How can this problem be solved using arrays alone? (without functions or anytheing else) i couldnt figure out how to display the arrays side by side.
Declare two integer arrays list1 and list2 of size 10. Fill both arrays with the random numbers from 5 to 25. Display two arrays side to side as shown in the sample output. Input an integer n Check if if n is found in any of the arrays and print its location if it is found. Please note that your output will be different because the arrays are initialized randomly Sample input / output: Array #1 - Array #2 25 9 8 5 Array #1 - Array #2 6 25 5 5 25 23 25 20 25 5 Enter a number: 13 Enter a number: 17 13 was found in 1 arrau Location of 13 in Array #1 : 2 17 was found in both arraus Location of 17 in Array #1: 9 Location of 17 in Array #2:
Solution
#include <iostream>
#include <cstdlib> /* srand, rand */
#include <ctime> // time
#include<iomanip>
using namespace std;
int main() {
int list1[10],list2[10],n,flag1 = 0,flag2=0,pos1 = -1,pos2=-1;
srand(1000);
for(int i=0;i<10;i++){
list1[i] = rand()%21+5;
list2[i] = rand()%21+5;
}
cout<<\"Array #1 - Array #2\"<<endl;
for(int i=0;i<10;i++){
cout<<\" \"<<list1[i]<<\" \"<<list2[i]<<endl;
}
cout<<\"Enter a number : \";
cin>>n;
for(int i=0;i<10;i++){
if(list1[i]==n){
flag1 = 1;
pos1 = i;
break;
}
}
for(int i=0;i<10;i++){
if(list2[i]==n){
flag2 = 1;
pos2 = i;
break;
}
}
if(flag1 && flag2){
cout<<n<<\" was found in both arrays\"<<endl;
cout<<\"Location of \"<<n<<\" found in array #1 :\"<<pos1<<endl;
cout<<\"Location of \"<<n<<\" found in array #2 :\"<<pos2<<endl;
}
else if(flag1){
cout<<n<<\" was found in 1 array\"<<endl;
cout<<\"Location of \"<<n<<\" found in array #1 :\"<<pos1<<endl;
}
else if(flag2){
cout<<n<<\" was found in 1 array\"<<endl;
cout<<\"Location of \"<<n<<\" found in array #2 :\"<<pos2<<endl;
}
else
cout<<n<<\" was not found in any array\"<<endl;
return 0;
}
.
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How can this problem be solved using arrays alone- (without functions.docx
1. How can this problem be solved using arrays alone? (without functions or anytheing else) i
couldnt figure out how to display the arrays side by side.
Declare two integer arrays list1 and list2 of size 10. Fill both arrays with the random numbers
from 5 to 25. Display two arrays side to side as shown in the sample output. Input an integer n
Check if if n is found in any of the arrays and print its location if it is found. Please note that
your output will be different because the arrays are initialized randomly Sample input / output:
Array #1 - Array #2 25 9 8 5 Array #1 - Array #2 6 25 5 5 25 23 25 20 25 5 Enter a number: 13
Enter a number: 17 13 was found in 1 arrau Location of 13 in Array #1 : 2 17 was found in both
arraus Location of 17 in Array #1: 9 Location of 17 in Array #2:
Solution
#include <iostream>
#include <cstdlib> /* srand, rand */
#include <ctime> // time
#include<iomanip>
using namespace std;
int main() {
int list1[10],list2[10],n,flag1 = 0,flag2=0,pos1 = -1,pos2=-1;
srand(1000);
for(int i=0;i<10;i++){
list1[i] = rand()%21+5;
list2[i] = rand()%21+5;
}
cout<<"Array #1 - Array #2"<<endl;
for(int i=0;i<10;i++){
cout<<" "<<list1[i]<<" "<<list2[i]<<endl;
}
cout<<"Enter a number : ";
cin>>n;
for(int i=0;i<10;i++){
if(list1[i]==n){
flag1 = 1;
2. pos1 = i;
break;
}
}
for(int i=0;i<10;i++){
if(list2[i]==n){
flag2 = 1;
pos2 = i;
break;
}
}
if(flag1 && flag2){
cout<<n<<" was found in both arrays"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else if(flag1){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
}
else if(flag2){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else
cout<<n<<" was not found in any array"<<endl;
return 0;
}
![How can this problem be solved using arrays alone? (without functions or anytheing else) i
couldnt figure out how to display the arrays side by side.
Declare two integer arrays list1 and list2 of size 10. Fill both arrays with the random numbers
from 5 to 25. Display two arrays side to side as shown in the sample output. Input an integer n
Check if if n is found in any of the arrays and print its location if it is found. Please note that
your output will be different because the arrays are initialized randomly Sample input / output:
Array #1 - Array #2 25 9 8 5 Array #1 - Array #2 6 25 5 5 25 23 25 20 25 5 Enter a number: 13
Enter a number: 17 13 was found in 1 arrau Location of 13 in Array #1 : 2 17 was found in both
arraus Location of 17 in Array #1: 9 Location of 17 in Array #2:
Solution
#include <iostream>
#include <cstdlib> /* srand, rand */
#include <ctime> // time
#include<iomanip>
using namespace std;
int main() {
int list1[10],list2[10],n,flag1 = 0,flag2=0,pos1 = -1,pos2=-1;
srand(1000);
for(int i=0;i<10;i++){
list1[i] = rand()%21+5;
list2[i] = rand()%21+5;
}
cout<<"Array #1 - Array #2"<<endl;
for(int i=0;i<10;i++){
cout<<" "<<list1[i]<<" "<<list2[i]<<endl;
}
cout<<"Enter a number : ";
cin>>n;
for(int i=0;i<10;i++){
if(list1[i]==n){
flag1 = 1;](https://image.slidesharecdn.com/howcanthisproblembesolvedusingarraysalone-withoutfunctions-230209002025-dbaa6fab/85/How-can-this-problem-be-solved-using-arrays-alone-without-functions-docx-1-320.jpg)
![pos1 = i;
break;
}
}
for(int i=0;i<10;i++){
if(list2[i]==n){
flag2 = 1;
pos2 = i;
break;
}
}
if(flag1 && flag2){
cout<<n<<" was found in both arrays"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else if(flag1){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #1 :"<<pos1<<endl;
}
else if(flag2){
cout<<n<<" was found in 1 array"<<endl;
cout<<"Location of "<<n<<" found in array #2 :"<<pos2<<endl;
}
else
cout<<n<<" was not found in any array"<<endl;
return 0;
}](data:image/gif;base64,R0lGODlhAQABAIAAAAAAAP///yH5BAEAAAAALAAAAAABAAEAAAIBRAA7)