A metal cube dissolves in acid such that an edge of the cube decreases by 0 30 mm/min. How
fast is the Volume of the cube changing when the edge is 8.80 min? The volume is changing at a
rate of mm^3/min (round to the nearest integer as needed .)
Solution
V=a^3
=>dV/dt=3a^2 da/dt
=>dV/dt=3*(8.8)^2 * (-0.3)
=>dV/dt=-69.696 mm3/min