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Chapter Two Random Variable L1-  Discrete random variable L2-  Continuous random variable
Jan 2009 DISCRETE RANDOM VARIABLES ,[object Object],[object Object],[object Object],Learning Objectives:
Jan 2009 ,[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object],[object Object]
Jan 2009 Examples   of random variables: The  number of scratches  on a surface.   Integer values ranging from zero to about 5 are possible values.  X  = { 0, 1, 2, 3, 4,5} The  time taken to complete an examination.  Possible values are 15 minutes to over 3 hours. X  = { 15  x   180 }
Jan 2009 DISCRETE RANDOM VARIABLE ,[object Object],X  is a discrete random variable if :   ,[object Object]
Jan 2009 Example 1:  The sample space for a machine breakdown problem is  S = { electrical, mechanical, misuse } and each of these failures is associated with a repair cost of about RM200, RM350 and RM50 respectively. Identify the random variable giving reasons for your answer. Example 2:  The analysis of the surface of semi conductor wafer records the number of particles of contamination that exceed a certain size. Identify the possible random variable and its values.
Jan 2009 Probability mass function may typically be given in tabular or  graphical form If from  Example 1  that  P( cost=50)=0.3,  P (cost = 200) = 0.2  and  P (cost = 350) = 0.5. The probability mass function is given either  X = x   50  200  350  f ( x ) = P(X=  x )   0.3  0.2  0.5 tabular form line graph P(  x  ) 50 200 350 0.3 0.2 0.5 cost
Jan 2009 CUMULATIVE DISTRIBUTION FUNCTION   The cumulative distribution  F( x ) of a discrete random  variable X with probability mass function  f ( x ) is The cumulative distribution of F( x ) is an increasing step function with steps at the values taken by the random variable. The height of the steps are probabilities of taking these values.
Jan 2009 From  Example 1 ( machine breakdowns)  : The probability distribution is The following cumulative distribution is obtained   X = x   50  200  350  f ( x ) = P(X=  x )   0.3  0.2  0.5
Jan 2009 Graph of F( x )  F(  x  ) 50 200 350 0.5 0.3 1.0 Cost ( RM )
Jan 2009 MEAN AND VARIANCE :- Discrete R.V   We can summarize probability distribution by its mean and variance. Mean or expected value is   Variance of X is given as Standard deviation of X is   

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Chapter 2 discrete_random_variable_2009

  • 1. Chapter Two Random Variable L1- Discrete random variable L2- Continuous random variable
  • 2.
  • 3.
  • 4. Jan 2009 Examples of random variables: The number of scratches on a surface. Integer values ranging from zero to about 5 are possible values. X = { 0, 1, 2, 3, 4,5} The time taken to complete an examination. Possible values are 15 minutes to over 3 hours. X = { 15 x 180 }
  • 5.
  • 6. Jan 2009 Example 1: The sample space for a machine breakdown problem is S = { electrical, mechanical, misuse } and each of these failures is associated with a repair cost of about RM200, RM350 and RM50 respectively. Identify the random variable giving reasons for your answer. Example 2: The analysis of the surface of semi conductor wafer records the number of particles of contamination that exceed a certain size. Identify the possible random variable and its values.
  • 7. Jan 2009 Probability mass function may typically be given in tabular or graphical form If from Example 1 that P( cost=50)=0.3, P (cost = 200) = 0.2 and P (cost = 350) = 0.5. The probability mass function is given either X = x 50 200 350 f ( x ) = P(X= x ) 0.3 0.2 0.5 tabular form line graph P( x ) 50 200 350 0.3 0.2 0.5 cost
  • 8. Jan 2009 CUMULATIVE DISTRIBUTION FUNCTION The cumulative distribution F( x ) of a discrete random variable X with probability mass function f ( x ) is The cumulative distribution of F( x ) is an increasing step function with steps at the values taken by the random variable. The height of the steps are probabilities of taking these values.
  • 9. Jan 2009 From Example 1 ( machine breakdowns) : The probability distribution is The following cumulative distribution is obtained X = x 50 200 350 f ( x ) = P(X= x ) 0.3 0.2 0.5
  • 10. Jan 2009 Graph of F( x ) F( x ) 50 200 350 0.5 0.3 1.0 Cost ( RM )
  • 11. Jan 2009 MEAN AND VARIANCE :- Discrete R.V We can summarize probability distribution by its mean and variance. Mean or expected value is Variance of X is given as Standard deviation of X is  