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Is f bijective and if so, calculate the n order derivative of its .pdf
Is f bijective and if so, calculate the n order derivative of its .pdfWird geladen in ... 3
integrate e7 x(e7 x + 3)52 dxthe actual question is ln 7.pdf
23. Mar 2023•0 gefällt mir•2 Aufrufe
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integrate e7 x(e7 x + 3)5/2 dx the actual question is: ? ? ln 7 ln 5 e7 x(e7 x + 3)5/2 dx Solution We\'ll solve this integral using substitution technique: We\'ll substitute [e^(7x) + 3] by t. Differentiating both sides we\'ll get: [7e^(7x)dx = dt] [e^(7x)dx = dt/7] We\'ll re-write the integral: [int e^(7x)*(e^7x + 3)^(5/2)dx = int t^(5/2)dt/7] [int t^(5/2)dt/7 = t^(5/2 + 1)/(7(5/2 + 1)) + C] [int t^(5/2)dt/7 = t^(7/2)/(7*(7/2)) + C] [int e^(7x)*(e^7x + 3)^(5/2)dx = 2(e^(7x) + 3)^(7/2)/49 + C] Therefore, the requested integral of the given function is [int e^(7x)*(e^(7x)+3)^(5/2)dx = (2sqrt[(e^(7x) + 3)^7])/49 + C.].
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integrate e7 x(e7 x + 3)52 dxthe actual question is ln 7.pdf
- integrate e7 x(e7 x + 3)5/2 dx the actual question is: ? ? ln 7 ln 5 e7 x(e7 x + 3)5/2 dx Solution We'll solve this integral using substitution technique: We'll substitute [e^(7x) + 3] by t. Differentiating both sides we'll get: [7e^(7x)dx = dt] [e^(7x)dx = dt/7] We'll re-write the integral: [int e^(7x)*(e^7x + 3)^(5/2)dx = int t^(5/2)dt/7] [int t^(5/2)dt/7 = t^(5/2 + 1)/(7(5/2 + 1)) + C] [int t^(5/2)dt/7 = t^(7/2)/(7*(7/2)) + C] [int e^(7x)*(e^7x + 3)^(5/2)dx = 2(e^(7x) + 3)^(7/2)/49 + C] Therefore, the requested integral of the given function is [int e^(7x)*(e^(7x)+3)^(5/2)dx = (2sqrt[(e^(7x) + 3)^7])/49 + C.]
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