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Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm Solution Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm.
Step1 Error lies ; .1252 =.0625 Mole of O2 will .pdf
Step1 Error lies ; .1252 =.0625 Mole of O2 will .pdf
aswrd
a Happy Times Debt value 130 YTM 10.00% Market Cap 350.00 Return on equity 15% Joe\'s Debt 30.00 EBIT 17.00 Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value 233.98 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT- Depreciation) 16.15 17.28 18.49 19.78 255.15 Tax 5.65 6.05 6.47 6.92 89.30 PAT 10.50 11.23 12.02 12.86 165.85 Net cash flow 8.29 8.87 9.49 10.15 162.95 PV of Cash flows 106.97 Market value of debt 30 EV of Joe 136.97 Shares outstanding 2.3 Maximum share price 59.55 (EV/Shares outstanding) b Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value (Using EV/EBIDTA of 9) 210.58 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT-Depreciation) 16.15 17.28 18.49 19.78 231.75 Tax 5.65 6.05 6.47 6.92 81.11 PAT 10.50 11.23 12.02 12.86 150.64 Net cash flow 8.29 8.87 9.49 10.15 147.74 PV of Cash flows 99.41 Market value of debt 30 EV of Joe 129.41 Shares outstanding 2.3 Maximum share price 56.26 (EV/Shares outstanding) Solution a Happy Times Debt value 130 YTM 10.00% Market Cap 350.00 Return on equity 15% Joe\'s Debt 30.00 EBIT 17.00 Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value 233.98 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT- Depreciation) 16.15 17.28 18.49 19.78 255.15 Tax 5.65 6.05 6.47 6.92 89.30 PAT 10.50 11.23 12.02 12.86 165.85 Net cash flow 8.29 8.87 9.49 10.15 162.95 PV of Cash flows 106.97 Market value of debt 30 EV of Joe 136.97 Shares outstanding 2.3 Maximum share price 59.55 (EV/Shares outstanding) b Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value (Using EV/EBIDTA of 9) 210.58 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT-Depreciation) 16.15 17.28 18.49 19.78 231.75 Tax 5.65 6.05 6.47 6.92 81.11 PAT 10.50 11.23 12.02 12.86 150.64 Net cash flow 8.29 8.87 9.49 10.15 147.74 PV of Cash flows 99.41 Market value of debt 30 EV of Joe 129.41 Shares outstanding 2.3 Maximum share price 56.26 (EV/Shares outstanding).
a Happy Times Debt value 130 YTM 10.00 Mark.pdf
a Happy Times Debt value 130 YTM 10.00 Mark.pdf
aswrd
OH is a poor leaving group, so it first has toget hydrogenated (become OH2 +). Also, it is highly encumbered withthe 2,2 dimethyl group. Solution OH is a poor leaving group, so it first has toget hydrogenated (become OH2 +). Also, it is highly encumbered withthe 2,2 dimethyl group..
OH is a poor leaving group, so it first has toget.pdf
OH is a poor leaving group, so it first has toget.pdf
aswrd
Molarity = Moles/Volume = 2/2 =1 M Solution Molarity = Moles/Volume = 2/2 =1 M.
Molarity = MolesVolume = 22 =1 M .pdf
Molarity = MolesVolume = 22 =1 M .pdf
aswrd
Hydrophobic molecules tend to be non-polar and, thus, prefer other neutral molecules and non-polar solvents. Hydrophobic molecules in water often cluster Solution Hydrophobic molecules tend to be non-polar and, thus, prefer other neutral molecules and non-polar solvents. Hydrophobic molecules in water often cluster.
Hydrophobic molecules tend to be non-polar and, t.pdf
Hydrophobic molecules tend to be non-polar and, t.pdf
aswrd
There are two types of atomic bonds - ionic bonds and covalent bonds. They differ in their structure and properties. Covalent bonds consist of pairs of electrons shared by two atoms, and bind the atoms in a fixed orientation. Relatively high energies are required to break them (50 - 200 kcal/mol). Whether two atoms can form a covalent bond depends upon their electronegativity i.e. the power of an atom in a molecule to attract electrons to itself. If two atoms differ considerably in their electronegativity - as sodium and chloride do - then one of the atoms will lose its electron to the other atom. This results in a positively charged ion (cation) and negatively charged ion (anion). The bond between these two ions is called an ionic bond. Covalent BondsIonic Bonds Polarity:LowHigh Formation:A covalent bond is formed between two non-metals that have similar electronegativities. Neither atom is \"strong\" enough to attract electrons from the other. For stabilization, they share their electrons from outer molecular orbit with othersAn ionic bond is formed between a metal and a non-metal. Non-metals(-ve ion) are \"stronger\" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond. Shape:Definite shapeNo definite shape What is it?:Covalent bonding is a form of chemical bonding between two non metallic atoms which is characterized by the sharing of pairs of electrons between atoms and other covalent bonds.Ionic bond, also known as electrovalent bond is a type of bond formed from the electrostatic attraction between oppositely charged ions in a chemical compound. These kinds of bonds occur mainly between a metallic and a non metallic atom. Melting point:lowHigh Examples:Methane (CH4), Hydro Chloric acid (HCl)Sodium chloride (NaCl), Sulphuric Acid (H2SO4 ) Occurs between:Two non-metalsOne metal and one non-metal Boiling point:LowHigh State at room temperature:Liquid or gaseousSolid Ability to conduct electricity in molten/aqueous state: Yes Ability to conduct electricity in solid state: Solution There are two types of atomic bonds - ionic bonds and covalent bonds. They differ in their structure and properties. Covalent bonds consist of pairs of electrons shared by two atoms, and bind the atoms in a fixed orientation. Relatively high energies are required to break them (50 - 200 kcal/mol). Whether two atoms can form a covalent bond depends upon their electronegativity i.e. the power of an atom in a molecule to attract electrons to itself. If two atoms differ considerably in their electronegativity - as sodium and chloride do - then one of the atoms will lose its electron to the other atom. This results in a positively charged ion (cation) and negatively charged ion (anion). The bond between these two ions is called an ionic bond. Covalent BondsIonic Bonds Polarity:LowHigh Formation:A covalent bond is formed between two non-metals that have similar electronegativities. .
There are two types of atomic bonds - ionic bonds and covalent bonds.pdf
There are two types of atomic bonds - ionic bonds and covalent bonds.pdf
aswrd
T(n) = theta(nlog(2) n) T(n) = sqrt(2T(n/2) + C1 where n>1 so for n>1 T(n) = theta(nlog(2)n) Solution T(n) = theta(nlog(2) n) T(n) = sqrt(2T(n/2) + C1 where n>1 so for n>1 T(n) = theta(nlog(2)n).
T(n) = theta(nlog(2) n)T(n) = sqrt(2T(n2) + C1 where n1 so for.pdf
T(n) = theta(nlog(2) n)T(n) = sqrt(2T(n2) + C1 where n1 so for.pdf
aswrd
Showing a truth table that has the four motion sensors as inputs and an alarm trigger as the output when at least two motion sensors are activated at the same time. Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Solution Showing a truth table that has the four motion sensors as inputs and an alarm trigger as the output when at least two motion sensors are activated at the same time. Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T.
Showing a truth table that has the four motion sensors as inputs and.pdf
Showing a truth table that has the four motion sensors as inputs and.pdf
aswrd
Empfohlen
Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm Solution Step1 Error lies ; .125/2 =.0625 Mole of O2 will remain unreacted. Step2 We have .125 mole NO2 and .0625 mole unreacted O2 Step3 P= nRT/V ; n=.1875; P= .1875x.0821x300/4.5 =1.02625 atm=1.03 atm.
Step1 Error lies ; .1252 =.0625 Mole of O2 will .pdf
Step1 Error lies ; .1252 =.0625 Mole of O2 will .pdf
aswrd
a Happy Times Debt value 130 YTM 10.00% Market Cap 350.00 Return on equity 15% Joe\'s Debt 30.00 EBIT 17.00 Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value 233.98 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT- Depreciation) 16.15 17.28 18.49 19.78 255.15 Tax 5.65 6.05 6.47 6.92 89.30 PAT 10.50 11.23 12.02 12.86 165.85 Net cash flow 8.29 8.87 9.49 10.15 162.95 PV of Cash flows 106.97 Market value of debt 30 EV of Joe 136.97 Shares outstanding 2.3 Maximum share price 59.55 (EV/Shares outstanding) b Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value (Using EV/EBIDTA of 9) 210.58 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT-Depreciation) 16.15 17.28 18.49 19.78 231.75 Tax 5.65 6.05 6.47 6.92 81.11 PAT 10.50 11.23 12.02 12.86 150.64 Net cash flow 8.29 8.87 9.49 10.15 147.74 PV of Cash flows 99.41 Market value of debt 30 EV of Joe 129.41 Shares outstanding 2.3 Maximum share price 56.26 (EV/Shares outstanding) Solution a Happy Times Debt value 130 YTM 10.00% Market Cap 350.00 Return on equity 15% Joe\'s Debt 30.00 EBIT 17.00 Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value 233.98 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT- Depreciation) 16.15 17.28 18.49 19.78 255.15 Tax 5.65 6.05 6.47 6.92 89.30 PAT 10.50 11.23 12.02 12.86 165.85 Net cash flow 8.29 8.87 9.49 10.15 162.95 PV of Cash flows 106.97 Market value of debt 30 EV of Joe 136.97 Shares outstanding 2.3 Maximum share price 59.55 (EV/Shares outstanding) b Year 1.00 2 3 4 5 EBIT(Growth rate 7%) 17.00 18.19 19.46 20.83 22.28 Terminal value (Using EV/EBIDTA of 9) 210.58 Terminal value is calculated using the formula - Year 5 Cash flow*(1+Growth rate)/(ROE-Growth rate) Net working capital(6% of EBIT) 1.02 1.09 1.17 1.25 1.34 Capex(12% of EBIT) 2.04 2.18 2.34 2.50 2.67 Depreciation(5% of EBIT) 0.85 0.91 0.97 1.04 1.11 Profit before tax(EBIT-Depreciation) 16.15 17.28 18.49 19.78 231.75 Tax 5.65 6.05 6.47 6.92 81.11 PAT 10.50 11.23 12.02 12.86 150.64 Net cash flow 8.29 8.87 9.49 10.15 147.74 PV of Cash flows 99.41 Market value of debt 30 EV of Joe 129.41 Shares outstanding 2.3 Maximum share price 56.26 (EV/Shares outstanding).
a Happy Times Debt value 130 YTM 10.00 Mark.pdf
a Happy Times Debt value 130 YTM 10.00 Mark.pdf
aswrd
OH is a poor leaving group, so it first has toget hydrogenated (become OH2 +). Also, it is highly encumbered withthe 2,2 dimethyl group. Solution OH is a poor leaving group, so it first has toget hydrogenated (become OH2 +). Also, it is highly encumbered withthe 2,2 dimethyl group..
OH is a poor leaving group, so it first has toget.pdf
OH is a poor leaving group, so it first has toget.pdf
aswrd
Molarity = Moles/Volume = 2/2 =1 M Solution Molarity = Moles/Volume = 2/2 =1 M.
Molarity = MolesVolume = 22 =1 M .pdf
Molarity = MolesVolume = 22 =1 M .pdf
aswrd
Hydrophobic molecules tend to be non-polar and, thus, prefer other neutral molecules and non-polar solvents. Hydrophobic molecules in water often cluster Solution Hydrophobic molecules tend to be non-polar and, thus, prefer other neutral molecules and non-polar solvents. Hydrophobic molecules in water often cluster.
Hydrophobic molecules tend to be non-polar and, t.pdf
Hydrophobic molecules tend to be non-polar and, t.pdf
aswrd
There are two types of atomic bonds - ionic bonds and covalent bonds. They differ in their structure and properties. Covalent bonds consist of pairs of electrons shared by two atoms, and bind the atoms in a fixed orientation. Relatively high energies are required to break them (50 - 200 kcal/mol). Whether two atoms can form a covalent bond depends upon their electronegativity i.e. the power of an atom in a molecule to attract electrons to itself. If two atoms differ considerably in their electronegativity - as sodium and chloride do - then one of the atoms will lose its electron to the other atom. This results in a positively charged ion (cation) and negatively charged ion (anion). The bond between these two ions is called an ionic bond. Covalent BondsIonic Bonds Polarity:LowHigh Formation:A covalent bond is formed between two non-metals that have similar electronegativities. Neither atom is \"strong\" enough to attract electrons from the other. For stabilization, they share their electrons from outer molecular orbit with othersAn ionic bond is formed between a metal and a non-metal. Non-metals(-ve ion) are \"stronger\" than the metal(+ve ion) and can get electrons very easily from the metal. These two opposite ions attract each other and form the ionic bond. Shape:Definite shapeNo definite shape What is it?:Covalent bonding is a form of chemical bonding between two non metallic atoms which is characterized by the sharing of pairs of electrons between atoms and other covalent bonds.Ionic bond, also known as electrovalent bond is a type of bond formed from the electrostatic attraction between oppositely charged ions in a chemical compound. These kinds of bonds occur mainly between a metallic and a non metallic atom. Melting point:lowHigh Examples:Methane (CH4), Hydro Chloric acid (HCl)Sodium chloride (NaCl), Sulphuric Acid (H2SO4 ) Occurs between:Two non-metalsOne metal and one non-metal Boiling point:LowHigh State at room temperature:Liquid or gaseousSolid Ability to conduct electricity in molten/aqueous state: Yes Ability to conduct electricity in solid state: Solution There are two types of atomic bonds - ionic bonds and covalent bonds. They differ in their structure and properties. Covalent bonds consist of pairs of electrons shared by two atoms, and bind the atoms in a fixed orientation. Relatively high energies are required to break them (50 - 200 kcal/mol). Whether two atoms can form a covalent bond depends upon their electronegativity i.e. the power of an atom in a molecule to attract electrons to itself. If two atoms differ considerably in their electronegativity - as sodium and chloride do - then one of the atoms will lose its electron to the other atom. This results in a positively charged ion (cation) and negatively charged ion (anion). The bond between these two ions is called an ionic bond. Covalent BondsIonic Bonds Polarity:LowHigh Formation:A covalent bond is formed between two non-metals that have similar electronegativities. .
There are two types of atomic bonds - ionic bonds and covalent bonds.pdf
There are two types of atomic bonds - ionic bonds and covalent bonds.pdf
aswrd
T(n) = theta(nlog(2) n) T(n) = sqrt(2T(n/2) + C1 where n>1 so for n>1 T(n) = theta(nlog(2)n) Solution T(n) = theta(nlog(2) n) T(n) = sqrt(2T(n/2) + C1 where n>1 so for n>1 T(n) = theta(nlog(2)n).
T(n) = theta(nlog(2) n)T(n) = sqrt(2T(n2) + C1 where n1 so for.pdf
T(n) = theta(nlog(2) n)T(n) = sqrt(2T(n2) + C1 where n1 so for.pdf
aswrd
Showing a truth table that has the four motion sensors as inputs and an alarm trigger as the output when at least two motion sensors are activated at the same time. Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Solution Showing a truth table that has the four motion sensors as inputs and an alarm trigger as the output when at least two motion sensors are activated at the same time. Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T Sensor1 Sensor1 Sensor1 Sensor1 Output 1 F F F F F 2 F F F T F 3 F F T F F 4 F F T T T 5 F T F F F 6 F T F T T 7 F T T F T 8 F T T T T 9 T F F F F 10 T F F T T 11 T F T F T 12 T F T T T 13 T T F F T 14 T T F T T 15 T T T F T 16 T T T T T.
Showing a truth table that has the four motion sensors as inputs and.pdf
Showing a truth table that has the four motion sensors as inputs and.pdf
aswrd
Due to persence of two large R groups which produce steric hindence. Solution Due to persence of two large R groups which produce steric hindence..
Due to persence of two large R groups which produ.pdf
Due to persence of two large R groups which produ.pdf
aswrd
Probability of obtaining six =p= 1/5 Probability of not obtaining six=q=1- 1/5=4/5 number of throughs= n= 5 probability of obtaing at least one six =1-prbability of obtaing no six [=1-(4/5)^5] [=.67232] probability of obtaing exactly three six= [^5C_3(1/5)^3(4/5)^2] [=10xx(16/3125)=.0512] Note use binomial dstribution t calculate probability. Solution Probability of obtaining six =p= 1/5 Probability of not obtaining six=q=1- 1/5=4/5 number of throughs= n= 5 probability of obtaing at least one six =1-prbability of obtaing no six [=1-(4/5)^5] [=.67232] probability of obtaing exactly three six= [^5C_3(1/5)^3(4/5)^2] [=10xx(16/3125)=.0512] Note use binomial dstribution t calculate probability..
Probability of obtaining six =p= 15Probability of not obtaining s.pdf
Probability of obtaining six =p= 15Probability of not obtaining s.pdf
aswrd
Solution.
Solution.pdf
Solution.pdf
aswrd
Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced. Reaction 2 is also a redox reaction. In KClO3, Cl is in oxidation state Cl5+ and O is O2-. When it decomposes, Cl is reduced to Cl- while O is oxidized to O2. Reaction 3 is a neutralization reaction. An acid plus a base produces a salt plus water. Solution Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced. Reaction 2 is also a redox reaction. In KClO3, Cl is in oxidation state Cl5+ and O is O2-. When it decomposes, Cl is reduced to Cl- while O is oxidized to O2. Reaction 3 is a neutralization reaction. An acid plus a base produces a salt plus water..
Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced..pdf
Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced..pdf
aswrd
Natalie is suffering form a disease called Cystic fibrosis. It is an genetic condition in which the lungs and the digestive system become clogged with sticky mucus. Symptoms usually starts in early childhood. The main symptoms include: Advice: Solution Natalie is suffering form a disease called Cystic fibrosis. It is an genetic condition in which the lungs and the digestive system become clogged with sticky mucus. Symptoms usually starts in early childhood. The main symptoms include: Advice:.
Natalie is suffering form a disease called Cystic fibrosis. It is an.pdf
Natalie is suffering form a disease called Cystic fibrosis. It is an.pdf
aswrd
I am sorry i could not see the problem. Please post again. Solution I am sorry i could not see the problem. Please post again..
I am sorry i could not see the problem. Please post again.Solu.pdf
I am sorry i could not see the problem. Please post again.Solu.pdf
aswrd
b.false The alkanes are distinguished by having no functional group and being the most chemically inert (non-reactive) of all organic families. Solution b.false The alkanes are distinguished by having no functional group and being the most chemically inert (non-reactive) of all organic families..
b.false The alkanes are distinguished by having .pdf
b.false The alkanes are distinguished by having .pdf
aswrd
In terms of structure : A purine is a heterocyclic aromatic compound that consists of a pyrimidine ring fused to a imidazole ring.It consists of 2 carbon- nitrogen rings together with four nitrogen atoms whereas pyrimidine is a heterocyclic aromatic compound consisting of nitrogen atoms that are present on 1st and 3rd position of the ring.So,pyrimidine contains 1 carbon- nitrogen ring and two nitrogen atoms. In terms of molecular weight: Molecular weight of purine is 120.11 g/mol whereas molecular weight of pyrimidine is 80.088 g/mol. The pneumonic device that can be used to memorise which bases are purines vs pyrimidines are : for purine nucleotides : It can be remembered as Pure as gold or pure as AG.So,purines are Adenine and guanine. for pyrimidines:It can be remembered as cut the Py because it sound like pie. Also, pie has one ring and so does pyrimidine.So, pyrimidines are cytosine, uracil and thymine. Solution In terms of structure : A purine is a heterocyclic aromatic compound that consists of a pyrimidine ring fused to a imidazole ring.It consists of 2 carbon- nitrogen rings together with four nitrogen atoms whereas pyrimidine is a heterocyclic aromatic compound consisting of nitrogen atoms that are present on 1st and 3rd position of the ring.So,pyrimidine contains 1 carbon- nitrogen ring and two nitrogen atoms. In terms of molecular weight: Molecular weight of purine is 120.11 g/mol whereas molecular weight of pyrimidine is 80.088 g/mol. The pneumonic device that can be used to memorise which bases are purines vs pyrimidines are : for purine nucleotides : It can be remembered as Pure as gold or pure as AG.So,purines are Adenine and guanine. for pyrimidines:It can be remembered as cut the Py because it sound like pie. Also, pie has one ring and so does pyrimidine.So, pyrimidines are cytosine, uracil and thymine..
In terms of structure A purine is a heterocyclic aromatic compound.pdf
In terms of structure A purine is a heterocyclic aromatic compound.pdf
aswrd
In virtually every decision they make, executives today consider some kind of forecast. Sound predictions of demands and trends are no longer luxury items, but a necessity, if managers are to cope with seasonality, sudden changes in demand levels, price-cutting maneuvers of the competition, strikes, and large swings of the economy. Forecasting can help them deal with these troubles; but it can help them more, the more they know about the general principles of forecasting, what it can and cannot do for them currently, and which techniques are suited to their needs of the moment. Here the authors try to explain the potential of forecasting to managers, focusing special attention on sales forecasting for products of Corning Glass Works as these have matured through the product life cycle. Also included is a rundown of forecasting techniques. Strategic planning focuses largely on managing interaction with environmental forces, which include competitors, government, suppliers, customers, various interest groups and other factors that affect your business and its prospects. Your ability as a small business owner-manager to deal with these groups will vary widely depending on the group and on the timing. Also, you may be able to get more of what you want from a supplier than from a competitor (although size, distance, the percentage of the supplier\'s business you represent and your record of dependability as a customer can affect this relationship). How you manage these and other relationships is one of the decisions you will make during the strategic planning process. Because of major changes in the business environment, your familiarity with strategic planning and your ability to implement it is critical. At one time, business owner-managers assessed the environment on a continuum that ran between very stable and very unstable. Businesses, such as the producers of automobiles, furniture and other consumer goods, operated in a relatively stable and predictable world. This also was true of many service firms, such as banks and savings and loans. Typically, the environment included competition that was limited to a stable group of competitors, loyal customers and a relatively slow transfer of information. Many small businesses could thrive in this environment. Other small investors entered fields such as xerography, computers and computer component production, software design and chemical research. Some of these grew rapidly, becoming names with which we all are familiar: Xerox, IBM, Apple and Microsoft. But many more failed. Today, experts agree that more businesses face an unstable business environment. Improvements in information processing and telecommunications have made major changes in most industries. Along with this, improvements in transportation and the growth of foreign economies (specifically in Europe and Asia) have created a global marketplace and redefined certain industries. In addition, as consumers are exposed to more choices, loy.
In virtually every decision they make, executives today consider som.pdf
In virtually every decision they make, executives today consider som.pdf
aswrd
Heat released by 0.025 mol of H3PO4 = 525 J Heat released by 2 moles of H3PO4 = 2/0.025 x 525 = 42000 J Hrxn = - heat released by 2 moles of H3PO4 = -42000 J = -42 kJ Solution Heat released by 0.025 mol of H3PO4 = 525 J Heat released by 2 moles of H3PO4 = 2/0.025 x 525 = 42000 J Hrxn = - heat released by 2 moles of H3PO4 = -42000 J = -42 kJ.
Heat released by 0.025 mol of H3PO4 = 525 JHeat released by 2 mole.pdf
Heat released by 0.025 mol of H3PO4 = 525 JHeat released by 2 mole.pdf
aswrd
An Arrhenius acid is a substance that when added to water increases the concentration of H1+ ions. An Arrhenius base is is a substance that when added to water increases the concentration of OH1- ions. A Bronsted acid is a substance that can donate a hydrogen ion. A Bronsted base is a substance that can accept a hydrogen ion. A Lewis acid accepts lone pair electrons. A Lew base donates lone pair electrons. Solution An Arrhenius acid is a substance that when added to water increases the concentration of H1+ ions. An Arrhenius base is is a substance that when added to water increases the concentration of OH1- ions. A Bronsted acid is a substance that can donate a hydrogen ion. A Bronsted base is a substance that can accept a hydrogen ion. A Lewis acid accepts lone pair electrons. A Lew base donates lone pair electrons..
An Arrhenius acid is a substance that when added .pdf
An Arrhenius acid is a substance that when added .pdf
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Five broad principles guide AARP’s evaluation of tax options. Proposals to reform the tax code, stimulate the economy, raise additional revenue for any purpose, or modify specific tax provisions should take into account these principles. Equity—Revenue-raising methods should consider people’s ability to pay and should, to the extent possible, achieve vertical and horizontal equity. Taxation should be progressive, and people with comparable incomes should be taxed at comparable rates. Taxes may also be related to benefits derived from government services. Economic neutrality—Taxes should be as neutral as possible in their treatment of economic activity and should not unduly encourage behavior undertaken simply to avoid taxation. Often this can be achieved by a combination of a broad taxable base and a low tax rate. In addition taxes should not unduly hinder economic growth, induce inflation, or discourage savings. Taxes may be used to mitigate economic costs imposed on society that were not fully captured through market prices. Administrative efficiency—Taxes should be simple for taxpayers to understand and comply with, and as easy as possible to administer. The need to collect data on taxpayers and enforce tax laws should be balanced against the protection of individual liberties and privacy. Revenue—The tax system must produce sufficient revenue to pay for important national, state, and local priorities and maintain fiscal stability. Stable and reliable public policies and programs require adequate and consistent sources of revenue. Social and other policy goals—A balance must be struck between using the tax system to address social policy goals (through such measures as tax expenditures or earmarking revenue) and raising adequate revenues simply and equitably. Sometimes the above principles conflict with each other. In these cases AARP may weigh the relative importance of each of the key principles. AARP’s position on tax policies take into account the net fiscal impact of a given policy proposal, not only its tax component. Economic neutrality—Typically taxes create some inefficiencies by distorting economic choices and thus people’s behavior in the market. One major goal of most tax reform proposals is to reduce these distortions and encourage stronger economic growth. Proponents of consumption taxes note that income taxes encourage consumption over saving. Integrating the individual and corporate income taxes would reduce distortions that influence how businesses are organized and how income is transferred from corporations to shareholders. By eliminating certain tax deductions and other preferences, fundamental restructuring of the current income tax would also improve the neutrality and efficiency of the tax system. Administrative efficiency—The degree of administrative complexity depends greatly on the form of the tax. A VAT can have high administrative costs because it increases the number of taxpayers and requires detailed record ke.
Five broad principles guide AARP’s evaluation of tax options. Propos.pdf
Five broad principles guide AARP’s evaluation of tax options. Propos.pdf
aswrd
E(in ev) = 12400 / ( in Ao) E = 12400 / 5400 = 2.296 ev E= 2.296 * 1.6*10-19 J power = energy / time 15 = n E /t (n/t) = 15 /( 2.296 * 1.6 * 10-19) = 4.08 * 1019 Solution E(in ev) = 12400 / ( in Ao) E = 12400 / 5400 = 2.296 ev E= 2.296 * 1.6*10-19 J power = energy / time 15 = n E /t (n/t) = 15 /( 2.296 * 1.6 * 10-19) = 4.08 * 1019.
E(in ev) = 12400 ( in Ao) E = 12400 5400 = 2.296 ev E= 2.2.pdf
E(in ev) = 12400 ( in Ao) E = 12400 5400 = 2.296 ev E= 2.2.pdf
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cost = input(\"Enter the price of the dinner:) rating - input(\"Enter the rating of the dinner\") tip = 0.0 if int(rating) == 1: tip = 20.0 elif int(rating) == 2: tip = 15.0 elif int(rating) == 3: tip = 10.0 print float(cost)*(tip/100) Solution cost = input(\"Enter the price of the dinner:) rating - input(\"Enter the rating of the dinner\") tip = 0.0 if int(rating) == 1: tip = 20.0 elif int(rating) == 2: tip = 15.0 elif int(rating) == 3: tip = 10.0 print float(cost)*(tip/100).
cost = input(Enter the price of the dinner)rating - input(Ent.pdf
cost = input(Enter the price of the dinner)rating - input(Ent.pdf
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Conductance : Conductance is the ability of a material to pass electrons It is equal to reciprocal of the resistance. Conductance C = 1/ R where R is resistance of the cell Solution Conductance : Conductance is the ability of a material to pass electrons It is equal to reciprocal of the resistance. Conductance C = 1/ R where R is resistance of the cell.
Conductance Conductance is the ability of a material to pass ele.pdf
Conductance Conductance is the ability of a material to pass ele.pdf
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calcium chloride (CaCl2) is the ionic compound CO2 , CS2 , SO2 and OF2 are covalent compounds. Solution calcium chloride (CaCl2) is the ionic compound CO2 , CS2 , SO2 and OF2 are covalent compounds..
calcium chloride (CaCl2) is the ionic compoundCO2 , CS2 , SO2 and .pdf
calcium chloride (CaCl2) is the ionic compoundCO2 , CS2 , SO2 and .pdf
aswrd
A. are aromatic because Benzene and Aromaticity Unusual stability of benzene, heat of hydrogenation versus trienes Pi molecular orbitals of benzene Huckel’s rules: aromatic anions and cations, aromaticity of heterocycles Cyclobutadiene, benzene, and Frost’s circle Electrophilic aromatic substitution, mechanism and energy diagrams Br2, Br2/FeBr3, nitration, sulfonation of benzene Friedel-Crafts alkylation and acylation, problems encountered Electrophilic aromatic substitution Directing groups in detail, resonance versus inductive effects, steric control Changing ortho / para directors to meta directors Addition and removal of directing/blocking groups and retrosynthetic analyses of highly substituted benzenes Electrophilic aromatic substitution of polycyclic aromatic compounds: napthlene and phenanthrene Heterocycles Aliphatic heterocycles & reactivities: aziridines versus epoxides and thioranes, synthesis and acidic activation of aziridines Aromatic heterocycles: acid-base properties of pyridine, pyrimidine, pyrrole, imidazole, etc. Electrophilic aromatic substitution reactivity and regioselectivity of pyrrole, furan, benzene, pyridine, etc. Synthesis of pyrroles, furan, and thiophene from ?-dicarbonyl compounds Furan and thiophene in Diels-Alder chemistry Fischer indole synthesis, regioselectivity of indoles in electrophilic aromatic substitution Pyridine as a base, a nucleophile, and an acyl transfer catalyst (DMAP) Pyridine in nucleophilic aromatic substitution: Chichibabin reaction and addition of PhLi Synthesis of pyridines: Hantzsch condensation Synthesis of quinolines and isoquinolines from anilines Solution A. are aromatic because Benzene and Aromaticity Unusual stability of benzene, heat of hydrogenation versus trienes Pi molecular orbitals of benzene Huckel’s rules: aromatic anions and cations, aromaticity of heterocycles Cyclobutadiene, benzene, and Frost’s circle Electrophilic aromatic substitution, mechanism and energy diagrams Br2, Br2/FeBr3, nitration, sulfonation of benzene Friedel-Crafts alkylation and acylation, problems encountered Electrophilic aromatic substitution Directing groups in detail, resonance versus inductive effects, steric control Changing ortho / para directors to meta directors Addition and removal of directing/blocking groups and retrosynthetic analyses of highly substituted benzenes Electrophilic aromatic substitution of polycyclic aromatic compounds: napthlene and phenanthrene Heterocycles Aliphatic heterocycles & reactivities: aziridines versus epoxides and thioranes, synthesis and acidic activation of aziridines Aromatic heterocycles: acid-base properties of pyridine, pyrimidine, pyrrole, imidazole, etc. Electrophilic aromatic substitution reactivity and regioselectivity of pyrrole, furan, benzene, pyridine, etc. Synthesis of pyrroles, furan, and thiophene from ?-dicarbonyl compounds Furan and thiophene in Diels-Alder chemistry Fischer indole synthesis, regioselectivity of indoles in electrophilic aroma.
A. are aromatic because Benzene and Aromaticity.pdf
A. are aromatic because Benzene and Aromaticity.pdf
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ASR: ASR is an expansive form of reaction between silica in aggregates potassium and sodium alkalis mostly from cement but also from aggregates, pozzolons admixtures and mixing water. The reactivity is potentially harmful when it produces significant expansion. indication of presence of alkali aggregate reactivity may be a network of closed and spall joints. or movement of portion of structure.ASR can be controlled through a proper selection of aggregates. Sulphate attack: Excessive amount of sulphates in soil and water may attack concrete by reacting with hydrated compounds in hydrant cement paste. these reactions can induce sufficient pressure to disintegrate concrete. sulphate attck is more common where the concrete is subjected to both drying and wetting for the best defence against the external sulfate attack. DEF: Delayed Ettringite formation is a special form of sulfate internal attack it occurs in concrete which can be cured at delayed temperature for example where steam curing has been used. it was originally identified in steam cured concrete sleepers. It causes Expansion of concrete due to Etringite formation within the paste and can cause serious disintegration. DEF generally occurs when the Ettringite crystals exert an expansive force. the total amount of ettingite formed during hydration is decomposed. Freezing/ Thawing: The most potentially disrupting feature is freezing and thawing while concrete is wet particularly in presence id decieng chemicals the detoriation is caused by freezing of water and subsequent expansion of the paste during freezing water is displaced by ice formation in the paste so that is accomodated and that is not disruptive. Microscopic air bubbles form the space for water to enter and thus relieve the hydraulic pressure generated the concrete with low water cement ratio is durable the concret with high cementatious ratio air entrained concrete with low water cement ratio withstands great number of cycles to freezing and thawing. Corrosion: The concrete protects the embedded steel with its highly alkaline nature High PH Environment in concrete causes the highly passive & non corroding protective oxide film to form on steel. However the chlorides from sea water can destroy and penetrate the film once chloride corrosion threshhold is reached the an electric cell is formed along steel between steel bars and electro chemical process of carrions begins. Solution ASR: ASR is an expansive form of reaction between silica in aggregates potassium and sodium alkalis mostly from cement but also from aggregates, pozzolons admixtures and mixing water. The reactivity is potentially harmful when it produces significant expansion. indication of presence of alkali aggregate reactivity may be a network of closed and spall joints. or movement of portion of structure.ASR can be controlled through a proper selection of aggregates. Sulphate attack: Excessive amount of sulphates in soil and water may attack concrete by reacting w.
ASRASR is an expansive form of reaction between silica in aggrega.pdf
ASRASR is an expansive form of reaction between silica in aggrega.pdf
aswrd
Answer 1 : Basic Earning per share Basic Earning per share = BE/BS = 25700/ 10600 = 2.42 Working Notes BE = Income available for common stock holders Net Income 50000 Less: Intt on Bonds (100000*6.5%) 6500 ------------- EBT 43500 Less Tax paid @ 30% 13050 ---------------- Income after tax 30450 Less Dividend paid to Prefered stock holder 4750 ------------------ Amount Available common 25700 Stock holder ----------- BS = Weighted avaerage no. of common stock = Share at begining 9600 May, 1 Share issued 1200 weight 1200 *8/12 800 SeP, 30 Share issued 800 Weight 800*3/12 200 ------------ Total no. of shares 10600 ----------------- Answer - 2 Dialute Earning Per share = Net Income/Avg shares+other convertible instuments = (50000-1950)/15100 = 48050/15100 = 3.18 Working notes Avg Share = 10600 Prefered stock (1000*2) = 2000 Bonds (100000/1000*25) = 2500 -------------------------- Total shares = 15100 --------------------------- Incremental EPS of Preferred Stock = 4750/2000 = 4750/2000 = 2.38 Incremental EPS of Bonds = interest/ incremental no. of shares due to conversion of bonds = 6500-1950/2500 = 4550/2500 = 1.82 Answer 3 Incremental Earning per share Bonds = $ 1.82 Preferred = $ 2.38 Solution Answer 1 : Basic Earning per share Basic Earning per share = BE/BS = 25700/ 10600 = 2.42 Working Notes BE = Income available for common stock holders Net Income 50000 Less: Intt on Bonds (100000*6.5%) 6500 ------------- EBT 43500 Less Tax paid @ 30% 13050 ---------------- Income after tax 30450 Less Dividend paid to Prefered stock holder 4750 ------------------ Amount Available common 25700 Stock holder ----------- BS = Weighted avaerage no. of common stock = Share at begining 9600 May, 1 Share issued 1200 weight 1200 *8/12 800 SeP, 30 Share issued 800 Weight 800*3/12 200 ------------ Total no. of shares 10600 ----------------- Answer - 2 Dialute Earning Per share = Net Income/Avg shares+other convertible instuments = (50000-1950)/15100 = 48050/15100 = 3.18 Working notes Avg Share = 10600 Prefered stock (1000*2) = 2000 Bonds (100000/1000*25) = 2500 -------------------------- Total shares = 15100 --------------------------- Incremental EPS of Preferred Stock = 4750/2000 = 4750/2000 = 2.38 Incremental EPS of Bonds = interest/ incremental no. of shares due to conversion of bonds = 6500-1950/2500 = 4550/2500 = 1.82 Answer 3 Incremental Earning per share Bonds = $ 1.82 Preferred = $ 2.38.
Answer 1 Basic Earning per shareBasic Earning per share = BEBS.pdf
Answer 1 Basic Earning per shareBasic Earning per share = BEBS.pdf
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anl Solution anl.
anlSolutionanl.pdf
anlSolutionanl.pdf
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Due to persence of two large R groups which produce steric hindence. Solution Due to persence of two large R groups which produce steric hindence..
Due to persence of two large R groups which produ.pdf
Due to persence of two large R groups which produ.pdf
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Probability of obtaining six =p= 1/5 Probability of not obtaining six=q=1- 1/5=4/5 number of throughs= n= 5 probability of obtaing at least one six =1-prbability of obtaing no six [=1-(4/5)^5] [=.67232] probability of obtaing exactly three six= [^5C_3(1/5)^3(4/5)^2] [=10xx(16/3125)=.0512] Note use binomial dstribution t calculate probability. Solution Probability of obtaining six =p= 1/5 Probability of not obtaining six=q=1- 1/5=4/5 number of throughs= n= 5 probability of obtaing at least one six =1-prbability of obtaing no six [=1-(4/5)^5] [=.67232] probability of obtaing exactly three six= [^5C_3(1/5)^3(4/5)^2] [=10xx(16/3125)=.0512] Note use binomial dstribution t calculate probability..
Probability of obtaining six =p= 15Probability of not obtaining s.pdf
Probability of obtaining six =p= 15Probability of not obtaining s.pdf
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Solution.
Solution.pdf
Solution.pdf
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Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced. Reaction 2 is also a redox reaction. In KClO3, Cl is in oxidation state Cl5+ and O is O2-. When it decomposes, Cl is reduced to Cl- while O is oxidized to O2. Reaction 3 is a neutralization reaction. An acid plus a base produces a salt plus water. Solution Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced. Reaction 2 is also a redox reaction. In KClO3, Cl is in oxidation state Cl5+ and O is O2-. When it decomposes, Cl is reduced to Cl- while O is oxidized to O2. Reaction 3 is a neutralization reaction. An acid plus a base produces a salt plus water..
Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced..pdf
Reaction 1 is a redox reaction. Na is oxidized while Cl is reduced..pdf
aswrd
Natalie is suffering form a disease called Cystic fibrosis. It is an genetic condition in which the lungs and the digestive system become clogged with sticky mucus. Symptoms usually starts in early childhood. The main symptoms include: Advice: Solution Natalie is suffering form a disease called Cystic fibrosis. It is an genetic condition in which the lungs and the digestive system become clogged with sticky mucus. Symptoms usually starts in early childhood. The main symptoms include: Advice:.
Natalie is suffering form a disease called Cystic fibrosis. It is an.pdf
Natalie is suffering form a disease called Cystic fibrosis. It is an.pdf
aswrd
I am sorry i could not see the problem. Please post again. Solution I am sorry i could not see the problem. Please post again..
I am sorry i could not see the problem. Please post again.Solu.pdf
I am sorry i could not see the problem. Please post again.Solu.pdf
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b.false The alkanes are distinguished by having no functional group and being the most chemically inert (non-reactive) of all organic families. Solution b.false The alkanes are distinguished by having no functional group and being the most chemically inert (non-reactive) of all organic families..
b.false The alkanes are distinguished by having .pdf
b.false The alkanes are distinguished by having .pdf
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In terms of structure : A purine is a heterocyclic aromatic compound that consists of a pyrimidine ring fused to a imidazole ring.It consists of 2 carbon- nitrogen rings together with four nitrogen atoms whereas pyrimidine is a heterocyclic aromatic compound consisting of nitrogen atoms that are present on 1st and 3rd position of the ring.So,pyrimidine contains 1 carbon- nitrogen ring and two nitrogen atoms. In terms of molecular weight: Molecular weight of purine is 120.11 g/mol whereas molecular weight of pyrimidine is 80.088 g/mol. The pneumonic device that can be used to memorise which bases are purines vs pyrimidines are : for purine nucleotides : It can be remembered as Pure as gold or pure as AG.So,purines are Adenine and guanine. for pyrimidines:It can be remembered as cut the Py because it sound like pie. Also, pie has one ring and so does pyrimidine.So, pyrimidines are cytosine, uracil and thymine. Solution In terms of structure : A purine is a heterocyclic aromatic compound that consists of a pyrimidine ring fused to a imidazole ring.It consists of 2 carbon- nitrogen rings together with four nitrogen atoms whereas pyrimidine is a heterocyclic aromatic compound consisting of nitrogen atoms that are present on 1st and 3rd position of the ring.So,pyrimidine contains 1 carbon- nitrogen ring and two nitrogen atoms. In terms of molecular weight: Molecular weight of purine is 120.11 g/mol whereas molecular weight of pyrimidine is 80.088 g/mol. The pneumonic device that can be used to memorise which bases are purines vs pyrimidines are : for purine nucleotides : It can be remembered as Pure as gold or pure as AG.So,purines are Adenine and guanine. for pyrimidines:It can be remembered as cut the Py because it sound like pie. Also, pie has one ring and so does pyrimidine.So, pyrimidines are cytosine, uracil and thymine..
In terms of structure A purine is a heterocyclic aromatic compound.pdf
In terms of structure A purine is a heterocyclic aromatic compound.pdf
aswrd
In virtually every decision they make, executives today consider some kind of forecast. Sound predictions of demands and trends are no longer luxury items, but a necessity, if managers are to cope with seasonality, sudden changes in demand levels, price-cutting maneuvers of the competition, strikes, and large swings of the economy. Forecasting can help them deal with these troubles; but it can help them more, the more they know about the general principles of forecasting, what it can and cannot do for them currently, and which techniques are suited to their needs of the moment. Here the authors try to explain the potential of forecasting to managers, focusing special attention on sales forecasting for products of Corning Glass Works as these have matured through the product life cycle. Also included is a rundown of forecasting techniques. Strategic planning focuses largely on managing interaction with environmental forces, which include competitors, government, suppliers, customers, various interest groups and other factors that affect your business and its prospects. Your ability as a small business owner-manager to deal with these groups will vary widely depending on the group and on the timing. Also, you may be able to get more of what you want from a supplier than from a competitor (although size, distance, the percentage of the supplier\'s business you represent and your record of dependability as a customer can affect this relationship). How you manage these and other relationships is one of the decisions you will make during the strategic planning process. Because of major changes in the business environment, your familiarity with strategic planning and your ability to implement it is critical. At one time, business owner-managers assessed the environment on a continuum that ran between very stable and very unstable. Businesses, such as the producers of automobiles, furniture and other consumer goods, operated in a relatively stable and predictable world. This also was true of many service firms, such as banks and savings and loans. Typically, the environment included competition that was limited to a stable group of competitors, loyal customers and a relatively slow transfer of information. Many small businesses could thrive in this environment. Other small investors entered fields such as xerography, computers and computer component production, software design and chemical research. Some of these grew rapidly, becoming names with which we all are familiar: Xerox, IBM, Apple and Microsoft. But many more failed. Today, experts agree that more businesses face an unstable business environment. Improvements in information processing and telecommunications have made major changes in most industries. Along with this, improvements in transportation and the growth of foreign economies (specifically in Europe and Asia) have created a global marketplace and redefined certain industries. In addition, as consumers are exposed to more choices, loy.
In virtually every decision they make, executives today consider som.pdf
In virtually every decision they make, executives today consider som.pdf
aswrd
Heat released by 0.025 mol of H3PO4 = 525 J Heat released by 2 moles of H3PO4 = 2/0.025 x 525 = 42000 J Hrxn = - heat released by 2 moles of H3PO4 = -42000 J = -42 kJ Solution Heat released by 0.025 mol of H3PO4 = 525 J Heat released by 2 moles of H3PO4 = 2/0.025 x 525 = 42000 J Hrxn = - heat released by 2 moles of H3PO4 = -42000 J = -42 kJ.
Heat released by 0.025 mol of H3PO4 = 525 JHeat released by 2 mole.pdf
Heat released by 0.025 mol of H3PO4 = 525 JHeat released by 2 mole.pdf
aswrd
An Arrhenius acid is a substance that when added to water increases the concentration of H1+ ions. An Arrhenius base is is a substance that when added to water increases the concentration of OH1- ions. A Bronsted acid is a substance that can donate a hydrogen ion. A Bronsted base is a substance that can accept a hydrogen ion. A Lewis acid accepts lone pair electrons. A Lew base donates lone pair electrons. Solution An Arrhenius acid is a substance that when added to water increases the concentration of H1+ ions. An Arrhenius base is is a substance that when added to water increases the concentration of OH1- ions. A Bronsted acid is a substance that can donate a hydrogen ion. A Bronsted base is a substance that can accept a hydrogen ion. A Lewis acid accepts lone pair electrons. A Lew base donates lone pair electrons..
An Arrhenius acid is a substance that when added .pdf
An Arrhenius acid is a substance that when added .pdf
aswrd
Five broad principles guide AARP’s evaluation of tax options. Proposals to reform the tax code, stimulate the economy, raise additional revenue for any purpose, or modify specific tax provisions should take into account these principles. Equity—Revenue-raising methods should consider people’s ability to pay and should, to the extent possible, achieve vertical and horizontal equity. Taxation should be progressive, and people with comparable incomes should be taxed at comparable rates. Taxes may also be related to benefits derived from government services. Economic neutrality—Taxes should be as neutral as possible in their treatment of economic activity and should not unduly encourage behavior undertaken simply to avoid taxation. Often this can be achieved by a combination of a broad taxable base and a low tax rate. In addition taxes should not unduly hinder economic growth, induce inflation, or discourage savings. Taxes may be used to mitigate economic costs imposed on society that were not fully captured through market prices. Administrative efficiency—Taxes should be simple for taxpayers to understand and comply with, and as easy as possible to administer. The need to collect data on taxpayers and enforce tax laws should be balanced against the protection of individual liberties and privacy. Revenue—The tax system must produce sufficient revenue to pay for important national, state, and local priorities and maintain fiscal stability. Stable and reliable public policies and programs require adequate and consistent sources of revenue. Social and other policy goals—A balance must be struck between using the tax system to address social policy goals (through such measures as tax expenditures or earmarking revenue) and raising adequate revenues simply and equitably. Sometimes the above principles conflict with each other. In these cases AARP may weigh the relative importance of each of the key principles. AARP’s position on tax policies take into account the net fiscal impact of a given policy proposal, not only its tax component. Economic neutrality—Typically taxes create some inefficiencies by distorting economic choices and thus people’s behavior in the market. One major goal of most tax reform proposals is to reduce these distortions and encourage stronger economic growth. Proponents of consumption taxes note that income taxes encourage consumption over saving. Integrating the individual and corporate income taxes would reduce distortions that influence how businesses are organized and how income is transferred from corporations to shareholders. By eliminating certain tax deductions and other preferences, fundamental restructuring of the current income tax would also improve the neutrality and efficiency of the tax system. Administrative efficiency—The degree of administrative complexity depends greatly on the form of the tax. A VAT can have high administrative costs because it increases the number of taxpayers and requires detailed record ke.
Five broad principles guide AARP’s evaluation of tax options. Propos.pdf
Five broad principles guide AARP’s evaluation of tax options. Propos.pdf
aswrd
E(in ev) = 12400 / ( in Ao) E = 12400 / 5400 = 2.296 ev E= 2.296 * 1.6*10-19 J power = energy / time 15 = n E /t (n/t) = 15 /( 2.296 * 1.6 * 10-19) = 4.08 * 1019 Solution E(in ev) = 12400 / ( in Ao) E = 12400 / 5400 = 2.296 ev E= 2.296 * 1.6*10-19 J power = energy / time 15 = n E /t (n/t) = 15 /( 2.296 * 1.6 * 10-19) = 4.08 * 1019.
E(in ev) = 12400 ( in Ao) E = 12400 5400 = 2.296 ev E= 2.2.pdf
E(in ev) = 12400 ( in Ao) E = 12400 5400 = 2.296 ev E= 2.2.pdf
aswrd
cost = input(\"Enter the price of the dinner:) rating - input(\"Enter the rating of the dinner\") tip = 0.0 if int(rating) == 1: tip = 20.0 elif int(rating) == 2: tip = 15.0 elif int(rating) == 3: tip = 10.0 print float(cost)*(tip/100) Solution cost = input(\"Enter the price of the dinner:) rating - input(\"Enter the rating of the dinner\") tip = 0.0 if int(rating) == 1: tip = 20.0 elif int(rating) == 2: tip = 15.0 elif int(rating) == 3: tip = 10.0 print float(cost)*(tip/100).
cost = input(Enter the price of the dinner)rating - input(Ent.pdf
cost = input(Enter the price of the dinner)rating - input(Ent.pdf
aswrd
Conductance : Conductance is the ability of a material to pass electrons It is equal to reciprocal of the resistance. Conductance C = 1/ R where R is resistance of the cell Solution Conductance : Conductance is the ability of a material to pass electrons It is equal to reciprocal of the resistance. Conductance C = 1/ R where R is resistance of the cell.
Conductance Conductance is the ability of a material to pass ele.pdf
Conductance Conductance is the ability of a material to pass ele.pdf
aswrd
calcium chloride (CaCl2) is the ionic compound CO2 , CS2 , SO2 and OF2 are covalent compounds. Solution calcium chloride (CaCl2) is the ionic compound CO2 , CS2 , SO2 and OF2 are covalent compounds..
calcium chloride (CaCl2) is the ionic compoundCO2 , CS2 , SO2 and .pdf
calcium chloride (CaCl2) is the ionic compoundCO2 , CS2 , SO2 and .pdf
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A. are aromatic because Benzene and Aromaticity Unusual stability of benzene, heat of hydrogenation versus trienes Pi molecular orbitals of benzene Huckel’s rules: aromatic anions and cations, aromaticity of heterocycles Cyclobutadiene, benzene, and Frost’s circle Electrophilic aromatic substitution, mechanism and energy diagrams Br2, Br2/FeBr3, nitration, sulfonation of benzene Friedel-Crafts alkylation and acylation, problems encountered Electrophilic aromatic substitution Directing groups in detail, resonance versus inductive effects, steric control Changing ortho / para directors to meta directors Addition and removal of directing/blocking groups and retrosynthetic analyses of highly substituted benzenes Electrophilic aromatic substitution of polycyclic aromatic compounds: napthlene and phenanthrene Heterocycles Aliphatic heterocycles & reactivities: aziridines versus epoxides and thioranes, synthesis and acidic activation of aziridines Aromatic heterocycles: acid-base properties of pyridine, pyrimidine, pyrrole, imidazole, etc. Electrophilic aromatic substitution reactivity and regioselectivity of pyrrole, furan, benzene, pyridine, etc. Synthesis of pyrroles, furan, and thiophene from ?-dicarbonyl compounds Furan and thiophene in Diels-Alder chemistry Fischer indole synthesis, regioselectivity of indoles in electrophilic aromatic substitution Pyridine as a base, a nucleophile, and an acyl transfer catalyst (DMAP) Pyridine in nucleophilic aromatic substitution: Chichibabin reaction and addition of PhLi Synthesis of pyridines: Hantzsch condensation Synthesis of quinolines and isoquinolines from anilines Solution A. are aromatic because Benzene and Aromaticity Unusual stability of benzene, heat of hydrogenation versus trienes Pi molecular orbitals of benzene Huckel’s rules: aromatic anions and cations, aromaticity of heterocycles Cyclobutadiene, benzene, and Frost’s circle Electrophilic aromatic substitution, mechanism and energy diagrams Br2, Br2/FeBr3, nitration, sulfonation of benzene Friedel-Crafts alkylation and acylation, problems encountered Electrophilic aromatic substitution Directing groups in detail, resonance versus inductive effects, steric control Changing ortho / para directors to meta directors Addition and removal of directing/blocking groups and retrosynthetic analyses of highly substituted benzenes Electrophilic aromatic substitution of polycyclic aromatic compounds: napthlene and phenanthrene Heterocycles Aliphatic heterocycles & reactivities: aziridines versus epoxides and thioranes, synthesis and acidic activation of aziridines Aromatic heterocycles: acid-base properties of pyridine, pyrimidine, pyrrole, imidazole, etc. Electrophilic aromatic substitution reactivity and regioselectivity of pyrrole, furan, benzene, pyridine, etc. Synthesis of pyrroles, furan, and thiophene from ?-dicarbonyl compounds Furan and thiophene in Diels-Alder chemistry Fischer indole synthesis, regioselectivity of indoles in electrophilic aroma.
A. are aromatic because Benzene and Aromaticity.pdf
A. are aromatic because Benzene and Aromaticity.pdf
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ASR: ASR is an expansive form of reaction between silica in aggregates potassium and sodium alkalis mostly from cement but also from aggregates, pozzolons admixtures and mixing water. The reactivity is potentially harmful when it produces significant expansion. indication of presence of alkali aggregate reactivity may be a network of closed and spall joints. or movement of portion of structure.ASR can be controlled through a proper selection of aggregates. Sulphate attack: Excessive amount of sulphates in soil and water may attack concrete by reacting with hydrated compounds in hydrant cement paste. these reactions can induce sufficient pressure to disintegrate concrete. sulphate attck is more common where the concrete is subjected to both drying and wetting for the best defence against the external sulfate attack. DEF: Delayed Ettringite formation is a special form of sulfate internal attack it occurs in concrete which can be cured at delayed temperature for example where steam curing has been used. it was originally identified in steam cured concrete sleepers. It causes Expansion of concrete due to Etringite formation within the paste and can cause serious disintegration. DEF generally occurs when the Ettringite crystals exert an expansive force. the total amount of ettingite formed during hydration is decomposed. Freezing/ Thawing: The most potentially disrupting feature is freezing and thawing while concrete is wet particularly in presence id decieng chemicals the detoriation is caused by freezing of water and subsequent expansion of the paste during freezing water is displaced by ice formation in the paste so that is accomodated and that is not disruptive. Microscopic air bubbles form the space for water to enter and thus relieve the hydraulic pressure generated the concrete with low water cement ratio is durable the concret with high cementatious ratio air entrained concrete with low water cement ratio withstands great number of cycles to freezing and thawing. Corrosion: The concrete protects the embedded steel with its highly alkaline nature High PH Environment in concrete causes the highly passive & non corroding protective oxide film to form on steel. However the chlorides from sea water can destroy and penetrate the film once chloride corrosion threshhold is reached the an electric cell is formed along steel between steel bars and electro chemical process of carrions begins. Solution ASR: ASR is an expansive form of reaction between silica in aggregates potassium and sodium alkalis mostly from cement but also from aggregates, pozzolons admixtures and mixing water. The reactivity is potentially harmful when it produces significant expansion. indication of presence of alkali aggregate reactivity may be a network of closed and spall joints. or movement of portion of structure.ASR can be controlled through a proper selection of aggregates. Sulphate attack: Excessive amount of sulphates in soil and water may attack concrete by reacting w.
ASRASR is an expansive form of reaction between silica in aggrega.pdf
ASRASR is an expansive form of reaction between silica in aggrega.pdf
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Answer 1 : Basic Earning per share Basic Earning per share = BE/BS = 25700/ 10600 = 2.42 Working Notes BE = Income available for common stock holders Net Income 50000 Less: Intt on Bonds (100000*6.5%) 6500 ------------- EBT 43500 Less Tax paid @ 30% 13050 ---------------- Income after tax 30450 Less Dividend paid to Prefered stock holder 4750 ------------------ Amount Available common 25700 Stock holder ----------- BS = Weighted avaerage no. of common stock = Share at begining 9600 May, 1 Share issued 1200 weight 1200 *8/12 800 SeP, 30 Share issued 800 Weight 800*3/12 200 ------------ Total no. of shares 10600 ----------------- Answer - 2 Dialute Earning Per share = Net Income/Avg shares+other convertible instuments = (50000-1950)/15100 = 48050/15100 = 3.18 Working notes Avg Share = 10600 Prefered stock (1000*2) = 2000 Bonds (100000/1000*25) = 2500 -------------------------- Total shares = 15100 --------------------------- Incremental EPS of Preferred Stock = 4750/2000 = 4750/2000 = 2.38 Incremental EPS of Bonds = interest/ incremental no. of shares due to conversion of bonds = 6500-1950/2500 = 4550/2500 = 1.82 Answer 3 Incremental Earning per share Bonds = $ 1.82 Preferred = $ 2.38 Solution Answer 1 : Basic Earning per share Basic Earning per share = BE/BS = 25700/ 10600 = 2.42 Working Notes BE = Income available for common stock holders Net Income 50000 Less: Intt on Bonds (100000*6.5%) 6500 ------------- EBT 43500 Less Tax paid @ 30% 13050 ---------------- Income after tax 30450 Less Dividend paid to Prefered stock holder 4750 ------------------ Amount Available common 25700 Stock holder ----------- BS = Weighted avaerage no. of common stock = Share at begining 9600 May, 1 Share issued 1200 weight 1200 *8/12 800 SeP, 30 Share issued 800 Weight 800*3/12 200 ------------ Total no. of shares 10600 ----------------- Answer - 2 Dialute Earning Per share = Net Income/Avg shares+other convertible instuments = (50000-1950)/15100 = 48050/15100 = 3.18 Working notes Avg Share = 10600 Prefered stock (1000*2) = 2000 Bonds (100000/1000*25) = 2500 -------------------------- Total shares = 15100 --------------------------- Incremental EPS of Preferred Stock = 4750/2000 = 4750/2000 = 2.38 Incremental EPS of Bonds = interest/ incremental no. of shares due to conversion of bonds = 6500-1950/2500 = 4550/2500 = 1.82 Answer 3 Incremental Earning per share Bonds = $ 1.82 Preferred = $ 2.38.
Answer 1 Basic Earning per shareBasic Earning per share = BEBS.pdf
Answer 1 Basic Earning per shareBasic Earning per share = BEBS.pdf
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