1. EXPERIMENT – 6
OBJECT: -To perform unsymmetrical fault analysis.
CODE
clc
clearall
z1=.2i
z2=.2i
z0=.05i
Ea=1
a=-.5+.866i
Ib=17.32
zf=input('Please Enter the value of zf');
k=input('Enter 1 for 1LG, Enter 2 for LL, Enter 3 for 2LG Enter 4 for 3phase
fault');
switch(k)
case 1
Ia=(3*Ea/(z1+z2+z0+3*zf));
If=Ia*Ib
case 2
Ia1=(Ea/z1+z2+zf);
Ia2=((a*a-a)*Ia1);
If=Ia2*Ib
case 3
Ia3=(Ea/z1+(z2*(z0+3*zf)/(z2+z0+3*zf)));
Ia4=(-(Ea-Ia3*z1)/(z0+3*zf));
Ia5=3*Ia4;
If=Ia5*Ib
case 4
Ia6=Ea/z1;
If=Ia6*Ib
end
[Theta,rho]=cart2pol(real(If),imag(If))
a=Theta*180/pi
i=[rho a]

2. RESULT:-
z1 =0 + 0.2000i
z2 =0 + 0.2000i
z0 = 0 + 0.0500i
Ea =1
a = -0.5000 + 0.8660i
Ib =17.3200
Please Enter the value of zf0
Enter 1 for 1LG, Enter 2 for LL, Enter 3 for 2LG Enter 4 for 3phase fault1
If =0 -1.1547e+002i
Theta =-1.5708
rho = 115.4667
a = -90
i = 115.4667 -90.0000