James Stewart Calclus 6e chapter 7.4 problem 40 I figured out what the eqaution of the tangent line at points (1,0) was: 7x-7. the other point at (e,7/e) is where I\'m having difficulty at, my answet was: 7-e^1 but webassign counted it wrong Solution y = 7(lnx)/x y\' = 7/x^2 - 7lnx/x^2 y\'(1) = 7 line is 7x-y =7 y =7x-7.

1. James Stewart Calclus 6e chapter 7.4 problem 40
I figured out what the eqaution of the tangent line at points (1,0) was: 7x-7.
the other point at (e,7/e) is where I'm having difficulty at, my answet was: 7-e^1 but webassign
counted it wrong
Solution
y = 7(lnx)/x y' = 7/x^2 - 7lnx/x^2 y'(1) = 7 line is 7x-y =7 y =7x-7