Let X be normally distributed with mean ? = 12 and standard deviation ? = 3. Use a standard normal curve area table. A.Find P(X ? 0). B. Find P(X > 6). C.Find P(3 ? X ? 15). D.Find P(6 ?X? 15). PLEASE SHOW ALL WORK A.Find P(X ? 0). B. Find P(X > 6). C.Find P(3 ? X ? 15). D.Find P(6 ?X? 15). PLEASE SHOW ALL WORK Solution (A) P(X ? 0) = P((X-mean)/s <(0-12)/3) = P(Z<-4) =0 (from standard normal table) (B) P(X>6) = P(Z>(6-12)/3) = P(Z>-2) = 0.9772 (C) P(3 ? X ? 15) = P((3-12)/3.

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