A man and a woman agree to meet at a cafe at about noon. If the man arrives at a time uniformly distributed between 11:35 and 12:15 and if the woman independently arrives at a time uniformly distributed between 11:50 and 12:40 , what is the probability that the first to arrive waits no longer than 5 minutes? Solution 1. Get the distribution of each person separately, one for the man and one for the woman. Recall that the uniform distribution is f(x)=1/(b-a), for a.