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Mathematics 7
M e a s u r e s o f C e n t r a l T e n d e n c y
MODE of Grouped Data
MR. CARLO JUSTINO J. LUNA
Malabanias Integrated School
Angeles City
The only way to learn
mathematics
is to do
mathematics.
Activity: What-You-Already-Know
Find the mode of each of the following sets of
numbers.
a. 3, 2, 2, 4, 5, 1, 4, 6, 4
b. 77, 80, 90, 65, 77, 89, 80
c. 1987, 1993, 1985, 1990
Answer
Answer
Answer
a. 3, 2, 2, 4, 5, 1, 4, 6, 4
MODE: 4
b. 77, 80, 90, 65, 77, 89, 80
MODE: 77 and 80
c. 1987, 1993, 1985, 1990
MODE: No mode
For the next set of questions,
refer to the given frequency
distribution table of the
grades of a group of students.
1. Determine the modal class.
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5
Answer
Modal Class: 81 – 85
The modal class is the class with the
highest frequency.
2. What is the lower class boundary of the
modal class?
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5 Answer
Modal Class
lbmo = 80.5
3. What is the frequency of the modal
class?
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5 Answer
Modal Class
fmo = 18
4. What is the frequency of the class
preceding the modal class?
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5 Answer
Modal Class
fb = 12
5. What is the frequency of the class after
the modal class?
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5 Answer
Modal Class
fa = 7
6. What is the class size?
Answer
Grades
Number of
Students
91 – 95 3
86 – 90 7
81 – 85 18
76 – 80 12
71 – 75 5
i = 5
Solution
Observe how the modal grade of the students is computed.
Mo = +80.5
[ 18 –___________________
2( ) – –
12
5
18 12 7
]
= 80.5 +
6
17
5
= 80.5 + 0.35 5
= 80.5 + 1.75
= 𝟖𝟐. 𝟐𝟓
Hence, the modal grade
of the students is 82.25.
80.5 is the lower
class boundary of the
modal class
lbmo
18 is the frequency
of the modal class
fmo
12 is the frequency
of the class before
the modal class
fb
7 is the frequency of
the class after the
modal class
fa
5 is the class size
i
How did we solve for the
modal grade of the students?
Can you give the formula for
the mode of grouped data?
Formula
To solve for the mode of grouped data, use the formula:
𝑀𝑜 = 𝑙𝑏 𝑚𝑜 +
𝑓𝑚𝑜 − 𝑓𝑏
2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎
𝑖
where
𝑙𝑏 𝑚𝑜 is the lower class boundary of the modal class
𝑓𝑚𝑜 is the frequency of the modal class
𝑓𝑏 is the frequency of the class before the modal class
𝑓𝑎 is the frequency of the class after the modal class
𝑖 is the class size
LET’S PRACTICE!
The following
distribution gives
the number of
hours allotted by
50 students to do
their assignments
in a week. Find
the modal hour.
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
14
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
14
12
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
14
12
10
SOLUTION
Hours
Number of
Students
17 – 20 4
13 – 16 10
9 – 12 14
5 – 8 12
1 – 4 9
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
14
12
10
4 Compute the mode.
SOLUTION
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
9 – 12
8.5
14
12
10
4
SOLUTION
= 8.5 +
2
6
4
𝑀𝑜 = 𝑙𝑏 𝑚𝑜 +
𝑓𝑚𝑜 − 𝑓𝑏
2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎
𝑖
= 8.5 +
14 − 12
2 14 − 12 − 10
4
𝑴𝒐 = 𝟗. 𝟖𝟐
= 8.5 + (0.33)4
= 8.5 + 1.32
MORE PRACTICE!
Find the mode
using the
frequency
distribution of the
heights of 40
students.
Height
(inches)
Number of
Students
70 – 72 4
67 – 69 9
64 – 66 10
61 – 63 8
58 – 60 3
55 – 57 4
52 – 54 2SOLUTION
SKIP
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
64 – 66
63.5
10
8
9
3
SOLUTION
= 63.5 +
2
3
3
𝑀𝑜 = 𝑙𝑏 𝑚𝑜 +
𝑓𝑚𝑜 − 𝑓𝑏
2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎
𝑖
= 63.5 +
10 − 8
2 10 − 8 − 9
3
𝑴𝒐 = 𝟔𝟓. 𝟓
= 63.5 + 2
EVALUATE YOURSELF
Find the mode of
20 students
whose scores on a
15-point test are
given in the
following
distribution:
Scores
Number of
Students
13 – 15 2
10 – 12 5
7 – 9 8
4 – 6 4
1 – 3 1
SOLUTION
Modal Class :
𝒍𝒃 𝒎𝒐:
𝒇 𝒎𝒐:
𝒇 𝒃:
𝒇 𝒂:
𝒊:
7 – 9
6.5
8
4
5
3
SOLUTION
= 6.5 +
4
7
3
𝑀𝑜 = 𝑙𝑏 𝑚𝑜 +
𝑓𝑚𝑜 − 𝑓𝑏
2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎
𝑖
= 6.5 +
8 − 4
2 8 − 4 − 5
3
𝑴𝒐 = 𝟖. 𝟐𝟏
= 6.5 + 0.57 3
= 6.5 + 1.71
VALUING:
Do you have a person or a
thing in your life that you
consider as a mode?
Mathematics 7
M e a s u r e s o f C e n t r a l T e n d e n c y
MODE of Grouped Data
MR. CARLO JUSTINO J. LUNA
Malabanias Integrated School
Angeles City

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Mode of Grouped Data - Math 7 (4th Quarter)

  • 1. Mathematics 7 M e a s u r e s o f C e n t r a l T e n d e n c y MODE of Grouped Data MR. CARLO JUSTINO J. LUNA Malabanias Integrated School Angeles City
  • 2. The only way to learn mathematics is to do mathematics.
  • 3. Activity: What-You-Already-Know Find the mode of each of the following sets of numbers. a. 3, 2, 2, 4, 5, 1, 4, 6, 4 b. 77, 80, 90, 65, 77, 89, 80 c. 1987, 1993, 1985, 1990 Answer Answer Answer
  • 4. a. 3, 2, 2, 4, 5, 1, 4, 6, 4 MODE: 4
  • 5. b. 77, 80, 90, 65, 77, 89, 80 MODE: 77 and 80
  • 6. c. 1987, 1993, 1985, 1990 MODE: No mode
  • 7. For the next set of questions, refer to the given frequency distribution table of the grades of a group of students.
  • 8. 1. Determine the modal class. Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5 Answer
  • 9. Modal Class: 81 – 85 The modal class is the class with the highest frequency.
  • 10. 2. What is the lower class boundary of the modal class? Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5 Answer Modal Class
  • 12. 3. What is the frequency of the modal class? Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5 Answer Modal Class
  • 14. 4. What is the frequency of the class preceding the modal class? Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5 Answer Modal Class
  • 16. 5. What is the frequency of the class after the modal class? Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5 Answer Modal Class
  • 18. 6. What is the class size? Answer Grades Number of Students 91 – 95 3 86 – 90 7 81 – 85 18 76 – 80 12 71 – 75 5
  • 19. i = 5
  • 20. Solution Observe how the modal grade of the students is computed. Mo = +80.5 [ 18 –___________________ 2( ) – – 12 5 18 12 7 ] = 80.5 + 6 17 5 = 80.5 + 0.35 5 = 80.5 + 1.75 = 𝟖𝟐. 𝟐𝟓 Hence, the modal grade of the students is 82.25.
  • 21. 80.5 is the lower class boundary of the modal class lbmo
  • 22. 18 is the frequency of the modal class fmo
  • 23. 12 is the frequency of the class before the modal class fb
  • 24. 7 is the frequency of the class after the modal class fa
  • 25. 5 is the class size i
  • 26. How did we solve for the modal grade of the students? Can you give the formula for the mode of grouped data?
  • 27. Formula To solve for the mode of grouped data, use the formula: 𝑀𝑜 = 𝑙𝑏 𝑚𝑜 + 𝑓𝑚𝑜 − 𝑓𝑏 2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎 𝑖 where 𝑙𝑏 𝑚𝑜 is the lower class boundary of the modal class 𝑓𝑚𝑜 is the frequency of the modal class 𝑓𝑏 is the frequency of the class before the modal class 𝑓𝑎 is the frequency of the class after the modal class 𝑖 is the class size
  • 28. LET’S PRACTICE! The following distribution gives the number of hours allotted by 50 students to do their assignments in a week. Find the modal hour. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9
  • 29. SOLUTION Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊:
  • 30. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 SOLUTION
  • 31. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 SOLUTION
  • 32. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 14 SOLUTION
  • 33. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 14 12 SOLUTION
  • 34. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 14 12 10 SOLUTION
  • 35. Hours Number of Students 17 – 20 4 13 – 16 10 9 – 12 14 5 – 8 12 1 – 4 9 Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 14 12 10 4 Compute the mode. SOLUTION
  • 36. Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 9 – 12 8.5 14 12 10 4 SOLUTION = 8.5 + 2 6 4 𝑀𝑜 = 𝑙𝑏 𝑚𝑜 + 𝑓𝑚𝑜 − 𝑓𝑏 2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎 𝑖 = 8.5 + 14 − 12 2 14 − 12 − 10 4 𝑴𝒐 = 𝟗. 𝟖𝟐 = 8.5 + (0.33)4 = 8.5 + 1.32
  • 37. MORE PRACTICE! Find the mode using the frequency distribution of the heights of 40 students. Height (inches) Number of Students 70 – 72 4 67 – 69 9 64 – 66 10 61 – 63 8 58 – 60 3 55 – 57 4 52 – 54 2SOLUTION SKIP
  • 38. Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 64 – 66 63.5 10 8 9 3 SOLUTION = 63.5 + 2 3 3 𝑀𝑜 = 𝑙𝑏 𝑚𝑜 + 𝑓𝑚𝑜 − 𝑓𝑏 2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎 𝑖 = 63.5 + 10 − 8 2 10 − 8 − 9 3 𝑴𝒐 = 𝟔𝟓. 𝟓 = 63.5 + 2
  • 39. EVALUATE YOURSELF Find the mode of 20 students whose scores on a 15-point test are given in the following distribution: Scores Number of Students 13 – 15 2 10 – 12 5 7 – 9 8 4 – 6 4 1 – 3 1 SOLUTION
  • 40. Modal Class : 𝒍𝒃 𝒎𝒐: 𝒇 𝒎𝒐: 𝒇 𝒃: 𝒇 𝒂: 𝒊: 7 – 9 6.5 8 4 5 3 SOLUTION = 6.5 + 4 7 3 𝑀𝑜 = 𝑙𝑏 𝑚𝑜 + 𝑓𝑚𝑜 − 𝑓𝑏 2 𝑓𝑚𝑜 − 𝑓𝑏 − 𝑓𝑎 𝑖 = 6.5 + 8 − 4 2 8 − 4 − 5 3 𝑴𝒐 = 𝟖. 𝟐𝟏 = 6.5 + 0.57 3 = 6.5 + 1.71
  • 41. VALUING: Do you have a person or a thing in your life that you consider as a mode?
  • 42. Mathematics 7 M e a s u r e s o f C e n t r a l T e n d e n c y MODE of Grouped Data MR. CARLO JUSTINO J. LUNA Malabanias Integrated School Angeles City