The document contains 10 questions and answers about physics quantities and measurement. It discusses prefixes like micro, nano, and pico and their relationships. It also covers converting between units, writing measurements in standard form, significant figures, and calculating the area of a chocolate wrapper given its length and width.

1. Written and compose by:    
hysics Physical quantities and Measurement Chapter 1
Q No 1: Express the following quantities using prefixes.
‫ربمن‬‫وسال‬1:‫رکںی،۔‬‫اظرہ‬‫ےس‬‫دمد‬‫یک‬‫ز‬‫س‬‫ک‬‫ف‬‫رپی‬‫وک‬‫دقماروں‬‫ذلی‬‫دنمرہج‬
--------------------------------------------
Q No 2: How do the prefixes micro, nano and pico related to each other?
‫ربمن‬‫وسال‬2:‫رکںی۔‬‫ایبن‬‫قلعت‬‫ںیم‬‫آسپ‬‫اک‬‫وکیپ‬،‫ونین‬،‫امرکیئو‬‫ز‬‫س‬‫ک‬‫ف‬‫رپی‬
Ans : As we know that 12 9 6
10 , 10 , 10Pico Nano Micro  
  
So 3 9
1 10 10pico  
  3
1 10pico nano
 
Also 3 6
1 10 10nano  
  6
1 10nano 
  µ
Q No 3:Your Hair grow at the rate of 1mm per day. Find their growth rate in 1
nms
‫ربمن‬‫وسال‬3:‫روزاہن‬‫ابل‬‫ےک‬‫آپ‬'mm1'‫ڑبےتھ‬‫ےس‬‫رشح‬‫یک‬‫رشح‬‫یک‬‫ڑبےنھ‬‫ےک‬‫۔ان‬‫ںیہ‬''‫۔‬‫رکںی‬‫م‬‫ولعم‬‫ںیم‬
Ans : Given : Growth of Hair per day = 1mm per day. Find: Growth in 1
nms
=?
Solution: As we know 3
1 1 10mm m
  and 4
1 86400sec 8.64 10day s  
Growth of Hair per day
3
3 4 1
4
1 10 1
10
8.648.64 10
m
ms
s

  
  

7 1 2 7 1
0.1157 10 11.57 10 10ms ms    
     9 1 1
11.57 10 11.57ms nms  
   Ans
Q No 4: Rewrite the following in Standard form.
‫ربمن‬‫وسال‬4:‫وک‬‫ذلی‬‫درج‬‫ڈنیٹس‬‫رڈ‬‫ےیھکل۔‬‫ںیم‬‫افرم‬
(a) 27
1168 10

27 3 27 24
1168 10 1.168 10 10 1.168 10  
     
------------------------
(c) 5
725 10 kg

5 2 5 3
725 10 7.25 10 10 10kg g 
     7.25g
----------------------------
(b) 5
32 10
5 1 5 6
32 10 3.2 10 10 3.2 10     
----------------------------
(d) 8
0.02 10

8 8 2 10
0.02 10 2 10 10 2 10   
     
--------------------------------
P
(a) 5000g
5000 5 1000g g  3
5 10 g  5kg
------------------------
(c) 10
52 10 kg

10
52 10 kg
 10 3 10 3
52 10 10 52 10g g  
    
1 7 1 7
5.2 10 10 5.2 10g g 
     6
5.2 10 5.2g g
  
----------------------------
(b) 2000000W
2000000W 6
2 10  2MW
----------------------------
(d) 8
225 10 s

8
225 10 s
 2 8 2 8
2.25 10 10 2.25 10s s 
    
6
2.25 10 2.25s s
   Ans
--------------------------------

2. Written and compose by:    
Q No 5: Write the following quantities in standard form.
‫ربمن‬‫وسال‬5:‫ڈنیٹس‬‫وک‬‫ذلی‬‫درج‬‫رڈ‬‫ےیھکل۔‬‫ںیم‬‫افرم‬
(a) 6400km
3
6400 6.4 10km km 
------------------------
(c) 1
300,000,000ms
1 8 1
300,000,000 3 10ms ms 
 
----------------------------
(b) 380,000km
5
380000 3.8 10km km 
----------------------------
(d) second in a day
1 day = 24 60 60sec 86400sec  
4
8.64 10 s 
--------------------------------
Q No 7: A screw gauge has 50 divisions on its circular scale. The pitch of the screw gauge is 0.5mm.Find L.C?
‫ربمن‬‫وسال‬7:‫رپ‬‫لیکس‬‫رسرلک‬‫یک‬‫جیگ‬‫رکسوی‬‫اکی‬50‫چپ‬‫یک‬‫جیگ‬‫رکسوی‬‫۔‬‫ںیہ‬‫درےج‬0.5‫۔‬‫رکںی‬‫ولعمم‬‫ٹن‬‫اکو‬‫ٹ‬‫س‬‫لی‬‫اک‬‫اس‬‫۔‬‫ےہ‬‫رٹیم‬‫یلم‬
Ans : Given : No of division on scale = 50 Pitch = 0.5mm Find : L.C=?
0.5
. 0.01
. 50
Pitch mm
L C mm
No ofDiv
   . Or 0.001 cm
0.01
10
cm
Q No 8: Which of the following quantities have three significant figure?
‫ربمن‬‫وسال‬8:‫دنہوسں‬‫امہ‬‫ںیم‬‫دقماروں‬‫نک‬‫ںیم‬‫ذلی‬‫درج‬‫دعتاد‬‫یک‬3‫۔‬‫ےہ‬
(a) 3.0066m (b) 0.00309kg (c) 27
5.05 10 kg
 (d) 301.0s
Ans ( b , c )
Q No 9: What are the following significant figures in the following measurement?
‫ربمن‬‫وسال‬9:‫رکںی‬‫ولعمم‬‫دعتاد‬‫یک‬‫دنہوسں‬‫امہ‬‫ےک‬‫دقماروں‬‫ذلی‬‫درج‬‫۔‬
(a) 1.009m (b) 0.00450kg (c) 27
1.66 10 kg
 (d) 2001s
Significant Fig: (a) 4 (b) 3 (c) 3 (d) 4
Q No 10: A chocolate wrapper is 6.7 cm long and 5.4 cm wide. Calculate its area up to reasonable number of S.F?
‫وس‬‫ربمن‬‫ال‬10:‫یک‬
‫ئ‬
‫پ‬‫ری‬‫اچٹیلک‬6.7 cm‫اور‬‫ابملیئ‬5.4cm‫۔‬‫رکںی‬‫م‬‫ولعم‬‫اریای‬‫اک‬‫اس‬‫۔‬‫ےہ‬‫وچڑایئ‬
Ans : Given: L = 6.7cm , W = 5.4 cm Find : Area =?
Formula: A = L  W
A = 2
6.7 5.4 36.18cm cm cm 