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Unit One Part 5:
intermolecular forces



    we have looked at the
      bonds in molecules,
    now turn our attention
     to the bonds / forces
      between molecules
5
Unit One
Part of molecules (pg56-58)
Properties
Intermolecular forces (pg59-66)
Solubility (pg66-68)
Gecko feet


Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
Gecko feet
              how do geckos walk on
               walls? to understand
             this cool phenomena we
              have to understand the
                attraction between
                    molecules...




Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
O
             H
                                 O

2-methylpropan-2-ol   ethoxyethane
   tert-butanol        diethyl ether
      C4H10O                 C4H10O
     mp 26°C             mp by looking at
                                 –116°C
                      lets start
                        these two simple
                      molecules...they are
                      structural isomers...
O
             H
                              O

2-methylpropan-2-ol   ethoxyethane
   tert-butanol       diethyl ether
      C4H10O             C4H10O
     mp 26°C           mp –116°C
                         same atoms...but
                           very different
                         properties...why?
why are the physical
characteristics so different?
is it the bonds
in the molecule?



            yes...
     C–O–C versus C–O–H
          ...but...
...or is it
something more?
pentane    2-methylbutane           2,2-dimethyl
  C5H12         C5H12                  propane
bp 36.2˚C      bp 28˚C                   C5H12
                   three more          bp 9.6˚C
               isomers...this time
                  no change in
              functional groups...
pentane             2-methylbutane   2,2-dimethyl
  C5H12                  C5H12          propane
bp 36.2˚C               bp 28˚C           C5H12
                                        bp 9.6˚C
            ...but they still have
              different physical
                  properties!
similar bonds, but very
    different properties
need to understand
forces between
        molecules
...of course, this is controlled by
the bonds in the molecules...
...and the electrons
                              (of course)




...of course, this is controlled by
the bonds in the molecules...
before we can look
                           at the forces we
                         need to define a few
                               terms...




...of course, this is controlled by
the bonds in the molecules...
Bond dipoles
(separation of charge)

  H        Cl            δ+          δ–

 we now know that
 electrons are not
   shared evenly
 between atoms...

      δ+ δ–          =
      H Cl                    H Cl
Bond dipoles
(separation of charge)

  H     Cl        δ+                      δ–




      δ+ δ–   =          ...they are attracted
                           towards the most
      H Cl             H Cl
                        electronegative atom
                        and the bond is said
                            to be polarised
Bond dipoles
(separation of charge)

  H     Cl        δ+               δ–

                            the bond dipole
                              refers to the
                          difference in charge
                           on each atom and
                            their separation
      δ+ δ–   =
      H Cl             H Cl
H
                     2.1
                     Li      Be      B     C     N     O     F
                     1.0     1.5    2.0   2.5   3.0   3.5   4.0
                      Na     Mg     Al    Si     P     S    Cl
      Pauli scale of 0.9     1.2    1.5   1.8   2.1   2.5   3.0
   electronegativities K     Ca                             Br
  allows us to predict0.8    1.0                            2.8
     bond polarity...
                      Rb     Sr                              I
                      0.8    1.0                            2.5


                         EN
 Bond Type           difference Examples                     Calculation


     ionic                  > 1.7          NaCl        3.0(Cl) - 0.9(Na) = 2.1

                                          CH3O–H        3.5(O) - 2.1(H) = 1.4
polar covalent         0.5 – 1.7
                                           H–Cl         3.0(Cl) - 2.1(H) = 0.9

   covalent             0 – 0.4
                                          CH3–H         2.5(C) - 2.1(H) = 0.4    Pg
                                           H–H          2.1(H) - 2.1(H) = 0.0
                                                                                 35
electro-
                                                            negative
  1                                                                             18

  H    2                                               13   14   15   16   17   He
                                                                           9
  Li Be                                                B    C    N    O    F Ne
                                                                           F

  Na Mg    3   4   5   6   7    8   9   10   11   12   Al   Si   P    S    Cl   Ar

  K    Ca Sc Ti    V   Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr

  Rb Sr    Y   Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te                      I    Xe

  Cs Ba La Hf Ta       W Re Os         Ir Pt Au Hg Tl Pb Bi Po At Rn
  87                                 We do not have to remember
  Fr Ra Ac
  Fr
                                all the values, just the general trend
                               (and eventually the effect of different
                                          functional groups)
electro-
positive
Molecular dipoles
(su m of b on d dipo les)
               if we add all the
                individual bond
             dipoles together we
     Cl            get the...

   H   C
         H
     H




             polar
             molecules
Molecular dipoles
(su m of b on d dipo les)
                    ...the molecular
                    dipole or dipole
      Cl                 moment

   H   C
         H
     H     dipole
           moment




             polar
             molecules
Molecular dipoles
(su m of b on d dipo les)
         Cl

    H   C
                          H   O
          H
      H     dipole          H
               moment              dipole
   ...compounds with              moment
  a dipole moment are




                    polar
     said to be polar
        molecules




                    molecules
Molecular dipoles
(su m of b on d dipo les) if the bond dipoles
                      cancel each other out (thats
                      why shape is important), the
             Cl       molecule will have no dipole
                             moment and is

          Cl C Cl              non-polar

           Cl

          no dipole
          moment


     non-polar
     m o l e c u l e s
Inductive effects
  ( lo n g ran ge e ffect s)
                  a functional group that
                  attracts electrons is an
                   electron withdrawing
                       group (EWG)

        H2                        H2                   H2
        C
                                 >C>
                  or                         or     δ+ C δ–
  H3C        Cl          H 3C           Cl        H3C δ+ Cl




electron-withdrawing group
Inductive effects
  ( lo n g ran ge e ffect s)
                  first it causes a bond
                     dipole in its own
                            bonds

        H2                       H2                   H2
        C
                                >C>
                  or                        or     δ+ C δ–
  H3C        Cl         H 3C           Cl        H3C δ+ Cl




electron-withdrawing group
Inductive effects
  ( lo n g ran ge e ffect s)
                ...and this dipole
             induces a bond dipole
               in bonds next to it

        H2                            H2                  H2
        C
                                     >C>
                    or                          or     δ+ C δ–
  H3C        Cl             H 3C           Cl        H3C δ+ Cl




electron-withdrawing group
Inductive effects
  ( lo n g ran ge e ffect s)
         the further from
          the functional
        group the smaller
         this polarisation

        H2                           H2                  H2
        C
                                    >C>
                     or                        or     δ+ C δ–
  H3C        Cl              H 3C         Cl        H3C δ+ Cl




electron-withdrawing group
Inductive effects
( lo n g ran ge e ffect s)
     a group that
  pushes electrons
  away (alkyl) is an
  electron donating
        group


                       H 3C > C



electron-donating group
...and the inductive
effect in action...
Acidity
      O                   H               O       H       H
              H       O                               O
H3C       O               H         H3C       O           H
                    we measure
                   acidity by how
                      readily a




 high                                low
                  compound looses
                         H+




 pKa                                 pKa
Acidity
                           the more stable
                            the anion the
                           more readily the
                          compound looses
      O               H          H+            O       H       H
              H   O                                        O
H3C       O           H                  H3C       O           H




 high                                         low
 pKa                                          pKa
Acidity
      O               H                   O         H       H
              H   O                                     O
H3C       O           H            H3C        O             H

                            the more stable the
                          anion, the more acidic
                          the compound and the



 high                                low
                           reaction shifts to the
                                  right...




 pKa                                 pKa
Acidity
      O                       H                O       H       H
              H           O                                O
H3C       O                   H          H3C       O           H

                 this is measured by
               pKa...the lower the pKa
                 the more acidic the



 high                                     low
              compound...more about
                this later in semester




 pKa                                      pKa
Acidity
      O               H                  O        H       H
              H   O                                   O
H3C       O           H           H3C        O            H


                          electron withdrawing
                          groups help stabilise



 high                               low
                            negative charges




 pKa                                pKa
unit 3
  This topic is covered in
 detail in unit 3 but at the
  moment all we have to
      remember is...
high pKa
    O
                 molecule is basic, this
                   means it wants the

            H   proton H+ or the anion is
                        unstable


R       O

            wants                    H+
low pKa
       O
                            H
R                   O
molecule with a low pKa
 will loose a proton H+
readily to go from HA to



                           losses   H+
      H+ and A– or...
low pKa
     O           ...the molecule can
                  stabilise an anion
                  (negative charge)




             H
 R       O

negative charge stable
Acidity
      O                       H                               O                 H       H
              H           O                                                         O
H3C       O                   H                        H3C         O                    H


                                                     O                       O
      O                       O
                                            Cl                H     Cl                  H
              H    Cl                  H                 O                  «       O
H3C       O                <      O                                 Cl
                                                  Cl                      Cl
 pKa = 4.75             pKa = 2.85               pKa = 1.48              pKa = 0.70
              CO2H                Cl
                                                         Cl                 CO2H
                                           CO2H
         Cl
      pKa = 2.85                  pKa = 4.05                      pKa = 4.50
Acidity
      O                       H        wants                  H
                                                              O+                H       H
              H           O                                                         O
H3C       O                   H                        H3C         O                    H


                                                     O                       O
      O                       O
                                            Cl                H     Cl                  H
              H    Cl                  H                 O                  «       O
H3C       O                <      O                                 Cl
                                                  Cl                      Cl
 pKa = 4.75             pKa = 2.85               pKa = 1.48              pKa = 0.70
              CO2H                Cl
                                                         Cl                 CO2H
                                           CO2H
         Cl
      pKa = 2.85                  pKa = 4.05                      pKa = 4.50
Acidity
                       the more electron
      O                       H
                    withdrawing groups the                      O                 H       H
                   more stable the negative
                            O                                                         O
              H    charge and so the pKa is
H3C       O                   H
                   lower and the compound
                                                         H3C         O                    H
                         is more acidic

                                                       O                       O
      O                      O
                                              Cl                H     Cl                  H
              H     Cl                H                    O                  «       O
H3C       O                 <    O                                    Cl
                                                    Cl                      Cl
 pKa = 4.75              pKa = 2.85                pKa = 1.48              pKa = 0.70
              CO2H               Cl
                                                           Cl                 CO2H
                                          CO2H
         Cl
      pKa = 2.85                 pKa = 4.05                         pKa = 4.50
Acidity
              losses          H            H+                                           H
      O                                                       O                 H
              H           O                                                         O
H3C       O                   H                        H3C         O                    H


                                                     O                       O
      O                       O
                                            Cl                H     Cl                  H
              H    Cl                  H                 O                  «       O
H3C       O                <      O                                 Cl
                                                  Cl                      Cl
 pKa = 4.75             pKa = 2.85               pKa = 1.48              pKa = 0.70
              CO2H                Cl
                                                         Cl                 CO2H
                                           CO2H
         Cl
      pKa = 2.85                  pKa = 4.05                      pKa = 4.50
Acidity
                                O

                               R       O
      O                       H    stable                      O                 H       H
              H           O                                                          O
H3C       O                   H                         H3C         O                    H


                                                      O                       O
      O                       O
                                             Cl                H     Cl                  H
              H    Cl                   H                 O                  «       O
H3C       O                <       O                                 Cl
                                                   Cl                      Cl
 pKa = 4.75             pKa = 2.85                pKa = 1.48              pKa = 0.70
              CO2H                 Cl
                                                          Cl                 CO2H
                                            CO2H
         Cl
      pKa = 2.85                   pKa = 4.05                      pKa = 4.50
Acidity
      O                       H                                O                 H       H
              H           O                                                          O
H3C       O                   H                       H3C           O                    H
                               the further away the
                              electron withdrawing
                                 group from the
                                                      O                       O
      O                       Onegative charge the
                                smaller the effect
                                             Cl                H     Cl                  H
              H    Cl                  H                  O                  «       O
H3C       O                <      O                                  Cl
                                                Cl                         Cl
 pKa = 4.75             pKa = 2.85             pKa = 1.48                 pKa = 0.70
              CO2H                Cl
                                                          Cl                 CO2H
                                           CO2H
         Cl
      pKa = 2.85                  pKa = 4.05                       pKa = 4.50
you do not need
                    !
to learn these values!
how does all this
             effect intermolecular
                    forces??




so what intermolecular
       forces are there?
covalent bond
    (strong)
govern reactions


       H    Cl           H   Cl

                               forces between
                                molecules are
                             relatively weak BUT
                               very important!

            intermolecular
               attraction
                 (weak)
           physical properties
sorry...




            the next slide is
            awful (in all the
           worst senses of the
                  word)
typical energy
                             interaction                  (kJmol–1)
                      ionic-ionic (ionic bond)              250
intramolecular   carbon-containing covalent bond            350
     forces
                 oxygen-hydrogen covalent bond              460

                        hydrogen (H-) bond                  20

intermolecular               ion-dipole                     15
    forces
                            dipole-dipole                    2

                        London (dispersion)                  2
                  shows just how weak intermolecular
                      forces are by comparison...
transferable skill...
• Tables are rarely of any use in a
  presentation...
• Lots of text on a PowerPoint (or
  Keynote) slide is not only really dull
  but looks crap and is second only
  to the use of...
• ...bullet points in making you (and
  me) a little sleepy
• So stick to pictures (and a lot of
  preparation)
don’t get me started on the
           differences between...


    only the first is
 acceptable to me (but
most people can’t see
                       these
                       these
the difference between
         1 & 3)




    learn to do
  presentations
 right...it’ll serve




                       these
     you well!
why does NaCl
dissolve in water?   ...or, now lets look at
                       the intermolecular
                         forces (at last)!
H δ+             Cl    Hδ+
    δ--
   O    Na               O δ--
 H δ+                   Hδ+
                                            δ–
                                       δ+        δ+



             δ–   δ+
                                 Cl–
             δ+                                  δ+
                                       δ+    δ–




Ion-dipole
forces (15             kJmol-1)
H δ+             Cl    Hδ+
    δ--
   O    Na               O δ--
 H δ+                   Hδ+
                                               δ–
                                        δ+          δ+
                                        interaction of
                                       an ion (chloride)

             δ–   δ+
                                 Cl–
             δ+                                     δ+
                                          δ+    δ–




Ion-dipole
forces (15             kJmol-1)
H δ+             Cl    Hδ+
    δ--
   O    Na               O δ--
 H δ+                   Hδ+
                                            δ–
                                       δ+        δ+



             δ–   δ+
                                 Cl–
             δ+                             with a
                                                 δ+
                                       compound with
                                        a permanent
                                        δ+ δ–
                                        dipole (water)




Ion-dipole
forces (15             kJmol-1)
H δ+             Cl    Hδ+
    δ--
   O    Na               O δ--
 H δ+                   Hδ+
                                            δ–
                                       δ+        δ+



             δ–   δ+
                                 Cl–
             δ+                                  δ+
                                       δ+    δ–
                                          relatively



Ion-dipole
                                       strong...hence
                                       salt dissolves



forces (15             kJmol-1)
H δ+             Cl    Hδ+
    δ--
   O    Na               O δ--
 H δ+                   Hδ+
                                             δ–
                                       δ+note that water
                                                δ+
                                          interacts with
                                         both anion and
                                          cation...really
             δ–   δ+                          helps
                                 Cl–
             δ+                                   δ+
                                        δ+    δ–




Ion-dipole
forces (15             kJmol-1)
δ–        HO   Hδ+
              O      Na         O δ–
             H δ+


                                      organic
                                  compounds can
                                    do the same
                                   (but only O–H
                                       bond)




Ion-dipole
forces (15   kJmol-1)
δ+       δ–         δ+                δ–



                                    two molecules
                                   with a dipole will
                                       interact...
                    δ+        δ–
                                         weakly


              δ–         δ+




Dipole-dipole
forces (≈ 2   kJmol-1)
Polarmix polar
molecules
          /
              H3C                                                           Cl
     δ+             C O                 δ–       δ+              H C Cl          δ–
              H3C                                                   Cl

   this is why two polar
  molecules (like acetone
    & chloroform) will                                δ+         δ–
                             δ+        δ– δ+     δ–
  mix...they are attracted                             δ–        δ+
                             –δ         +δ δ–     δ+
       to each other                                        δ+         δ–
                                  δ+     δ– δ+         δ–
                       δ+         δ–     δ+      δ– δ+            δ–
                                  δ+     δ–            δ–        δ+
Polardo/not mix
molecules
          non-polar
      H                                       H2        H2
 δ+       O   δ–                              C         C         CH3
                                        H3C        C         C
      H                                            H2        H2

                                                but polar molecules
                                                won’t mix with non–
                                              polar...polar molecules
                                               run an exclusive club
                   δ+   δ–    δ+   δ–
                          δ+δ–                   and they won’t let
                              δ–   δ+
                         δ– δ+                    anyone else in...
                              δ–   δ+
                         δ– δ+
                              δ–   δ+
                         δ+ δ–
δ–                                          H2
  H3C δ+ O     CH3                   H3C            C
                                    H2         C         CH3
                         H3C        C          H2
      CH3     O δ+ CH3         C         CH3
              δ–               H2
       propanone                    butane
        acetone
   Mol Wt. 58; bp 56°C    Mol Wt. 58; bp –0.6°C
    permanent dipole           no dipole

                                         compare these two
                                         molecules...similar



Dipole-dipole
                                          size and identical
                                               weight...




& boiling points
δ–                                          H2
  H3C δ+ O     CH3                   H3C            C
                                    H2         C         CH3
                         H3C        C          H2
      CH3     O δ+ CH3         C         CH3
              δ–               H2
       propanone                    butane
        acetone
   Mol Wt. 58; bp 56°C    Mol Wt. 58; bp –0.6°C
    permanent dipole           no dipole




Dipole-dipole
& boiling points                         ...but very different
                                            boiling points...
δ–                                          H2
  H3C δ+ O     CH3                   H3C            C
                                    H2         C         CH3
                         H3C        C          H2
      CH3     O δ+ CH3         C         CH3
              δ–               H2
       propanone                    butane
        acetone
   Mol Wt. 58; bp 56°C    Mol Wt. 58; bp –0.6°C
    permanent dipole           no dipole
                             this is because
                          acetone has dipole–
                           dipole attractions
                           holding molecules



Dipole-dipole
                          together and butane
                                 doesn’t




& boiling points
...one intermolecular
force to rule them all...
δ+

        δ–   δ+       δ–

   δ+                     δ+




Hydrogen          H
                      O    H O


bonding
                  H              H
                  hydrogen bond
δ+

        δ–   δ+       δ–

   δ+                   δ+




Hydrogen
                     a special kind of
                  H dipole–dipole
                   interaction...occurs
                   O between...
                          H O


bonding
                  H               H
                  hydrogen bond
H-bond         H X
             polar bond
dono r     (X = O, N etc)


               X
H-bond       lone pair on
acceptor   electronegative
                atom
H-bonding                 it is responsible for
                                water being so
                               wonderfully odd




                            water’s
                            abnormal
                            properties
F.W. Starr/Wesleyan Univ.
δ– H δ+
                                      O
                       δ+H         H δ+
                             δ–
                            O H O δ–
                       δ+ H     δ+ Hδ+
                                          δ–
                     δ+ O δ–            O H δ+
                      H       H δ+    H δ+


                   three molecules
                    of similar size

H2O (MW=18): boiling point 100°C
                    and / or shape


H2S .(MW=34): boiling point –60°C
CH4 (MW=16): boiling point –162°C
...yet water has
 phenomenally high                     δ– H δ+
boiling point...all due                O
 to H–bonding! (also
     explains ice)        δ+H         H δ+
                                δ–
                               O H O δ–
                          δ+ H     δ+ Hδ+
                                           δ–
                          δ+ O δ–        O H δ+
                          H     H δ+   H δ+




H2O (MW=18): boiling point 100°C
H2S .(MW=34): boiling point –60°C
CH4 (MW=16): boiling point –162°C
Methanol                     methanol only has one
                             O–H bond so can only
                            form one H-bond so has
                              much lower bp (less
                                  attraction)
              CH3
          δ+ Oδ–δ+ δ–
           H     H O
             δ–       CH3
           O δ+
      H3C     H     H δ+
                 O δ–
                CH3




1 hydrogen bond
boiling point 62°C
H-bonding
carboxylic acids                  carboxylic acids are also
                                   capable of forming H–
                                 bonds between OH (H-bond
                                 donor) and C=O (polarised
                                   so lone pair is H-bond
                                         acceptor)




                    δ– δ+ δ–
                    O   H O
               δ+
         H3C                   CH3
                    O H O
                    δ– δ+ δ–
H-bonding
carboxylic acids
- solubility
   ...H-bonding allows some
  acids to dissolve in water as
   good attraction (hence we
   can have vinegar (shown)        δ+ H O δ–
  and glacial acetic acid (very
            different)            δ–O    H
                     H3C              H
                          δ+ δ– δ+ δ–
                     H      O H O
                        δ–            H
                       O H δ+
Hydrogen bonding
 vital in biology...
protein
secondary
structure
H   O   R2 H    H
        N               N
                N
    O   H R1 Hδ+ O δ–

            δ– O δ+ H   H R4
                    N
                            N
                R3 H    O   H



Hydrogen
                                  β-sheets
                            and α-helix etc are all
                            formed by H-bonding
                               between amides



bonding
without
               H-bonding no
                DNA double
                   helix!




©Benny Herudek 3D Hifi - High Fidelity 3d Graphics Solutions
                                                              DNA
H
        N           N H   O       CH3

    N               N   H N
            N                 N
                          O
        adenine           thymine




Hydrogen
                                    Watson-Crick base
                                        pairing (or
                                       whatever the
                                    biochemists call it)



bonding
all molecules can
           interact...




     don’t need a dipole
         to interact
         because...
London (van der Waals
 or dispersion) forces




   here we have two
     molecules...
London (van der Waals
 or dispersion) forces


                                δ–           δ+
       ...chance allows the
    electrons of one molecule
       to bunch at one end
     causing an imbalance of
            electrons...


                                     momentary
                                       dipole
London (van der Waals
 or dispersion) forces


                              δ–           δ+




                                   momentary
    ...a disturbance in the          dipole
    force...or setting up a
     momentary dipole...
London (van der Waals
 or dispersion) forces


δ–             δ+     δ–                     δ+



                     ...as electrons don’t like each
                     other this new bunch repulse
                    electrons in a near by molecule
     induced               momentary
                         and set up an induced
                                 dipole...
      dipole                 dipole
London (van der Waals
 or dispersion) forces     this causes dipole–dipole
                       attraction (momentarily)...but it
                      will soon stop as the electrons are
                              always on the move




δ–             δ+      δ–                      δ+
               attraction



     induced                momentary
      dipole                  dipole
Larger
surface area




      the larger the molecule,
    the bigger the surface area
      and the more electrons
             involved...
                                  Bigger
                                  the force
Larger
surface area




      ...this means a bigger
     momentary dipole can be
              formed...
                               Bigger
                               the force
Larger
surface area




     and thus greater attraction   Bigger
                                   the force
Larger
surface area           H                 H H H H H H
                                      H    C     C      C
                   H C H                C     C      C    H
                      H                H H H H H H
                   methane                   hexane
                 CH4 (MW=16)             C6H14 (MW=86)
             mp –182°C; bp –164°C       mp –95°C; bp 69°C
                   gas at rt               liquid at rt

           H H H H H H H H H H H H H H H H H H H H
       H    C      C       C     C     C      C   C   C   C   C
          C    C        C     C     C     C     C   C   C   C   H
        H H H H H H H H H H H H H H H H H H H H
                                     eicosane
                                 C20H42 (MW=282)
                                mp 36°C; bp 343°C



                                             Bigger
                    ...this goes    solid at rt
        someway to explaining why bigger
       molecules have higher boiling point
             (bp)...but other factors
                  also involved
                                             the force
Larger
surface area




          pentane                   2,2-dimethylpropane
          bp 36°C                         bp 9.5°C

         and at last explains the
       difference between isomers
                                         Bigger
                                         the force
Gecko feet
            ...and it is van der
          Waals forces that are
         responsible for Gecko’s
                ‘sticky’ feet!




Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
solvation




interaction of molecules & solvent
propanol
                                      H
                              H O
                          O
propanol & water mix                  H
 as they can interact
    by H-bonds...         H       H
                              O

                        water

soluble
alcohol (OH) makes propanol


                        means water
                       loving in Latin
                           (I think)




hydrophilic
hexane
                       H       H
                           O
            H                          H
   no interaction
        O
between molecules                  O
so hexane floats on
       waterH                          H
                           O
                       H       H
                      water

insoluble
hexane
          H       H
              O
     H                    H
 O                    O
     H                    H
                       polar molecules
              O       (water) do not mix
          H       H     with non-polar


         water
                      molecules (hexane)




insoluble
non-polar grease makes hexane




                       means water
                         fearing
                        (hating)




hydrophobic
polar
dissolves
 ...conversely, non-polar
   compounds dissolve




                            polar
      other non-polar
        compounds
hydrophilic

dissolves
    doesn’t really
        need
    explanation...
                     hydrophilic
hydrophobic

dissolves
      hydrophobic
propanoic acid




✔
 H       H
     O       O               H
                     H O
                 O
                             H
                 H       H
                     O
                         H-bonding allows
                     molecules to interact, thus
                     mixing...hydrophobic ethyl



         water
                      chain too small to effect
                             interaction
hydrophilic




✔
H       H
    O       O               H
                    H O
                O
                            H
                H       H
                    O



        water
butanoic acid




✔
 H       H
     O       O                H
                     H O
                 O
                              H
                 H       H
                     O
                            addition of one
                         more carbon to chain
                         does not make much
                         difference...butanoic


         water
                          acid still soluble in
                                 water
hexanoic acid




 /
✔✘
       O                  H
               H O
           O
                          H
           H         H
               O
              but a pentyl chain is
             pushing our luck...non-
           polar chain starts to effect


   water
            solubility and only a little
                   will dissolve
✘
decanoic acid
       O                   H
                H O
           O
                           H
           H           H
                O

                 get to a point where
                  the blob of grease
               controls the properties
                and overcomes the H-


   water         bond interactions...
✘
hydrophobic
      O                  H
              H O
          O
                         H
          H          H
              O

            ...to give us a compound
          that will not mix with water
            as too much of it is non-


  water
           polar. So decanoic acid is
                   hydrophobic
✘
                         sugar

                              O    OH
                HO

                         HO        OH
                              OH
   we can have the
reverse...a very polar
  molecule will not
dissolve / mix with a
  non-polar solvent
                         hexane
✘
     sugar

       O      OH
HO

 HO           OH
       OH

             ...each OH group is polar
             and thus will not mix with



     hexane
                     hexane...
✘
 sugar - hydrophilic

          O    OH
    HO

     HO        OH
          OH          very little interactions
                    between two molecules so
                         they do not mix




hexane - hydrophobic
✔
     sugar

       O     OH
HO

 HO          OH
       OH
                ...obvious I hope
               (sugar dissolves in
             coffee!)...due to all the
             OH groups H-bonding


     water           to water
✔
         sugar
                 H       H
         O           O
     H       H               O
                         H        H
             O       O             H
HO                       H       O
 H                       H         H
     O               O       lots of hydrogen bonding

     H       O                       H
                 H       H       O
     O H             O
                                 H
                     H
             water
doesn’t this look good!




especially after all this chemistry
what have
 we learnt?




                     all about
              intermolecular
                       forces
read
part   6

   ©paulbence@flickr

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Unit One Part 5: Intermolecular Forces

  • 1. Unit One Part 5: intermolecular forces we have looked at the bonds in molecules, now turn our attention to the bonds / forces between molecules
  • 2. 5 Unit One Part of molecules (pg56-58) Properties Intermolecular forces (pg59-66) Solubility (pg66-68)
  • 3. Gecko feet Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
  • 4. Gecko feet how do geckos walk on walls? to understand this cool phenomena we have to understand the attraction between molecules... Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
  • 5. O H O 2-methylpropan-2-ol ethoxyethane tert-butanol diethyl ether C4H10O C4H10O mp 26°C mp by looking at –116°C lets start these two simple molecules...they are structural isomers...
  • 6. O H O 2-methylpropan-2-ol ethoxyethane tert-butanol diethyl ether C4H10O C4H10O mp 26°C mp –116°C same atoms...but very different properties...why?
  • 7. why are the physical characteristics so different?
  • 8. is it the bonds in the molecule? yes... C–O–C versus C–O–H ...but...
  • 10. pentane 2-methylbutane 2,2-dimethyl C5H12 C5H12 propane bp 36.2˚C bp 28˚C C5H12 three more bp 9.6˚C isomers...this time no change in functional groups...
  • 11. pentane 2-methylbutane 2,2-dimethyl C5H12 C5H12 propane bp 36.2˚C bp 28˚C C5H12 bp 9.6˚C ...but they still have different physical properties!
  • 12. similar bonds, but very different properties
  • 13. need to understand forces between molecules
  • 14. ...of course, this is controlled by the bonds in the molecules...
  • 15. ...and the electrons (of course) ...of course, this is controlled by the bonds in the molecules...
  • 16. before we can look at the forces we need to define a few terms... ...of course, this is controlled by the bonds in the molecules...
  • 17. Bond dipoles (separation of charge) H Cl δ+ δ– we now know that electrons are not shared evenly between atoms... δ+ δ– = H Cl H Cl
  • 18. Bond dipoles (separation of charge) H Cl δ+ δ– δ+ δ– = ...they are attracted towards the most H Cl H Cl electronegative atom and the bond is said to be polarised
  • 19. Bond dipoles (separation of charge) H Cl δ+ δ– the bond dipole refers to the difference in charge on each atom and their separation δ+ δ– = H Cl H Cl
  • 20. H 2.1 Li Be B C N O F 1.0 1.5 2.0 2.5 3.0 3.5 4.0 Na Mg Al Si P S Cl Pauli scale of 0.9 1.2 1.5 1.8 2.1 2.5 3.0 electronegativities K Ca Br allows us to predict0.8 1.0 2.8 bond polarity... Rb Sr I 0.8 1.0 2.5 EN Bond Type difference Examples Calculation ionic > 1.7 NaCl 3.0(Cl) - 0.9(Na) = 2.1 CH3O–H 3.5(O) - 2.1(H) = 1.4 polar covalent 0.5 – 1.7 H–Cl 3.0(Cl) - 2.1(H) = 0.9 covalent 0 – 0.4 CH3–H 2.5(C) - 2.1(H) = 0.4 Pg H–H 2.1(H) - 2.1(H) = 0.0 35
  • 21. electro- negative 1 18 H 2 13 14 15 16 17 He 9 Li Be B C N O F Ne F Na Mg 3 4 5 6 7 8 9 10 11 12 Al Si P S Cl Ar K Ca Sc Ti V Cr Mn Fe Co Ni Cu Zn Ga Ge As Se Br Kr Rb Sr Y Zr Nb Mo Tc Ru Rh Pd Ag Cd In Sn Sb Te I Xe Cs Ba La Hf Ta W Re Os Ir Pt Au Hg Tl Pb Bi Po At Rn 87 We do not have to remember Fr Ra Ac Fr all the values, just the general trend (and eventually the effect of different functional groups) electro- positive
  • 22. Molecular dipoles (su m of b on d dipo les) if we add all the individual bond dipoles together we Cl get the... H C H H polar molecules
  • 23. Molecular dipoles (su m of b on d dipo les) ...the molecular dipole or dipole Cl moment H C H H dipole moment polar molecules
  • 24. Molecular dipoles (su m of b on d dipo les) Cl H C H O H H dipole H moment dipole ...compounds with moment a dipole moment are polar said to be polar molecules molecules
  • 25. Molecular dipoles (su m of b on d dipo les) if the bond dipoles cancel each other out (thats why shape is important), the Cl molecule will have no dipole moment and is Cl C Cl non-polar Cl no dipole moment non-polar m o l e c u l e s
  • 26. Inductive effects ( lo n g ran ge e ffect s) a functional group that attracts electrons is an electron withdrawing group (EWG) H2 H2 H2 C >C> or or δ+ C δ– H3C Cl H 3C Cl H3C δ+ Cl electron-withdrawing group
  • 27. Inductive effects ( lo n g ran ge e ffect s) first it causes a bond dipole in its own bonds H2 H2 H2 C >C> or or δ+ C δ– H3C Cl H 3C Cl H3C δ+ Cl electron-withdrawing group
  • 28. Inductive effects ( lo n g ran ge e ffect s) ...and this dipole induces a bond dipole in bonds next to it H2 H2 H2 C >C> or or δ+ C δ– H3C Cl H 3C Cl H3C δ+ Cl electron-withdrawing group
  • 29. Inductive effects ( lo n g ran ge e ffect s) the further from the functional group the smaller this polarisation H2 H2 H2 C >C> or or δ+ C δ– H3C Cl H 3C Cl H3C δ+ Cl electron-withdrawing group
  • 30. Inductive effects ( lo n g ran ge e ffect s) a group that pushes electrons away (alkyl) is an electron donating group H 3C > C electron-donating group
  • 32. Acidity O H O H H H O O H3C O H H3C O H we measure acidity by how readily a high low compound looses H+ pKa pKa
  • 33. Acidity the more stable the anion the more readily the compound looses O H H+ O H H H O O H3C O H H3C O H high low pKa pKa
  • 34. Acidity O H O H H H O O H3C O H H3C O H the more stable the anion, the more acidic the compound and the high low reaction shifts to the right... pKa pKa
  • 35. Acidity O H O H H H O O H3C O H H3C O H this is measured by pKa...the lower the pKa the more acidic the high low compound...more about this later in semester pKa pKa
  • 36. Acidity O H O H H H O O H3C O H H3C O H electron withdrawing groups help stabilise high low negative charges pKa pKa
  • 37. unit 3 This topic is covered in detail in unit 3 but at the moment all we have to remember is...
  • 38. high pKa O molecule is basic, this means it wants the H proton H+ or the anion is unstable R O wants H+
  • 39. low pKa O H R O molecule with a low pKa will loose a proton H+ readily to go from HA to losses H+ H+ and A– or...
  • 40. low pKa O ...the molecule can stabilise an anion (negative charge) H R O negative charge stable
  • 41. Acidity O H O H H H O O H3C O H H3C O H O O O O Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 42. Acidity O H wants H O+ H H H O O H3C O H H3C O H O O O O Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 43. Acidity the more electron O H withdrawing groups the O H H more stable the negative O O H charge and so the pKa is H3C O H lower and the compound H3C O H is more acidic O O O O Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 44. Acidity losses H H+ H O O H H O O H3C O H H3C O H O O O O Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 45. Acidity O R O O H stable O H H H O O H3C O H H3C O H O O O O Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 46. Acidity O H O H H H O O H3C O H H3C O H the further away the electron withdrawing group from the O O O Onegative charge the smaller the effect Cl H Cl H H Cl H O « O H3C O < O Cl Cl Cl pKa = 4.75 pKa = 2.85 pKa = 1.48 pKa = 0.70 CO2H Cl Cl CO2H CO2H Cl pKa = 2.85 pKa = 4.05 pKa = 4.50
  • 47. you do not need ! to learn these values!
  • 48. how does all this effect intermolecular forces?? so what intermolecular forces are there?
  • 49. covalent bond (strong) govern reactions H Cl H Cl forces between molecules are relatively weak BUT very important! intermolecular attraction (weak) physical properties
  • 50. sorry... the next slide is awful (in all the worst senses of the word)
  • 51. typical energy interaction (kJmol–1) ionic-ionic (ionic bond) 250 intramolecular carbon-containing covalent bond 350 forces oxygen-hydrogen covalent bond 460 hydrogen (H-) bond 20 intermolecular ion-dipole 15 forces dipole-dipole 2 London (dispersion) 2 shows just how weak intermolecular forces are by comparison...
  • 53. • Tables are rarely of any use in a presentation... • Lots of text on a PowerPoint (or Keynote) slide is not only really dull but looks crap and is second only to the use of... • ...bullet points in making you (and me) a little sleepy • So stick to pictures (and a lot of preparation)
  • 54. don’t get me started on the differences between... only the first is acceptable to me (but most people can’t see these these the difference between 1 & 3) learn to do presentations right...it’ll serve these you well!
  • 55. why does NaCl dissolve in water? ...or, now lets look at the intermolecular forces (at last)!
  • 56. H δ+ Cl Hδ+ δ-- O Na O δ-- H δ+ Hδ+ δ– δ+ δ+ δ– δ+ Cl– δ+ δ+ δ+ δ– Ion-dipole forces (15 kJmol-1)
  • 57. H δ+ Cl Hδ+ δ-- O Na O δ-- H δ+ Hδ+ δ– δ+ δ+ interaction of an ion (chloride) δ– δ+ Cl– δ+ δ+ δ+ δ– Ion-dipole forces (15 kJmol-1)
  • 58. H δ+ Cl Hδ+ δ-- O Na O δ-- H δ+ Hδ+ δ– δ+ δ+ δ– δ+ Cl– δ+ with a δ+ compound with a permanent δ+ δ– dipole (water) Ion-dipole forces (15 kJmol-1)
  • 59. H δ+ Cl Hδ+ δ-- O Na O δ-- H δ+ Hδ+ δ– δ+ δ+ δ– δ+ Cl– δ+ δ+ δ+ δ– relatively Ion-dipole strong...hence salt dissolves forces (15 kJmol-1)
  • 60. H δ+ Cl Hδ+ δ-- O Na O δ-- H δ+ Hδ+ δ– δ+note that water δ+ interacts with both anion and cation...really δ– δ+ helps Cl– δ+ δ+ δ+ δ– Ion-dipole forces (15 kJmol-1)
  • 61. δ– HO Hδ+ O Na O δ– H δ+ organic compounds can do the same (but only O–H bond) Ion-dipole forces (15 kJmol-1)
  • 62. δ+ δ– δ+ δ– two molecules with a dipole will interact... δ+ δ– weakly δ– δ+ Dipole-dipole forces (≈ 2 kJmol-1)
  • 63. Polarmix polar molecules / H3C Cl δ+ C O δ– δ+ H C Cl δ– H3C Cl this is why two polar molecules (like acetone & chloroform) will δ+ δ– δ+ δ– δ+ δ– mix...they are attracted δ– δ+ –δ +δ δ– δ+ to each other δ+ δ– δ+ δ– δ+ δ– δ+ δ– δ+ δ– δ+ δ– δ+ δ– δ– δ+
  • 64. Polardo/not mix molecules non-polar H H2 H2 δ+ O δ– C C CH3 H3C C C H H2 H2 but polar molecules won’t mix with non– polar...polar molecules run an exclusive club δ+ δ– δ+ δ– δ+δ– and they won’t let δ– δ+ δ– δ+ anyone else in... δ– δ+ δ– δ+ δ– δ+ δ+ δ–
  • 65. δ– H2 H3C δ+ O CH3 H3C C H2 C CH3 H3C C H2 CH3 O δ+ CH3 C CH3 δ– H2 propanone butane acetone Mol Wt. 58; bp 56°C Mol Wt. 58; bp –0.6°C permanent dipole no dipole compare these two molecules...similar Dipole-dipole size and identical weight... & boiling points
  • 66. δ– H2 H3C δ+ O CH3 H3C C H2 C CH3 H3C C H2 CH3 O δ+ CH3 C CH3 δ– H2 propanone butane acetone Mol Wt. 58; bp 56°C Mol Wt. 58; bp –0.6°C permanent dipole no dipole Dipole-dipole & boiling points ...but very different boiling points...
  • 67. δ– H2 H3C δ+ O CH3 H3C C H2 C CH3 H3C C H2 CH3 O δ+ CH3 C CH3 δ– H2 propanone butane acetone Mol Wt. 58; bp 56°C Mol Wt. 58; bp –0.6°C permanent dipole no dipole this is because acetone has dipole– dipole attractions holding molecules Dipole-dipole together and butane doesn’t & boiling points
  • 68. ...one intermolecular force to rule them all...
  • 69. δ+ δ– δ+ δ– δ+ δ+ Hydrogen H O H O bonding H H hydrogen bond
  • 70. δ+ δ– δ+ δ– δ+ δ+ Hydrogen a special kind of H dipole–dipole interaction...occurs O between... H O bonding H H hydrogen bond
  • 71. H-bond H X polar bond dono r (X = O, N etc) X H-bond lone pair on acceptor electronegative atom
  • 72. H-bonding it is responsible for water being so wonderfully odd water’s abnormal properties F.W. Starr/Wesleyan Univ.
  • 73. δ– H δ+ O δ+H H δ+ δ– O H O δ– δ+ H δ+ Hδ+ δ– δ+ O δ– O H δ+ H H δ+ H δ+ three molecules of similar size H2O (MW=18): boiling point 100°C and / or shape H2S .(MW=34): boiling point –60°C CH4 (MW=16): boiling point –162°C
  • 74. ...yet water has phenomenally high δ– H δ+ boiling point...all due O to H–bonding! (also explains ice) δ+H H δ+ δ– O H O δ– δ+ H δ+ Hδ+ δ– δ+ O δ– O H δ+ H H δ+ H δ+ H2O (MW=18): boiling point 100°C H2S .(MW=34): boiling point –60°C CH4 (MW=16): boiling point –162°C
  • 75. Methanol methanol only has one O–H bond so can only form one H-bond so has much lower bp (less attraction) CH3 δ+ Oδ–δ+ δ– H H O δ– CH3 O δ+ H3C H H δ+ O δ– CH3 1 hydrogen bond boiling point 62°C
  • 76. H-bonding carboxylic acids carboxylic acids are also capable of forming H– bonds between OH (H-bond donor) and C=O (polarised so lone pair is H-bond acceptor) δ– δ+ δ– O H O δ+ H3C CH3 O H O δ– δ+ δ–
  • 77. H-bonding carboxylic acids - solubility ...H-bonding allows some acids to dissolve in water as good attraction (hence we can have vinegar (shown) δ+ H O δ– and glacial acetic acid (very different) δ–O H H3C H δ+ δ– δ+ δ– H O H O δ– H O H δ+
  • 78. Hydrogen bonding vital in biology...
  • 80. H O R2 H H N N N O H R1 Hδ+ O δ– δ– O δ+ H H R4 N N R3 H O H Hydrogen β-sheets and α-helix etc are all formed by H-bonding between amides bonding
  • 81. without H-bonding no DNA double helix! ©Benny Herudek 3D Hifi - High Fidelity 3d Graphics Solutions DNA
  • 82. H N N H O CH3 N N H N N N O adenine thymine Hydrogen Watson-Crick base pairing (or whatever the biochemists call it) bonding
  • 83. all molecules can interact... don’t need a dipole to interact because...
  • 84. London (van der Waals or dispersion) forces here we have two molecules...
  • 85. London (van der Waals or dispersion) forces δ– δ+ ...chance allows the electrons of one molecule to bunch at one end causing an imbalance of electrons... momentary dipole
  • 86. London (van der Waals or dispersion) forces δ– δ+ momentary ...a disturbance in the dipole force...or setting up a momentary dipole...
  • 87. London (van der Waals or dispersion) forces δ– δ+ δ– δ+ ...as electrons don’t like each other this new bunch repulse electrons in a near by molecule induced momentary and set up an induced dipole... dipole dipole
  • 88. London (van der Waals or dispersion) forces this causes dipole–dipole attraction (momentarily)...but it will soon stop as the electrons are always on the move δ– δ+ δ– δ+ attraction induced momentary dipole dipole
  • 89. Larger surface area the larger the molecule, the bigger the surface area and the more electrons involved... Bigger the force
  • 90. Larger surface area ...this means a bigger momentary dipole can be formed... Bigger the force
  • 91. Larger surface area and thus greater attraction Bigger the force
  • 92. Larger surface area H H H H H H H H C C C H C H C C C H H H H H H H H methane hexane CH4 (MW=16) C6H14 (MW=86) mp –182°C; bp –164°C mp –95°C; bp 69°C gas at rt liquid at rt H H H H H H H H H H H H H H H H H H H H H C C C C C C C C C C C C C C C C C C C C H H H H H H H H H H H H H H H H H H H H H eicosane C20H42 (MW=282) mp 36°C; bp 343°C Bigger ...this goes solid at rt someway to explaining why bigger molecules have higher boiling point (bp)...but other factors also involved the force
  • 93. Larger surface area pentane 2,2-dimethylpropane bp 36°C bp 9.5°C and at last explains the difference between isomers Bigger the force
  • 94. Gecko feet ...and it is van der Waals forces that are responsible for Gecko’s ‘sticky’ feet! Autumn, K., et al. 2002. Evidence for van der Waals adhesion in gecko setae. Proc. Natl. Acad. Sci. USA 99, 12252-12256
  • 96. propanol H H O O propanol & water mix H as they can interact by H-bonds... H H O water soluble
  • 97. alcohol (OH) makes propanol means water loving in Latin (I think) hydrophilic
  • 98. hexane H H O H H no interaction O between molecules O so hexane floats on waterH H O H H water insoluble
  • 99. hexane H H O H H O O H H polar molecules O (water) do not mix H H with non-polar water molecules (hexane) insoluble
  • 100. non-polar grease makes hexane means water fearing (hating) hydrophobic
  • 101. polar dissolves ...conversely, non-polar compounds dissolve polar other non-polar compounds
  • 102. hydrophilic dissolves doesn’t really need explanation... hydrophilic
  • 103. hydrophobic dissolves hydrophobic
  • 104. propanoic acid ✔ H H O O H H O O H H H O H-bonding allows molecules to interact, thus mixing...hydrophobic ethyl water chain too small to effect interaction
  • 105. hydrophilic ✔ H H O O H H O O H H H O water
  • 106. butanoic acid ✔ H H O O H H O O H H H O addition of one more carbon to chain does not make much difference...butanoic water acid still soluble in water
  • 107. hexanoic acid / ✔✘ O H H O O H H H O but a pentyl chain is pushing our luck...non- polar chain starts to effect water solubility and only a little will dissolve
  • 108. ✘ decanoic acid O H H O O H H H O get to a point where the blob of grease controls the properties and overcomes the H- water bond interactions...
  • 109. ✘ hydrophobic O H H O O H H H O ...to give us a compound that will not mix with water as too much of it is non- water polar. So decanoic acid is hydrophobic
  • 110. sugar O OH HO HO OH OH we can have the reverse...a very polar molecule will not dissolve / mix with a non-polar solvent hexane
  • 111. sugar O OH HO HO OH OH ...each OH group is polar and thus will not mix with hexane hexane...
  • 112. ✘ sugar - hydrophilic O OH HO HO OH OH very little interactions between two molecules so they do not mix hexane - hydrophobic
  • 113. sugar O OH HO HO OH OH ...obvious I hope (sugar dissolves in coffee!)...due to all the OH groups H-bonding water to water
  • 114. sugar H H O O H H O H H O O H HO H O H H H O O lots of hydrogen bonding H O H H H O O H O H H water
  • 115. doesn’t this look good! especially after all this chemistry
  • 116. what have we learnt? all about intermolecular forces
  • 117. read part 6 ©paulbence@flickr