Thank you! -i=110(xix)2=72 Let p,2 be the 100pth percentile of a chi-squared random variable with degrees of freedom. The following table lists values of p,2 for specific combinations of p and : Construct the 90% confidence interval for 2. (1.419,7.218) (1.548,8.782) (3.785, 26.667) (42.562.1654).