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Four distinct circles are drawn in a plane. What is the maximum number of points, where at least
two of the circles intersect?
Solution
out of 4 we can select any two in 4c2 ways =12 ways.
so the total number of pints of intersection =(2)(12)=24(maximum)

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  • 1. Four distinct circles are drawn in a plane. What is the maximum number of points, where at least two of the circles intersect? Solution out of 4 we can select any two in 4c2 ways =12 ways. so the total number of pints of intersection =(2)(12)=24(maximum)