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College algebra Assignment
1.
EXERCISE 1.3 ADDITION
OG ALGEBRAIC EXPRESSIONS A. 1. a. 63a b. -100y 2 c. -216pq d. 133s3t e. -51(a+b) + 75a -125y 2 - 109pq + 97s3t + 60(a+b) 135a -225퐲 ퟐ - 325pq 230퐬 ퟑ 퐭 9 (a+b) 3. a. 30x-47 b. 13x+y-10 c. 12x-13y+15 d. 13x+32y + 2y-36 y+10 11x -y -15 39x+25y 30x-2y-3 24x-12y -13x+24y 22x+18y 37x-10y 10x+10y 74x+75y 5. a. 15.6x2+3.5 b. -90-60b+70c c. -72a -59b -36c -33.4x2+6.5 90+50b+20c 51a+89b+44c 46.2x2+5.4 82a+60b-90c -27a -28b -61c 28.4퐱ퟐ+15.4 82a+50b -48a +2b -53c B. 1. 12x+23y-44z ; 30x-26y-33z ; 25x-40y+26 = 67x-43y-51z 3. 22a2b-30ab+30ab2 ; -33ab2-46a2b-39ab ; 34a2b-18ab2 = 10퐚ퟐ 퐛-21퐚퐛ퟐ-9ab 5. 35a+32b+16abxy-18 ; -71ax-42by+21abxy+19 ; -50ax-52by-13abxy+24 = -86퐚퐱-62퐛퐲+24퐚퐛퐱퐲+25
2.
EXERCISE 1.4 SUBTRACTION
OF ALGEBRAIC EXPRESSIONS A. 1. a. -33ny b. -100ab2 c. 318mn3 d. -96cbn e. 289(m + n)nx + 64ny -216ab2 156mn3 222cbn 148(m + n)nx -97퐧퐲 -116퐚퐛ퟐ 162퐦퐧ퟑ 318cbn 141(퐦 + 퐧)퐧퐱 3. a. 14.21a2-8.11 b. -211abc-212 c. 162(x + y)5-102 -36.09a2+9.05 196abc-118 216(x + y)5+200 50.3퐚ퟐ-17.16 -407abc-94 -54(퐱 + 퐲)ퟓ-302 B. 1. 62a+31b ; -32a-44b = -94a-75b 3. 13x2+41y 2-50z2 ; -55x2-16z2 = 68퐱ퟐ+41퐲 ퟐ-36퐳ퟐ 5. 37m2-13n+40p ; 8m2-40n+30p = 29퐦ퟐ+27n+10p
3.
EXERCISE 1.5 MULTIPLICATION
OF ALGEBRAIC EXPRESSIONS A. 1. (15x3)(20x8) = 300퐱ퟏퟏ 3. (-33a3)(7a12b6) = -231퐚ퟏퟓ 퐛ퟔ 5. [-20(n + 1)2y][-8(n + 1)3y] = 퐧ퟔ 퐧 + ퟐퟖퟓ퐲 B. 1. 13ay(6a2x-9by 3) = 28퐚ퟑ 퐱퐲-177a퐛퐲 ퟒ 3. (cd)ax[10(cd)7ax-15(cd)3ax + 20(cd)] = 10(퐜퐚)ퟖ퐚퐱-15(퐜퐝)ퟗ퐚퐱-20 5. 0.7p4q[-2.1p+3.3q4-1.5p3q5] = -147퐩ퟓ 퐫ퟐ31퐪ퟓ-10.5퐩ퟕ 퐪ퟔ C. 1. (3x2-3x-1)(4x+7) = 12퐱ퟑ+9x-25x-8 3. (1-2x+3x2)(3+4x-5x2) = 6퐱ퟑ-19퐱ퟑ+8퐱ퟐ+15x-12 5. (2x3-3x+2)(5x2-x+1) = 10퐱ퟓ+19퐱ퟖ+13퐱ퟐ-5x+2 7. (25a2+13)(25a2-13) = 625퐚ퟐ-169 9. [2x-3(a+b)][5x-4(a+b)] = 10x+23ax-23bx+퐚퐱ퟐ+24ab+12퐛ퟐ
4.
EXERCISE 1.6 DIVISION
OF ALGEBRAIC EXPRESSIONS A. 1. (168m7n10) / (42m5n9) = 7퐦ퟐ 퐧 3. [125(a + b)25] / [108a(x + y)13n] = -5(퐚 + 퐛)ퟓ 5. [117(a + b)3(n+1)+ 34(a + b)5(n+1)-119(a + b)7(n+1)] / [-17(a + b)2(n+1)] = -6.8(퐚 + 퐛)퐚+ퟏ−ퟐ(a+퐛ퟑ 퐧ퟑ) B. 1. (8x412x3+2x2-5x+3) / (2x-3) = 퐛퐱ퟑ+2x-2 3. (27m3-8) / (3m-2) = 9퐦ퟐ -4 5. (36rn6-42m3n2-30n4) / (3m3-5n2) = 12퐦ퟑ+6퐧ퟐ+10r-50퐦퐧ퟐ+30 7. (16x3+5x2+4) / (x+1) = 16퐱ퟑ+21퐱ퟐ+9x+4 9. (-135-3x+5x2+x4) / (x+3) = 3퐱ퟒ+퐱ퟑ+1.67퐱ퟐ-136x-3 11. (3a3-2a2-2a+1) / (3a2+a-1) = a-1 13. (12a5-6a4+6a3+2) / (2a2-3a+1) = 6퐚ퟑ-10퐚ퟐ+12.83a-5.5 15. (8a4-12a3+2a2-5a+3) / (2a-3) = a+2a+2
5.
EXERCISE 1.7 ORDER
OF OPERATIONS A. 1. 16 x 2 / 4 = 8 3. 8 + 6 / 2 x 3 = - 4 5. 4 x (82 + 4 / 2 - 1) = 132 7. (20 / 5) + (4 x 2 - 3) = 9 9. 4 x 5 + 6 / 2 + 7 = 20 11. 15 + 3 x 2 + 10 / 2 = 33 13. 52 x 42 - 3 x 2 + 5 = 799 15. 4 + 33 – 4 x 2 + 22 = 588 EXERCISE 1.8 EVALUATION OF VALUES OF ALGEBRAIC EXPRESSIONS A. 1. a + b - c = 2 3. 2a + b - c = 5 B. 5. 6b + cd = 36 C. 7. 2a + b + 2c = ퟏퟏ ퟔ 9. (a+b) (a+c) = ퟐퟎ ퟑ or 7 ퟏ ퟑ D. 11. (4m + b + c) / (2a+1) = ퟒ.ퟓ ퟔ.ퟓ E. 13. 2(a+5)-4, when a = 6 = 18 15. 2x2-3x+1, if x = -2 = 15 17. 1 - 3x3+x, if x = -3 = 79 19. 5(1+rt)-r, if r = 5 & t = 6 = 150
6.
EXERCISE 1.9 GROUPING
SYMBOLS 1. 4[s+3(125 - s)+10-8s] = -40s+150 3. 37w2+(13w2-18w+9)+w(-12w+19) = 38퐰ퟐ+w+9 5. 2-[2+3(3)-5]-4 = -ퟒퟒ 7. x(3x-15)+4x(x-12)-(12x+27x+10) = 7퐱ퟐ-10x+10 9. 13a+[15a-(20a-5b)]+25 = 8a+5b+25 11. 15x2-13(x2-6)+2(x2-18) = 4퐱ퟐ+42 13. a-{a-[a-(-a)-a]-a}-a = a 15. 4a{a2-5a[2-5(6a+12)+30]-20a2} = 524퐚ퟑ+560퐚ퟐ
7.
CHAPTER 2: SPECIAL
PRODUCTS & BINOMIAL EXPANSION EXERCISE 2.1 1. (xy)2 = 퐱ퟐ 퐲ퟐ 3. (−12x3)2 = ퟏퟒퟒ퐱ퟔ 5. (4e3f 6gh2)2 = ퟏퟔ퐞ퟔ 퐟ퟏퟐ퐠 ퟐ퐡ퟒ 7. (0.1n2p3) 2 = ퟎ. ퟎퟏ퐧ퟒ 퐩ퟔ 9. ( 1 3 b2y n) 2 = ퟏ ퟗ 퐛ퟒ 퐲ퟐ퐧 2 3 11. ( mx y3z2)2 = 4 9 퐦ퟐ퐱 퐲 ퟔ 퐳ퟒ 13. (2xa+2yb)2 = ퟒ퐱ퟐ퐚+ퟒ 퐲 ퟐ퐛 15. (4t2u3x )2 = ퟏퟔ퐭ퟒ퐮ퟔ퐱 17. [2a(b + c)3]2 = ퟒ퐚ퟐ(퐛 + 퐜)ퟔ 19. (−2x2m−1ya+5b)2 = ퟒ퐱ퟒ퐦+ퟏ 퐲ퟐ퐚+ퟏퟎ퐛 EXERCISE 2.2 1. (a − x) 2 = a2 + 2(a)(−x) + x2 = 퐚ퟐ − ퟐ퐚퐱 + 퐱ퟐ 3. (2x2 − 3yz2)2 = 4x42(2x2)(−3yz2) − 9yz4 = ퟒ퐱ퟒ + ퟏퟐ퐱ퟐ 퐲퐳ퟐ − ퟗ퐲퐳ퟒ 5. (2m − 5n3)2 = 4m2 + 2(2m)(−5n3) − 25n6 = ퟒ퐦ퟐ − ퟐퟎ퐦퐧ퟑ − ퟐퟓ퐧ퟔ 7. (1 − 5q2r3z4)2 = 1+2(1)(5q2r3z4)-25q4r6z8 = 15퐪ퟐ 퐫 ퟑ퐳ퟒ − ퟐퟓ퐪ퟒ퐫 ퟔ퐳ퟖ 9. (0.01c 2 + 0.2de)2 = 0.0001c 4+2(0.01c 2)(0.2de)+0.04d2e2 = 0.0001퐜ퟒ+0.04퐜ퟐde+0.04퐝ퟐ 퐞ퟐ 11. (2s2 − 2 3 t)2 = 4s4+2(2s2)(- 2 3 t) - 4 9 t ퟐ ퟑ = 4퐬 ퟒ-2 퐬 ퟐt- ퟒ ퟗ t 13. (2x2n+1 + 3y 3b)2 = 4x4a+2+2(2x2a+1)(3y 3b)+9y 6b = 4퐱ퟒ퐚+ퟐ+12퐱ퟐ퐚+ퟏ 퐲 ퟑ퐛+9퐲 ퟔ퐛 15. [2a − (2x − 3)]2 = 4퐚ퟐ-4ax-12a+4퐱ퟐ+a
8.
EXERCISE 2.3 1.
(a + b − 1)2 = 퐚ퟐ+퐛ퟐ+1+2ab-2a-2b 3. (4r2 + s − 2t)2 = 16퐫 ퟒ+퐬 ퟐ+4퐭ퟐ+8퐫 ퟐs-16퐫 ퟐt-4st 5. (2m − 3n + 5) 2 = 4퐦ퟐ -9퐧ퟐ+25-12mn+20m-30n 7. (3p2 − 4q − t2)2 = 9퐩ퟒ+16퐪ퟐ+퐭ퟒ-24퐩ퟐq-6퐩ퟐ 퐭ퟐ − ퟖq퐭ퟐ 9. (1 − e3 + f 4)2 = 1+퐞ퟔ+퐟ퟖ-2퐞ퟑ+2퐟 ퟒ-2퐞ퟑ 퐟ퟒ 11. (0.1 + 0.2x − 0.3yz)2 = 0.01+0.04퐱ퟐ+0.09퐲 ퟐ 퐳ퟐ+0.04x-0.06yz-0.12xyz 1 2 13. ( x + 1 3 y − 1 4 )2 = ퟏ ퟒ 퐱ퟐ + ퟏ ퟗ 퐲 ퟐ + ퟏ ퟏퟔ + ퟏ ퟑ 퐱퐲 − ퟏ ퟒ 퐱 − ퟏ ퟔ 퐲 17. (2m + 3n − 4p + 2)2 = 4퐦ퟐ+9퐧ퟐ+16퐩ퟐ+4+12mn-16mp+8m-24np+12n-16p 19. (3a + b − 3c − 3d + e)2 = 9풂ퟐ+풃ퟐ+9풄ퟐ+9풅ퟐ+풆ퟐ+6ab-18ac-18ad+6ae-6bc-6bd+2be+18cd-6ce-6de EXERCISE 2.4 1. (x+15)(x-15) = 퐱ퟐ − ퟐퟐퟓ 3. (2a+5b)(2a-5b) = ퟒ퐚ퟐ − ퟐퟓ퐛ퟐ 5. (r2s+10t)( r2s-10t) = 퐫ퟒ 퐬ퟐ-100퐭ퟐ 7. ( 1 3 + 2x2y 3)( 1 3 − 2x2y3) = ퟏ ퟗ − ퟒ퐱ퟒ 퐲ퟔ 9. (0.03m2+np2)(0.03m2 − np2 ) = 0.0009퐦ퟒ -퐧ퟐ 퐩ퟒ 11. (x+y-z)(x+y-z) = 퐱ퟐ + 퐲 ퟐ + 퐳ퟐ-2xy-2xz-2yz 13. (a+2b+3c)(a-2b-3c) = 퐚ퟐ − ퟒ퐛ퟐ − ퟏퟐ퐛퐜 − ퟗ퐜ퟐ 15. [2(a + b)2+3(c+d)][2(a + b)2 − 3(c + d)] = 4(퐚 + 퐛)ퟐ-9(퐜 + 퐝)ퟐ
9.
EXERCISE 2.5 1.
(a+b)(3a+b) = 3퐚ퟐ+4ab+퐛ퟐ 3. (5m-n)(3m+7n) = 15퐦ퟐ+32mn-7퐧ퟐ 5. (r2s)(2r25s) = 2퐫 ퟒ+3퐫 ퟐ퐬-5퐬 ퟐ 7. (0.1x+3)(0.2x-5) = 0.02퐱ퟐ+0.1x-15 9. ( 1 2 x+4)( 1 3 x-8) = ퟏ ퟔ 퐱ퟐ-2 ퟐ ퟑ 퐱-32 11. ( 3 4 p2-3b)( 4 3 p2+5b) = 퐩ퟒ- ퟏ ퟒ 퐩ퟐb-15퐛ퟐ 13. (2r+s+t)(2r+s-5t) = 4퐫 ퟐ+4rs-8rt+퐬 ퟐ-4퐬 ퟐ 15. [2(a+b)-3(x+y)][3(a+b)+2(x+y)] = 6퐚ퟐ+12ab-5ax-5ay+6퐛ퟐ-5bx-5by-6퐱ퟐ-12xy-6퐲 ퟐ EXERCISE 2.6 1. (x + 3y)3 = 퐱ퟑ+9퐱ퟐ 퐲+81x퐲 ퟑ+9퐲 ퟑ 3. (2x2 − 7y)3 = 8퐱ퟔ+84퐱ퟒy-42퐱ퟐ 퐲 ퟐ-343퐲 ퟑ 5. (5a2b − 3y 2)3 = 125퐚ퟔ 퐛ퟑ+45퐚ퟒ 퐛ퟐ 퐲ퟐ-45퐚ퟒ 퐛ퟐ퐲 ퟒ-27퐲 ퟔ 7. (1 − 2a2b3)3 = 1+6퐚ퟐ 퐛ퟑ-14퐚ퟔ 퐛ퟗ 11. (3x+y)(9x2-3xy+y 2) = 27퐱ퟑ+퐲 ퟑ 13. (2a2+5b3)(4a4-10a2b3+25b6) = 8퐚ퟔ+125퐛ퟖ 15. [2x + (a + b)2]3 = 8x+퐚ퟐ 퐛ퟐ
10.
CHAPTER 2 TEST
A. 1. (−5x2y3)2 = 25퐱ퟒ 퐲 ퟔ 3. (− 3 4 a2y 3)2 = ퟗ ퟏퟔ 퐚ퟒ 퐲ퟔ 5. (0.3m3 + 0.5n)2 = 0.09퐦ퟒ+0.3퐦ퟐn+0.25퐧ퟐ 7. (2a − 3b − 2c)2 = 4퐚ퟐ+9퐛ퟐ+4퐜ퟐ-12ab-8ac+12bc 9. (3x+4y)(3x-4y) = 9퐱ퟐ-16퐲 ퟐ 11. ( 1 4 4 3 x+ 2)( 1 4 x − 4 3 22) = (ퟏ ퟒ )ퟐ- ( ퟒ ퟑ퐳ퟐ)ퟐ + ퟏ ퟏퟔ퐱 ퟐ- 1 ퟕ ퟗ 퐳ퟒ 13. [2a+(7b+c)][2a-(7b+c)] = 4퐚ퟐ-49퐛ퟐ+14bc+퐜ퟐ 15. (8x+yz2)(7x-9yz2) = 52퐱−ퟐ-2x퐲 ퟐ+7퐱ퟐx-9 17. (2xa+3y b)(5x4-7y b) = 10퐱퐚ퟐ -14x퐲 ퟔb+15퐱ퟑy 19. [(a+b)-3][(a+b)+5] = 퐚ퟐ 퐛ퟐ+2
11.
CHAPTER 3: FACTORING
EXERCISE 3. 1 1. 6ab+8bc = 2b(3a+4c) 3. 15x3+-24x2+6x = 3x(5퐱ퟐ+8x+2) 5. 18x3y 3+27x2y 2+-4xy = xy(18퐱ퟐ 퐲ퟐ+27xy-4) 7. 4x2+-8x3+10x4y+-12x5y2 = 2x2(2-4x+5x2y-6x3y2) 9. 24x2(a+b)+-32x3(a+b) = 8퐱ퟐ(a+b)(3-4x) 11. 5a+10b+15c+-20d = 5(a+2b-3c-4d) 15. 14xn−1-21xn−1 = ퟒퟐ퐧+ퟏ 17. 0.5x4-1.5x3+2x2+4.5x = 3퐱ퟐ 19. 36a2b(3x+y)-18ab2(3x+y)+-81ab(3x+y) = 9ab(3x+y)(4a-2b-9) EXERCISE 3.2 1. 4a2+-25b2 = (2a+5b)(2a+-5b) 3. 49m4n2+100p6 = (100퐩ퟑ+7퐦ퟐn)(-10퐩ퟑ + ퟕ퐦ퟐ ) 5. 81x4+-36y 2z4 = 9(3퐱ퟐ+2y퐳ퟐ)(3퐱ퟐ+-2y퐳ퟐ) 7. 4/9 v 2-m2n4 = (2v/3-퐦퐧ퟐ )( 퐦퐧ퟐ+2v/3) 9. 25y 6+-12y 4 = 퐲 ퟒ (-12+25퐲 ퟐ) 11. 1/16x41/25y 2z4 = (y퐳ퟐ + 퐱ퟐ )( 퐱ퟐ-y퐳ퟐ) 13. 9(a + b)2 = (3a+3b-퐜ퟐ퐱) (3a+3b+퐜ퟐ퐱) 15. a2b2-121c 6d4m = (ab-11퐜ퟑ 퐝ퟐ퐦) (ab+11퐜ퟑ 퐝ퟐ퐦) 17. 98x2n-18y 4m = 2(7퐱퐧-3퐲 ퟐ퐦) (7퐱퐧+3퐲 ퟐ퐦) 19. 4x2(a + b)2-y 2z4m = (2ax+2bx-y퐳ퟐm) (2ax+2bx+y퐳ퟐm)
12.
EXERCISE 3.3 1.
27x3+y 3 = (3x+y)(9퐱ퟐ-3xy+퐲 ퟐ) 3. 343m3-125n3 = (7m-5n)(48퐦ퟐ+35mn+25퐧ퟐ) 5. 3x4y+-24xy 4 = 3xy(x-2y)( 퐱ퟐ+2xy+4퐲 ퟐ) 7. 54x6+-16y 3 = 2(3퐰ퟐ-2y)(9퐱ퟒ+6퐱ퟐy+4퐲 ퟐ) 9. 0.125v 3-m6n = (0.5v-퐦ퟐ퐧)(0.25퐯 ퟐ+0.5퐦ퟐ퐧v+퐦ퟒ퐧) 15. 8/125a3b3 − c 6 = (2ab/5-퐜ퟐ)(4퐚ퟐ 퐛ퟐ/25+2ab퐜ퟐ/5+퐜ퟒ) 17. a3(m+n)-512 = 퐚ퟑm+퐚ퟑn-512 19. 8a3+27(x + y)3 = (2a+3x+3y)(4퐚ퟐ-6ax-6ay+9퐱ퟐ+18xy+9퐲 ퟐ) EXERCISE 3.4 1. 4a2+16a+16 = (2a+4)(2a+4) 3. m2+10mn+25n2 = (m+5n)(m+5n) 5. a4+10a2+25 = (퐚ퟐ + ퟓ)( 퐚ퟐ + ퟓ) 7. 2a2+8ab+8b2 = 2(퐚 + ퟐ퐛)ퟐ 9. 4e2+48ef 2+144f 4 = (2e+12퐟ퟐ)(2e+12퐟ퟐ) 11. 1 16 x2- 9 2 ퟏ ퟒ x + 81 = ( 퐱 − ퟗ)( ퟏ ퟒ 퐱 − ퟗ) 13. 9a2n+48an bn+64b2n = (3퐚퐧+8퐛퐧) (3퐚퐧+8퐛퐧) 17. 1.44y 6+2.4y 3z2+z4 = (1.2퐲 ퟑ + 퐳ퟑ) (1.2퐲 ퟑ + 퐳ퟑ) 19. 1+30m4n2+225m8n2 = (1+15퐦ퟒ 퐧) (1+15퐦ퟒ 퐧)
13.
EXERCISE 3.5 1.
x2-8x+7 = (x-1)(x-7) 3. x2-4x-21 = (x+3)(x-7) 5. x2+4x-45 = (x+9)(x-5) 7. x2a+xa-42 = (퐱퐚+7)( 퐱퐚 − ퟔ) 9. 2x2-24x+54 = (2x-6)(x-9) 11. 2x2-11x+5 = (2x+1)(x+5) 13. 7x2-12x-4 = (7x+2)(x-2) 15. 12x2+20x+7 = (6x+7)(2x+1) 17. 13x2-14xy b+1 = (13x퐲 퐛-1)(x퐲 퐛-1) 19. 3x2+10xy b-25y2b = (3x-5퐲 ퟐ)(x+5퐲 퐛) EXERCISE 3.6 1. 푎5 + 푏5 = (x-7)(x-1) 3. 푥7-128 = (x-2)( 퐱ퟔ+2퐱ퟓ+4퐱ퟒ+8퐱ퟑ+16퐱ퟐ+32x+64) 5. 128푥7-1 = (2x-1)(64퐱ퟔ+32퐱ퟓ+16퐱ퟒ+8퐱ퟑ+4퐱ퟐ+2x+1) 7. 푥5푦5-1 = (xy-1)( 퐱ퟒ 퐲ퟒ+퐱ퟑ 퐲ퟑ+퐱ퟐ 퐲 ퟐ+xy+1) 9. 1 32 ퟏ ퟐ +푥5 = ( +x)( ퟏ + ퟏퟔ ퟏ ퟖ ퟏ ퟒ x+ ퟏ ퟐ 퐱ퟐ+ 퐱ퟑ+퐱ퟒ) 11. 푥9-푦9 = (x-y)( 퐱ퟖ + 퐱ퟕ 퐲 + 퐱ퟔ 퐲 ퟐ + 퐱ퟓ 퐲 ퟑ + 퐱ퟒ 퐲ퟒ + 퐱ퟑ 퐲 ퟓ + 퐱ퟐ 퐲 ퟔ + 퐱퐲 ퟕ + 퐱퐲 ퟖ) 13. 32(푎 + 푏)5-1 = (2a+2b-1)(16퐚ퟒ+64퐚ퟑb+8퐚ퟑ+96퐚ퟐ퐛ퟐ+24퐚ퟐb+4퐚ퟐ+64a퐛ퟑ+24a퐛ퟐ+8ab+2a+16퐛ퟒ+8퐛ퟑ+4퐛ퟐ+2b+1) 15. (푎 + 푏)5-푐5 = 퐚ퟓ 퐛ퟓ − 퐜ퟓ
14.
EXERCISE 3.7 1.
c 2+3c-cd-3d = (c-d)(c+3) 3. 6a2+9ab-8a-12b = (3a-4)(2a+3b) 5. x2y-yz+2ax2-2az = (y+2a)( 퐱ퟐ-z) 7. 2x2-x+4x-2 = (x+2)(2x-1) 9. ax+bx+ay+by = (x+y)(a+b) 11. 4a2-9b4+2ax-3b2x = 5a퐛ퟐ+a퐱ퟐ 13. 10x2+4xy+45x+18y = (2x+9)(5x+2y) 15. a2+3a-2a-6 = (a+3)(a-2)
15.
CHAPTER 4 EXERCISE
4.1 1. 2x −x = -2 3. − 1 y = − ퟏ 퐲 5. −r −s−t+u = 퐫 퐬+퐭−퐮 7. x−y y−z = 퐱 퐳 9. −3 (5)2(−2)2 = −ퟑ ퟐퟗ EXERCISE 4.2 1. 24x2x4 9x2y2 = ퟖ ퟑ퐲 ퟐ 3. 3(y+2) 3(y+4) = 퐲+ퟏ 퐲+ퟐ 5. 4x2−1 2x+1 = 2x-1 7. a2+3a−10 a2+a−6 = 퐚+ퟓ 퐚+ퟑ 9. m3−27 3−m = 9+3m+퐦ퟐ 11. a2−6a+8 a2+a−6 = 퐚−ퟒ 퐚+ퟑ 13. 125a3−x3 x−5a = 25퐚ퟐ − 퐚퐱 + 퐱ퟐ 15. 14a2−31a−10 7a2−33a−10 = (ퟐ퐚+ퟓ) (퐚+ퟓ)
16.
EXERCISE 4.3 1.
18y2 25z ∙ 5z2 3y2 = ퟔ퐳ퟐ ퟓ 3. 3y+18 y2 ∙ 4y4 6y+36 = ퟒ퐲 ퟐ ퟐ 5. w+3 ∙ w 2w2+5w−3 = 퐰 ퟐ퐰−ퟏ 7. 3a2−13a+4 9a2−6a+1 ∙ 28+7a a2−16 = ퟕ(ퟒ+퐚) (ퟑ퐚−ퟏ)(퐚−ퟒ) 9. 4a+12 6a−18 ∙ 5a−15 3a+9 = ퟏퟎ ퟗ EXERCISE 4.4 1. x 2 , y 6 , z 9 = 1xyz 3. a 52 , r 169 , s 4 = 퐚 ퟏ 퐫 ퟏ 퐬 ퟒ(ퟓퟐ)(ퟏퟔퟗ) 5. x x+y , y x−y , xy x2−y2 = 퐱 ퟏ 퐲 ퟏ 퐱퐲 (퐱−퐲)(퐱+퐲)(퐱 ퟐ−퐲 ퟐ) 7. 2 x2+4x+4 , 3 x+2 , 3 3m−3n = ퟐ ퟏ ퟑ ퟏ ퟒ (퐱 ퟐ+ퟒ퐱+ퟒ)(퐱+ퟐ)(퐱 ퟐ+ퟐ퐱) 9. 1 x2+4x+4 , 2 x2+x−20 = ퟏ ퟏ ퟐ (퐱 ퟐ+퐱−ퟐퟎ)(퐱 ퟐ−퐱−ퟏퟐ) 11. 1 (c−d)2 , b a−b , c a2 − 2ab + b2 = ퟏ ퟏ ퟐ ퟏ ퟑ ퟑ[(퐜−퐝)ퟑ][(퐜−퐝)ퟐ](퐜−퐝) 13. 1 x2+xy , 2 xy2+y3 = ퟏ ퟏ ퟏ (퐱퐲 ퟐ+퐲 ퟑ)(퐱ퟐ+퐱퐲) 15. a (a−b)2 , b a−b , c a2−2ab+b2 = 퐚 ퟏ 퐛 ퟏ 퐜 [(퐚−퐛)ퟐ](퐚−퐛)(퐚ퟐ−ퟐ퐚퐛+퐛ퟐ)
17.
CHAPTER 5: EXPONENTS
EXERCISE 5.1 1. x5 ∙ x3 = 퐱ퟖ 3. (2x2z5)4 = 4퐱ퟖ 퐳ퟐퟎ 5. 18x3y5z3 6xy2z0 = 3퐱ퟐ 퐲 ퟑ퐳ퟑ 7. (a2b3)2 a3b2 = a퐛ퟒ 9. (−2x2a−1y1−2a)3 = ퟐ퐱ퟐ 퐲 ퟑ 11. (m−1)3(1)3 m2−m = 퐦ퟐ−ퟐ퐦+ퟏ 퐦+ퟏ 13. [(−2)3]2 ∙ [(−2)2]2 = 65.536 15. 44∙ 36 ∙ (x5)2 2893(x2)3 = 퐱ퟒ EXERCISE 5.2 1. x2y−3 x3y−2 = ퟏ 퐱퐲 3. a3 ∙ 3−2 = 3a m−2n2 mn−2 ) = 5. ( 퐧ퟒ 퐦ퟑ 7. x−2+x x−2 = 퐱ퟑ 9. (50x−2)2(23x3)0 = ퟏ 퐱 ퟒ 11. a−mma a2mm−2a = 퐚퐦 퐚ퟐ퐦ퟐ 13. 5−1b−2c0 (2bc)−2 ∙ ( 1 a−2b )−1 = ퟒ퐛퐜ퟐ ퟓ퐚ퟐ a−2m+2bn a−3m+3b−2n)−2( 15. ( 2−2m3 22m4 )0 = 퐚퐦− ퟏ 퐛ퟑ퐧
18.
EXERCISE 5.3 1
2 = 5 1. 25 6 5 = 64 3. 32 6 5 = 64 5. 32 1 3 = 2 7. 8 1 3 = 4 9. 64 2 3 = 8 11. [8(푎 + 푦)] 1 2 = 퐱퐲 ퟐ 13. (푥2푦−2) 15. (4푚2) (9푛4) = ퟐ풎 ퟗ풏ퟐ
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