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7. Astudert in a lab exerts a 25 N force to pull a block a distance of48 cm. Ifatotal of 1 1 J of work is done, the angle between the force and the displacement is a, 890 b. 66 c. 61Â° A 102-g sparrow flying at 12.3 m/s wishes to have equal kinetic and gravitational potential energies. The height that will accomplish this is a. 0.315 m b. 0.628 m c. 0.787 m ? d. 24 e. none of the above S. d. 1.13 m e. 7.72 m Earth\'s mass is 5.98 x 10* kg. Calculate the value of g at a point 4.8 x 10 km from the centre of Earth. a. 9.8 x 10 N/kg b. 8.3 x 10 N/kg c. 1.7 x 10 N/kg 9. d. 1.7 x 10 N/kg e. 9.8x 10 Nkg A piece of paper becomes electrically charged when a charged rod of plastic is placed close to it. This is referred to as a. charging by a conductor b. charging by induction c. charging by an insulator 10. d. e. charging by contact charging by electricity 20 cm 20 em C, 11 . Four charged spheres, A, D, P, and T are arranged as shown below. Sphere A has a charge of +4.5x 10 sphere D has a charge of-6.2x 10 Csphere Phas a charge of 7.5x 10 C, and sphere T has a charge of -1.5x 101C. Which two spheres exert the smallesr force on each other? a. A and D b. A and T c. A and F P and D P and T d. e. 3 of 13 Solution 7. W = F * d * cos x; where x is the angle between force and displacement W = 11J, d = 0.48m, F = 25N solving for cos x = 11/(25*0.48) = 0.91 x= arc cos (0.91) ~ 89 degrees - (a) 8. 0.5* m * v^2 = m*g*h cancelling out m h = 0.5 * v^2/g = 0.5*12.3^2 / 9.81 = 7.72 m - (e) .

7. Astudert in a lab exerts a 25 N force to pull a block a distance of48 cm. Ifatotal of 1 1 J of
work is done, the angle between the force and the displacement is a, 890 b. 66 c. 61Â° A 102-g
sparrow flying at 12.3 m/s wishes to have equal kinetic and gravitational potential energies. The
height that will accomplish this is a. 0.315 m b. 0.628 m c. 0.787 m ? d. 24 e. none of the above
S. d. 1.13 m e. 7.72 m Earth's mass is 5.98 x 10* kg. Calculate the value of g at a point 4.8 x 10
km from the centre of Earth. a. 9.8 x 10 N/kg b. 8.3 x 10 N/kg c. 1.7 x 10 N/kg 9. d. 1.7 x 10
N/kg e. 9.8x 10 Nkg A piece of paper becomes electrically charged when a charged rod of plastic
is placed close to it. This is referred to as a. charging by a conductor b. charging by induction c.
charging by an insulator 10. d. e. charging by contact charging by electricity 20 cm 20 em C, 11 .
Four charged spheres, A, D, P, and T are arranged as shown below. Sphere A has a charge of
+4.5x 10 sphere D has a charge of-6.2x 10 Csphere Phas a charge of 7.5x 10 C, and sphere T has
a charge of -1.5x 101C. Which two spheres exert the smallesr force on each other? a. A and D b.
A and T c. A and F P and D P and T d. e. 3 of 13
Solution
7.
W = F * d * cos x; where x is the angle between force and displacement
W = 11J, d = 0.48m, F = 25N
solving for cos x = 11/(25*0.48) = 0.91
x= arc cos (0.91) ~ 89 degrees - (a)
8. 0.5* m * v^2 = m*g*h
cancelling out m
h = 0.5 * v^2/g
= 0.5*12.3^2 / 9.81 = 7.72 m - (e)

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6.3. (a) In which form does Cd(II) occur mainly in a water of the following composition: pH = 7.8 Solution (a) pH=7.8=-log [H+] [H+]=10^-7.8=1.585*10^-8M Also, [H+][OH-]=1*10^-14=Ionic product of water [OH-]=(1*10^-14)/[H+]=(1*10^-14)/(1.585*10^-8)=6.309*10^-7M Alkalinity=[OH-]+[CO3 2- ]=1.3*10^-3 eq/L [CO32-]=(1.3*10^-3 eq/L)-[OH-]=(1.3*10^-3 eq/L)-(6.309*10^-7M)=(1.3*10^-3 eq/L)=1/2*(1.3*10^-3 eq/L)=0.65*10^-3mol/L [For [OH-]eq=[OH]M ,but for Carbonate, 2eq=1mol] Thus,[CO32-]>>>[OH-] Also,Cd2+ +CO32- <--->CdCO3 ,log K=4.5,K=10^-4.5 But,Ca2+ +CO32- <--->CdCO3,log K=8.5 So,CdCO3 will precipitate first and CaCO3 later, Also, Cd T =1*10^-9 M<<<Ca T =1*10^-3 M And Cd 2+ +2OH- <--->Cd(OH)2 ,log K=14.3 The value of log K is much higher, so Cd(II) must be predominant as Cd(CO3) b) yes, CdCO3 precipitates due to very high equilibrium constant for this reaction compared to that for Cd(OH)2 c)[EDTA]=10^-7 mol/L Cd 2+ +EDTA 4- <--->CdEDTA 2- , log K=16.5,K=10^-16.5 K=[CdEDTA 2- ]/[Cd 2+ ][EDTA 4- ] or,[CdEDTA 2- ]=K*[Cd 2+ ][EDTA 4- ]=10^-16.5 *(10^-7)*[Cd2+]=10^-23.5 [Cd2+] But ,Cd 2+ +CO3 2- <--->CdCO3 ,log K=4.5,K=10^-4.5 Similarly,[CdCO3]=10^-4.5 *(6.309*10^-7)*[Cd2+]=(6.309*10^-11.5) [Cd2+] where., [OH-]=6.309*10^-7M Hence ,[CdEDTA 2- ]<[CdCO3] CdCO3 remains the predominant form for Cd(II) .

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6. What are the differences between objects and abstract data types Solution Differences between Objects and Abstract data types: ______________________________________________ Objects: Object is an instance of a class and it has states and behaviours of class. Abstract data type: It is a data type of abstract and it hides the representation of class, and it is typically implemented as a class and each instance of Abstract data type is usually an object of that class. Objects and Abstract data types are not the same. But these are not different with each other. Objects are a kind of Abstract data types. An Abstract data type is an interface.But objects are instance of a class, with its own copy of any non-static variables. Abstract data type is a collection of methods but in case of objects it is not an interface.It is an representation of a class with new operator. A class can have one or more Abstract data types in the same way class can have one or more objects also. To understand you with clear for Example, Collection interface is Abstract data type, ArrayList is a class and you can make ArrayList object with new operator. .

6- What are the differences between objects and abstract data typesSol.docx

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6. What do the bubbles in boiling water principally c a. air b. O2 (e and H2e c. H20 d. vacuum e. nitrogen What is the correct name for Co3(PO4)4? a. cobalt phosphate b. tricobalt tetraphosphate c. cobalt (II) phosphate d. cobalt (III) phosphate e. cobalt (IV) phosphate 7. 8. How many neutrons are contained in *He? a. 0 b. 1 c. 2 d. 3 e. 4 9. How many electrons are contained in He 2 2 a. d. 3 e. 4 Solution 6) the bubbles in boiling water contains water vapours, hence H2O(g), as the vapour pressur eof li 7) The name for anion is phosphate , there are four phosphate groups The oxidation state of cobalt is 3x + 4(-3) = 0 x = +4 So the correct name is Cobal(IV)phosphate 8) neutrons = mass number - atomic number = 4-2 = 2 9) Electrons = 0 as the number of electrons in Helium in its ground state = 2 The charge is +2, which represents removal of two electrons .

6- What do the bubbles in boiling water principally c a- air b- O2 (e.docx

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6. Both solutions and colloids are mixtures. Differentiate between them. Solution Although solutions and colloid both are mixtures but we can differentiate solution and colloid on the basis of some parameter given below: 1) Particle size: Particle size of solution is less than 1nm or (10 -9 ) m Particles size of colloid are between 1nm to 1000 nm 2) Visibility In solutions the visibility of substances dissolved in it are not possible even with optical means. While in colloid it may be visible with ultra microscope. 3) Diffusion Diffusion is very rapid in solution while very slow in colloid 4) setting Solution doesn\'t settle while colloid may settle down under centrifuge . 5) Nature: Solution is Homogeneous in nature while colloid is heterogeneous in nature. 6) Tyndall effect Solution doesn\'t show Tyndall effect Colloid shows Tyndall effect So we can say that solution and colloid both are mixture but there are a lot of difference between them. .

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6). The Town of Elmwood applied for a competitive grant from the state government for providing an after- school recreational program for at-risk children from low-income families. On 2/1/2005, Elmwood was notified that it had been awarded a grant of $100,000 for the program. The program provides up to $1,000 per child served provided that family annual income is less than $25,000. The grant provides for reimbursement of all allowable costs of conducting the program on a twice-monthly basis. No time limit is imposed for completion of the program. Any unused grant award may be carried forward to the next fiscal year. By 12/31/2005, Elmwood?s fiscal year-end, $74,000 had been expended in providing recreational services for eligible beneficiaries. Reimbursement of $71,000 had been received from the state by this date. Required: [12 pts.] a). What are the eligibility requirements of this grant? b). As of 12/31/2005, identify the following: (1). Cash Received (2). Program Revenue (3). Expenditures Solution Total Expenditure = $ 74000 Cash Received = $ 71000 Revenue = 71000-74000 = $ 3000 The program must be carried on & also the expenditure will be for the children whose family income is less than $ 25000/-. .

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