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Project in Math Submitted by: Nikka Verone C. Bacongon Submitted to:  Sir Cadiz
1st quarter
Evaluating Functions The value of x=2 Substitute  2 in the given equation. Given: f(x)=3x+2 f(2)=3(2)+2       =6+2       =8 Another example! The value of x=3 The value of x=a+1 Given:  f(x)=2x+6  f(x)=3x+2 =3(a+1)+2 =2(3)+6 =3a+3+2 =6+6 =3a+5  f(x)=12
Inverse Function Consider the function f(x) = 2x + 1. We know how to evaluate f at 3, f(3) = 23 + 1 = 7.  In this section it helps to think of f as transforming a 3 into a  7  f(x)=x+3  y=x+3 x=y+3 Example: f(x)=6-2  f(x)=2x  y=2x+5 X=6y-2 X+2=6y 3 x=2y+5 (x )=(2y)3 x-5=y 6       6 3 -1 (x)= f 2 (x)=x+2=y 3x=2y f -1 6 2     2 (x)=3x=y f -1 2
2nd Quarter
Synthetic division 2x8-6x2+11x-6 X-2 2  -6  11  -6 2x2-2x+7+    8 +2 4  -4  14 X-2 2  -2  7  8 r. Add
The exponent should be in order, if one is gone add 0x with the missing exponent 2x4+3x2+4x-36 X+2 2x4+0x3+3x2+4x-36 Now you can divide it. X+2 2  0  3    4     36  -4  8  -22   36 2  -4 11  -18   0 2x3-4x2+11x-18
Exponetial Function Given: Another example!  25 ½ 16 3/2  = (52) ½ (24) 3/2 =51 Transpose it. 2 12/2 =5 2 6= 64
3rd Quarter
Logarithm Function Before solving logarithm you need to arrange it first. Example: Log 7 x=0 log x  8 =3 7 0=x X 3=8 After arranging you can solve for the log . Log 7 x=0 log x  8 =3 7 0=x X 3=8 X=1 X 3 =2 3 X=2
Law of Logarithm logb MP = p logbM logb MN  log3 81 4 = 4 log3 81 = 4(4) =16 log 2 32 log2 (8)(4) log2 8+log2 4 3+2 =5 Transpose 8 & 4 using 2 logb m  n  log3 9 = log3 27 3  log 3 27 – log 3 3 = 3-1 =2
4th Quarter
Parts of a circle Tangent Radius Point of tangency Diameter Center Point Chord Secant
Radian   Degree Degree to Radian r=  πd 180o Example Cancel the degrees And find the GCF of the  Given numbers. 150oπ 180o 150 π 30 180 5 π 6
Radian to Degrees Example: The value of Pi is 180o 5 π 12 5(180o)     12 900o   12o =75o
End

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Project in Mathematics. Functions

  • 1. Project in Math Submitted by: Nikka Verone C. Bacongon Submitted to: Sir Cadiz
  • 3. Evaluating Functions The value of x=2 Substitute 2 in the given equation. Given: f(x)=3x+2 f(2)=3(2)+2 =6+2 =8 Another example! The value of x=3 The value of x=a+1 Given: f(x)=2x+6 f(x)=3x+2 =3(a+1)+2 =2(3)+6 =3a+3+2 =6+6 =3a+5 f(x)=12
  • 4. Inverse Function Consider the function f(x) = 2x + 1. We know how to evaluate f at 3, f(3) = 23 + 1 = 7. In this section it helps to think of f as transforming a 3 into a  7 f(x)=x+3 y=x+3 x=y+3 Example: f(x)=6-2 f(x)=2x y=2x+5 X=6y-2 X+2=6y 3 x=2y+5 (x )=(2y)3 x-5=y 6 6 3 -1 (x)= f 2 (x)=x+2=y 3x=2y f -1 6 2 2 (x)=3x=y f -1 2
  • 6. Synthetic division 2x8-6x2+11x-6 X-2 2 -6 11 -6 2x2-2x+7+ 8 +2 4 -4 14 X-2 2 -2 7 8 r. Add
  • 7. The exponent should be in order, if one is gone add 0x with the missing exponent 2x4+3x2+4x-36 X+2 2x4+0x3+3x2+4x-36 Now you can divide it. X+2 2 0 3 4 36 -4 8 -22 36 2 -4 11 -18 0 2x3-4x2+11x-18
  • 8. Exponetial Function Given: Another example! 25 ½ 16 3/2 = (52) ½ (24) 3/2 =51 Transpose it. 2 12/2 =5 2 6= 64
  • 10. Logarithm Function Before solving logarithm you need to arrange it first. Example: Log 7 x=0 log x 8 =3 7 0=x X 3=8 After arranging you can solve for the log . Log 7 x=0 log x 8 =3 7 0=x X 3=8 X=1 X 3 =2 3 X=2
  • 11. Law of Logarithm logb MP = p logbM logb MN log3 81 4 = 4 log3 81 = 4(4) =16 log 2 32 log2 (8)(4) log2 8+log2 4 3+2 =5 Transpose 8 & 4 using 2 logb m n log3 9 = log3 27 3 log 3 27 – log 3 3 = 3-1 =2
  • 13. Parts of a circle Tangent Radius Point of tangency Diameter Center Point Chord Secant
  • 14. Radian Degree Degree to Radian r=  πd 180o Example Cancel the degrees And find the GCF of the Given numbers. 150oπ 180o 150 π 30 180 5 π 6
  • 15. Radian to Degrees Example: The value of Pi is 180o 5 π 12 5(180o) 12 900o 12o =75o
  • 16. End