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Two different enzymes are able to catalyze the same reaction, AB. They both have the same Vmax, but differ in their Km for the substrate A. For enzyme 1 , the Km is 1.0mM; for enzyme 2, the Km is 10mM. When enzyme 1 was incubated with 0.1mMA, it was observed that B was produced at a rate of 0.0020 mmoles/minute. a. What is the value of the Vmax of the enzymes? b. What will be the rate of production of B when enzyme 2 is incubated with 0.1mMA ? c. What will be the rate of production of B when enzyme 1 is incubated with 1M (i.e., 1000mM ) A? d. Which enzyme is a more efficient catalyst?.

Two different enzymes are able to catalyze the same reaction, AB. They both have the same
Vmax, but differ in their Km for the substrate A. For enzyme 1 , the Km is 1.0mM; for enzyme
2, the Km is 10mM. When enzyme 1 was incubated with 0.1mMA, it was observed that B was
produced at a rate of 0.0020 mmoles/minute. a. What is the value of the Vmax of the enzymes?
b. What will be the rate of production of B when enzyme 2 is incubated with 0.1mMA ? c. What
will be the rate of production of B when enzyme 1 is incubated with 1M (i.e., 1000mM ) A? d.
Which enzyme is a more efficient catalyst?

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Tree: inin A recursave tree data structure. Note the retationship between this class and Recursivelist; the only major difference is that rest has been replaced by _ subtrees to handte multiple recursive sub-parts. Hen \# wa Private Attributes =m= \# The item stored at this tree's root, or None if the tree is enpty. root: optional [Anyl \# The list of alt subtrees of this tree. - subtrees: List [Tree] \# mum Representation Invariants === \# - If self. root is None then self. subtrees is an enpty list. This setting of attributes represents an enpty Tree. Note: self. _ subtrees may be empty when selt._root is not None. This setting of attributes represents a tree consisting of just one node. def swap_down(setf) None: "*=Swap the root of this Tree with the frargest of its chitdren until the originat root's value is at a position where it's larger than or equal to all of its children. In the case of a tie, swap with the one that cones first in subtrees. >t= Tree(1, [1)tsswapdownt) print(t) \& No swaps are made 1 t._subtrees =[Tree(2,[1]. Tree (3, [1)] print(t) 1 3233> t. 5wapdown() ss print (t) in 1 swapped with 3 3 2 1 t-large =Tree(3,ITree(5,ITree(7,tTree(2,11), Tree(1, [1]) 1), 1) Tree (4, [1] 1]> print (t __targe) 3 7 2 1 mos targe-swap_down( ) print(t_large) =3 swapped with 5 , and then with 7 . \# The beton are methods given to you. Do NoT change these. def init_(self, root: Any, subtrees: List (Treel) None: wanitiatize a new Tree with the given root vatue and subtrees. If eroots is None, the tree is eapty. Preconditiont if sroot> is None, then ksubtreess is enpty. self, _root =root self.-subtrees = subtrees def is empty(self boolt nHinReturn True if this tree is enty. t1=Trec( None, [1)t1.15 _etopty() True t2=Tree(3,11) t2.1s_empty () Fatise winl return self,_root is None det _str (sett) str: \# The below are nethods given to you. Do NoT change these. def _init (self, root: Any, subtrees: List(TreeJ) Wonet "anitialize a new Tree with the given root value and subtrees. If eroot> is None, the tree is empty. Precondition: if is None, then esubtrees> is empty. ren self root = root self._subtrees: = subtrees def is empty (self) bool: wawpeturn True if this tree is empty. tI= Tree (None, []) t1,is_empty () True >t2=Tree(3, [1) > t2.is_empty ( ) False a return self. root is None def _str_ ( self f str: m*Return a string representation of this: tree. For each node, its iten is printed before any of its descendants' items. The output is nicely indented. You may find this method helpful for debugging. return self._str_indented () , steip( ) def str_indented(setf, depth: int =0) str: in*peturn an indented string representation of this-tree. The indentation level is: specified by the : return e tiset 5=1+ depth + str (set( root )+ ' ln3 for subtree in self . subtrees: * Note that the "depth' argument to the recursive catl is \# modified. 5+= subtree. _str_indented(depth + 1) returnis if nane _ingort doctest doctest. testmod (1) import python_ta.

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Holdier Curriculum Vitae (April 2024).pdf

Holdier Curriculum Vitae (April 2024).pdf

Holdier Curriculum Vitae (April 2024).pdf

Making and Justifying Mathematical Decisions.pdf

Making and Justifying Mathematical Decisions.pdf

Making and Justifying Mathematical Decisions.pdf

Mixin Classes in Odoo 17 How to Extend Models Using Mixin Classes

Mixin Classes in Odoo 17 How to Extend Models Using Mixin Classes

Mixin Classes in Odoo 17 How to Extend Models Using Mixin Classes

Two different enzymes are able to catalyze the same reaction, AB. The.pdf

1. Two different enzymes are able to catalyze the same reaction, AB. They both have the same Vmax, but differ in their Km for the substrate A. For enzyme 1 , the Km is 1.0mM; for enzyme 2, the Km is 10mM. When enzyme 1 was incubated with 0.1mMA, it was observed that B was produced at a rate of 0.0020 mmoles/minute. a. What is the value of the Vmax of the enzymes? b. What will be the rate of production of B when enzyme 2 is incubated with 0.1mMA ? c. What will be the rate of production of B when enzyme 1 is incubated with 1M (i.e., 1000mM ) A? d. Which enzyme is a more efficient catalyst?