Test 1 skema q&a

UNIVERSITI TUN HUSSEIN ONN MALAYSIA
FACULTY OF MECHANICAL AND MANUFACTURING ENGINEERING
BTI10202 COMPUTER PROGRAMMING

TEST 1-MONDAY

Write a program to calculate mass of the liquid in a tank. Allow the user to input the
volume either in cm or meter, and prompt the user to recalculate if desire.

Note that:

Oil density (ρ)= 850 kg/m3

Mass=ρV

The output should be similar to:


#include<stdio.h>

#include<conio.h>

#include<math.h>

main(){

float oildensity, tankvolume,mass=0;

char oilunit,again;

printf("This program calculate the mass of oil in a tank");

start:

printf("nnEnter oil density: ");scanf("%f",&oildensity);

printf("Enter tank volume: ");scanf("%f",&tankvolume);

printf("nEnter volume unit(m=meter, c=centimeter): ");scanf("%s",&oilunit);

recalculate:

switch (oilunit){

case 'c':

mass= oildensity*((pow(tankvolume,3))/pow(100,3)); break;

case 'm':

mass= oildensity*(pow(tankvolume,3)); break;

default:

printf("You have entered a wrong type of unit");

printf("nnEnter oil density unit(g for gram/k for kg): ");scanf("%s",&oilunit);

goto recalculate; }

printf("nntThe Mass of oil is %.4fkg",mass);

printf("nnDo you want to re-calculate: ");scanf("%s",&again);

if(again=='y' || again=='Y')

goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

main(){


char oilunit,again;


start:




recalculate:

if (oilunit== 'c'){

mass= oildensity*((pow(tankvolume,3))/pow(100,3)); }

else if (oilunit== 'm'){

mass= oildensity*(pow(tankvolume,3));}

else{



goto recalculate; }


printf("nnDo you want to re-calculate(enter y for yes): ");scanf("%s",&again);


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


char oilunit,again;


start:




recalculate:

switch (oilunit){

case 'c':

mass= oildensity*(tankvolume/100); break;

case 'm':

mass= oildensity*tankvolume; break;

default:



goto recalculate;

}


printf("nnDo you want to re-calculate: ");scanf("%s",&again);


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


char oilunit,again;


start:




recalculate:

if (oilunit== 'c'){

mass= oildensity*(tankvolume/100); }

else if (oilunit== 'm'){

mass= oildensity*tankvolume;}

else{



goto recalculate;

}




goto start;

getch();

}


TEST 1-TUESDAY

Base on the table develop a simple program on how long should a
man/woman should exercise to burn calories off either by jogging or
bicycling. The user must be able to keep calculating until the key end
otherwise.

Example: A 65kg woman needs to burn of 800 calories by jogging, how
long does she need to jog in order to burn of all of the calories.

�� 540
Energy output: ��ℎ�� Δ 64 x
68�� 68

�� 800
Duration: Δ
�� 516.17

The output should be similar to :


#include<stdio.h>

#include<conio.h>

main(){

float calorin,weight,totalhour=0;

int type;

char again;

printf("ttt444Exercise Calculator444nn");

start:

printf("nEnter calories intake: ");scanf("%f",&calorin);

printf("Enter your weight: ");scanf("%f",&weight);

choose:

printf("nPlease choose type of exercise n1. Joggingn2. BicyclingnPlease enter type:
");scanf("%d",&type);

switch(type){

case 1:

totalhour=calorin/(weight*(540/68));

printf("ntIn order to burn %.f of calories you need to jog for
%.1fhr",calorin,totalhour);break;

case 2:


printf("ntIn order to burn %.f of calories you need to cycle for

default:

goto choose;break;

}


goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("nPlease choose type of exercise n1. Joggingn2. BicyclingnPlease enter type:

if (type==1){


printf("ntIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour); }

else if (type==2){


printf("ntIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour); }

else { goto choose;}


goto start;

getch();

}


TEST 1-TUESDAY

man/woman should exercise to burn calories off either by jogging or
playing tennis. The user must be able to keep calculating until the key
end otherwise.


�� 540
68�� 68

�� 800
Duration: Δ
�� 508.23



#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("nPlease choose type of exercise n1. Joggingn2. TennisnPlease enter type:

switch(type){

case 1:


printf("ntIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour);break;

case 2:


printf("ntIn order to burn %.f of calories you need to play intense tennis for %.1fhr",
calorin,totalhour); break;

default:

goto choose; break; }



goto start;

getch();

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("nPlease choose type of exercise n1. Joggingn2. TennisnPlease enter type:

if(type==1){


printf("ntIn order to burn %.f of calories you need to jog for %.1fhr",calorin,totalhour);}

else if(type==2){


printf("ntIn order to burn %.f of calories you need to play intense tennis for
%.1fhr",calorin,totalhour); }

else{

goto choose; }



goto start;

getch();

}


TEST 1-TUESDAY

man/woman should exercise to burn calories off either by fast swimming
or bicycling. The user must be able to keep calculating until the key end
otherwise.


�� 540
68�� 68

�� 800
Duration: Δ
�� 508.23



#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("nPlease choose type of exercise n1. Fast Swimmingn2. BicyclingnPlease enter type:

switch(type){

case 1:


printf("ntIn order to burn %.f of calories you need to fast swimming for

case 2:


printf("ntIn order to burn %.f of calories you need to cycle for
%.1fhr",calorin,totalhour);

break;

default:

goto choose;break;

}


#include<stdio.h>

#include<conio.h>

main(){


int type;

char again;


start:



choose:

printf("nPlease choose type of exercise n1. Fast Swimmingn2. BicyclingnPlease enter type:

if(type==1){


printf("ntIn order to burn %.f of calories you need to fast swimming for %.1fhr",
calorin,totalhour);}

else if (type==2){


printf("ntIn order to burn %.f of calories you need to cycle for %.1fhr",calorin,totalhour); }

else{

goto choose; }


goto start;

getch();

}


TEST 1-WEDNESDAY

Develop a simple program to calculate
radius of a circle. The user need to
choose whether to input area or
circumference of the circle.

Note that:

area= πxrad2

and circumference = 2xπxrad


The user must be able to keep calculating until the key end otherwise.


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,again;

float radius,circumference,area;

printf("t444This program calculate radius of a circle444");

start:

printf("nna:areanc:circumferencennEnter the information that you have:");

scanf("%s",&type);

cal:

switch(type){

case 'a':

printf("nEnter area of a circle:");scanf("%f",&area);

radius = sqrt(area/PI);

printf("nThe area of a circle is %.2f while the radius is %.4f",area,radius); break;

case 'c':

printf("nEnter circumference of a circle:");scanf("%f",&circumference);

radius= circumference/(PI*2);

printf("nThe circumference of a circle is %.2f while the radius is
%.4f",circumference,radius);break;

default:

printf("na:areanc:circumferencennPlease re-enter selection:");

scanf("%s",&type); goto cal; }

if(again=='y' || again=='Y') { goto start;}

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,again;


printf("t444This program calculate radius of a circle444");

start:

printf("nna:areanc:circumferencennEnter the information that you have:");

scanf("%s",&type);

cal:

if (type=='a'){

printf("nEnter area of a circle:");scanf("%f",&area);

radius = sqrt(area/PI);

printf("nThe area of a circle is %.2f while the radius is %.4f",area,radius);}

else if(type== 'c'){

printf("nEnter circumference of a circle:");scanf("%f",&circumference);

radius=circumference/(PI*2);

printf("nThe circumference of a circle is %.2f while the radius is %.4f",circumference,radius);}

else{


scanf("%s",&type); goto cal;}


goto start;

getch();

}


TEST 1-WEDNESDAY

Develop a simple program to calculate
either an area or perimeters of a semi
circle. The program must prompt the
user to input radius.

Note that:

area= πxrad2



20.7075



#include<stdio.h>

#include<conio.h>

#define PI 3.1415

main(){

char type,again;

float radius,circumference,area,perimeters;

printf("t444SEMI-CIRCLE CALCULATOR444");

start:

printf("na:areanp:perimetersnnEnter selection:");

scanf("%s",&type);

printf("nEnter radius of the semi-circle:");

scanf("%f",&radius);

cal:

switch(type){

case 'a':

area= 0.5*(PI*pow(radius,2));

printf("nThe area of a semi-circle for %.2f radius is %.4f",radius,area); break;

case 'p':

circumference= 2*PI*radius;

perimeters= (2 *radius)+ (circumference/2);

printf("nThe perimeters of a semi-circle for %.2f of radius is %.4f",radius,perimeters);break;

default:

printf("wrong selection");

printf("na:areanp:PerimetersnnPlease re-enter selection:");



goto start;

getch(); }


#include<stdio.h>

#include<conio.h>

#define PI 3.1415

main(){

char type,again;

float radius,circumference,area,perimeters;

printf("t444SEMI-CIRCLE CALCULATOR444");

start:

printf("na:areanp:perimetersnnEnter selection:");

scanf("%s",&type);

printf("nEnter radius of the semi-circle:");


cal:

if(type=='a'){

area= 0.5*(PI*pow(radius,2));

printf("nThe area of a semi-circle for %.2f radius is %.4f",radius,area);}

else if(type=='p'){


perimeters= (2 *radius)+ (circumference/2);

printf("nThe perimeters of a semi-circle for %.2f of radius is %.4f",radius,perimeters);}

else{ printf("wrong selection");

printf("na:areanp:PerimetersnnPlease re-enter selection:");

scanf("%s",&type); goto cal;

}


goto start;

getch();

}


TEST 1-THURSDAY

Write a program to prove the theory of prefix and postfix in C Program slybuss. Allow the
user to keep testing until ‘n’ is keyed in by the user

Note that:

Postfix : a++,a—

Prefix :++a,--a



#include<stdio.h>

#include<conio.h>

main(){

int a,prepost;

char b;

printf("tThis program is use to proof theory of postfix and prefix");

sekalilagi:

printf("nnEnter value a: "); scanf("%d",&a);

choose:

printf("nPlease choosen1. postfixn2. PrefixnPlease enter your choice: ");
scanf("%d",&prepost);

switch (prepost){

case 1:

printf("npostfix/a++ for a is %d at the end a =%d", a++,a);

printf("nand a after ; is %d",a);

printf("nnpostfix/a-- for a is %d at the end a =%d", a--,a);

printf("nand a after ; is %d",a); break;

case 2:

printf("nprefix/++a for a = %d at the end a =%d", ++a,a);


printf("nnprefix/--a for a = %d at the end a =%d", --a,a);

printf("nand a after ; is %d",a); break;

default: goto choose; }

printf("nnEnter n to stop re-trying: "); scanf("%s",&b);

if (b!='n'){ goto sekalilagi;}

getch();

}


#include<stdio.h>

#include<conio.h>

main(){

int a,prepost;

char b;

printf("tThis program is use to proof theory of postfix and prefix");

sekalilagi:

printf("nnEnter value a: "); scanf("%d",&a);

choose:

printf("nPlease choosen1. postfixn2. PrefixnPlease enter your choice: ");
scanf("%d",&prepost);

if (prepost==1){

printf("npostfix/a++ for a is %d at the end a =%d", a++,a);


printf("nnpostfix/a-- for a is %d at the end a =%d", a--,a);

printf("nand a after ; is %d",a); }

else if (prepost==2){

printf("nprefix/++a for a = %d at the end a =%d", ++a,a);


printf("nnprefix/--a for a = %d at the end a =%d", --a,a);

printf("nand a after ; is %d",a);}

else { goto choose;}


if (b!='n'){ goto sekalilagi;}

getch();

}


TEST 1-FRIDAY

Write a program to segregat number of students according to :

GRADE E: 0 <= mark <=49

GRADE D: 50 <=mark <=59

GRADE C: 60 <= mark <=69

GRADE B: 70 <= mark <=79

GRADE A: 80 <= mark <=100



#include<stdio.h>

#include<conio.h>

int main(){

int noofstudent=0,mark=0, gradeA=0,gradeB=0,gradeC=0,gradeD=0,gradeE=0;

int i=1;

printf("44The Program segregrate the number of students according to grade44 ");

printf("nnEnter Number of student: "); scanf ("%d",&noofstudent);

loop:

printf("%d student mark: ",i); scanf ("%d",&mark);

if (mark>=0 && mark <=49)

{ gradeE++; }

else if (mark>=50 && mark <=59)

{ gradeD++; }


{ gradeC++; }


{ gradeB++; }


{ gradeA++; }

i++;

if (i<noofstudent)

goto loop;


printf("n______________________________________________n ");

printf("nThere is %d students receive grade A ",gradeA);

printf("nThere is %d students receive grade B ",gradeB);

printf("nThere is %d students receive grade C ",gradeC);

printf("nThere is %d students receive grade D ",gradeD);

printf("nThere is %d students receive grade E ",gradeE);

getch();

return 0;

}


TEST 1-FRIDAY

Develelope a simple program which
receive radius of a circle from user and
allowed user to choose between
calculating area of a circle or
circumferense of a circle,:

Note that:

area= πxrad2





#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,b;


printf("This program calculate Area or Circumference of a circle");

again:

printf("na:areanc:circumferencennEnter selection:");scanf("%s",&type);

printf("nEnter radius of a circle:"); scanf("%f",&radius);

cal:

switch(type){

case 'a':

area= PI*pow(radius,2);

printf("nThe area of a circle for %.2fcm radius is %.4f",radius,area); break;

case 'c':


printf("nThe circumference of a circle for %.2fcm radius is %.4f",radius,circumference);break;

default:





if (b!='n'){ goto again;}

getch();

}


#include<stdio.h>

#include<conio.h>

#include<math.h>

#define PI 3.1416

main(){

char type,b;


printf("This program calculate Area or Circumference of a circle");

again:

printf("na:areanc:circumferencennEnter selection:");

scanf("%s",&type);

printf("nEnter radius of a circle:");


cal:

if (type=='a'){

area= PI*pow(radius,2);

printf("nThe area of a circle for %.2fcm radius is %.4f",radius,area); }

else if (type=='c') {


printf("nThe circumference of a circle for %.2fcm radius is
%.4f",radius,circumference);}

else {





if (b!='n'){ goto again;}

getch(); }

Test 1 skema q&a

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Test 1 skema q&a