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Absolute Value and Distance
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
L R
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x.
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative.
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative. To clarify the two choices for
the distance, we put the absolute value symbol “l l” around the
expression as l x – y l, to remind us “to take the positive (or 0)
one” as the distance between x and y.
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative. To clarify the two choices for
the distance, we put the absolute value symbol “l l” around the
expression as l x – y l, to remind us “to take the positive (or 0)
one” as the distance between x and y. Facts about the “l l”:
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative. To clarify the two choices for
the distance, we put the absolute value symbol “l l” around the
expression as l x – y l, to remind us “to take the positive (or 0)
one” as the distance between x and y. Facts about the “l l”:
1. l # l ≥ 0 or “distance” is non–negative.
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative. To clarify the two choices for
the distance, we put the absolute value symbol “l l” around the
expression as l x – y l, to remind us “to take the positive (or 0)
one” as the distance between x and y. Facts about the “l l”:
1. l # l ≥ 0 or “distance” is non–negative.
2. l x – y l = l y – x l = the distance between x and y
so “distance” is symmetric (mutual).
L R
Length from L to R is R – L
To find the distance, a nonnegative number, between two points
L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt).
Absolute Value and Distance
If we don’t know the values of x and y, then the distance is
either x – y or y – x. For example, if x = 5 and y = 2,
then the distance between them is x – y = 3
where as y – x = –3 is negative. To clarify the two choices for
the distance, we put the absolute value symbol “l l” around the
expression as l x – y l, to remind us “to take the positive (or 0)
one” as the distance between x and y. Facts about the “l l”:
1. l # l ≥ 0 or “distance” is non–negative.
2. l x – y l = l y – x l = the distance between x and y
so “distance” is symmetric (mutual).
3. With y = 0, l x l = l –x l = the distance from x (or –x) to 0.
0 5
Hence | 5 | = 5
| 5 | = 5
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
a distance of 5
Absolute Value and Distance
0 5-5
Hence | 5 | = 5 = | -5 |
| 5 | = 5
a distance of 5a distance of 5
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
a distance of 5a distance of 5
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
{
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | =
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5)
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
Fact I. |x*y| = |x|*|y|.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6.
Warning: In general |x ± y|  |x| ± |y|.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6.
Warning: In general |x ± y|  |x| ± |y|.
For instance, |2 – 3 |  |2| – |3|  |2| + |3|.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
|x|=
x if x is positive or 0.
–x (opposite of x) if x is negative.{
Hence | –5 | = –(–5) = 5.
Since the absolute value is never negative, an equation
such as |x14 – 3x9 + 1 | = –2 doesn't have any solution.
Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6.
Warning: In general |x ± y|  |x| ± |y|.
For instance, |2 – 3 |  |2| – |3|  |2| + |3|.
0 5-5
Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0.
| -5 | = 5 | 5 | = 5
Because it is a distance measurement, |x| is nonnegative.
Algebraic definition of absolute value
A “| |” can not be split
into two | |’s when
adding or subtracting.
Because –5 is negative,
use the 2nd part of the
rule and take its
opposite to obtain
its abs. value.
The geometric meaning of the absolute value of x or |x|,
is the distance measured from x to 0 on the real line.
Absolute Value and Distance
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations.
Absolute Value Equations
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression)
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
In picture, if | x | = 3 then
0 x = 3x = –3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
b. | –2x | = 5
In picture, if | x | = 3 then
0 x = 3x = –3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
b. | –2x | = 5
In picture, if | x | = 3 then
0 x = 3x = –3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Drop the “| |” and set the formula to 5 and –5.
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
b. | –2x | = 5
–2x = –5 or –2x = 5
In picture, if | x | = 3 then
0 x = 3x = –3
Drop the “| |” and set the formula to 5 and –5.
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
b. | –2x | = 5
–2x = –5 or –2x = 5
x = 5/2
In picture, if | x | = 3 then
0 x = 3x = –3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Drop the “| |” and set the formula to 5 and –5.
Absolute Value Equations
Fact II: If |#| = a, a >0, (where # is any expression) then
# = –a or # = a.
Example A. Solve for x.
a. | x | = 3 then x = –3 or x = 3
b. | –2x | = 5
–2x = –5 or –2x = 5
x = –5/2x = 5/2
In picture, if | x | = 3 then
0 x = 3x = –3
Because |x±y|  |x|±|y|, many steps for solving regular
equations are not valid for | |-equations. We have to solve an
| |-equation by rephrasing it into two equations without the | |.
0 a–a
Drop the “| |” and set the formula to 5 and –5.
Absolute Value Equations
c. | 2x – 3 | = 5
Absolute Value Equations
c. | 2x – 3 | = 5
Drop the “| |”.
Absolute Value Equations
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
Drop the “| |”.
Absolute Value Equations
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = –2
Drop the “| |”.
Absolute Value Equations
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = –2
x = –1
Drop the “| |”.
Absolute Value Equations
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 82x = –2
x = –1
Drop the “| |”.
Absolute Value Equations
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
2 – 3x = 22 – 3x = –2 or
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
2 – 3x = 22 – 3x = –2
–3x = –4
or
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
2 – 3x = 22 – 3x = –2
–3x = –4
or
x = 4/3
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
2 – 3x = 22 – 3x = –2
–3x = 0–3x = –4
or
x = 4/3
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
Absolute Value Equations
Absolute Value Equations
d. | 2 – 3x | + 2 = 4
We have to isolate the | |-term before the dropping the “| |”.
| 2 – 3x | + 2 = 4
| 2 – 3x | = 2
Drop the | |.
2 – 3x = 22 – 3x = –2
–3x = 0
x = 0
–3x = –4
or
x = 4/3
c. | 2x – 3 | = 5
2x – 3 = –5 or 2x – 3 = 5
2x = 8
x = 4
2x = –2
x = –1
Drop the “| |”.
Incorrect versions:
2–3x+2=–4 or 2–3x+2=4
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|.
Absolute Value Equations
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”.
Absolute Value Equations
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
yx
same distance
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9|
yx
same distance
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
yx
same distance
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
Example B. Solve for x geometrically if |x – 7| = 12.
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
Example B. Solve for x geometrically if |x – 7| = 12.
We want the locations of x's that are 12 units away from 7.
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
Example B. Solve for x geometrically if |x – 7| = 12.
We want the locations of x's that are 12 units away from 7.
7
1212
x x
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
Example B. Solve for x geometrically if |x – 7| = 12.
We want the locations of x's that are 12 units away from 7.
7
1212
x x
We see that x = –5 or x = 19.
The geometric meaning of | x | as “distance from 0 and x” may
be extended to the meaning for |x – y|. The geometric meaning
of |x – y| = |y – x| = “distance between x and y”. Note the two
versions reflect that “distance” is always mutual in the sense
that “going from x to y” is as much as “going from y to x”.
Absolute Value Equations
|9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7.
We can solve for x using this method.
yx
same distance
Example B. Solve for x geometrically if |x – 7| = 12.
We want the locations of x's that are 12 units away from 7.
7
1212
x x
(Solve it algebraically and verify these are the answers.)
We see that x = –5 or x = 19.
Absolute Value Equations
c
r
x = c + r
Recall |x*y| = |x|*|y|, so we can pull out constant multiple
hence |3x| = 3|x| and |3x – 6| = |3(x – 2)| = 3|(x – 2)|.
In general, the abs–equation means to find x where
|x – c| = r ( ≥ 0)
distance between x and c is r.
in picture:
r
x = c – r
Hence the solutions for |x – 3 | = 2
are x = 3 – 2 =1 and x = 3 + 2 = 5.
Example C. Solve for x geometrically if |–3x + 6| = 4. Draw.
Since |–3x – 6| = |–3(x + 2)| = 3|x + 2| so
3|x + 2| = 4 or that |x – (–2)| = 4/3.
Hence x = (–2) ± 4/3
or x = –2/3 and x = –3 1
3
–2 x = –2/3x = –3
4/34/3
1
3
|x – (–2)| = 4/3
Ex. A.
1. Is it always true that I+x| = x? Give reason for your answer.
2. Is it always true that |–x| = x? Give reason for your answer.
Absolute Value Equations
Ex. B. Drop the | | and write the problem into two equations
then solve for x (if any) and label the answer(s) on the real
line.
3. |x| = 2 4. |x| = 5 5. |–x| = 2 6. |–x| = 5
7. |x| = –2 8. |–2x| = 6 9. |–3x| = 6 10. |–x| = –5
11. |3 – x| = –5 12. |3 + x| = 7 13. |x – 9| = 5
14. |5 – x| = 5 15. |4 + x| = 9 16. |2x + 1| = 3
17. |4 – 5x| = 3 18. |3 + 2x| = 7 19. |–2x + 3| = 5
20. |4 – 5x| = –3 21. |2x + 1| – 1= 5 22. 3|2x + 1| – 1= 5
Absolute Value Equations
Ex. C. Solve for x by using the geometric method.
31. |7x – 2| = 1
23. |3 – x| = 5 24. |x – 5| = 5 25. |7 – x| = 3
26. |8 + x| = 9 27. |x + 1| = 3 28. |2x + 1| = 3
30. |3 + 2x| = 729. |–2x + 3| = 2

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4 absolute value and distance x

  • 2. To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance
  • 3. L R To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance
  • 4. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance
  • 5. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance
  • 6. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x.
  • 7. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative.
  • 8. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative. To clarify the two choices for the distance, we put the absolute value symbol “l l” around the expression as l x – y l, to remind us “to take the positive (or 0) one” as the distance between x and y.
  • 9. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative. To clarify the two choices for the distance, we put the absolute value symbol “l l” around the expression as l x – y l, to remind us “to take the positive (or 0) one” as the distance between x and y. Facts about the “l l”:
  • 10. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative. To clarify the two choices for the distance, we put the absolute value symbol “l l” around the expression as l x – y l, to remind us “to take the positive (or 0) one” as the distance between x and y. Facts about the “l l”: 1. l # l ≥ 0 or “distance” is non–negative.
  • 11. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative. To clarify the two choices for the distance, we put the absolute value symbol “l l” around the expression as l x – y l, to remind us “to take the positive (or 0) one” as the distance between x and y. Facts about the “l l”: 1. l # l ≥ 0 or “distance” is non–negative. 2. l x – y l = l y – x l = the distance between x and y so “distance” is symmetric (mutual).
  • 12. L R Length from L to R is R – L To find the distance, a nonnegative number, between two points L and R on a ruler, we subtract: R – L (i.e. Right Pt – Left Pt). Absolute Value and Distance If we don’t know the values of x and y, then the distance is either x – y or y – x. For example, if x = 5 and y = 2, then the distance between them is x – y = 3 where as y – x = –3 is negative. To clarify the two choices for the distance, we put the absolute value symbol “l l” around the expression as l x – y l, to remind us “to take the positive (or 0) one” as the distance between x and y. Facts about the “l l”: 1. l # l ≥ 0 or “distance” is non–negative. 2. l x – y l = l y – x l = the distance between x and y so “distance” is symmetric (mutual). 3. With y = 0, l x l = l –x l = the distance from x (or –x) to 0.
  • 13. 0 5 Hence | 5 | = 5 | 5 | = 5 The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. a distance of 5 Absolute Value and Distance
  • 14. 0 5-5 Hence | 5 | = 5 = | -5 | | 5 | = 5 a distance of 5a distance of 5 The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 15. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 a distance of 5a distance of 5 The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 16. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 17. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 18. |x|= x if x is positive or 0. { 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 19. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 20. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 21. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 22. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 23. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 24. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. Fact I. |x*y| = |x|*|y|. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 25. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 26. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6. Warning: In general |x ± y|  |x| ± |y|. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 27. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6. Warning: In general |x ± y|  |x| ± |y|. For instance, |2 – 3 |  |2| – |3|  |2| + |3|. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 28. |x|= x if x is positive or 0. –x (opposite of x) if x is negative.{ Hence | –5 | = –(–5) = 5. Since the absolute value is never negative, an equation such as |x14 – 3x9 + 1 | = –2 doesn't have any solution. Fact I. |x*y| = |x|*|y|. For example, |–2*3 | = |–2|*|3| = 6. Warning: In general |x ± y|  |x| ± |y|. For instance, |2 – 3 |  |2| – |3|  |2| + |3|. 0 5-5 Hence | 5 | = 5 = | -5 | = distance from 5 or –5 to 0. | -5 | = 5 | 5 | = 5 Because it is a distance measurement, |x| is nonnegative. Algebraic definition of absolute value A “| |” can not be split into two | |’s when adding or subtracting. Because –5 is negative, use the 2nd part of the rule and take its opposite to obtain its abs. value. The geometric meaning of the absolute value of x or |x|, is the distance measured from x to 0 on the real line. Absolute Value and Distance
  • 29. Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. Absolute Value Equations
  • 30. Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. Absolute Value Equations
  • 31. Fact II: If |#| = a, a >0, (where # is any expression) Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. Absolute Value Equations
  • 32. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 33. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 34. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 35. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 In picture, if | x | = 3 then 0 x = 3x = –3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 36. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 b. | –2x | = 5 In picture, if | x | = 3 then 0 x = 3x = –3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 37. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 b. | –2x | = 5 In picture, if | x | = 3 then 0 x = 3x = –3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Drop the “| |” and set the formula to 5 and –5. Absolute Value Equations
  • 38. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 b. | –2x | = 5 –2x = –5 or –2x = 5 In picture, if | x | = 3 then 0 x = 3x = –3 Drop the “| |” and set the formula to 5 and –5. Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Absolute Value Equations
  • 39. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 b. | –2x | = 5 –2x = –5 or –2x = 5 x = 5/2 In picture, if | x | = 3 then 0 x = 3x = –3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Drop the “| |” and set the formula to 5 and –5. Absolute Value Equations
  • 40. Fact II: If |#| = a, a >0, (where # is any expression) then # = –a or # = a. Example A. Solve for x. a. | x | = 3 then x = –3 or x = 3 b. | –2x | = 5 –2x = –5 or –2x = 5 x = –5/2x = 5/2 In picture, if | x | = 3 then 0 x = 3x = –3 Because |x±y|  |x|±|y|, many steps for solving regular equations are not valid for | |-equations. We have to solve an | |-equation by rephrasing it into two equations without the | |. 0 a–a Drop the “| |” and set the formula to 5 and –5. Absolute Value Equations
  • 41. c. | 2x – 3 | = 5 Absolute Value Equations
  • 42. c. | 2x – 3 | = 5 Drop the “| |”. Absolute Value Equations
  • 43. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 Drop the “| |”. Absolute Value Equations
  • 44. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = –2 Drop the “| |”. Absolute Value Equations
  • 45. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = –2 x = –1 Drop the “| |”. Absolute Value Equations
  • 46. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 82x = –2 x = –1 Drop the “| |”. Absolute Value Equations
  • 47. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Absolute Value Equations
  • 48. d. | 2 – 3x | + 2 = 4 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Absolute Value Equations
  • 49. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 50. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 51. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 52. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 53. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. 2 – 3x = 22 – 3x = –2 or c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 54. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. 2 – 3x = 22 – 3x = –2 –3x = –4 or c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 55. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. 2 – 3x = 22 – 3x = –2 –3x = –4 or x = 4/3 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 56. d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. 2 – 3x = 22 – 3x = –2 –3x = 0–3x = –4 or x = 4/3 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4 Absolute Value Equations
  • 57. Absolute Value Equations d. | 2 – 3x | + 2 = 4 We have to isolate the | |-term before the dropping the “| |”. | 2 – 3x | + 2 = 4 | 2 – 3x | = 2 Drop the | |. 2 – 3x = 22 – 3x = –2 –3x = 0 x = 0 –3x = –4 or x = 4/3 c. | 2x – 3 | = 5 2x – 3 = –5 or 2x – 3 = 5 2x = 8 x = 4 2x = –2 x = –1 Drop the “| |”. Incorrect versions: 2–3x+2=–4 or 2–3x+2=4
  • 58. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. Absolute Value Equations
  • 59. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Absolute Value Equations
  • 60. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations
  • 61. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations yx same distance
  • 62. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| yx same distance
  • 63. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. yx same distance
  • 64. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance
  • 65. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance Example B. Solve for x geometrically if |x – 7| = 12.
  • 66. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance Example B. Solve for x geometrically if |x – 7| = 12. We want the locations of x's that are 12 units away from 7.
  • 67. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance Example B. Solve for x geometrically if |x – 7| = 12. We want the locations of x's that are 12 units away from 7. 7 1212 x x
  • 68. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance Example B. Solve for x geometrically if |x – 7| = 12. We want the locations of x's that are 12 units away from 7. 7 1212 x x We see that x = –5 or x = 19.
  • 69. The geometric meaning of | x | as “distance from 0 and x” may be extended to the meaning for |x – y|. The geometric meaning of |x – y| = |y – x| = “distance between x and y”. Note the two versions reflect that “distance” is always mutual in the sense that “going from x to y” is as much as “going from y to x”. Absolute Value Equations |9 – 3| = 6 = |3 – 9| and |(–8) – (–1)| = 7. We can solve for x using this method. yx same distance Example B. Solve for x geometrically if |x – 7| = 12. We want the locations of x's that are 12 units away from 7. 7 1212 x x (Solve it algebraically and verify these are the answers.) We see that x = –5 or x = 19.
  • 70. Absolute Value Equations c r x = c + r Recall |x*y| = |x|*|y|, so we can pull out constant multiple hence |3x| = 3|x| and |3x – 6| = |3(x – 2)| = 3|(x – 2)|. In general, the abs–equation means to find x where |x – c| = r ( ≥ 0) distance between x and c is r. in picture: r x = c – r Hence the solutions for |x – 3 | = 2 are x = 3 – 2 =1 and x = 3 + 2 = 5. Example C. Solve for x geometrically if |–3x + 6| = 4. Draw. Since |–3x – 6| = |–3(x + 2)| = 3|x + 2| so 3|x + 2| = 4 or that |x – (–2)| = 4/3. Hence x = (–2) ± 4/3 or x = –2/3 and x = –3 1 3 –2 x = –2/3x = –3 4/34/3 1 3 |x – (–2)| = 4/3
  • 71. Ex. A. 1. Is it always true that I+x| = x? Give reason for your answer. 2. Is it always true that |–x| = x? Give reason for your answer. Absolute Value Equations Ex. B. Drop the | | and write the problem into two equations then solve for x (if any) and label the answer(s) on the real line. 3. |x| = 2 4. |x| = 5 5. |–x| = 2 6. |–x| = 5 7. |x| = –2 8. |–2x| = 6 9. |–3x| = 6 10. |–x| = –5 11. |3 – x| = –5 12. |3 + x| = 7 13. |x – 9| = 5 14. |5 – x| = 5 15. |4 + x| = 9 16. |2x + 1| = 3 17. |4 – 5x| = 3 18. |3 + 2x| = 7 19. |–2x + 3| = 5 20. |4 – 5x| = –3 21. |2x + 1| – 1= 5 22. 3|2x + 1| – 1= 5
  • 72. Absolute Value Equations Ex. C. Solve for x by using the geometric method. 31. |7x – 2| = 1 23. |3 – x| = 5 24. |x – 5| = 5 25. |7 – x| = 3 26. |8 + x| = 9 27. |x + 1| = 3 28. |2x + 1| = 3 30. |3 + 2x| = 729. |–2x + 3| = 2