The slide show review slope intercept form and provides instruction for a constructivist activity for students to discover the relationship between the slopes of two parallel or two perpendicular lines.
8. Review:SlopeInterceptForm y = mx + b m is the slope of the line bis the y-intercept Life is easy when you’re in slope intercept form
9. y -intercept y = mx + b The y-intercept is the y value when x = 0. Visually, the y-intercept is y value when the line crosses the y axis http://www.mathsisfun.com/data/function-grapher.php
10. Slope (𝑥2,𝑦2) y = mx + b Slope Slider Slope ofvertical lines? (𝑥1,𝑦1)
12. Review: Finding the Equation of the Line given a Slope and a Point on the Line y = mx + b Given the slope, m, and a point, (x , y), then we can find b, the y-intercept. b = y – mx Once we find b, we can find the equation of the line.
13. Practice: Finding the Equation of the Line given the Slope and a Point on the Line p = (-2 , 2) m = 4p = (-3 , 4) m = -2p = (-2 , 2/3) m = -4/3
14. Graphing Activity 1. Graph line segments. Be sure that each endpoint is an integer coordinate, such as (1,3) or (-3,0)Compute and record their slope. 2. Then graph a parallel line to each of the three line segments. Compute and record the slopes of the parallel lines. Then delete the parallel lines. 3. Then graph a perpendicular line to each of the three line segments. Compute and record the slopes of the perpendicular lines.
21. Find the Slope of a Perpendicular Line y = -3x – 2 y = (1/3)x + 2 y – 1 = 6x 2y = 5x + 3 y = 6 x = -3
22. Find the Equation of the Parallel Line that passes through the Given Point. y = (1/3)x + 2 , p = (2 , -3) 2y = 5x + 3 , p = (1/2 , 2/3) y = 6 , p = (6 , 0) x = -3 , p = (1 , 2)
23. Find the Equation of the Perpendicular Line that passes through the Given Point. y = -3x – 2 , p = (-1 , 4) 4y = 8x , p = (1 , 1/3) y = 6 , p = (6 , 0) x = -3 , p = (1 , 2)