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Suppose you have two infinite sets A and B, and you are shown a pairing in which each element
from A is associated with exactly one element from B and no two elements of A are paired up
with the same element of B. In this pairing, however, there are elements of b that are not paired
up with elements of A.
Does this imply that the cardinality A and the cardinality of B are not equal? Carefully explain
why or why not.
Suppose we replace the word "infinite'' with "finite" would that change your answer?
Explain.
Solution
I believe that in order for the cardinality to be the same there must exist a mapping
that is not only one-to-one (injective) but also onto (surjective). The pairing you described
between A and B is not surjective since there exist elements in B that are not paired with A.

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Suppose you have two infinite sets A and B, and you are shown a pair.pdf

  • 1. Suppose you have two infinite sets A and B, and you are shown a pairing in which each element from A is associated with exactly one element from B and no two elements of A are paired up with the same element of B. In this pairing, however, there are elements of b that are not paired up with elements of A. Does this imply that the cardinality A and the cardinality of B are not equal? Carefully explain why or why not. Suppose we replace the word "infinite'' with "finite" would that change your answer? Explain. Solution I believe that in order for the cardinality to be the same there must exist a mapping that is not only one-to-one (injective) but also onto (surjective). The pairing you described between A and B is not surjective since there exist elements in B that are not paired with A.