3. Evaluating Functions The value of x=2 Substitute 2 in the given equation. Given: f(x)=3x+2 f(2)=3(2)+2 =6+2 =8 Another example! The value of x=3 The value of x=a+1 Given: f(x)=2x+6 f(x)=3x+2 =3(a+1)+2 =2(3)+6 =3a+3+2 =6+6 =3a+5 f(x)=12
4. Inverse Function Consider the function f(x) = 2x + 1. We know how to evaluate f at 3, f(3) = 23 + 1 = 7. In this section it helps to think of f as transforming a 3 into a 7 f(x)=x+3 y=x+3 x=y+3 Example: f(x)=6-2 f(x)=2x y=2x+5 X=6y-2 X+2=6y 3 x=2y+5 (x )=(2y)3 x-5=y 6 6 3 -1 (x)= f 2 (x)=x+2=y 3x=2y f -1 6 2 2 (x)=3x=y f -1 2
7. The exponent should be in order, if one is gone add 0x with the missing exponent 2x4+3x2+4x-36 X+2 2x4+0x3+3x2+4x-36 Now you can divide it. X+2 2 0 3 4 36 -4 8 -22 36 2 -4 11 -18 0 2x3-4x2+11x-18
8. Exponetial Function Given: Another example! 25 ½ 16 3/2 = (52) ½ (24) 3/2 =51 Transpose it. 2 12/2 =5 2 6= 64
10. Logarithm Function Before solving logarithm you need to arrange it first. Example: Log 7 x=0 log x 8 =3 7 0=x X 3=8 After arranging you can solve for the log . Log 7 x=0 log x 8 =3 7 0=x X 3=8 X=1 X 3 =2 3 X=2
11. Law of Logarithm logb MP = p logbM logb MN log3 81 4 = 4 log3 81 = 4(4) =16 log 2 32 log2 (8)(4) log2 8+log2 4 3+2 =5 Transpose 8 & 4 using 2 logb m n log3 9 = log3 27 3 log 3 27 – log 3 3 = 3-1 =2