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GANDHINAGAR INSTITUTE OF
TECHNOLOGY
MECHANICAL DEPARTMENT
VECTOR CALCULUS AND LINEAR ALGEBRA
NAME :- PARTHIV PAL
ENROLLMENT NO. :- 160120119062
SEMESTER :- 2
TOPIC :- ROW SPACE,COLUMN SPACE AND NULL SPACE & RANK
AND NULLITY
GUIDED BY :- PROF SANDIP PANCHAL
• ROW SPACE:-
The subspace of Rn spanned by the row vectors of A is called the
row space of A.
• COLUMN SPACE:-
The subspace of Rm spanned by the column vector of A is called
the column space of A.
• NULL SPACE:-
The solution space of the homogeneous system of equations
AX=0 is called the null space of A.
BASIS FOR ROW SPACE:-
• THEOREM 1:- Elementary row transformation do not change the row
space and null space of the matrix.
• THEOREM 2:- If B is the row echelon form of A then the row vectors
of B with leading 1’s form of the basis for the row space of B, hence
form a basis for the row space of A.
BASIS FOR COLUMN SPACE :-
THEOREM 1 :- If A and B are the row equivalent matrices then,
(1) A set of the column vector of matrix A is linearly independent
if and only if the corresponding column vector of B are linearly
independent.
THEOREM 2 :- If B is the row echelon form of the matrix then,
(1) The column vector containing the leading 1’s of the row
vector from a basis for the column space of B
NULL SPACE:-
• The basis for the null space of A is the basis for the solution space of
the homogeneous system AX=0.
Example:- Find a basis for the row and column spaces of A.
solution R21-2R1 , R3+R1
R3+R2
(-1/7)R2











0000
7/4110
2541
A =B
Basis for the row space of A = Non zero row of B = {(1,4,5,2) , (0,1,1,4/7)}
Leading 1’s appear in column 1 and 2.
BasisforthecolumnspaceofA= { 









3
1
4
}
RANK AND NULLITY :-
• The dimension of row/column space of a matrix A(the no. of the non
zero rows in the row echelon form of A) is called the rank of A and is
denoted by
• If A is an m*n matrix then,
rank(A) < min (m,n)
Thus the largest possible value of rank(A)=min(m,n) where min(m,n)
means the smaller of m and n.
Ρ(A)
NULLITY :-
• The dimension of the null space of a matrix A is called the nullity of A
and is denoted by nullity(A).
DIMENSION THEOREM :-
• If A is an m*n matrix then,
rank(A)+nullity(A)=n(number of columns)
• If A is an m*n matrix then nullity(A) represents the number of
parameter in the general solution of AX=0.
Example:-Find the rank and nullity of the matrix.
Solution:- Reducing matrix to the row echelon form,
(1/2)R1













000
204
2/101
A
R2-4R1









 

000
000
2/101
A =B
Rank(A) = Number of non zero rows =1
Nullity (A) = n – rank(A)
= 3 – 1
= 2
THANK YOU…

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Row Space,Column Space and Null Space & Rank and Nullity

  • 1. GANDHINAGAR INSTITUTE OF TECHNOLOGY MECHANICAL DEPARTMENT VECTOR CALCULUS AND LINEAR ALGEBRA
  • 2. NAME :- PARTHIV PAL ENROLLMENT NO. :- 160120119062 SEMESTER :- 2 TOPIC :- ROW SPACE,COLUMN SPACE AND NULL SPACE & RANK AND NULLITY GUIDED BY :- PROF SANDIP PANCHAL
  • 3. • ROW SPACE:- The subspace of Rn spanned by the row vectors of A is called the row space of A. • COLUMN SPACE:- The subspace of Rm spanned by the column vector of A is called the column space of A. • NULL SPACE:- The solution space of the homogeneous system of equations AX=0 is called the null space of A.
  • 4. BASIS FOR ROW SPACE:- • THEOREM 1:- Elementary row transformation do not change the row space and null space of the matrix. • THEOREM 2:- If B is the row echelon form of A then the row vectors of B with leading 1’s form of the basis for the row space of B, hence form a basis for the row space of A.
  • 5. BASIS FOR COLUMN SPACE :- THEOREM 1 :- If A and B are the row equivalent matrices then, (1) A set of the column vector of matrix A is linearly independent if and only if the corresponding column vector of B are linearly independent. THEOREM 2 :- If B is the row echelon form of the matrix then, (1) The column vector containing the leading 1’s of the row vector from a basis for the column space of B
  • 6. NULL SPACE:- • The basis for the null space of A is the basis for the solution space of the homogeneous system AX=0.
  • 7. Example:- Find a basis for the row and column spaces of A. solution R21-2R1 , R3+R1 R3+R2
  • 8. (-1/7)R2            0000 7/4110 2541 A =B Basis for the row space of A = Non zero row of B = {(1,4,5,2) , (0,1,1,4/7)} Leading 1’s appear in column 1 and 2. BasisforthecolumnspaceofA= {           3 1 4 }
  • 9. RANK AND NULLITY :- • The dimension of row/column space of a matrix A(the no. of the non zero rows in the row echelon form of A) is called the rank of A and is denoted by • If A is an m*n matrix then, rank(A) < min (m,n) Thus the largest possible value of rank(A)=min(m,n) where min(m,n) means the smaller of m and n. Ρ(A)
  • 10. NULLITY :- • The dimension of the null space of a matrix A is called the nullity of A and is denoted by nullity(A). DIMENSION THEOREM :- • If A is an m*n matrix then, rank(A)+nullity(A)=n(number of columns) • If A is an m*n matrix then nullity(A) represents the number of parameter in the general solution of AX=0.
  • 11. Example:-Find the rank and nullity of the matrix. Solution:- Reducing matrix to the row echelon form, (1/2)R1              000 204 2/101 A
  • 12. R2-4R1             000 000 2/101 A =B Rank(A) = Number of non zero rows =1 Nullity (A) = n – rank(A) = 3 – 1 = 2