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# Part A A weather balloon is inflated to a volume of 25-1 L at a pressu.docx

Part A A weather balloon is inflated to a volume of 25.1 L at a pressure of 745 mmHg and a temperature of 28.1 C. The balloon rises in the atmosphere to an altitude where the pressure is 370. mmHg and the temperature is -13.2 Â°C Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude. Vballoon Submit Request Answer
Solution
for gases
PV/T = constant
so
P2V2 / T2 = P1V1/T1
V2 = P1 x V1 x T2 / ( T1 x P2)
given
P1 = 745 mm Hg
V1 = 25.1 L
T1 = 28.1 C = 28.1 + 273 K = 301.1 K
P2 = 370 mm Hg
V2 = ??
T2 = -13.2 C = -13.2 + 273 K = 259.8 K
plug in the values
V2 = 745 mmHg x 25.1 L x 259.8 K / (370 mm Hg x 301.1 K)
V2 = 43.61 L
so
the volume of ballon at the altitude is 43.61 L
.

Part A A weather balloon is inflated to a volume of 25.1 L at a pressure of 745 mmHg and a temperature of 28.1 C. The balloon rises in the atmosphere to an altitude where the pressure is 370. mmHg and the temperature is -13.2 Â°C Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude. Vballoon Submit Request Answer
Solution
for gases
PV/T = constant
so
P2V2 / T2 = P1V1/T1
V2 = P1 x V1 x T2 / ( T1 x P2)
given
P1 = 745 mm Hg
V1 = 25.1 L
T1 = 28.1 C = 28.1 + 273 K = 301.1 K
P2 = 370 mm Hg
V2 = ??
T2 = -13.2 C = -13.2 + 273 K = 259.8 K
plug in the values
V2 = 745 mmHg x 25.1 L x 259.8 K / (370 mm Hg x 301.1 K)
V2 = 43.61 L
so
the volume of ballon at the altitude is 43.61 L
.

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### Part A A weather balloon is inflated to a volume of 25-1 L at a pressu.docx

1. 1. Part A A weather balloon is inflated to a volume of 25.1 L at a pressure of 745 mmHg and a temperature of 28.1 C. The balloon rises in the atmosphere to an altitude where the pressure is 370. mmHg and the temperature is -13.2 Â°C Assuming the balloon can freely expand, calculate the volume of the balloon at this altitude. Vballoon Submit Request Answer Solution for gases PV/T = constant so P2V2 / T2 = P1V1/T1 V2 = P1 x V1 x T2 / ( T1 x P2) given P1 = 745 mm Hg V1 = 25.1 L T1 = 28.1 C = 28.1 + 273 K = 301.1 K P2 = 370 mm Hg V2 = ?? T2 = -13.2 C = -13.2 + 273 K = 259.8 K plug in the values V2 = 745 mmHg x 25.1 L x 259.8 K / (370 mm Hg x 301.1 K) V2 = 43.61 L
2. 2. so the volume of ballon at the altitude is 43.61 L