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a)40 b)28 c)58 Solution a)40 b)28 c)58.

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8886781233 17368915236 #include #include int main() { int i, n, *data , p; /* get the number of inputs from the user */ printf(\"Enter the number of inputs:\"); scanf(\"%d\", &n); /* dynamically allocate memory to store i/p values */ data = (int *) malloc(sizeof(int) * n); /* get the input data from the user */ for (i = 0; i < n; i++) { printf(\"data[%d]: \", i); scanf(\"%d\", &data[i]); } /* sorts the given numbers */ bubbleSort(data, n ,p ); } void bubbleSort(int *data, int n , int p) { int i, temp, k = 1, l,j; if (n > 0) { for (i = n; i > 0; i--) { if (data[i] > data[i - 1]) { temp = data[i]; data[i] = data[i - 1]; data[i - 1] = temp; } if( p = = 0) { p++; l = n; for ( i = 0 ; i < n ; i++) { prinft ( %d, data[i]) } bubbleSort(data, i - 2 , p ); } else { for ( j = n - 1 ; j < l ; j++) { if (data[j] > data[j - 1]) { temp = data[j]; data[j] = data[j - 1]; data[j - 1] = temp; } } for ( j = 0 ; j < l ; j++) { prinft ( %d, data[j]) } bubbleSort(data, i - 2,p); } } } return; } Solution 8886781233 17368915236 #include #include int main() { int i, n, *data , p; /* get the number of inputs from the user */ printf(\"Enter the number of inputs:\"); scanf(\"%d\", &n); /* dynamically allocate memory to store i/p values */ data = (int *) malloc(sizeof(int) * n); /* get the input data from the user */ for (i = 0; i < n; i++) { printf(\"data[%d]: \", i); scanf(\"%d\", &data[i]); } /* sorts the given numbers */ bubbleSort(data, n ,p ); } void bubbleSort(int *data, int n , int p) { int i, temp, k = 1, l,j; if (n > 0) { for (i = n; i > 0; i--) { if (data[i] > data[i - 1]) { temp = data[i]; data[i] = data[i - 1]; data[i - 1] = temp; } if( p = = 0) { p++; l = n; for ( i = 0 ; i < n ; i++) { prinft ( %d, data[i]) } bubbleSort(data, i - 2 , p ); } else { for ( j = n - 1 ; j < l ; j++) { if (data[j] > data[j - 1]) { temp = data[j]; data[j] = data[j - 1]; data[j - 1] = temp; } } for ( j = 0 ; j < l ; j++) { prinft ( %d, data[j]) } bubbleSort(data, i - 2,p); } } } return; }.

888678123317368915236 #include stdio.h #include stdlib.h.pdf

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18) One device is attached to a physical interface The switch can be remotely managed The default VIan has been configured 19) Flow control 20) Encapsulation 21) HTTP,TCP,IP,Ethernet 22) They define how messages are exchanged between the source and the destination Solution 18) One device is attached to a physical interface The switch can be remotely managed The default VIan has been configured 19) Flow control 20) Encapsulation 21) HTTP,TCP,IP,Ethernet 22) They define how messages are exchanged between the source and the destination.

18) One device is attached to a physical interface The switch c.pdf

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1.Joseph could not restrain himself before all those who stood by him, and he cried out, “Make everyone go out from me!” So no one stood with him while Joseph made himself known to his brothers. And he wept aloud, and the Egyptians and the house of Pharaoh heard it. Then Joseph said to his brothers, “I am Joseph; does my father still live?” But his brothers could not answer him, for they were dismayed in his presence. a. Joseph could not restrain himself before all those who stood by him: Joseph ordered all the Egyptians out of the room and was then alone with his brothers. His great emotion showed that Joseph did not cruelly manipulate his brothers. He was directed by God to make these arrangements and it hurt him to do it. b. Joseph made himself known to his brothers: This perhaps means that Joseph told them he was Joseph and showed his brothers that he was circumcised. Jewish legend says the brothers could never believe this high Egyptian official was Joseph unless he showed he was circumcised. c. But his brothers could not answer him, for they were dismayed in his presence: Because of the punishment they anticipated, the great emotion of Joseph, his manner of revelation, and the total shock of learning Joseph was not only alive but right in front of them, the brothers were dismayed. Pharaoh and Joseph send the brothers home with many gifts. Joseph gave them carts, according to the command of Pharaoh, and he gave them provisions for the journey: The sons of Israel received transportation, provision, garments, and riches because of who their favored brother was. Pharaoh blessed the sons of Jacob for Joseph’s sake. i. “To return to Canaan with ‘carts from Egypt’ was the cultural equivalent of landing a jumbo jet among a tribe of isolated savages. It would be the stuff legends are made of.” (Boice) b. See that you do not become troubled along the way: The idea behind the words “become troubled” is literally become angry or quarrel. Joseph knew as soon as these men left his presence they would be tempted to act in selfish, unspiritual ways. They had to anticipate and guard against this. Jacob hears the good news – that Joseph lives. Then they went up out of Egypt, and came to the land of Canaan to Jacob their father. And they told him, saying, “Joseph is still alive, and he is governor over all the land of Egypt.” And Jacob’s heart stood still, because he did not believe them. But when they told him all the words which Joseph had said to them, and when he saw the carts which Joseph had sent to carry him, the spirit of Jacob their father revived. Then Israel said, “It is enough. Joseph my son is still alive. I will go and see him before I die.” a. He did not believe them: Jacob was told Joseph was dead and believed it. Then he was told Joseph was alive, and he did not believe it until his sons told him the words of Joseph and showed him the blessings that came to them through Joseph. Then he believed Joseph was alive, though he had not yet seen.

1.Joseph could not restrain himself before all those who stood by hi.pdf

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(a) Total amount of I2 = 50/1000 x 0.010 = 0.0005 mol = 0.5 mmol Let a be the number of millimoles of I2 extracted Millimoles of I2 left in aqueous phase = 0.5 - a Distribution coefficient D = [I2](organic)/[I2](aqueous) = [(mmol of I2)(organic)/V(organic)]/[mmol of I2)(aqueous)/V(aqueous)] = [(a/50)]/[(0.5 - a)/50] = 85 a/(0.5 - a) = 85 a = 0.4942 mmol Thus amount of I2 extracted = 0.4942 mmol (b) Amount of I2 left in aqueous phase = 0.5 - 0.4942 = 0.0058 mmol = 5.8 x 10-6 mol Concentration of I2 in aqueous phase = moles/volume (in L) = 5.8 x 10-6/0.050 = 1.16 x 10-4 M Solution (a) Total amount of I2 = 50/1000 x 0.010 = 0.0005 mol = 0.5 mmol Let a be the number of millimoles of I2 extracted Millimoles of I2 left in aqueous phase = 0.5 - a Distribution coefficient D = [I2](organic)/[I2](aqueous) = [(mmol of I2)(organic)/V(organic)]/[mmol of I2)(aqueous)/V(aqueous)] = [(a/50)]/[(0.5 - a)/50] = 85 a/(0.5 - a) = 85 a = 0.4942 mmol Thus amount of I2 extracted = 0.4942 mmol (b) Amount of I2 left in aqueous phase = 0.5 - 0.4942 = 0.0058 mmol = 5.8 x 10-6 mol Concentration of I2 in aqueous phase = moles/volume (in L) = 5.8 x 10-6/0.050 = 1.16 x 10-4 M.

(a) Total amount of I2 = 501000 x 0.010 = 0.0005 mol = 0.5 mmolLe.pdf

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Nursing is a healthcare profession in which they serve the patients and ought to have medical knowledge. Nurses generally are more in contact with the patients and have knowledge of patient\'s relatives, behaviour, experience in dealing with patients, communication skills. They are the most important connection link between the doctors and the patient. Nurses also have knowledge about the medical cases, projects related to community and cultural awareness.Hence, they form integral part of the medical system. In genetic testing, various people from higher to lower classes, different caste and creed come for checkup. The nurses are supposed to inform and consult the patients about the necessities of genetic testing. The informed consent is necessary to be obtained by explaining the importance of genetic testing. Also, the ethical issues are to be followed by each and every medical institution. Since the public has trust in nurses, they are supposed to convince the patients about the genetic testing advantages. They help the people to understand the basics of genetic testing and the cons of it if not performed before the delivery. Some set of population think that carrying out these tests are against the will of nature or sometimes economical issues arise due to higher charges of these tests. Hence it is necessary to make people aware of their misconceptions and provide them good medical facilities. Solution Nursing is a healthcare profession in which they serve the patients and ought to have medical knowledge. Nurses generally are more in contact with the patients and have knowledge of patient\'s relatives, behaviour, experience in dealing with patients, communication skills. They are the most important connection link between the doctors and the patient. Nurses also have knowledge about the medical cases, projects related to community and cultural awareness.Hence, they form integral part of the medical system. In genetic testing, various people from higher to lower classes, different caste and creed come for checkup. The nurses are supposed to inform and consult the patients about the necessities of genetic testing. The informed consent is necessary to be obtained by explaining the importance of genetic testing. Also, the ethical issues are to be followed by each and every medical institution. Since the public has trust in nurses, they are supposed to convince the patients about the genetic testing advantages. They help the people to understand the basics of genetic testing and the cons of it if not performed before the delivery. Some set of population think that carrying out these tests are against the will of nature or sometimes economical issues arise due to higher charges of these tests. Hence it is necessary to make people aware of their misconceptions and provide them good medical facilities..

Nursing is a healthcare profession in which they serve the patients .pdf

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yes.because the deposted money can be multiply with 10 and it beco.pdf

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When the substituent groups are oriented in the same direction, the diastereomer is referred to as cis, whereas, when the substituents are oriented in opposing directions, the diastereomer is referred to as trans. An example of a small hydrocarbon displaying cis/trans isomerism is 2-butene. Alicyclic compounds can also display cis/trans isomerism. As an example of a geometric isomer due to a ring structure, consider 1,2-dichlorocyclohexane: is/trans isomerism (also known as geometric isomerism, configuration isomerism, or E/Z isomerism) is a form of stereoisomerism describing the orientation of functional groups within a molecule. In general, such isomers contain double bonds, which cannot rotate, but they can also arise from ring structures, wherein the rotation of bonds is greatly restricted. Cis and trans isomers occur both in organic molecules and in inorganic coordination complexes. The terms cis and trans are from Latin, in which cis means \"on the same side\" and trans means \"on the other side\" or \"across\". The term \"geometric isomerism\" is considered an obsolete synonym of \"cis/trans isomerism\" by IUPAC.[1] It is sometimes used as a synonym for general stereoisomerism (e.g., optical isomerism being called geometric isomerism); the correct term for non-optical stereoisomerism is diastereomerism. Solution When the substituent groups are oriented in the same direction, the diastereomer is referred to as cis, whereas, when the substituents are oriented in opposing directions, the diastereomer is referred to as trans. An example of a small hydrocarbon displaying cis/trans isomerism is 2-butene. Alicyclic compounds can also display cis/trans isomerism. As an example of a geometric isomer due to a ring structure, consider 1,2-dichlorocyclohexane: is/trans isomerism (also known as geometric isomerism, configuration isomerism, or E/Z isomerism) is a form of stereoisomerism describing the orientation of functional groups within a molecule. In general, such isomers contain double bonds, which cannot rotate, but they can also arise from ring structures, wherein the rotation of bonds is greatly restricted. Cis and trans isomers occur both in organic molecules and in inorganic coordination complexes. The terms cis and trans are from Latin, in which cis means \"on the same side\" and trans means \"on the other side\" or \"across\". The term \"geometric isomerism\" is considered an obsolete synonym of \"cis/trans isomerism\" by IUPAC.[1] It is sometimes used as a synonym for general stereoisomerism (e.g., optical isomerism being called geometric isomerism); the correct term for non-optical stereoisomerism is diastereomerism..

When the substituent groups are oriented in the s.pdf

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using System; public category take a look at one.00m; Console.WriteLine (d); } } When I initial ran the on top of (or one thing similar) I expected it to output simply one (which is what it might are on .NET 1.0) - however in reality, the output was one.00. The decimal sort does not normalize itself - it remembers what percentage decimal digits it\'s (by maintaining the exponent wherever possible) and on info, zero could also be counted as a major digit. i do not understand the precise nature of what exponent is chosen (where there\'s a choice) once 2 totally different decimals ar increased, divided, added etc, however you will realize it attention-grabbing to manipulate with programs like the following: using System; public category take a look at zero.00000000000010000m; whereas (d != 0m) } } Solution using System; public category take a look at one.00m; Console.WriteLine (d); } } When I initial ran the on top of (or one thing similar) I expected it to output simply one (which is what it might are on .NET 1.0) - however in reality, the output was one.00. The decimal sort does not normalize itself - it remembers what percentage decimal digits it\'s (by maintaining the exponent wherever possible) and on info, zero could also be counted as a major digit. i do not understand the precise nature of what exponent is chosen (where there\'s a choice) once 2 totally different decimals ar increased, divided, added etc, however you will realize it attention-grabbing to manipulate with programs like the following: using System; public category take a look at zero.00000000000010000m; whereas (d != 0m) } }.

using System;public category take a look at one.00m; Console.W.pdf

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Tunnel through the IPv4:- ->Internet traffic is expected to be carried via tunnels as the Internet infrastructure migrates from IPv4, the current version of the Internet protocol, to the long-anticipated upgrade known as IPv6. ->IPv4 uses 32-bit addresses and can support 4.3 billion devices connected directly to the Internet. ->Internet:-Will probably move to IPv6 “from the edges in” -> IPv6 will be adopted:-First by smaller organizations with greater flexibility and higher tolerance for difficulties of pioneering -> IPv6 packet is formed normally:- Sent to a router capable of encapsulating it in an IPv4 packet. ->Used to allow IPv6 network nodes to send packets over an IPv4 network infrastructure ->Presents a challenge for IPv6 header construction -> Source node determines which packets must be encapsulated ->Based on the routing information the node maintains in its own routing table. Types of Tunnels:- 1)RFC 2893 originally specified two different tunneling types –Configured and automatic 2)RFC 4213, which made RFC 2893 obsolete – Removed references to automatic tunneling 3)Configured tunnels –Require that end point addresses be determined in the encapsulator device 4) From configuration data stored for each tunnel. Solution Tunnel through the IPv4:- ->Internet traffic is expected to be carried via tunnels as the Internet infrastructure migrates from IPv4, the current version of the Internet protocol, to the long-anticipated upgrade known as IPv6. ->IPv4 uses 32-bit addresses and can support 4.3 billion devices connected directly to the Internet. ->Internet:-Will probably move to IPv6 “from the edges in” -> IPv6 will be adopted:-First by smaller organizations with greater flexibility and higher tolerance for difficulties of pioneering -> IPv6 packet is formed normally:- Sent to a router capable of encapsulating it in an IPv4 packet. ->Used to allow IPv6 network nodes to send packets over an IPv4 network infrastructure ->Presents a challenge for IPv6 header construction -> Source node determines which packets must be encapsulated ->Based on the routing information the node maintains in its own routing table. Types of Tunnels:- 1)RFC 2893 originally specified two different tunneling types –Configured and automatic 2)RFC 4213, which made RFC 2893 obsolete – Removed references to automatic tunneling 3)Configured tunnels –Require that end point addresses be determined in the encapsulator device 4) From configuration data stored for each tunnel..

Tunnel through the IPv4--Internet traffic is expected to be carr.pdf

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The sum is 250.SolutionThe sum is 250..pdf

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The key activity areas for securities firms are : i. Investing: Security firms act as agents for investors and provide risk diversification and liquidity services to holders of mutual funds. The major risks are underperforming stock market whereby investors flee to other avenues of investing. ii. Investment Banking: These functions relate to underwriting both debt and equity. The major risk is unsold securities and money on the table due to ineffective pricing. iii. Market Making: Market making involves the creation of a secondary market in an asset by a securities firm or investment bank facilitating the smooth transactions of trading in the market. In case of a crash this can lead to unsold securities and selling at a significant discount thus losing a lot. iv. Trading: Securities trader takes an active net position in an underlying instrument or asset. The risk are snall bid ask spread and high fluctuating prices leading to loss on trading positions v. Cash Management: Security firms bank deposit-like cash management accounts to individual investors. Again the proper pricing is needed else there may be a significant loss on the position. vi. Mergers and Acquisitions: Investment banks provide advice on mergers and acquisitions. The risk are improper pricing leading to loss or not realizing proper synergies vi. Other Service Functions: include custody and escrow services, clearance and settlement services and research and advisory services. They may result in losses if there is a credit risk present which usually is common. Solution The key activity areas for securities firms are : i. Investing: Security firms act as agents for investors and provide risk diversification and liquidity services to holders of mutual funds. The major risks are underperforming stock market whereby investors flee to other avenues of investing. ii. Investment Banking: These functions relate to underwriting both debt and equity. The major risk is unsold securities and money on the table due to ineffective pricing. iii. Market Making: Market making involves the creation of a secondary market in an asset by a securities firm or investment bank facilitating the smooth transactions of trading in the market. In case of a crash this can lead to unsold securities and selling at a significant discount thus losing a lot. iv. Trading: Securities trader takes an active net position in an underlying instrument or asset. The risk are snall bid ask spread and high fluctuating prices leading to loss on trading positions v. Cash Management: Security firms bank deposit-like cash management accounts to individual investors. Again the proper pricing is needed else there may be a significant loss on the position. vi. Mergers and Acquisitions: Investment banks provide advice on mergers and acquisitions. The risk are improper pricing leading to loss or not realizing proper synergies vi. Other Service Functions: include custody and escrow services, clearance and settlement services and re.

The key activity areas for securities firms are i. Investing Se.pdf

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The finger like projections of intestine known as villi increases surface area of small intestines. The surface of small intestine is lined up with epithelial cells containing brush borders or microvilli that help to absorb nutrients into the blood or lymph, which later moves to the body cells. Due to the presence of specialized proteins within the microvilli known as porters, the nutrients move into the cells. Human gut flora contains several types of bacterial species in the small intestines that are involved in the production of vitamin K, B as well as metabolism of bile acid and xenobiotics. So, correct option is d.transferring nutrients across intestinal membranes Solution The finger like projections of intestine known as villi increases surface area of small intestines. The surface of small intestine is lined up with epithelial cells containing brush borders or microvilli that help to absorb nutrients into the blood or lymph, which later moves to the body cells. Due to the presence of specialized proteins within the microvilli known as porters, the nutrients move into the cells. Human gut flora contains several types of bacterial species in the small intestines that are involved in the production of vitamin K, B as well as metabolism of bile acid and xenobiotics. So, correct option is d.transferring nutrients across intestinal membranes.

The finger like projections of intestine known as villi increases su.pdf

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The answer isC. 12In establishing paternity by dna fingerprintin.pdf

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Technically, micro RNA or miRNA are defined as small non-coding (translationally inactive) RNA molecules which have a major role in expression of other genes by the means of gene- silencing or post-transcriptional modifications. The miRNA are found in a variety of organisms including eukaryotes, plants, viruses and humans. Functionally, the miRNAs are actively engaged in modulating gene expression in organisms. The major functions of miRNAs can be discussed as below: 1. Gene/RNA silencing: The function of gene silencing using miRNAs can be brought about at both transcriptional or post-transcriptional levels. The miRNA can either cleave the newly synthesized mRNA strand into two or more smaller units or prevent its access to the translatinal machinery by blocking the nucleotides by binding to it. 2. Post-trancriptional regulation of mRNA: This function of miRNA is very unique and important in nature. The miRNA are actively engaged in removing the 3\' polyadenylation cap of the untranslated region of the mRNA which deteriorates the structural stability of the nascent mRNA molecule. This prevents structural stabilization of the newly synthesized mRNA molecule from destruction and also impairs the post-transcriptional modification by the ubiquitination protein assembly. Binding of miRNA to the mRNA at specific sites also makes it prone to cleavage and thus prevents the appropriate post-transcriptional modifications. Thus, the major fucntions of miRNA remains in regulation of gene expression/silencing and modulating post-transcriptional modifications. Owing to these crucial moleular features, miRNAs are actively being used in pre-clinical research as potential therapeutics. Solution Technically, micro RNA or miRNA are defined as small non-coding (translationally inactive) RNA molecules which have a major role in expression of other genes by the means of gene- silencing or post-transcriptional modifications. The miRNA are found in a variety of organisms including eukaryotes, plants, viruses and humans. Functionally, the miRNAs are actively engaged in modulating gene expression in organisms. The major functions of miRNAs can be discussed as below: 1. Gene/RNA silencing: The function of gene silencing using miRNAs can be brought about at both transcriptional or post-transcriptional levels. The miRNA can either cleave the newly synthesized mRNA strand into two or more smaller units or prevent its access to the translatinal machinery by blocking the nucleotides by binding to it. 2. Post-trancriptional regulation of mRNA: This function of miRNA is very unique and important in nature. The miRNA are actively engaged in removing the 3\' polyadenylation cap of the untranslated region of the mRNA which deteriorates the structural stability of the nascent mRNA molecule. This prevents structural stabilization of the newly synthesized mRNA molecule from destruction and also impairs the post-transcriptional modification by the ubiquitination protein assembly. Bi.

Technically, micro RNA or miRNA are defined as small non-coding (tra.pdf

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The activation of macrophages by the TH1 effector cells is a defect .pdf

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Solution(1a)Let A=(a,x)where a= distance from origin to y axis.pdf

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Theyre called molecular compounds. Solutio.pdf

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Polygon.java public class Polygon { private int numSides; private double sideLength; private double xCoord; private double yCoord; private double apothem; private double perimeter; private double area; //Constructor public Polygon (double xCentCoord, double yCentCoord, int countSides, double measLength, double measApothem, double measPerimeter) { xCoord = xCentCoord; yCoord = yCentCoord; numSides = countSides; sideLength = measLength; apothem = measApothem; perimeter = measPerimeter; } //No argument constructor public Polygon () { xCoord = 0.0; yCoord = 0.0; numSides = 4; sideLength = 10.0; apothem = 5.0; perimeter = 20.0; } //Setter Methods //setX() public void setXCoord(double xCentCoord) { xCoord = xCentCoord; } //setY() public void setYCoord(double yCentCoord) { yCoord = yCentCoord; } //setNumSides() public void setNumSides(int countSides) { numSides = countSides; } //setSideLength() public void setSideLength(double measLength) { sideLength = measLength; } //setApothem() public void setApothem(double measApothem) { apothem = measApothem; } //Getter methods //getXCoord public double getXCoord() { return xCoord; } //getYCoord public double getYCoord() { return yCoord; } //getNumSides public int getNumSides() { return numSides; } //getSideLength() public double getSideLength() { return sideLength; } //getApothem() public double getApothem() { return apothem; } //getPerimeter() public double getPerimeter() { return perimeter; } //getArea() public double getArea() { return area; } //Calculate for perimeter public double getPerimeter(Polygon multiple){ double perimeter = multiple.getNumSides() * multiple.getSideLength(); return perimeter; } //Calculate for area public double getArea(Polygon multiple) { double area = 0.5 * multiple.getApothem() * multiple.getPerimeter(); return area; } //toString method public String toString() { String str = \"numsides= \" + numSides + \", sideLength= \" + sideLength; return str; } } TestPolygon.java //import Scanner import java.util.Scanner; public class TestPolygon { public static void main(String[] args) { //Construct a point with x = 1.0, y = 1.0 Polygon multiple = new Polygon(); //Display the values using toString System.out.println(\"toString() results: \" + multiple.toString()); //Call the getter methods double xCoord2 = multiple.getXCoord(); double yCoord2 = multiple.getYCoord(); int numSides2 = multiple.getNumSides(); double sideLength2 = multiple.getSideLength(); double apothem2 = multiple.getApothem(); double perimeter2 = multiple.getPerimeter(); double area2 = multiple.getArea(); //Print results System.out.println(\"xCoord= \" + xCoord2 + \", yCoord= \" + yCoord2 + \", apothem= \" +apothem2); System.out.println(\"getNumsides() results: \" + numSides2); System.out.println(\"getSideLength() results: \" + sideLength2); System.out.println(\"getXCoord() results: \" + xCoord2); System.out.println(\"getYCoord() results: \" + yCoord2); System.out.println(\"getApothem() results: \" + apothem2); System.out.pr.

Polygon.javapublic class Polygon { private int numSides; priva.pdf

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ph = 7ln (0.120.1);ph = 1.27625 ----ANSWERSolutionph = 7.pdf

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OutputSolutionOutput.pdf

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a)40 b)28 c)58 .pdf

1. a)40 b)28 c)58 Solution a)40 b)28 c)58

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