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Expanding single brackets              Remember to multiply all the terms
                                         inside the bracket by the term
           x                           immediately in front of the bracket



        4(2a + 3) = 8a + 12                              If there is no term in
                                                         front of the bracket,
                x                                          multiply by 1 or -1

 Expand these brackets and simplify wherever possible:

   1.   3(a - 4) =                          7.   4r(2r + 3) =

   2.   6(2c + 5) =                         8.   - (4a + 2) =

   3.   -2(d + g) =                         9.   8 - 2(t + 5) =

   4.   c(d + 4) =
                                            10. 2(2a + 4) + 4(3a + 6) =
   5.   -5(2a - 3) =
                                            11. 2p(3p + 2) - 5(2p - 1) =
   6.   a(a - 6) =
Expanding double brackets
                                        Split the double brackets into 2
                                       single brackets and then expand
                                          each bracket and simplify

     (3a + 4)(2a – 5)
                                                      “3a lots of 2a – 5
                                                     and 4 lots of 2a – 5”

= 6a2 – 15a + 8a – 20
                                         If a single bracket is squared
                                         (a + 5)2 change it into double
= 6a2 – 7a – 20                               brackets (a + 5)(a + 5)

Expand these brackets and simplify :

1.    (c + 2)(c + 6) =                      4.   (p + 2)(7p – 3) =

2.    (2a + 1)(3a – 4) =                    5.   (c + 7)2 =

3.    (3a – 4)(5a + 7) =                    6.   (4g – 1)2 =
Factorising – common factors
                                               Factorising is basically the
            Factorising
                                             reverse of expanding brackets.
                                              Instead of removing brackets
5x2 + 10xy = 5x(x + 2y)                        you are putting them in and
                                             placing all the common factors
                                                          in front.
            Expanding
Factorise the following (and check by expanding):


   15 – 3x =                                10pq + 2p =
   2a + 10 =                                20xy – 16x =
   ab – 5a =                                24ab + 16a2 =
   a2 + 6a =                                r2 + 2 r =
   8x2 – 4x =                               3a2 – 9a3 =
Factorising – quadratic expressions

 a 2  2ab  b 2               a 2  b2 




a 2  2ab  b 2               ax  by  cx  dy 
Factorising – grouping and difference of two squares

Grouping into pairs                  Difference of two squares

Fully factorise this expression:     Fully factorise this expression:
6ab + 9ad – 2bc – 3cd                4x2 – 25

Factorise in 2 parts                 Look for 2 square numbers
                                     separated by a minus. Simply
                                     Use the square root of each
Rewrite as double brackets           and a “+” and a “–” to get:


 Fully factorise these:              Fully factorise these:
 (a) wx + xz + wy + yz               (a) 81x2 – 1
 (b) 2wx – 2xz – wy + yz             (b) 4 – t2
 (c) 8fh – 20fm + 6gh – 15gm         (c) 16y2 - 64
 Answers:                            Answers:
 (a) (x + y)(w + z)                  (a) (9x + 1)(9x – 1)
 (b) (2x – y)(w – z)                 (b) (2 + t)(2 – t)
 (c) (4f + 3g)(2h – 5m)              (c) 16(y2 + 4)
Factorise each of the following


x  6m  9
 2
                     3r  6rp  3 p
                        2             2
                                          25 x  120 xy  100 y
                                              2                   2
Factorise each of the following


( x  5)  9
       2
                                  4(m  1) 2  25
Simplifying Algebraic Fractions

    Reduce this fraction

       12         43        Factorise the numerator and

                            denominator, cancel the

                  53
                             common factors
       15
Simplify by factorising
1                           Cancel the common factors
      6c  2
           32 c c
         
      2c     2c
                                       Factorise
                                      first before
                                       cancelling
Simplify by factorising
     5                    6 p 4m6
                                 
    15m                        5
                          15 p m
Simplify
                Cancel the common factors        Write down what’s left
2
     7(c  1)          7(c  1)
                  
     (c  1)2       (c  1)(c  1)
                Let’s do one that isn’t already factorised

3                          Cancel the common factors          write down what’s left

     2 x  10     2( x  5)
                                                                        Grade A
     3 x  15     3( x  5)

                                             factorise the numerator first


                                             factorise the denominator
Factorise and Simplify
                         Cancel the common factors        Write down what’s left
4

       ( x2  9)  ( x  3)( x  3)                                            Grade A*

     x2  7 x  12 ( x  3)( x  4)
     Factorise the numerator first      Factorise the denominator


Simplify the expressions fully
1)     2x  6                                        4)   x2  16
         2x                                               x2  4 x
2)     5 x  10                                      5)     2 x2  8
       3x  6                                             x2  6 x  8
       x2  2 x                                           x2  5 x  6
3)
                                                     6)
       8 x  16                                            x2  x  6
Check your answers!!

1)   2 x  6  2( x  3)          
                                      x3
                                       x              Factorise the numerator
       2x         2x
     5 x  10  5( x  2)
2)                                      5             Factorise the denominator
                                      
     3x  6     3( x  2)               3             Cancel the common factors
                                                      Write down what’s left
     x2  2 x         x( x  2)         x
3)                                   
     8 x  16         8( x  2)         2

4)   x2  16      ( x  4)( x  4)
                                           x4
     x  4x
      2               x ( x  4)
5)     2 x2  8                2( x 2  4 )     2( x  2)( x  2)       2( x  2)
                                                                  
     x2  6 x  8           ( x  4)( x  2)    ( x  4)( x  2)         x4

     x2  5 x  6           ( x  3)( x  2)     
                                                     x2
6)                                                  x2
      x2  x  6            ( x  3)( x  2)
Factorise the numerator first
 Factorise and Simplify
                                     Factorise the denominator
k 2  36          (a  b) 2  9b 2   Cancel the common factors
(k  6) 2            a 2  2ab       Write down what’s left
Algebraic fractions – Addition and subtraction

   Like ordinary fractions you can only add or subtract algebraic
            fractions if their denominators are the same

 Simplify     3     +   4_
              x         y

                                                        Addition
                                                    a c ad  bc
                                                      
                                                    b d   bd

                                                    Multiply the top
                                                     and bottom of
                                                    each fraction by
                                                   the same amount
Test yourself!!

Simplify.
    x 3x
1)           =
   10 10
    5     2
2)           =
   7x 7x
   4m 2m  1
3)             =
    5       5
Simplify   x   –   x-5
           2        6
Simplify
            Addition
1   3      a c ad  bc
            
x 2 x     b d   bd
Simplify
              Addition
  3    2    a c ad  bc
             
 x y yx   b d   bd
Simplify
            Subtraction
 2   3p     a c ad  bc
 2
     2       
p qr pr     b d   bd
Simplify
              Subtraction
 2 x 3x  3
             a c ad  bc
  2    4        
              b d   bd
Algebraic fractions – Multiplication and division

                      Again just use normal fractions principles
 Simplify:


   x                        x 5y       2
      5t                       2
   y                       10 y 4 x




                                                    a c ac
                                                      
                                                    b d bd
                                           Multiplication
Simplify
                    Multiplication
  2x  y    5x
                         a c ac
    y      3x  y           
                          b d bd
Test yourself!!!
2x 9 y             5a 2b 3c
                      2
                         
3 10 x             6c      10 ab




            3y                      a
                                     2
             5                     4b c
Test yourself!!!

x  4 6x
2       2                 9x  4 y
                            2     2
                                       3y
                                  
 3x    x2                  6y 3
                                     6x  4 y
Simplify
           Division
2x 4 y
          a c ad
7 14         
           b d bc
Simplify

x y
 2    2
        4( x  y )
    4
      
 3y      9x3 y 2
Simplify

x2  y2 2x  2 y
      3
        
 3 xy     x2 y

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PMR Form 3 Mathematics Algebraic Fractions

  • 1.
  • 2. Expanding single brackets Remember to multiply all the terms inside the bracket by the term x immediately in front of the bracket 4(2a + 3) = 8a + 12 If there is no term in front of the bracket, x multiply by 1 or -1 Expand these brackets and simplify wherever possible: 1. 3(a - 4) = 7. 4r(2r + 3) = 2. 6(2c + 5) = 8. - (4a + 2) = 3. -2(d + g) = 9. 8 - 2(t + 5) = 4. c(d + 4) = 10. 2(2a + 4) + 4(3a + 6) = 5. -5(2a - 3) = 11. 2p(3p + 2) - 5(2p - 1) = 6. a(a - 6) =
  • 3. Expanding double brackets Split the double brackets into 2 single brackets and then expand each bracket and simplify (3a + 4)(2a – 5) “3a lots of 2a – 5 and 4 lots of 2a – 5” = 6a2 – 15a + 8a – 20 If a single bracket is squared (a + 5)2 change it into double = 6a2 – 7a – 20 brackets (a + 5)(a + 5) Expand these brackets and simplify : 1. (c + 2)(c + 6) = 4. (p + 2)(7p – 3) = 2. (2a + 1)(3a – 4) = 5. (c + 7)2 = 3. (3a – 4)(5a + 7) = 6. (4g – 1)2 =
  • 4. Factorising – common factors Factorising is basically the Factorising reverse of expanding brackets. Instead of removing brackets 5x2 + 10xy = 5x(x + 2y) you are putting them in and placing all the common factors in front. Expanding Factorise the following (and check by expanding):  15 – 3x =  10pq + 2p =  2a + 10 =  20xy – 16x =  ab – 5a =  24ab + 16a2 =  a2 + 6a =  r2 + 2 r =  8x2 – 4x =  3a2 – 9a3 =
  • 5. Factorising – quadratic expressions a 2  2ab  b 2  a 2  b2  a 2  2ab  b 2  ax  by  cx  dy 
  • 6. Factorising – grouping and difference of two squares Grouping into pairs Difference of two squares Fully factorise this expression: Fully factorise this expression: 6ab + 9ad – 2bc – 3cd 4x2 – 25 Factorise in 2 parts Look for 2 square numbers separated by a minus. Simply Use the square root of each Rewrite as double brackets and a “+” and a “–” to get: Fully factorise these: Fully factorise these: (a) wx + xz + wy + yz (a) 81x2 – 1 (b) 2wx – 2xz – wy + yz (b) 4 – t2 (c) 8fh – 20fm + 6gh – 15gm (c) 16y2 - 64 Answers: Answers: (a) (x + y)(w + z) (a) (9x + 1)(9x – 1) (b) (2x – y)(w – z) (b) (2 + t)(2 – t) (c) (4f + 3g)(2h – 5m) (c) 16(y2 + 4)
  • 7. Factorise each of the following x  6m  9 2 3r  6rp  3 p 2 2 25 x  120 xy  100 y 2 2
  • 8. Factorise each of the following ( x  5)  9 2 4(m  1) 2  25
  • 9. Simplifying Algebraic Fractions Reduce this fraction 12 43 Factorise the numerator and  denominator, cancel the 53 common factors 15 Simplify by factorising 1 Cancel the common factors 6c 2 32 c c  2c 2c Factorise first before cancelling
  • 10. Simplify by factorising 5 6 p 4m6   15m 5 15 p m
  • 11. Simplify Cancel the common factors Write down what’s left 2 7(c  1) 7(c  1)  (c  1)2 (c  1)(c  1) Let’s do one that isn’t already factorised 3 Cancel the common factors write down what’s left 2 x  10 2( x  5)  Grade A 3 x  15 3( x  5) factorise the numerator first factorise the denominator
  • 12. Factorise and Simplify Cancel the common factors Write down what’s left 4 ( x2  9)  ( x  3)( x  3) Grade A* x2  7 x  12 ( x  3)( x  4) Factorise the numerator first Factorise the denominator Simplify the expressions fully 1) 2x  6 4) x2  16 2x x2  4 x 2) 5 x  10 5) 2 x2  8 3x  6 x2  6 x  8 x2  2 x x2  5 x  6 3) 6) 8 x  16 x2  x  6
  • 13. Check your answers!! 1) 2 x  6  2( x  3)  x3 x Factorise the numerator 2x 2x 5 x  10  5( x  2) 2) 5 Factorise the denominator  3x  6 3( x  2) 3 Cancel the common factors Write down what’s left x2  2 x x( x  2) x 3)   8 x  16 8( x  2) 2 4) x2  16 ( x  4)( x  4)   x4 x  4x 2 x ( x  4) 5) 2 x2  8 2( x 2  4 ) 2( x  2)( x  2) 2( x  2)    x2  6 x  8 ( x  4)( x  2) ( x  4)( x  2) x4 x2  5 x  6 ( x  3)( x  2)  x2 6)  x2 x2  x  6 ( x  3)( x  2)
  • 14. Factorise the numerator first Factorise and Simplify Factorise the denominator k 2  36 (a  b) 2  9b 2 Cancel the common factors (k  6) 2 a 2  2ab Write down what’s left
  • 15. Algebraic fractions – Addition and subtraction Like ordinary fractions you can only add or subtract algebraic fractions if their denominators are the same Simplify 3 + 4_ x y Addition a c ad  bc   b d bd Multiply the top and bottom of each fraction by the same amount
  • 16. Test yourself!! Simplify. x 3x 1)  = 10 10 5 2 2)  = 7x 7x 4m 2m  1 3)  = 5 5
  • 17. Simplify x – x-5 2 6
  • 18. Simplify Addition 1 3 a c ad  bc    x 2 x b d bd
  • 19. Simplify Addition 3 2 a c ad  bc    x y yx b d bd
  • 20. Simplify Subtraction 2 3p a c ad  bc 2  2   p qr pr b d bd
  • 21. Simplify Subtraction 2 x 3x  3  a c ad  bc 2 4   b d bd
  • 22. Algebraic fractions – Multiplication and division Again just use normal fractions principles Simplify: x x 5y 2  5t  2 y 10 y 4 x a c ac   b d bd Multiplication
  • 23. Simplify Multiplication 2x  y 5x  a c ac y 3x  y   b d bd
  • 24. Test yourself!!! 2x 9 y 5a 2b 3c  2  3 10 x 6c 10 ab 3y a 2 5 4b c
  • 25. Test yourself!!! x  4 6x 2 2 9x  4 y 2 2 3y   3x x2 6y 3 6x  4 y
  • 26. Simplify Division 2x 4 y  a c ad 7 14   b d bc
  • 27. Simplify x y 2 2 4( x  y ) 4  3y 9x3 y 2
  • 28. Simplify x2  y2 2x  2 y 3  3 xy x2 y