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if additional ice had melted after the final temperature had been recorded, but before the water was poured out of the calorimeter would the calculated value of the heat of fusion have been higher lower or unchanged
if additional ice had melted after the final temperature had been recorded, but before the water was poured out of the calorimeter would the calculated value of the heat of fusion have been higher lower or unchanged
Solution
Heat of fusion = (Q Heat lost by hot water - Q Heat gained by ice ) / mass of ice remaining
Heat of fusion is inversely proportional to remaining mass of ice
Now, if additional ice had melted after the final temperature had been recorded, then mass of ice would be less than recorded and heat of fusion calculated will be more than recorded after calculation
.

if additional ice had melted after the final temperature had been recorded, but before the water was poured out of the calorimeter would the calculated value of the heat of fusion have been higher lower or unchanged
if additional ice had melted after the final temperature had been recorded, but before the water was poured out of the calorimeter would the calculated value of the heat of fusion have been higher lower or unchanged
Solution
Heat of fusion = (Q Heat lost by hot water - Q Heat gained by ice ) / mass of ice remaining
Heat of fusion is inversely proportional to remaining mass of ice
Now, if additional ice had melted after the final temperature had been recorded, then mass of ice would be less than recorded and heat of fusion calculated will be more than recorded after calculation
.

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