2. Consider an 8x8 multiplier similar to the 4x4 one in Figure 5.18c. Assume that each AND gate has a delay of A and each adder has a delay of B. What is the overall delay of this multiplier? Solution the delay due to And gate=1unit AND gate delay * no of bits delay due to and gate=8A delay due to adder: delay at levels 1 to ( m – 1) units of n-bit adders = ( m – 1) × delay of one-unit 8-bit adder m=8 bit, delay=B so delay due to adder=7B over all delay=8A+7B.