This C code snippet contains 3 statements: 1) Sets the lower 3 bits of PORTC to 1 by ANDing with 0x07. 2) A while loop that runs as long as a bit is high on PIND. 3) Shifts the bits in PORTB left by two positions.
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Describe with only one sentence each of the following C statements .pdf
1. Describe with only one sentence each of the following C statements: PORTC = (PORTC 0
times07); while((PIND & _BV(PD7)) 1= 0) PORTA &= ~_BV(PA2) PORTB = PORTB 2;
Solution
a) PORT C values are with 0x07,which makes lower 3 bit values are 1
b)the loop will be exevuted until there is no value(0) in port D
d)Port B values are shifted by Left two times