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please provide clear, detailed explanations
120-V 25.29 When switch S in Fig. E25.29 Figure E25.29 is open, the voltmeter V reads 3.08 V
When the switch is closed, the volt- meter reading drops to 2.97 V, and the ammeter A reads
1.65 A. Find the emf, the internal resistance of the battery, and the circuit resistance R. Assume
that the two meters are ideal, so they don't affect S the circuit. bulb draw 25.3 acro mu of t 25 in
Th Wi
Solution
A) emf e = 3.08 V
B) ir =3.08-2.97 =0.11..
internal resistance r = 0.11/1.65 =0.067 ohms...
C) i =e/(R+r)...
R+r = e/i = 3.08/1.65 = 1.80
R = 1.8 ohms

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