A SERIES OF QUESTIONS TO MEASURE JOB SATISFACTION OF BUS DRIVER\'S IN NEW YORK CITY. A random sample of 100 drivers has an average score of 10.6, with a standard deviation of 2.8. What is your estimate of the average job satisfaction score for the population as a whole? Use the 95 percent confidence level. Solution Given a=0.05, |Z(0.025)|=1.96 (check standard normal table) So 95% CI is xbar±Z*s/n --> 10.6± 1.96*2.8/10 --> (10.0512, 11.1488).