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PA04 June 07 Q.3(c) C=f(2 x 12 x 10 -3 ) C=(f+2)(2 x 10 x 10 -3 ) (f+2)(2 x 10 x 10 -3 )=f(2 x 12 x 10 -3 ) 20(f+2)=24f 20f+40=24f 4f=40 f=10Hz F=10 c=10(2x12x10 -3 ) c=0.24ms -1
Logs...yippee (synoptic June 06 Q.5B) ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],I=kv n Ln|I|=ln|kv n | Ln|I|=ln|k|+ln|v n | Ln|I|=ln|k|+nln|v| ln|v| Ln|I| Y=mx+c ln|k| dy/dx=n

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Simple equations and logs

  • 1.  
  • 2. PA04 June 07 Q.3(c) C=f(2 x 12 x 10 -3 ) C=(f+2)(2 x 10 x 10 -3 ) (f+2)(2 x 10 x 10 -3 )=f(2 x 12 x 10 -3 ) 20(f+2)=24f 20f+40=24f 4f=40 f=10Hz F=10 c=10(2x12x10 -3 ) c=0.24ms -1
  • 3.