Blanton Plastics- a household plastic product manufacturer- borrowed $.docx

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Blanton Plastics, a household plastic product manufacturer, borrowed $28 million cash on October 1, 2013, to provide working capital for year-end production. Blanton issued a four-month, 12% promissory note to L&T Bank under a prearranged short-term line of credit. Interest on the note was payable at maturity. Each firm Solution Present vale of the bond 28,000,000.00 Amount of Total interest 28000000*12%*4/12 = 1,120,000.00 Future value of the bond = 29,120,000.00 Journal Entries 01-Oct-13 Cash 28,000,000.00 Bonds Payable 28,000,000.00 31-Dec-13 Interest Expense 840,000.00 Bonds Payable 840,000.00 31-Jan-14 Bonds Payble 28,840,000.00 Interets Expense 280,000.00 Cash 29,120,000.00 .

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Bob Company has the following balances on January 31, 2013. Cash $800 Supplies 900 Prepaid Insurance 3,400 Equipment 10,000 Accumulated Depreciation Solution 1. Supplies Expenses Dr. 640 To Supplies on Hand(Asset) 640 2. Insurance Expense A/C Dr. 170 To Prepaid Insurance 170 3. Depreciation A/c Dr. 500 To equipment( Assets) A/c 500 4. Utility Expenses Dr. 400 To Utilities Expenses Payable 400 THanks (CHIRAG NAGPAL) .

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Bob the scientist has a 100 mL solutin that contains 0.03 moles of each Pb2+ and Sr2+. Using selective precipitation, what is the concentration of CO3 2- you can add to the solution to separate the two metals? Solution Ksp PbCO3 = 1.6 x 10^-13 Ksp SrCO3 = 1.3 x 10^-9 PbCO3 with lower Ksp would precipitate first from the solution [Pb2+] = 0.03 mol/0.1 L = 0.3 M [Sr2+] = 0.03 mol/0.1 L = 0.3 M [CO3^2-] needed to precipitate PbCO3 = Ksp/[Pb2+] = 1.3 x 10^-13/0.3 = 4.33 x 10^-13 M All of PbCO3 is precipitates out first. [CO3^2-] needed to precipitate SrCO3 = Ksp/[Sr2+] = 1.3 x 10^-9/0.3 = 4.33 x 10^-9 M Then SrCO3 is precipitates by using higher concentration of CO3^2-. .

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Blanton Corporation purchased 12% of the outstanding shares of common stock of Worton Corporation as a long-term investment. Subsequently, Worton Corporation reported net income and declared and paid cash dividends. What journal entry would Blanton Corporation use to record the dividends it receives? debit Investment in Worton Corporation; credit Cash debit Cash; credit Dividend Revenue debit Investment in Worton Corporation; credit Income of Worton Corporation debit Cash; credit Investment in Worton Corporation Solution The journal entry that would be passed in this case is = First option = debit investment in Worton Corporation and Credit Cash. Regards. .

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Black Holes are cores of dying stars that have gravitationally collapsed even more then a neutron star (a neutron star is somewhat stable because of the pressure created by the compressed neutrons, which will counter the force of gravity). A black hole is basically infinitely small, but its radius is usually defined as the radius from which light can escape. Even for very massive stars this radius is small (we are talking a few hundred meters here compare to the 700,000km of your Sun). If you would fall towards such an object, your biggest problem would be that you need to deal with tidal forces. Explain why these tidal forces will cause all objects to be ripped into tiny pieces. Solution The tidal forces will cause all objects to be ripped into tiny pieces. How ?? Let\'s take an example - suppose we are falling toward the black hole with our legs towards the center. At the start, we will feel equal gravitational force all over the body. As we approach the center of black hole, the gravitational force on the legs will intensify and the gravitational force on the head will not be that high, this will generate a tidal gravitational force. These tidal forces get more and more intense as we get closer to the center, and eventually they will rip us apart. This is same as the moon tugs harder at the side of the Earth closest to it, causing the tide to rise up towards it, the black hole pulls harder at our feet than it does on our head. Same will happen with any object falling into the black hole. .

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Beyond aesthetics, what functional differences are there for running GNS3 as root versus running GNS3 as a non-root user? FUNCTIONAL DIFFERENCES FOR GNS3 NOT DB2. Solution During a root installation, subdirectories and files for the DB2 database product are created in a directory of the root users choosing unlike root users, non root users cannot choose where DB2 database products are installed.Nonroot installations are always placed in the $HOME/sqllib directory where $HOME represents the non root users home directory.The layout of the subdirectories within the sqllib directory of a non root is similar to that of a root installation For root installations, multiple instances can be created.Instance ownership is associated with the user id under which the instance was created Non root installations can have only one DB2 instance.The non root installation directory contains all of the DB2 database product files and instance files with no soft links. The following table summerizes the differences between root installations and non root installations user can select instalation directory .

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Beside the typical DBMS, what are some of the different data sources that an Internet application may need to access for data? Can a database be an integrator of these different data sources? Solution There are two types of data sources: Database Data Sources A database is a grouping of tables in a database management system. You must identify databases to the applications that access them. You can distribute databases across a network and involve various servers and database management systems. A database data source identifies the database information that the software needs to connect to a database. Logic Machine Data Sources A logic machine is the machine on which batch applications and master business functions run. You must identify logic machines using a data source definition. The data source definition must include the network information about the machine, such as a server name - HP9000, for example. When mapping logic objects for distributed processing, the software uses the machine data source (distributed processing data source) as the target location for processing logic objects. .

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Below are three independent and unrelated accounting errors. For each error: (1) Indicate the effect of each error on the income statement and balance sheet in the 2014 financial statements. (2) Prepare any journal entries each company should record in 2015 to correct the errors. Ignore tax effects. a. On December 28, 2014, Impact Imports received a $25,000 deposit from a customer for merchandise to be delivered in January 2015. Impact Imports recorded the deposit as sales revenue. b. At the end of 2014, Munger Engineering failed to accrue interest of $8,000 on a note payable. At the beginning of 2015, when the company paid cash for interest, it was recorded as interest expense. c. On December 31, 2014, Owen Corporation failed to accrue utilities expense of $6,800. In January 2015, when it paid the bill from the utility company, Owen made the following entry: Utilities expense 6,800 Cash 6,800 Solution (1) Indicate the effect of each error on the income statement and balance sheet in the 2014 financial statements. .

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Be sure to answer all parts. Give the Mino acid sequence of an octapeptide that contains the amino acids Cys, Pro, Phe (2 equiv), Met, Ile, Tyr Typ, and forms the following fragments when partially hydrolyzed with HCl: Ile-Tyr-Pro-Cys, Trp-Phe-Ile-Tyr, and Met-phe-Trp. Be sure to answer all parts. Give the amino acid sequence of an octapeptide that contains the amino acids Cys, Pro, Phe (2 equiv), Met, Ile, Tyr, Trp, and forms the following fragments when partially hydrolyzed with HCI: Ile-Ty-Pro-Cys, Trp-Phe-Ile-Tyr, and Met-Phe-Trp. Solution Phe have two equivalent that means peptide sequence contains two Phe. fragments are when partially hydrolyzed with HCl: Ile-Tyr-Pro-Cys.................>(1) Trp-Phe-Ile-Tyr..................> (2) and Met-phe-Trp.......................> (3) from equation (2) and (3), we write Met-phe-Trp-Phe-Ile-Tyr........> (4) from (1) and (4), we can write Met-phe-Trp-Phe-Ile-Tyr-Pro-Cys this is the sequence of octapeptide. .

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Based on the information in “Atom: Clash of the Titans”, please answer the following questions: 1. Why was it so important that the scientists investigating the atom be young and unattached to existing scientific thinking? 2. What connection did Bohr discover between atoms and light? 3. Why did Einstein hate Bohr’s ideas - quantum mechanics, electrons jumping and releasing light - about the atom? Solution 1) The scientists investigating the atom should be young as was then the young scientist Albert Einstein. His harsh arrogance led him barely any employment, thereby because of his undemanding job he had a lot of time to have deep thoughts. And that was the era wherin he worked on to prove the existence of atom. Though it was Boltzman who started work on this topic but due to his health conditions and alegations on him being irrelegious materialist lead to him comitting suicide. And the scientists should be unattached to existing scientific thinking as was scientist Neil Bohr who was fearless in his thinking and was ready to abandon common sense and human intution to find an explanation. 2)Bohr\'s connection between atoms and light was as follows-quantum jumps Light is emitted when an electron jumps from a higher orbit to a lower orbit and is absorbed when jumps from lower to higher orbit. In order to overcome the limitations of Bohr model and to develop a general model for atoms.The 2 developments contibuted a lot - 3)As the bohr idea of new atom and quantum jumps were not so traditional neither they matched classical science theories thus the old school people strongly opposed it. And Albert Einstein was one of them as he wanted to save the world of order and wanted to preserve the common sense. .

Based on the information in Atom- Clash of the Titans- please answer t.docx

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Both these questions go together Solution When we bring a magnet near a metal, the metal enters a magnetic field, all of the electrons inside the metal \"line up,\" causing a temporary magnetic alignment that is attracted to the magnet . That alignment dissipates once the magnetic field is removed and therefore, the only way for a metal to be repelled by a magnet is if it\'s first magnetized to the opposite pole. so if the metal is magnetised and the a magnet with the same pole is brought near it will repel Note:- its easy to magnetise a iron piece just rub the magnet over the metal in one direction many, many times. By rubbing a magnet over your metal continuously, you are aligning the electrons in the metal in a certain way, toward a certain polarity. The more that you do this, the longer the effect will last, taking more time for the electrons to return to their random or unpolarized state. so the answer to the question is 1) c 2) d .

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Boston Scientific faced the challenge of balancing openness and sharing with security and the need for restricting access to information. How did the use of technology allow the company to achieve both objectives at the same time? What kind of cultural changes were required for this to be possible? Are these more important than the technology- related issues? Develop a few examples to justify your answer. Solution The use of technology will definately allow the company to achieve both objectives at the same time. It explained in below given points . 1. With in the company we can apply the access rights on users level. We can identify the various group of users, and according to the need of users group, we can apply various access rights to each users groups. 2. Let take an example of social networking websites, lets suppose we have two users group in the company named A and B, where A have customer interfacing, so for user group A , we can enable the use of social networking websites, to communicate and make good relationship with customers. 3. Same can be done with company related emails also. We can sent the company related emails with digital signature. Here in this case the authentic user who having access rights can access the emails signed with digital signature. Technology related issues are more important t han the cultural changes, In terms of cultural changes, we can change the setting arrangements within the organization, so that users or the employess with same access rights sit together, and employess with less access rights sit together in other places. Because if both type of employess sit together then it can happen than authentic information gets leaked. .

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Based on the information in “Atom: Clash of the Titans”, please answer the following questions: 16. Why did Heisenberg want to destroy Schrödinger’s wave equation?What happened when he tried to call out Schrödinger in public? 17. Almost the entire scientific community had turned on Bohr and Heisenberg, saying that their “matrix mechanics” model of the atom was wrong. Why did they refuse to give up their ideas and admit they were wrong? please use correct sentences Solution 16. Heisenberg stated that the position and the velocity of particle / wave cannot be found at some point in space simultaneously. On the contrary Schrödinger wave equation gives the position of an atom and with defined quantum aspects of a system. However in the end these 2 theories went hand in hand. 17. Using this matrix mechanics which has superseded the Bohr\'s model, Heisenberg predicted that the electrons might not be revolving in orbits. The mathematics used to describe the model were unknown and uncertain to the scientific community. They refused to agree with the discrete energy states concept Nevertheless this was also complementing the Schrödinger’s wave equation which was widely accepted during that period of time. .

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6.3. (a) In which form does Cd(II) occur mainly in a water of the following composition: pH = 7.8 Solution (a) pH=7.8=-log [H+] [H+]=10^-7.8=1.585*10^-8M Also, [H+][OH-]=1*10^-14=Ionic product of water [OH-]=(1*10^-14)/[H+]=(1*10^-14)/(1.585*10^-8)=6.309*10^-7M Alkalinity=[OH-]+[CO3 2- ]=1.3*10^-3 eq/L [CO32-]=(1.3*10^-3 eq/L)-[OH-]=(1.3*10^-3 eq/L)-(6.309*10^-7M)=(1.3*10^-3 eq/L)=1/2*(1.3*10^-3 eq/L)=0.65*10^-3mol/L [For [OH-]eq=[OH]M ,but for Carbonate, 2eq=1mol] Thus,[CO32-]>>>[OH-] Also,Cd2+ +CO32- <--->CdCO3 ,log K=4.5,K=10^-4.5 But,Ca2+ +CO32- <--->CdCO3,log K=8.5 So,CdCO3 will precipitate first and CaCO3 later, Also, Cd T =1*10^-9 M<<<Ca T =1*10^-3 M And Cd 2+ +2OH- <--->Cd(OH)2 ,log K=14.3 The value of log K is much higher, so Cd(II) must be predominant as Cd(CO3) b) yes, CdCO3 precipitates due to very high equilibrium constant for this reaction compared to that for Cd(OH)2 c)[EDTA]=10^-7 mol/L Cd 2+ +EDTA 4- <--->CdEDTA 2- , log K=16.5,K=10^-16.5 K=[CdEDTA 2- ]/[Cd 2+ ][EDTA 4- ] or,[CdEDTA 2- ]=K*[Cd 2+ ][EDTA 4- ]=10^-16.5 *(10^-7)*[Cd2+]=10^-23.5 [Cd2+] But ,Cd 2+ +CO3 2- <--->CdCO3 ,log K=4.5,K=10^-4.5 Similarly,[CdCO3]=10^-4.5 *(6.309*10^-7)*[Cd2+]=(6.309*10^-11.5) [Cd2+] where., [OH-]=6.309*10^-7M Hence ,[CdEDTA 2- ]<[CdCO3] CdCO3 remains the predominant form for Cd(II) .

6-3- (a) In which form does Cd(II) occur mainly in a water of the foll.docx

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6. A solution of an acid, with a general formula HA, contains 0.400 moles of H\"\'. The acid solution is neutralized by 43.4 mL of sodium hydroxide. What is the molarity of the sodium hydroxide solution? 7. Write the balanced chemical equations for the removal of water from the following hydrated crystals. a) Copper(Il) sulfate pentahydrate b) Tin(II) chloride dehydrate c) Cobalt(II) chloride hexahydrate d) Magnesium sulfate heptahydrate oint of solution made hy dissolving 6.000 q of urea Solution 6) HA + NaOH ------------------> NaA + H2O moles of HA = moles of NaOH = 0.400 moles = 0.400 volume = 43.4 mL = 0.0434 L molarity of NaOH = moles / volume = 0.400 / 0.0434 = 9.21 M 7) a) CuSO4 .5H2O ------------------> CuSO4 + 5 H2O b) SnCl2 H2O ----------------------> SnCl2 + H2O c) CoCl2.6H2O --------------------> CoCl2 + 6H2O d) MgSO4 7H2O -------------------> MgSO4 + 7H2O .

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6. What are the differences between objects and abstract data types Solution Differences between Objects and Abstract data types: ______________________________________________ Objects: Object is an instance of a class and it has states and behaviours of class. Abstract data type: It is a data type of abstract and it hides the representation of class, and it is typically implemented as a class and each instance of Abstract data type is usually an object of that class. Objects and Abstract data types are not the same. But these are not different with each other. Objects are a kind of Abstract data types. An Abstract data type is an interface.But objects are instance of a class, with its own copy of any non-static variables. Abstract data type is a collection of methods but in case of objects it is not an interface.It is an representation of a class with new operator. A class can have one or more Abstract data types in the same way class can have one or more objects also. To understand you with clear for Example, Collection interface is Abstract data type, ArrayList is a class and you can make ArrayList object with new operator. .

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6. What do the bubbles in boiling water principally c a. air b. O2 (e and H2e c. H20 d. vacuum e. nitrogen What is the correct name for Co3(PO4)4? a. cobalt phosphate b. tricobalt tetraphosphate c. cobalt (II) phosphate d. cobalt (III) phosphate e. cobalt (IV) phosphate 7. 8. How many neutrons are contained in *He? a. 0 b. 1 c. 2 d. 3 e. 4 9. How many electrons are contained in He 2 2 a. d. 3 e. 4 Solution 6) the bubbles in boiling water contains water vapours, hence H2O(g), as the vapour pressur eof li 7) The name for anion is phosphate , there are four phosphate groups The oxidation state of cobalt is 3x + 4(-3) = 0 x = +4 So the correct name is Cobal(IV)phosphate 8) neutrons = mass number - atomic number = 4-2 = 2 9) Electrons = 0 as the number of electrons in Helium in its ground state = 2 The charge is +2, which represents removal of two electrons .

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6. Both solutions and colloids are mixtures. Differentiate between them. Solution Although solutions and colloid both are mixtures but we can differentiate solution and colloid on the basis of some parameter given below: 1) Particle size: Particle size of solution is less than 1nm or (10 -9 ) m Particles size of colloid are between 1nm to 1000 nm 2) Visibility In solutions the visibility of substances dissolved in it are not possible even with optical means. While in colloid it may be visible with ultra microscope. 3) Diffusion Diffusion is very rapid in solution while very slow in colloid 4) setting Solution doesn\'t settle while colloid may settle down under centrifuge . 5) Nature: Solution is Homogeneous in nature while colloid is heterogeneous in nature. 6) Tyndall effect Solution doesn\'t show Tyndall effect Colloid shows Tyndall effect So we can say that solution and colloid both are mixture but there are a lot of difference between them. .

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6). The Town of Elmwood applied for a competitive grant from the state government for providing an after- school recreational program for at-risk children from low-income families. On 2/1/2005, Elmwood was notified that it had been awarded a grant of $100,000 for the program. The program provides up to $1,000 per child served provided that family annual income is less than $25,000. The grant provides for reimbursement of all allowable costs of conducting the program on a twice-monthly basis. No time limit is imposed for completion of the program. Any unused grant award may be carried forward to the next fiscal year. By 12/31/2005, Elmwood?s fiscal year-end, $74,000 had been expended in providing recreational services for eligible beneficiaries. Reimbursement of $71,000 had been received from the state by this date. Required: [12 pts.] a). What are the eligibility requirements of this grant? b). As of 12/31/2005, identify the following: (1). Cash Received (2). Program Revenue (3). Expenditures Solution Total Expenditure = $ 74000 Cash Received = $ 71000 Revenue = 71000-74000 = $ 3000 The program must be carried on & also the expenditure will be for the children whose family income is less than $ 25000/-. .

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