Possible Hint: Let H act on G/H by left multiplication. The coset H exist in G/H is fixed by this action. By considering the possible number of points in a orbit, show that the other elements of G/H are also left fixed by the action. Solution p is the smallest prime that divides n the order of G H is a subgroup such that [G:H] = p. Let H act on G/H by left multiplication Then the coset H exist in G/H is fixed by this. Consider all possible points in an orbit, for all we find that G/H are also fixed by the action. As g belongs to G and gH is in G/H, we can see that g-1Hg is contained in H. As our selection of g was arbitrary, this is true for all g. Hence H is normal..