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ORGANIC CHEMISTRY 
CHM 207 
CHAPTER 6: 
HYDROXYL COMPOUNDS 
(ALCOHOLS AND PHENOL)
SUBTOPICS 
 Nomenclature of alcohols, phenols. 
 Classification of alcohols. 
 Physical properties of alcohols: 
- Physical state 
- Boiling points 
- Solubility of alcohols in water 
 Acidity of alcohols and phenols 
 Reactions of alcohols: 
- Reaction with sodium 
- Oxidation 
- Esterification 
- Halogenation and haloform reactions 
- Dehydration 
- Formation of ether (Williamson ether synthesis)
 Reactions of phenols: 
- Reaction with sodium 
- Esterification 
- Halogenation of the ring 
- Nitration of the ring 
 Tests to distinguish classes of alcohols: 
i) Lucas test 
ii) Oxidation 
 Haloform test to identify methyl alcohol group 
- Iodoform 
- Bromoform 
 Uses of alcohols and phenols.
ALCOHOLS 
 Alcohols: Organic compounds containing 
hydroxyl (-OH) functional groups. 
R OH 
 Phenols: Compounds with hydroxyl group bonded 
directly to an aromatic (benzene) ring. 
OH
NOMENCLATURE OF 
ALCOHOLS
IUPAC RULES 
1. Select the longest continuous chain of carbon atoms 
containing the hydroxyl group. 
2. Number the carbon atoms in this chain so that the 
one bonded to the –OH group has the lowest 
possible number. 
3. Form the parent alcohol name by replacing the final 
–e of the corresponding alkane name by –ol. When 
isomers are possible, locate the position of the –OH 
by placing the number (hyphenated) of the carbon 
atom to which the –OH is bonded immediately before 
the parent alcohol name. 
4. Name each alkyl branch chain (or other group) and 
designate its position by number.
This is the longest continuous chain that 
contains an hydroxyl group. 
Select this chain as the parent compound.
4 
3 
2 1 
This end of the chain is closest to the 
OH. Begin numbering here.
4 
3 
2 1 
3-methyl-2-butanol
This is the longest continuous chain that 
contains an hydroxyl group. 
Select this chain as the parent compound.
4 3 
2 1 
5 
This end of the chain is closest to the 
OH. Begin numbering here.
4 3 
2 
1 
5 3-methyl-2-pentanol
NOMENCLATURE OF CYCLIC 
ALCOHOLS 
 Using the prefix cyclo- 
 The hydroxyl group is assumed to be on C1. 
IUPAC name: 
new IUPAC name: 
H 
HO CH2CH3 
5 6 1 
4 3 2 
Br 
OH 
H 
trans-2-bromocyclohexanol 
trans-2-bromocyclohexan-1-ol 
1 
3 2 
1-ethylcyclopropanol 
1-ethylcyclopropan-1-ol
NOMENCLATURE OF ALCOHOLS 
CONTAINING TWO DIFFERENT 
FUNCTIONAL GROUPS 
 Alcohol containing double and triple bonds: 
- use the –ol suffix after the alkene or alkyne name. 
 The alcohol functional group takes precedence over 
double and triple bonds, so the chain is numbered in 
order to give the lowest possible number to the carbon 
atom bonded to the hydroxyl group. 
 The position of the –OH group is given by putting its 
number before the –ol suffix. 
 Numbers for the multiple bonds were once given early in 
the name.
EXAMPLE 
4 3 2 1 
CH2 CH CH2 CH CH3 
OH 
5 
1) Longest carbon chain that contains –OH group 
- 5 carbon 
2) Position of –OH group 
- Carbon-2 
3) Position of C=C 
- Carbon-4 
COMPLETE NAME = 4-penten-2-ol
 Some consideration: 
- OH functional group is named as a hydroxy 
substituent when it appears on a structure with a 
higher priority functional group such as acids, esters, 
aldehydes and ketones. 
- Examples: 
OH 
4 3 2 1 
OH 
1 2 
3 45 
6 O 
CH3 CH 
O 
CH2 C 
OH 
3-hydroxybutanoic acid 2-hydroxycyclohexanone
MAIN GROUPS 
Acids 
Esters 
Aldehydes 
Ketones 
Alcohols 
Amines 
Alkenes 
Alkynes 
Alkanes 
Ethers 
Halides 
decreasing priority
NOMENCLATURE OF DIOLS 
 Alcohols with two –OH groups are called diols or 
glycols. 
 Naming of diols is like other alcohols except that the 
suffix diol is used and two numbers are needed to 
tell where the two hydroxyl groups are located. 
OH 
3CH 2 1 3 CH 
CH2 OH 
OH 
OH 
5 
propane-1,2-diol trans-cyclopentane-1,2-diol 
IUPAC name 
1 
3 2 
4
NOMENCLATURE OF 
PHENOLS 
 The terms ortho (1,2-disubstituted), meta (1,3- 
disubstituted) and para (1,4-disubstituted) are often 
used in the common names. 
OH 
Br 
O2N OH 
OH 
CH3CH2 
IUPAC name: 
common name: 
2-bromophenol 
ortho-bromophenol 
3-nitrophenol 
meta-nitrophenol 
4-ethylphenol 
para-ethylphenol
 Phenols may be monohydric, dihydric or 
trihydric according to the number of hydroxyl 
groups present in the benzene ring. 
OH 
OH 
OH 
OH 
OH 
OH 
OH 
benzene-1,3-diol benzene-1,4-diol benzene-1,2,3-triol
CLASSIFICATION 
 According to the type of carbinol carbon atom (C bonded 
to the –OH group). 
C OH 
 Classes: 
i) Primary alcohol 
- -OH group attached to a primary carbon atom 
ii) Secondary alcohol 
- -OH group attached to a secondary carbon atom 
iii) Tertiary alcohol 
- -OH group attached to a tertiary carbon atom
TTYYPPEE SSTTRRUUCCTTUURREE EEXXAAMMPPLLEESS 
i) Primary (1°) 
ii) Secondary (2°) 
iii) Tertiary (3°) 
R C 
H 
OH 
H 
R C 
H 
OH 
R' 
R C 
R'' 
OH 
R' 
CH3 
CH3CH2-OH CH3CHCH2 
OH 
ethanol 2-methyl-1-propanol 
OH 
H3C CH 
CH2CH3 
OH 
2-butanol cyclohexanol 
CH3 
C 
OH 
CH3 
H3C 
2-methyl-2-propanol
Polyhydroxy Alcohols 
• Alcohols that contain more than one OH group 
attached to different carbons are called polyhydroxy 
alcohols. 
• Monohydroxy: one OH group per molecule. 
• Dihydroxy: two OH groups per molecule. 
• Trihydroxy: three OH groups per molecule.
PPHHYYSSIICCAALL PPRROOPPEERRTTIIEESS 
 PHYSICAL STATES OF ALCOHOLS 
- simple aliphatic alcohols and lower aromatic 
alcohols (such as phenylmethanol, C6H5CH2OH) 
→ liquids at room temperature. 
- highly branched alcohols and alcohols with twelve 
or more carbon atoms → solids.
 BOILING POINTS 
- The boiling points of alcohols are higher than those of 
alkanes and chloroalkanes of similar relative molecular mass. 
- For example: 
C2H5OH CH3CH2CH3 CH3Cl 
Relative molecular mass: 46 44 50.5 
Boiling point: 78°C -42°C -24°C 
- Reason: 
intermolecular hydrogen bonds exist between the –OH 
groups in the alcohol molecules. 
R 
δ- 
O 
H 
δ+ 
H R 
O 
Ar 
δ- δ+ 
O 
H 
H Ar 
O 
δ- 
δ- 
hydrogen bonding hydrogen bonding 
- Branched chain alcohols boils at a lower temperature (more 
volatile) than the straight chain alcohols with the same number of 
carbon atoms.
 SOLUBILITY OF ALCOHOLS IN WATER 
i) alcohols with short carbon chains (such as methanol, 
ethanol, and propanol) dissolve in water. 
- when alcohols dissolve in water, hydrogen bonds are formed 
between the –OH group of the alcohol molecule and the –OH 
group of the water molecule. 
ii) the solubility of alcohols in water decreases sharply with the 
increasing length of the carbon chain. Higher alcohols are 
insoluble in water. 
- alcohol contains a polar end (-OH group) called ‘hydrophilic’ 
and a non-polar end (the alkyl group) called ‘hydrophobic’. 
- the water solubility decreases as the alkyl group becomes 
larger.
iii) alcohols with more than one hydroxyl group (polyhydroxy 
alcohols) are more soluble than monohydroxy alcohols with 
the same number of carbon atoms. This is because they 
can form more hydrogen bonds with water molecule. 
iv) branched hydrocarbon increases the solubility of alcohol in 
water. 
- reason: branched hydrocarbon cause the hydrophobic 
region becomes compact so decrease surface area. As the 
surface area of the non-polar part in the molecule 
decreases, the solubility increases. 
* Phenol is sparingly soluble (9.3%) because of its compact 
shape and the particularly strong hydrogen bonds formed 
between phenolic –OH groups and water molecules.
AACCIIDDIITTYY OOFF AALLCCOOHHOOLLSS AANNDD PPHHEENNOOLLSS 
 Alcohol is weakly acidic. 
 In aqueous solution, alcohol will donated its proton to 
water molecule to give an alkoxide ion (R-O-). 
R-OH + H2O R-O- + H3O+ Ka = ~ 10-16 to 10-18 
alkoxide ion 
Example 
CH3CH2-OH + H2O CH3CH2-O- + H3O+ 
 The acid-dissociation constant, Ka, of an alcohol is defined 
by the equilibrium 
R-OH + H2O Ka R-O- + H3O+ 
Ka = [H3O+] [RO-] 
[ROH] 
pKa = - log (Ka) 
* More smaller the pKa 
value, the alcohol is 
more acidic
Acidity OF PHENOLS 
 Phenol is a stronger acid than alcohols and water. 
R-OH + H2O R-O- + H3O+ Ka = ~ 10-16 to 10-18 
alcohol alkoxide ion 
OH H2O O- H3O+ 
phenol phenoxide ion 
Ka = 1.2 x 10-10 
H2O + H2O HO- + H3O+ Ka = 1.8 x 10-16 
hydroxide ion
 Phenol is more acidic than alcohols by considering 
the resonance effect. 
i) The alkoxide ion (RO-) 
- the negative charge is confined to the oxygen and 
is not spread over the alkyl group. 
- this makes the RO- ion less stable and more 
susceptible to attack by positive ions such as H+ 
ions.
ii) The phenoxide ion 
- one of the lone pairs of electrons on the oxygen atom is 
delocalised into the benzene ring. 
- the phenoxide ion is more stable than the alkoxide ion 
because the negative charge is not confined to the 
oxygen atom but delocalised into the benzene ring. 
- the phenoxide ion is resonance stabilised by the 
benzene ring and this decreases the tendency for the 
phenoxide ion to react with H3O+. 
O O O O
EFFECTS OF Acidity 
 The acidity decreases as the substitution on the alkyl group increase. 
- Reason: a more highly substituted alkyl group inhibits solvation of 
the alkoxide ion and drives the dissociation equilibrium to the left. 
- For example: methanol is more acidic than t-butyl alcohol. 
 The present of electron-withdrawing atoms enhances the acidity of 
alcohols. 
- Reason: the electron withdrawing atom helps to stabilize the 
alkoxide ion. 
- For example: 2-chloroethanol is more acidic than ethanol because 
the electron-withdrawing chlorine atom helps to stabilize the 2- 
chloroethoxide ion. 
- alcohol with more than one electron withdrawing atoms are more 
acidic. For example, 2,2,-dichloroethanol is more acidic than 2- 
chloroethanol. 
- Example of electron-withdrawing atom/groups: 
Halogen atoms and NO2.
RREEAACCTTIIOONNSS OOFF AALLCCOOHHOOLLSS 
 Reaction with sodium 
 Oxidation 
 Esterification 
 Halogenation and haloform reactions 
 Dehydration 
 Formation of ether (Williamson ether 
synthesis)
Reaction with sodium 
 Alcohols reacts with Na at room temperature to 
form salts (sodium alkoxides) and hydrogen. 
2R-O-H + 2Na → 2R-O- Na+ + H2 
 For example: 
CH3CH2OH + Na → CH3CH2O-Na+ + 1/2H2 
alcohol sodium ethoxide 
 Reactivity of alcohols towards the reactions 
with sodium: 
CH3 > 1° > 2° > 3°
Oxidation 
H 
R C OH 
H 
H 
R C OH 
H 
Cr3O/pyridine = Collins reagent 
H 
R C OH 
H 
H 
R-C=O 
H 
R-C=O 
O 
R-C-OH 
Pyridinium chlorochromate (PCC) 
CH2Cl2, 25oC 
1o alcohol aldehyde 
Cu or Cr3O/pyridine 
1o alcohol aldehyde 
KMnO4/H+ or K2Cr2O7/H+ 
or CrO3/H+ 
1o alcohol carboxylic acid 
1° alcohol
O 
PCC 
Examples: 
1° alcohol 
CH3(CH2)4-CH2-OH CH3(CH2)4-C-H 
KMnO4/H+ or K2Cr2O7/H+ 
CH3(CH2)4-CH2-OH CH3(CH2)4-C-OH 
or CrO3/H+ 
O 
1-hexanol hexanal 
1-hexanol hexanoic acid
H 
R C OH 
R' 
O 
R-C-R' 
KMnO4/H+ or K2Cr2O7/H+ 
or CrO3/H+ 
2o alcohol ketone 
R" 
R C OH 
R' 
KMnO4/H+ or K2Cr2O7/H+ 
3o alcohol 
or CrO3/H+ no reaction 
2° alcohol 
3° alcohol 
Example: 
OH 
CH3 CH 
O 
CH2CH3 CH3 C 
CH2CH3 
KMnO4/H+ or K2Cr2O7/H+ 
or CrO3/H+ 
2-butanol 2-butanone
Esterification 
 Esterification: 
- the reaction between an alcohol and a carboxylic acid to 
form an ester and H2O. 
O 
R C 
O H H O R' 
H+ 
O 
CH3CH2-O-H CH3 C 
O H 
O 
CH3-O-H C 
OH 
H+ 
R C 
H+ 
O 
O R' 
O 
CH3 C 
O 
C 
OCH2CH3 
OCH3 
H2O 
H2O 
H2O 
carboxylic acid alcohol ester 
EXAMPLES 
ethanol ethanoic acid ethyl ethanoate 
methanol benzoic acid methyl benzoate 
H+ = catalyst
Esterification also occurs when alcohols 
react with derivatives of carboxylic acids 
such as acid chlorides 
O 
CH3-O-H CH3 C 
O 
Cl CH3 C 
OCH3 
HCl 
methanol ethanoyl chloride methyl ethanoate
Halogenation and haloform reactions 
1) Hydrogen halides (HBr or HCl or HI) 
R-OH + H-X → R-X + H2O 
Example: 
C2H5-OH + H-Br C2H5-Br + H2O 
• Reactivity of hydrogen halides decreases in order HI > 
HBr > HCl 
• Reactivity of alcohols with hydrogen halides: 
3° > 2° > 1° 
H+
2) Phosphorus trihalides, PX3 
3R-OH + PX3 3R-X + H3PO3 
(PX3 = PCl3 or PBr3 or PI3) 
Example: 
(CH3)2CHCH2-OH + PBr3 → (CH3)2CHCH2-Br 
isobutyl alcohol isobutyl bromide 
3) Phosphorus pentahalides (PX5) 
R-OH + PX5 → R-Cl + POCl3 + HCl 
phosphorus trichloride oxide 
(phosphorus oxychloride) 
RT 
Example: 
CH3CH2-OH + PCl5 → CH3CH2-Cl + POCl3 + HCl 
ethanol chloroethane (white fumes of HCl)
4) Thionyl chloride (SOCl2) 
R-OH + SOCl2 → R-Cl + SO2 + HCl 
Example: 
CH3(CH2)5CH2-OH + SOCl2 → CH3(CH2)5CH2-Cl + SO2 + HCl 
1-heptanol 1-chloroheptane
Dehydration 
 Dehydration of alcohols will formed alkenes and the 
products will followed Saytzeff rules. 
conc. H2SO4 R-CH2-CH2-OH R-CH=CH2 + H2O 
 Saytzeff rule: 
- A reaction that produces an alkene would favour the 
formation of an alkene that has the greatest number of 
substituents attached to the C=C group. 
CH3CH2-CH-CH3 
OH 
H+ 
H+ 
CH3CH2-CH=CH2 + H2O 
1-butene 
CH3CH=CH-CH3 + H2O 
2-butanol 
2-butene 
major product
 Reactivity of alcohols towards dehydration: 
3° > 2° > 1° 
 Reagents for dehydration: 
i) Concentrated H2SO4 
conc. H2SO4 CH3-CH2-OH CH2=CH2 + H2O 
ii) With phosphoric (v) acid 
OH 
85% H3PO4, 165-170oC H2O 
iii) Vapour phase dehydration of alcohols 
CH3CH2OH CH2=CH2 + H2O 
Al2O3 
heat
Formation of ether (Williamson ether 
synthesis) 
 Involves the SN2 attack of an alkoxide ion on an 
unhindered primary alkyl halides. 
 The alkoxide is made by adding Na, K or NaH to the 
alcohol. 
R-O- + R’-X → R-O-R’ + X-alkoxide 
(R’ must be primary) 
 The alkyl halides (or tosylate) must be primary, so that 
a back-side attack is not hindered. 
 If the alkyl halides is not primary, elimination usually 
occurs to form alkenes.
CH3CH2-OH Na 
CH3CH2-OH 
CH3I 
OH 
CH3CH2-OTs 
CH3CH2-O 
Na+ 
CH3CH2-O-CH3 
CH3I 
NaI 
CH3CH2-O-CH3 
OCH2CH3 
NaI 
EXAMPLES 
or 
1) Na 
2) 
1) Na 
2) 
cyclohexanol ethoxycyclohexane
Question: 
Alcohol W is a secondary alcohol with a molecular formula 
of C4H10O. 
Compound M C4H10O 
Alcohol W 
Step 1 
CrO3 / 
pyrridine 
Step 2 
H+ / heat 
Compound N 
(major) 
+ 
Compound O 
(minor) 
Reagent A 
C4H10ONa 
a) Draw and give the IUPAC name for alcohol W. 
b) Draw the structural formula for the following 
compounds: 
i) Compound M 
ii)Compound N 
iii)Compound O
c) Give the correct name for the following: 
i) Step 1 
ii) Step 2 
iii)Reagent A
Answers 
a) Alcohol W 
OH 
name: butan-2-ol 
b) i) compound M ii) compound N iii) Compound O 
O 
c) i) Step 1: Oxidation 
ii) Step 2: Dehydration (of alcohol) 
iii) Reagent A: Na Metal
RREEAACCTTIIOONNSS OOFF PPHHEENNOOLLSS 
 Reaction with sodium 
 Esterification 
 Halogenation of the ring 
 Nitration of the ring
REACTION WITH SODIUM 
OH Na O- Na+ 1/2 H2(g) 
sodium phenoxide 
REACTION WITH AQUEOUS SODIUM HYDROXIDE 
OH NaOH O- Na+ 
sodium phenoxide 
H2O 
ROH + NaOH no reaction
ESTERIFICATION 
OH 
OH 
NaOH 
H2O 
O 
C 
OH 
O 
ONa CH3CCl 
NaOH 
O 
OC 
O 
OCCH3 
H2O 
NaCl 
sodium phenoxide 
phenyl benzoate 
EXAMPLES 
H+
HALOGENATION 
 More reactive towards electrophilic substitution than benzene. 
 ortho-para director. 
1) Halogenation of phenol: 
 If liquid bromine or bromine water is added to an aqueous solution of phenol 
at room temperature, decolorisation occurs and a white precipitate of 2,4,6- 
tribromophenol is formed (bromination). 
 No catalyst (halogen carrier) is needed. 
 This reaction is used to test the presence of phenol and determine the mass 
of phenol in an aqueous solution. 
OH 
3X2 (aq) 
OH 
3Br2(aq) 
OH 
X X 
X 
OH 
Br Br 
Br 
3HX 
3HBr 
room 
temperature 
EXAMPLE 
room 
temperature 
2,4,6-tribromophenol (white precipitate)
 Phenol reacts similarly with chlorine or chlorine water to form 
white precipitate of 2,4,6-trichlorophenol. 
 This reaction is called chlorination of phenol. 
OH 
3Cl2 
OH 
Cl Cl 
room 3HCl 
Cl 
temperature 
2,4,6-trichlorophenol (white precipitate) 
 Monobromophenols are obtained if the bromine is dissolved in 
a non-polar solvent such as CCl4. 
OH 
2 2HBr 
2Br2 (CCl4) 
OH 
Br 
OH 
Br
NITRATION 
 Dilute nitric (v) acids reacts with phenol at room 
temperature to give a mixture of 2- and 4-nitrophenols. 
OH 
2 2HNO3 
< 20oC 2H2O 
OH 
NO2 
OH 
NO2 
2-nitrophenol 4-nitrophenol
 By using concentrated nitric (v) acid, the nitration of 
phenol yields 2,4,6-trinitrophenol (picric acid). 
 Picric acid is a bright yellow crystalline solid. It is used 
in the dyeing industry and in manufacture of explosives. 
OH 
3HNO3 
OH 
NO2 
NO2 
O2N 
3H2O 
2,4,6-trinitrophenol 
(picric acid)
CCHHEEMMIICCAALL TTEESSTTSS FFOORR PPHHEENNOOLLSS 
 Aqueous iron (III) chloride and aqueous bromine are used to 
test phenols. 
i) Complex formation with iron (III) chloride 
- when two or three drops of iron (III) chloride solution is 
added to a very dilute solution of phenol, a violet-blue 
coloration is produced. 
- methylphenol (toluene) produce a blue colour. 
OH 
O 
6 FeCl3 (neutral) H3[Fe3+ ( )6] 
3HCl 
phenoxide ligand violet complex
Phenol 
compound 
Colour of 
complex with 
FeCl3 (aq) 
Phenol 
compound 
Colour of 
complex with 
FeCl3 (aq) 
Violet Green 
Violet Red 
Blue Violet 
Violet 
OH 
OH 
CH3 
OH 
CH3 
OH 
COOH 
OH 
R 
O 
OH 
OH 
OH 
OCH3 
O
ii) Bromine water 
- when bromine water is added gradually to a concentrated 
solution of phenol, the bromine water is decolorised. 
- when excess bromine water is added, a white precipitate 
of 2,4,6-tribromophenol is obtained.
TTEESSTTSS TTOO DDIISSTTIINNGGUUIISSHH CCLLAASSSSEESS OOFF 
1) Lucas Test 
AALLCCOOHHOOLLSS 
- The alcohol is shaken with Lucas reagent (a solution 
of ZnCl2 in concentrated HCl). 
- Tertiary alcohol - Immediate cloudiness (due to the 
formation of alkyl chloride). 
- Secondary alcohol - Solution turns cloudy within 
about 5 minutes. 
- Primary alcohol - No cloudiness at room temperature.
CH3 
CH3 C CH3 
OH 
CH3 CH 
OH 
CH2CH3 
CH3CH2CH2CH2OH 
CH3 
CH3 C CH3 
Cl 
CH3 CH 
Cl 
CH2CH3 
HCl/ZnCl2 
room temperature 
3o alcohol (cloudy solution almost immediately) 
HCl/ZnCl2 
room temperature 
2o alcohol (cloudy solution within 5 minutes) 
HCl/ZnCl2 
room temperature 
no reaction 
1o alcohol
2) Oxidation of alcohols 
- only primary and secondary alcohols are oxidised by 
hot acidified KMnO4 or hot acidified K2Cr2O7 solution. 
- the alcohol is heated with KMnO4 or K2Cr2O7 in the 
presence of dilute H2SO4. 
- 1o or 2o alcohol: 
→ the purple colour of KMnO4 solution disappears. 
→ the colour of the K2Cr2O7 solution changes from 
orange to green. 
- 3o alcohol do not react with KMnO4 or K2Cr2O7.
3RCH2OH + Cr2O2- 
7 + 8H+ 3RCHO + 2Cr3+ + 7H2O 
1o alcohol (orange) aldehyde (green) 
3RCHO 
R' 
R CH 
R' 
OH R C 
O 
+ Cr2O2- 
7 + 8H+ 
aldehyde (orange) 
3RCOOH + 2Cr3+ + 7H2O 
carboxylic acid (green) 
3 + Cr2O2- 
7 + 8H+ 
2o alcohol (orange) 
3 + 2Cr3+ + 7H2O 
ketone (green)
HHAALLOOFFOORRMM TTEESSTT TTOO IIDDEENNTTIIFFYY MMEETTHHYYLL 
AALLCCOOHHOOLL GGRROOUUPP 
1) Iodoform: 
 Ethanol and secondary alcohols containing the group 
methyl alcohol group which react with alkaline 
solutions of iodine to form triiodomethane (iodoform, 
CHI3). 
 Triiodomethane – a pale yellow solid with a 
characteristic smell. 
H 
CH3 C 
OH 
(methyl alcohol group)
H 
CH3 C R 
OH 
+ 4I2 + 6NaOH CHI3 (s) + RCOONa + 5NaI + 5H2O 
triiodomethane 
(iodoform) 
yellow precipitate 
where R = hydrogen, alkyl or aryl group 
• The iodoform test can distinguish ethanol from methanol 
H 
CH3 C H 
OH 
+ 4I2 + 6OH CHI3 (s) + 5I- + 5H2O 
iodoform 
O 
H C O 
ethanol 
methanoate 
H 
H C H 
OH 
+ 4I2 + 6OH 
methanol 
no reaction 
positive iodoform test 
negative iodoform test
• The iodoform test can distinguish 2-propanol from 1-propanol 
CH3 
CH3 C H 
OH 
+ 4I2 + 6OH CHI3 (s) + 5I- + 5H2O 
iodoform 
O 
CH3 C O 
2-propanol 
ethanoate 
positive iodoform test 
H 
H H 
H C C C H 
no reaction 
OH 
+ 4I2 + 6OH 
H H negative iodoform test 
1-propanol 
* TERTIARY ALCOHOLS DO NOT GIVE POSITIVE 
IODOFORM TEST
2) BROMOFORM 
H 
CH3 C R 
OH 
+ 4Br2 + 6NaOH CHBr3 (s) + RCOONa + 5NaBr + 5H2O 
bromoform 
where R = hydrogen, alkyl or aryl group 
sample 
iodoform 
reagent
Question: 
a) Classify each of the following alcohols as 
primary, secondary or tertiary. 
i) 2-Propanol 
ii) 4-methylpentanol 
iii)2,3-dimethylbutan-2-ol 
b) Name a simple test to distinguish 1°, 2°, 3° 
alcohol. State the reagents and conditions 
required for the test and write down the 
expected observations.
Answer: 
a) i) 2° 
ii) 1° 
iii) 3° 
b) Test: Lucas test 
Reagent and conditions : Lucas reagent / 
Mixture of HCl and ZnCl2 
Observatios: 
- Clear homogenous solution change into 2 
layers or cloudiness 
- Rate of reaction: 3° > 2° > 1° alcohol
UUSSEESS OOFF AALLCCOOHHOOLLSS 
 As solvents: 
- examples: the lower alcohols such as methanol, 
ethanol and propanol. 
- methanol is used as a solvent for varnish and paints. 
 As fuels: 
- biofuel (fuel derived from a biological source). 
- ethanol can be produced from sugars such as sucrose 
from sugar cane, through fermentation and distillation. 
It can be blended with petrol and used as fuel in motor 
vehicles. 
- methylated spirit is ethanol made undrinkable by the 
addition of a little methanol. It is used as a fuel in 
camping stoves.
 In alcoholic drinks: 
- ethanol is used for making wine, beer and etc. 
 As intermediates: 
- methanol can be oxidised to methanal (HCHO), a 
chemical feedstock (starting material) for the 
manufacture of thermosetting plastics such as bakelite. 
- methanol is used to make methyl methacrylate which 
is used in the manufacture of another plastic called 
perspex. 
 In cosmetics: 
- ethanol is used as solvent for fragrances in perfumes 
and after-shave lotions. 
- polyhydroxyl alcohols (for example, glycerol) are used 
in moisturising creams.
UUSSEESS OOFF PPHHEENNOOLLSS 
 Making plastics such as bakelite (phenol-methanal 
plastic). 
 The synthesis of cyclohexanol and 
hexanedioic acid to make nylon 6,6. 
 Making dyes. 
 Making antiseptics such as 4-chloro-3,5- 
dimethylphenol which is active ingredient in 
‘Dettol’.

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Chapter 6 hydroxyl compounds

  • 1. ORGANIC CHEMISTRY CHM 207 CHAPTER 6: HYDROXYL COMPOUNDS (ALCOHOLS AND PHENOL)
  • 2. SUBTOPICS  Nomenclature of alcohols, phenols.  Classification of alcohols.  Physical properties of alcohols: - Physical state - Boiling points - Solubility of alcohols in water  Acidity of alcohols and phenols  Reactions of alcohols: - Reaction with sodium - Oxidation - Esterification - Halogenation and haloform reactions - Dehydration - Formation of ether (Williamson ether synthesis)
  • 3.  Reactions of phenols: - Reaction with sodium - Esterification - Halogenation of the ring - Nitration of the ring  Tests to distinguish classes of alcohols: i) Lucas test ii) Oxidation  Haloform test to identify methyl alcohol group - Iodoform - Bromoform  Uses of alcohols and phenols.
  • 4. ALCOHOLS  Alcohols: Organic compounds containing hydroxyl (-OH) functional groups. R OH  Phenols: Compounds with hydroxyl group bonded directly to an aromatic (benzene) ring. OH
  • 6. IUPAC RULES 1. Select the longest continuous chain of carbon atoms containing the hydroxyl group. 2. Number the carbon atoms in this chain so that the one bonded to the –OH group has the lowest possible number. 3. Form the parent alcohol name by replacing the final –e of the corresponding alkane name by –ol. When isomers are possible, locate the position of the –OH by placing the number (hyphenated) of the carbon atom to which the –OH is bonded immediately before the parent alcohol name. 4. Name each alkyl branch chain (or other group) and designate its position by number.
  • 7. This is the longest continuous chain that contains an hydroxyl group. Select this chain as the parent compound.
  • 8. 4 3 2 1 This end of the chain is closest to the OH. Begin numbering here.
  • 9. 4 3 2 1 3-methyl-2-butanol
  • 10. This is the longest continuous chain that contains an hydroxyl group. Select this chain as the parent compound.
  • 11. 4 3 2 1 5 This end of the chain is closest to the OH. Begin numbering here.
  • 12. 4 3 2 1 5 3-methyl-2-pentanol
  • 13. NOMENCLATURE OF CYCLIC ALCOHOLS  Using the prefix cyclo-  The hydroxyl group is assumed to be on C1. IUPAC name: new IUPAC name: H HO CH2CH3 5 6 1 4 3 2 Br OH H trans-2-bromocyclohexanol trans-2-bromocyclohexan-1-ol 1 3 2 1-ethylcyclopropanol 1-ethylcyclopropan-1-ol
  • 14. NOMENCLATURE OF ALCOHOLS CONTAINING TWO DIFFERENT FUNCTIONAL GROUPS  Alcohol containing double and triple bonds: - use the –ol suffix after the alkene or alkyne name.  The alcohol functional group takes precedence over double and triple bonds, so the chain is numbered in order to give the lowest possible number to the carbon atom bonded to the hydroxyl group.  The position of the –OH group is given by putting its number before the –ol suffix.  Numbers for the multiple bonds were once given early in the name.
  • 15. EXAMPLE 4 3 2 1 CH2 CH CH2 CH CH3 OH 5 1) Longest carbon chain that contains –OH group - 5 carbon 2) Position of –OH group - Carbon-2 3) Position of C=C - Carbon-4 COMPLETE NAME = 4-penten-2-ol
  • 16.  Some consideration: - OH functional group is named as a hydroxy substituent when it appears on a structure with a higher priority functional group such as acids, esters, aldehydes and ketones. - Examples: OH 4 3 2 1 OH 1 2 3 45 6 O CH3 CH O CH2 C OH 3-hydroxybutanoic acid 2-hydroxycyclohexanone
  • 17. MAIN GROUPS Acids Esters Aldehydes Ketones Alcohols Amines Alkenes Alkynes Alkanes Ethers Halides decreasing priority
  • 18. NOMENCLATURE OF DIOLS  Alcohols with two –OH groups are called diols or glycols.  Naming of diols is like other alcohols except that the suffix diol is used and two numbers are needed to tell where the two hydroxyl groups are located. OH 3CH 2 1 3 CH CH2 OH OH OH 5 propane-1,2-diol trans-cyclopentane-1,2-diol IUPAC name 1 3 2 4
  • 19. NOMENCLATURE OF PHENOLS  The terms ortho (1,2-disubstituted), meta (1,3- disubstituted) and para (1,4-disubstituted) are often used in the common names. OH Br O2N OH OH CH3CH2 IUPAC name: common name: 2-bromophenol ortho-bromophenol 3-nitrophenol meta-nitrophenol 4-ethylphenol para-ethylphenol
  • 20.  Phenols may be monohydric, dihydric or trihydric according to the number of hydroxyl groups present in the benzene ring. OH OH OH OH OH OH OH benzene-1,3-diol benzene-1,4-diol benzene-1,2,3-triol
  • 21. CLASSIFICATION  According to the type of carbinol carbon atom (C bonded to the –OH group). C OH  Classes: i) Primary alcohol - -OH group attached to a primary carbon atom ii) Secondary alcohol - -OH group attached to a secondary carbon atom iii) Tertiary alcohol - -OH group attached to a tertiary carbon atom
  • 22. TTYYPPEE SSTTRRUUCCTTUURREE EEXXAAMMPPLLEESS i) Primary (1°) ii) Secondary (2°) iii) Tertiary (3°) R C H OH H R C H OH R' R C R'' OH R' CH3 CH3CH2-OH CH3CHCH2 OH ethanol 2-methyl-1-propanol OH H3C CH CH2CH3 OH 2-butanol cyclohexanol CH3 C OH CH3 H3C 2-methyl-2-propanol
  • 23. Polyhydroxy Alcohols • Alcohols that contain more than one OH group attached to different carbons are called polyhydroxy alcohols. • Monohydroxy: one OH group per molecule. • Dihydroxy: two OH groups per molecule. • Trihydroxy: three OH groups per molecule.
  • 24.
  • 25. PPHHYYSSIICCAALL PPRROOPPEERRTTIIEESS  PHYSICAL STATES OF ALCOHOLS - simple aliphatic alcohols and lower aromatic alcohols (such as phenylmethanol, C6H5CH2OH) → liquids at room temperature. - highly branched alcohols and alcohols with twelve or more carbon atoms → solids.
  • 26.  BOILING POINTS - The boiling points of alcohols are higher than those of alkanes and chloroalkanes of similar relative molecular mass. - For example: C2H5OH CH3CH2CH3 CH3Cl Relative molecular mass: 46 44 50.5 Boiling point: 78°C -42°C -24°C - Reason: intermolecular hydrogen bonds exist between the –OH groups in the alcohol molecules. R δ- O H δ+ H R O Ar δ- δ+ O H H Ar O δ- δ- hydrogen bonding hydrogen bonding - Branched chain alcohols boils at a lower temperature (more volatile) than the straight chain alcohols with the same number of carbon atoms.
  • 27.  SOLUBILITY OF ALCOHOLS IN WATER i) alcohols with short carbon chains (such as methanol, ethanol, and propanol) dissolve in water. - when alcohols dissolve in water, hydrogen bonds are formed between the –OH group of the alcohol molecule and the –OH group of the water molecule. ii) the solubility of alcohols in water decreases sharply with the increasing length of the carbon chain. Higher alcohols are insoluble in water. - alcohol contains a polar end (-OH group) called ‘hydrophilic’ and a non-polar end (the alkyl group) called ‘hydrophobic’. - the water solubility decreases as the alkyl group becomes larger.
  • 28. iii) alcohols with more than one hydroxyl group (polyhydroxy alcohols) are more soluble than monohydroxy alcohols with the same number of carbon atoms. This is because they can form more hydrogen bonds with water molecule. iv) branched hydrocarbon increases the solubility of alcohol in water. - reason: branched hydrocarbon cause the hydrophobic region becomes compact so decrease surface area. As the surface area of the non-polar part in the molecule decreases, the solubility increases. * Phenol is sparingly soluble (9.3%) because of its compact shape and the particularly strong hydrogen bonds formed between phenolic –OH groups and water molecules.
  • 29. AACCIIDDIITTYY OOFF AALLCCOOHHOOLLSS AANNDD PPHHEENNOOLLSS  Alcohol is weakly acidic.  In aqueous solution, alcohol will donated its proton to water molecule to give an alkoxide ion (R-O-). R-OH + H2O R-O- + H3O+ Ka = ~ 10-16 to 10-18 alkoxide ion Example CH3CH2-OH + H2O CH3CH2-O- + H3O+  The acid-dissociation constant, Ka, of an alcohol is defined by the equilibrium R-OH + H2O Ka R-O- + H3O+ Ka = [H3O+] [RO-] [ROH] pKa = - log (Ka) * More smaller the pKa value, the alcohol is more acidic
  • 30. Acidity OF PHENOLS  Phenol is a stronger acid than alcohols and water. R-OH + H2O R-O- + H3O+ Ka = ~ 10-16 to 10-18 alcohol alkoxide ion OH H2O O- H3O+ phenol phenoxide ion Ka = 1.2 x 10-10 H2O + H2O HO- + H3O+ Ka = 1.8 x 10-16 hydroxide ion
  • 31.  Phenol is more acidic than alcohols by considering the resonance effect. i) The alkoxide ion (RO-) - the negative charge is confined to the oxygen and is not spread over the alkyl group. - this makes the RO- ion less stable and more susceptible to attack by positive ions such as H+ ions.
  • 32. ii) The phenoxide ion - one of the lone pairs of electrons on the oxygen atom is delocalised into the benzene ring. - the phenoxide ion is more stable than the alkoxide ion because the negative charge is not confined to the oxygen atom but delocalised into the benzene ring. - the phenoxide ion is resonance stabilised by the benzene ring and this decreases the tendency for the phenoxide ion to react with H3O+. O O O O
  • 33. EFFECTS OF Acidity  The acidity decreases as the substitution on the alkyl group increase. - Reason: a more highly substituted alkyl group inhibits solvation of the alkoxide ion and drives the dissociation equilibrium to the left. - For example: methanol is more acidic than t-butyl alcohol.  The present of electron-withdrawing atoms enhances the acidity of alcohols. - Reason: the electron withdrawing atom helps to stabilize the alkoxide ion. - For example: 2-chloroethanol is more acidic than ethanol because the electron-withdrawing chlorine atom helps to stabilize the 2- chloroethoxide ion. - alcohol with more than one electron withdrawing atoms are more acidic. For example, 2,2,-dichloroethanol is more acidic than 2- chloroethanol. - Example of electron-withdrawing atom/groups: Halogen atoms and NO2.
  • 34. RREEAACCTTIIOONNSS OOFF AALLCCOOHHOOLLSS  Reaction with sodium  Oxidation  Esterification  Halogenation and haloform reactions  Dehydration  Formation of ether (Williamson ether synthesis)
  • 35. Reaction with sodium  Alcohols reacts with Na at room temperature to form salts (sodium alkoxides) and hydrogen. 2R-O-H + 2Na → 2R-O- Na+ + H2  For example: CH3CH2OH + Na → CH3CH2O-Na+ + 1/2H2 alcohol sodium ethoxide  Reactivity of alcohols towards the reactions with sodium: CH3 > 1° > 2° > 3°
  • 36. Oxidation H R C OH H H R C OH H Cr3O/pyridine = Collins reagent H R C OH H H R-C=O H R-C=O O R-C-OH Pyridinium chlorochromate (PCC) CH2Cl2, 25oC 1o alcohol aldehyde Cu or Cr3O/pyridine 1o alcohol aldehyde KMnO4/H+ or K2Cr2O7/H+ or CrO3/H+ 1o alcohol carboxylic acid 1° alcohol
  • 37. O PCC Examples: 1° alcohol CH3(CH2)4-CH2-OH CH3(CH2)4-C-H KMnO4/H+ or K2Cr2O7/H+ CH3(CH2)4-CH2-OH CH3(CH2)4-C-OH or CrO3/H+ O 1-hexanol hexanal 1-hexanol hexanoic acid
  • 38. H R C OH R' O R-C-R' KMnO4/H+ or K2Cr2O7/H+ or CrO3/H+ 2o alcohol ketone R" R C OH R' KMnO4/H+ or K2Cr2O7/H+ 3o alcohol or CrO3/H+ no reaction 2° alcohol 3° alcohol Example: OH CH3 CH O CH2CH3 CH3 C CH2CH3 KMnO4/H+ or K2Cr2O7/H+ or CrO3/H+ 2-butanol 2-butanone
  • 39. Esterification  Esterification: - the reaction between an alcohol and a carboxylic acid to form an ester and H2O. O R C O H H O R' H+ O CH3CH2-O-H CH3 C O H O CH3-O-H C OH H+ R C H+ O O R' O CH3 C O C OCH2CH3 OCH3 H2O H2O H2O carboxylic acid alcohol ester EXAMPLES ethanol ethanoic acid ethyl ethanoate methanol benzoic acid methyl benzoate H+ = catalyst
  • 40. Esterification also occurs when alcohols react with derivatives of carboxylic acids such as acid chlorides O CH3-O-H CH3 C O Cl CH3 C OCH3 HCl methanol ethanoyl chloride methyl ethanoate
  • 41. Halogenation and haloform reactions 1) Hydrogen halides (HBr or HCl or HI) R-OH + H-X → R-X + H2O Example: C2H5-OH + H-Br C2H5-Br + H2O • Reactivity of hydrogen halides decreases in order HI > HBr > HCl • Reactivity of alcohols with hydrogen halides: 3° > 2° > 1° H+
  • 42. 2) Phosphorus trihalides, PX3 3R-OH + PX3 3R-X + H3PO3 (PX3 = PCl3 or PBr3 or PI3) Example: (CH3)2CHCH2-OH + PBr3 → (CH3)2CHCH2-Br isobutyl alcohol isobutyl bromide 3) Phosphorus pentahalides (PX5) R-OH + PX5 → R-Cl + POCl3 + HCl phosphorus trichloride oxide (phosphorus oxychloride) RT Example: CH3CH2-OH + PCl5 → CH3CH2-Cl + POCl3 + HCl ethanol chloroethane (white fumes of HCl)
  • 43. 4) Thionyl chloride (SOCl2) R-OH + SOCl2 → R-Cl + SO2 + HCl Example: CH3(CH2)5CH2-OH + SOCl2 → CH3(CH2)5CH2-Cl + SO2 + HCl 1-heptanol 1-chloroheptane
  • 44. Dehydration  Dehydration of alcohols will formed alkenes and the products will followed Saytzeff rules. conc. H2SO4 R-CH2-CH2-OH R-CH=CH2 + H2O  Saytzeff rule: - A reaction that produces an alkene would favour the formation of an alkene that has the greatest number of substituents attached to the C=C group. CH3CH2-CH-CH3 OH H+ H+ CH3CH2-CH=CH2 + H2O 1-butene CH3CH=CH-CH3 + H2O 2-butanol 2-butene major product
  • 45.  Reactivity of alcohols towards dehydration: 3° > 2° > 1°  Reagents for dehydration: i) Concentrated H2SO4 conc. H2SO4 CH3-CH2-OH CH2=CH2 + H2O ii) With phosphoric (v) acid OH 85% H3PO4, 165-170oC H2O iii) Vapour phase dehydration of alcohols CH3CH2OH CH2=CH2 + H2O Al2O3 heat
  • 46. Formation of ether (Williamson ether synthesis)  Involves the SN2 attack of an alkoxide ion on an unhindered primary alkyl halides.  The alkoxide is made by adding Na, K or NaH to the alcohol. R-O- + R’-X → R-O-R’ + X-alkoxide (R’ must be primary)  The alkyl halides (or tosylate) must be primary, so that a back-side attack is not hindered.  If the alkyl halides is not primary, elimination usually occurs to form alkenes.
  • 47. CH3CH2-OH Na CH3CH2-OH CH3I OH CH3CH2-OTs CH3CH2-O Na+ CH3CH2-O-CH3 CH3I NaI CH3CH2-O-CH3 OCH2CH3 NaI EXAMPLES or 1) Na 2) 1) Na 2) cyclohexanol ethoxycyclohexane
  • 48. Question: Alcohol W is a secondary alcohol with a molecular formula of C4H10O. Compound M C4H10O Alcohol W Step 1 CrO3 / pyrridine Step 2 H+ / heat Compound N (major) + Compound O (minor) Reagent A C4H10ONa a) Draw and give the IUPAC name for alcohol W. b) Draw the structural formula for the following compounds: i) Compound M ii)Compound N iii)Compound O
  • 49. c) Give the correct name for the following: i) Step 1 ii) Step 2 iii)Reagent A
  • 50. Answers a) Alcohol W OH name: butan-2-ol b) i) compound M ii) compound N iii) Compound O O c) i) Step 1: Oxidation ii) Step 2: Dehydration (of alcohol) iii) Reagent A: Na Metal
  • 51. RREEAACCTTIIOONNSS OOFF PPHHEENNOOLLSS  Reaction with sodium  Esterification  Halogenation of the ring  Nitration of the ring
  • 52. REACTION WITH SODIUM OH Na O- Na+ 1/2 H2(g) sodium phenoxide REACTION WITH AQUEOUS SODIUM HYDROXIDE OH NaOH O- Na+ sodium phenoxide H2O ROH + NaOH no reaction
  • 53. ESTERIFICATION OH OH NaOH H2O O C OH O ONa CH3CCl NaOH O OC O OCCH3 H2O NaCl sodium phenoxide phenyl benzoate EXAMPLES H+
  • 54. HALOGENATION  More reactive towards electrophilic substitution than benzene.  ortho-para director. 1) Halogenation of phenol:  If liquid bromine or bromine water is added to an aqueous solution of phenol at room temperature, decolorisation occurs and a white precipitate of 2,4,6- tribromophenol is formed (bromination).  No catalyst (halogen carrier) is needed.  This reaction is used to test the presence of phenol and determine the mass of phenol in an aqueous solution. OH 3X2 (aq) OH 3Br2(aq) OH X X X OH Br Br Br 3HX 3HBr room temperature EXAMPLE room temperature 2,4,6-tribromophenol (white precipitate)
  • 55.  Phenol reacts similarly with chlorine or chlorine water to form white precipitate of 2,4,6-trichlorophenol.  This reaction is called chlorination of phenol. OH 3Cl2 OH Cl Cl room 3HCl Cl temperature 2,4,6-trichlorophenol (white precipitate)  Monobromophenols are obtained if the bromine is dissolved in a non-polar solvent such as CCl4. OH 2 2HBr 2Br2 (CCl4) OH Br OH Br
  • 56. NITRATION  Dilute nitric (v) acids reacts with phenol at room temperature to give a mixture of 2- and 4-nitrophenols. OH 2 2HNO3 < 20oC 2H2O OH NO2 OH NO2 2-nitrophenol 4-nitrophenol
  • 57.  By using concentrated nitric (v) acid, the nitration of phenol yields 2,4,6-trinitrophenol (picric acid).  Picric acid is a bright yellow crystalline solid. It is used in the dyeing industry and in manufacture of explosives. OH 3HNO3 OH NO2 NO2 O2N 3H2O 2,4,6-trinitrophenol (picric acid)
  • 58. CCHHEEMMIICCAALL TTEESSTTSS FFOORR PPHHEENNOOLLSS  Aqueous iron (III) chloride and aqueous bromine are used to test phenols. i) Complex formation with iron (III) chloride - when two or three drops of iron (III) chloride solution is added to a very dilute solution of phenol, a violet-blue coloration is produced. - methylphenol (toluene) produce a blue colour. OH O 6 FeCl3 (neutral) H3[Fe3+ ( )6] 3HCl phenoxide ligand violet complex
  • 59. Phenol compound Colour of complex with FeCl3 (aq) Phenol compound Colour of complex with FeCl3 (aq) Violet Green Violet Red Blue Violet Violet OH OH CH3 OH CH3 OH COOH OH R O OH OH OH OCH3 O
  • 60. ii) Bromine water - when bromine water is added gradually to a concentrated solution of phenol, the bromine water is decolorised. - when excess bromine water is added, a white precipitate of 2,4,6-tribromophenol is obtained.
  • 61. TTEESSTTSS TTOO DDIISSTTIINNGGUUIISSHH CCLLAASSSSEESS OOFF 1) Lucas Test AALLCCOOHHOOLLSS - The alcohol is shaken with Lucas reagent (a solution of ZnCl2 in concentrated HCl). - Tertiary alcohol - Immediate cloudiness (due to the formation of alkyl chloride). - Secondary alcohol - Solution turns cloudy within about 5 minutes. - Primary alcohol - No cloudiness at room temperature.
  • 62. CH3 CH3 C CH3 OH CH3 CH OH CH2CH3 CH3CH2CH2CH2OH CH3 CH3 C CH3 Cl CH3 CH Cl CH2CH3 HCl/ZnCl2 room temperature 3o alcohol (cloudy solution almost immediately) HCl/ZnCl2 room temperature 2o alcohol (cloudy solution within 5 minutes) HCl/ZnCl2 room temperature no reaction 1o alcohol
  • 63. 2) Oxidation of alcohols - only primary and secondary alcohols are oxidised by hot acidified KMnO4 or hot acidified K2Cr2O7 solution. - the alcohol is heated with KMnO4 or K2Cr2O7 in the presence of dilute H2SO4. - 1o or 2o alcohol: → the purple colour of KMnO4 solution disappears. → the colour of the K2Cr2O7 solution changes from orange to green. - 3o alcohol do not react with KMnO4 or K2Cr2O7.
  • 64. 3RCH2OH + Cr2O2- 7 + 8H+ 3RCHO + 2Cr3+ + 7H2O 1o alcohol (orange) aldehyde (green) 3RCHO R' R CH R' OH R C O + Cr2O2- 7 + 8H+ aldehyde (orange) 3RCOOH + 2Cr3+ + 7H2O carboxylic acid (green) 3 + Cr2O2- 7 + 8H+ 2o alcohol (orange) 3 + 2Cr3+ + 7H2O ketone (green)
  • 65. HHAALLOOFFOORRMM TTEESSTT TTOO IIDDEENNTTIIFFYY MMEETTHHYYLL AALLCCOOHHOOLL GGRROOUUPP 1) Iodoform:  Ethanol and secondary alcohols containing the group methyl alcohol group which react with alkaline solutions of iodine to form triiodomethane (iodoform, CHI3).  Triiodomethane – a pale yellow solid with a characteristic smell. H CH3 C OH (methyl alcohol group)
  • 66. H CH3 C R OH + 4I2 + 6NaOH CHI3 (s) + RCOONa + 5NaI + 5H2O triiodomethane (iodoform) yellow precipitate where R = hydrogen, alkyl or aryl group • The iodoform test can distinguish ethanol from methanol H CH3 C H OH + 4I2 + 6OH CHI3 (s) + 5I- + 5H2O iodoform O H C O ethanol methanoate H H C H OH + 4I2 + 6OH methanol no reaction positive iodoform test negative iodoform test
  • 67. • The iodoform test can distinguish 2-propanol from 1-propanol CH3 CH3 C H OH + 4I2 + 6OH CHI3 (s) + 5I- + 5H2O iodoform O CH3 C O 2-propanol ethanoate positive iodoform test H H H H C C C H no reaction OH + 4I2 + 6OH H H negative iodoform test 1-propanol * TERTIARY ALCOHOLS DO NOT GIVE POSITIVE IODOFORM TEST
  • 68. 2) BROMOFORM H CH3 C R OH + 4Br2 + 6NaOH CHBr3 (s) + RCOONa + 5NaBr + 5H2O bromoform where R = hydrogen, alkyl or aryl group sample iodoform reagent
  • 69. Question: a) Classify each of the following alcohols as primary, secondary or tertiary. i) 2-Propanol ii) 4-methylpentanol iii)2,3-dimethylbutan-2-ol b) Name a simple test to distinguish 1°, 2°, 3° alcohol. State the reagents and conditions required for the test and write down the expected observations.
  • 70. Answer: a) i) 2° ii) 1° iii) 3° b) Test: Lucas test Reagent and conditions : Lucas reagent / Mixture of HCl and ZnCl2 Observatios: - Clear homogenous solution change into 2 layers or cloudiness - Rate of reaction: 3° > 2° > 1° alcohol
  • 71. UUSSEESS OOFF AALLCCOOHHOOLLSS  As solvents: - examples: the lower alcohols such as methanol, ethanol and propanol. - methanol is used as a solvent for varnish and paints.  As fuels: - biofuel (fuel derived from a biological source). - ethanol can be produced from sugars such as sucrose from sugar cane, through fermentation and distillation. It can be blended with petrol and used as fuel in motor vehicles. - methylated spirit is ethanol made undrinkable by the addition of a little methanol. It is used as a fuel in camping stoves.
  • 72.  In alcoholic drinks: - ethanol is used for making wine, beer and etc.  As intermediates: - methanol can be oxidised to methanal (HCHO), a chemical feedstock (starting material) for the manufacture of thermosetting plastics such as bakelite. - methanol is used to make methyl methacrylate which is used in the manufacture of another plastic called perspex.  In cosmetics: - ethanol is used as solvent for fragrances in perfumes and after-shave lotions. - polyhydroxyl alcohols (for example, glycerol) are used in moisturising creams.
  • 73. UUSSEESS OOFF PPHHEENNOOLLSS  Making plastics such as bakelite (phenol-methanal plastic).  The synthesis of cyclohexanol and hexanedioic acid to make nylon 6,6.  Making dyes.  Making antiseptics such as 4-chloro-3,5- dimethylphenol which is active ingredient in ‘Dettol’.