Can anyone see if I did this right? Find volume of the solid formed by y=1+sec x and y=3 ; about y=1 =pi * integral from -pi/3 to pi/3 of (2^2 - sec ^2 (x)) dx =2pi(4x-tanx) from 0 to pi/3 =(8pi^2)/3-2pi square root 3 sorry if its confusing I don\'t know how to draw all the right symbols. Thank you. Solution u r correct..