he current direction is into the page at points magnetic field at point P, located at the center of the square of edge length-. m A 3.0×104 T ? 72x10\" ? C4.0 x 10T D 20x10T E 1.5x 10*T carry equal currents of 1 -15.0 A The figure belos is an nd viw of the condascions and B and out of the page at Cand D.Calcult te magnte of e 18. A bar magnet is points downward along the page as it falls. Which statement is correct? A The current in the loop flows first in a clockwise, then in a counsenclockwise direction dropped from above and falls through the loop of wire shown below. The south pole of the bar magnet Drop down B. The current in the loop flows first in C. The D. The current in the loop always flows in a counterclockwise direction a counterclockwise, then in a clockwise direction current in the loop always flows in a clockwise direction. current flows in the loop because both ends of the magnet move through the loop and a 2.3 2 resistor are used to form a circuit in the shape of a square. 140 cm by 14.0 cm. A from 0.70 T to 0.26 T in a time interval of 2.5 ms. The average induced current and its uniform but nonsteady magnetic field magnetic field is decreased f through the resistor, in this time interval, are closest to: A. 2.2 A, from a to b B. 1.5 A, from a to b C. 0.16 A, from b to a D. 0.34 A, from b to a E. 0.10 A, from b to a is perpendicular to the plane (out of the page) of the circuit. The magnitude of the ? ?114cm 2.3 2 20. Find the magnitude and direction of the induced current in the metal rail and moving rod. The magnetic field is uniform and directed as shown (clockwise: cw, counterclockwise: ccw). A. 5.0 A, ew B. 5.0 A, cew C. 1.2 A, cw D. I.I A, cew E. 2.0 A, cew 150 m 2.00 m/s
Solution
20)
Emf induced is given by:
e = BLv = 4*1.5*2 = 12 V
Current:
I = e/R
= 12/6
= 2 A
So, the correct option is:
(E) 2.0 A, ccw
.
he current direction is into the page at points magnetic field at poin.docx
1. he current direction is into the page at points magnetic field at point P, located at the center of the
square of edge length-. m A 3.0×104 T ? 72x10" ? C4.0 x 10T D 20x10T E 1.5x 10*T carry
equal currents of 1 -15.0 A The figure belos is an nd viw of the condascions and B and out of the
page at Cand D.Calcult te magnte of e 18. A bar magnet is points downward along the page as it
falls. Which statement is correct? A The current in the loop flows first in a clockwise, then in a
counsenclockwise direction dropped from above and falls through the loop of wire shown below.
The south pole of the bar magnet Drop down B. The current in the loop flows first in C. The D.
The current in the loop always flows in a counterclockwise direction a counterclockwise, then in
a clockwise direction current in the loop always flows in a clockwise direction. current flows in
the loop because both ends of the magnet move through the loop and a 2.3 2 resistor are used to
form a circuit in the shape of a square. 140 cm by 14.0 cm. A from 0.70 T to 0.26 T in a time
interval of 2.5 ms. The average induced current and its uniform but nonsteady magnetic field
magnetic field is decreased f through the resistor, in this time interval, are closest to: A. 2.2 A,
from a to b B. 1.5 A, from a to b C. 0.16 A, from b to a D. 0.34 A, from b to a E. 0.10 A, from b
to a is perpendicular to the plane (out of the page) of the circuit. The magnitude of the ? ?114cm
2.3 2 20. Find the magnitude and direction of the induced current in the metal rail and moving
rod. The magnetic field is uniform and directed as shown (clockwise: cw, counterclockwise:
ccw). A. 5.0 A, ew B. 5.0 A, cew C. 1.2 A, cw D. I.I A, cew E. 2.0 A, cew 150 m 2.00 m/s
Solution
20)
Emf induced is given by:
e = BLv = 4*1.5*2 = 12 V
Current:
I = e/R
= 12/6
= 2 A
So, the correct option is:
