d) 0-24 m e) 0-28 m 016- A 4 kg mass is projected down a rough ( )circ.docx

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d) 0.24 m e) 0.28 m 016: A 4 kg mass is projected down a rough ( )circular track (R-2 m) as shown. The speed of the mass at point A is 4 m/s, and at point B, it is 6 m/s. How much work is done on the mass between A and B by the force of friction? a)-19.2 b)-38.4 c) -28.8 d)-57.6 e)-9.4 017:An elevator has a weight of 1600 nn Solution 16. Result : (b) Explanation: By conservation of energy principle : K A +U A -W f = K B where , K A & K B are kinetic energies at A and B W f is the work done by friction force U A is the potential energy at A i.e. W f = K A +U A -K B = (1/2)mv A 2 + mgR - (1/2)mv B 2 = (1/2)*(4)*(4) 2 + (4)*(9.81)*(2) - (1/2)*(4)*(6) 2 = 32 J + 78.48 J - 72 J = 38.4 J As it acts in the direction opposite to that of motion , hence it has negative sign. So work done by friction force is : W f = -38.4 J .

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d) 0-24 m e) 0-28 m 016- A 4 kg mass is projected down a rough ( )circ.docx

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