Problem 3-2 National Scan, Inc., sells radio frequency inventory tags. Monthly sales for a seven-month period were as follows: A linear trend equation.(Round your intermediate calculations and final answer to 2 decimal places.) A five-month moving average. (Round your answer to 2 decimal places.) Exponential smoothing with a smoothing constant equal to .20, assuming a March forecast of 16(000). (Round your intermediate calculations and final answer to 2 decimal places.) A weighted average using .60 for August, .20 for July, and .20 for June. (Round your answer to 2 decimal places.) National Scan, Inc., sells radio frequency inventory tags. Monthly sales for a seven-month period were as follows: Solution As per rule I can answer four parts only. Yt = 15.75 + 0.9643 t Here t is month in numbers. For September, t would be 9. Yt = 15.75 + (0.9643 x 9) Yt = 24.43 2) 5 month moving average forecast for September =( 26 +21+19+26+12)/5 =20.80 4) In Na.

1. Problem Description and Analysis
In this Laboratory, you will design and simulate a simple ALU in Quatrus II Verilog. The
description and specification of the ALU is given below:
An ALU is a logic circuit that performs various Boolean and arithmetic operations on n-bit
operands. This ALU has 2 four-bit data inputs, A and B, a three-bit select input, S, and a four-bit
output, F. The functionality of this simple ALU is specified in the table below.
Operation
Inputs
S
Outputs
F
s2
s1
s0
f3
f2
f1
f0
Clear
0
0
0
0
0
0
0
B - A
0
0
1
B – A
A – B
0
1

2. 0
A – B
ADD
0
1
1
A + B
XOR
1
0
0
A XOR B
OR
1
1
0
A OR B
AND
1
1
0
A AND B
Preset
1
1
1
1
1
1
1
Table 1 – Functionality Table for ALU
Operation
Inputs
S
Outputs
F

3. s2
s1
s0
f3
f2
f1
f0
Clear
0
0
0
0
0
0
0
B - A
0
0
1
B – A
A – B
0
1
0
A – B
ADD
0
1
1
A + B
XOR
1
0
0
A XOR B
OR

4. 1
1
0
A OR B
AND
1
1
0
A AND B
Preset
1
1
1
1
1
1
1
Solution
module alu(s, A, B, F);
input [2:0] S;
input [3:0] A, B;
output reg [3:0] F;
always @(S, A, B)
case (S)
0: F = 0000;
1: F = B - A;
2: F = A - B;
3: F = A + B;
4: F = A ^ B;
5: F = A | B;
6: F = A & B;
7: F = 1111;
endcase
endmodule