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MCQs
THERMODYNAMICS
Physics Without Fear
www.physicsbeckons.wordpress.com
Zeroth law of thermodynamics: Two systems A and B each in thermal equilibrium
with a third system C are in thermal equilibrium with each other.
The thermodynamic equilibrium implies that the systems are at same temperature.
The temperature of a system is a bulk property. It can be assigned to an
assembly of a large number of particles but not to an individual particle.
Temperature indicates the direction of net transfer of heat between two
bodies.
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Thermodynamics: At a glance
The temperature is measured on a scale which is based on some
thermodynamic property. If thermodynamic property (e.g. electrical
resistance) varies linearly with temperature then the temperature of the
body whose resistance is is given by
𝑡𝑅
100
=
𝑅𝑡 − 𝑅0
𝑅100 − 𝑅0
T (Absolute ) = t (celsius )+ 273.15.
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Thermodynamics: At a glance
Heat: It is energy in transit. It is roughly the sum of kinetic energies of random
motion of particles constituting the system.
It is not a state variable like temperature, volume, pressure or internal energy.
Internal energy depends only on the actual state of a system and not on how
that state is attained. Therefore, change in internal energy is independent of the
path taken by the system for the change.
The equation of state for an ideal gas:
For n moles 𝐏𝐕 = 𝒏𝑹𝑻 where R = 8.31 J/mol K.
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Thermodynamics: At a glance
First law of thermodynamics:
If a quantity of heat dQ is given to a system, it changes its internal energy by
amount dU and does work dW; we have
𝑑𝑄 = 𝑑𝑈 + 𝑑𝑊
The first law of thermodynamics is just a manifestation of the principle of
conservation of energy.
If the system is a gas and the work is done under constant pressure P resulting in a
changes dV in the volume of the gas, then dW=PdV and the first law reads
𝑑𝑄 = 𝑑𝑈 + PdV
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Thermodynamics: At a glance
Indicator diagram : A graph between P and V of a system is called an indicator
diagram. The figure shows the graph when pressure remains constant and the volume
changes from V1 to V2. The work done on the system is the area under the PV curve.
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Thermodynamics: At a glance
If P is not constant, the work done is given by
www.physicsbeckons.wordpress.com
Thermodynamics: At a glance
The work done is area under the indicator (P-V) graph.
Remember: An adiabatic P-V graph is steeper than an isotherm.
Work done in an isothermal process:
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Thermodynamics: At a glance
Work done in an adiabatic process:
If the change in the internal energy is zero, the first law gives
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Thermodynamics: At a glance
This means that whatever heat energy is supplied to the system, it is spent
in doing work by the system.
If heat is extracted from the system, then work must be done on the
system.
Efficiency of an ideal engine (Carnot Engine) is given by,
www.physicsbeckons.wordpress.com
Thermodynamics: At a glance
η = 1 −
𝑊𝑜𝑟𝑘 𝑜𝑢𝑡𝑝𝑢𝑡
𝐻𝑒𝑎𝑡 𝑖𝑛𝑝𝑢𝑡
= 1 −
𝑄2
𝑄1
= 1 −
𝑇2
𝑇1
1. A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much
should the temperature of the source be increased so as to increase its efficiency
by 50% of original efficiency?
1) 380 K
2) 275 K
3) 325 K
4) 250 K
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2. If Q, E and W denote respectively the heat added, change in internal energy
and the work done in a closed cycle process, then:
1) Q = 0
2) W = 0
3) Q = W = 0
4) E = 0
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Q3. In thermodynamic processes which of the following statements is not true?
1) In an adiabatic process PVγ = constant
2) In an adiabatic process the system is insulated from the surroundings
3) In an isochoric process pressure remains constant
4) In an isothermal process the temperature remains constant.
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Q4.The internal energy change in a system that has absorbed 2 Kcal of heat and
done 500 J of work is:
1) 7900 J
2) 8900 J
3) 6400 J
4) 5400 J
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Q5. If ΔU and ΔV represent the increase in internal energy and work done by the
system respectively in a thermodynamic process, which of the following is
true?
1) ΔU = -ΔW, in an isothermal process
2) ΔU = -ΔW, in an adiabatic process
3) ΔU = ΔW, in an isothermal process
4) ΔU = ΔW, in an adiabatic process
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Q6. During an isothermal expansion, a confined gas does –150 J of work against
its surroundings. This implies that
1) 150 J of heat has been added to the gas
2) 150 J of heat has been removed from the gas
3) 300 J has been added to the gas
4) no heat is transferred because the process is isothermal
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Q7. A thermodynamic system is taken through the cycle ABCD as shown in
figure. Heat rejected by the gas during the cycle is:
1) PV
2) 2PV
3) 4PV
4)1/2 PV
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V
A B
Q8. A gas is taken through the cycle A B C A, as shown. What is the net work done
by the gas?
1) Zero
2) –2000 J
3) 2000 J
4) 1000 J
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Q9. Pick the only reversible process among the following processes:
1) Movement of a particle on a frictionless track
2) Passage of current through a resistor
3) Passage of heat from water at 40 °C to water at 20 °C
4) Expansion of a gas coming out of a nozzle
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Q10. Pick the one that is not a state variable of a thermodynamic system:
1) Temperature
2) Heat
3) Volume
4) Internal energy
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Q11. The second law of thermodynamics is concerned essentially with
1) nature of heat flow
2) amount of heat flow
3) direction of heat flow
4) speed of heat flow
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Q12. Consider the following two statements:
A: A system is in steady state if its properties are independent of space.
B: A system is in steady state if its properties are independent of time.
Which of the following statements is true?
1) Both A and B are true
2) A is false but B is true
3) A is true but B is false
4) Both A and B are false
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Q13. Consider a refrigerator in a kitchen. Take the refrigerator and everything in
it to be our system. Which best describes the system's surroundings?
1) All of the air in the kitchen
2) Pans and gas stove in the kitchen
3) The air inside the refrigerator
4) Everything in the universe external to the system
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Q14: Two moles of a gas undergo expansion from volume V to 10V at a
temperature of 27°C. The work done in the process in J is
1) 4.5 × 102
2) 1.0 × 103
3) 5.0 × 103
4) 1.1 × 104
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Q15: Two moles of a monatomic gas are taken adiabatically from a state where
its temperature is 27 °C to a state where its temperature is 127 °C. The work done
in the process in J is
1) 2.5 × 103
2) 4.2 × 103
3) 6.8 × 105
4) 1.1 × 106
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Q16: A system goes to state 1 one from state 2. It can take paths labelled A, B, C.
The change in internal energy of the system is
1) smallest on A
2) smallest on B
3) smallest on C
4) same on all paths.
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A
B
C
V
P
Q17: An ideal gas heat engine operates between 227 °C and 127 °C. It absorbs
6.0 × 104 cal of heat at higher temperature. Amount of heat converted into work
is:
1) 4.8 × 104 cal
2) 6.0 × 104 cal
3) 2.4 × 104 cal
4) 1.2 × 104 cal
www.physicsbeckons.wordpress.com
www.physicsbeckons.wordpress.com
Q18. An engine has efficiency of 1/6. When the temperature of sink
is reduced by 62 °C, its efficiency is doubled. Temperature of the
source is:
1) 99 °C
2) 124 °C
3) 37 °C
4) 62 °C
Q19: Which of the following processes is reversible?
1) Transfer of heat by conduction
2) Transfer of heat by radiation
3) Isothermal compression
4) Electrical heating of a nichrome wire.
www.physicsbeckons.wordpress.com
www.physicsbeckons.wordpress.com
KEY
1. (4)
2. (4)
3. (3)
4. (1)
5. (4)
6. (2)
7. (2)
8. (4)
9. (1)
10. (2)
11. (3)
12. (2)
13. (4)
14. (4)
15. (1)
16. (4)
17. (4)
18. (1)
19. (3)
www.physicsbeckons.wordpress.com
ikg54@yahoo.co.in

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thermodynamics-mcqs.pdf

  • 2. Zeroth law of thermodynamics: Two systems A and B each in thermal equilibrium with a third system C are in thermal equilibrium with each other. The thermodynamic equilibrium implies that the systems are at same temperature. The temperature of a system is a bulk property. It can be assigned to an assembly of a large number of particles but not to an individual particle. Temperature indicates the direction of net transfer of heat between two bodies. www.physicsbeckons.wordpress.com Thermodynamics: At a glance
  • 3. The temperature is measured on a scale which is based on some thermodynamic property. If thermodynamic property (e.g. electrical resistance) varies linearly with temperature then the temperature of the body whose resistance is is given by 𝑡𝑅 100 = 𝑅𝑡 − 𝑅0 𝑅100 − 𝑅0 T (Absolute ) = t (celsius )+ 273.15. www.physicsbeckons.wordpress.com Thermodynamics: At a glance
  • 4. Heat: It is energy in transit. It is roughly the sum of kinetic energies of random motion of particles constituting the system. It is not a state variable like temperature, volume, pressure or internal energy. Internal energy depends only on the actual state of a system and not on how that state is attained. Therefore, change in internal energy is independent of the path taken by the system for the change. The equation of state for an ideal gas: For n moles 𝐏𝐕 = 𝒏𝑹𝑻 where R = 8.31 J/mol K. www.physicsbeckons.wordpress.com Thermodynamics: At a glance
  • 5. First law of thermodynamics: If a quantity of heat dQ is given to a system, it changes its internal energy by amount dU and does work dW; we have 𝑑𝑄 = 𝑑𝑈 + 𝑑𝑊 The first law of thermodynamics is just a manifestation of the principle of conservation of energy. If the system is a gas and the work is done under constant pressure P resulting in a changes dV in the volume of the gas, then dW=PdV and the first law reads 𝑑𝑄 = 𝑑𝑈 + PdV www.physicsbeckons.wordpress.com Thermodynamics: At a glance
  • 6. Indicator diagram : A graph between P and V of a system is called an indicator diagram. The figure shows the graph when pressure remains constant and the volume changes from V1 to V2. The work done on the system is the area under the PV curve. www.physicsbeckons.wordpress.com Thermodynamics: At a glance
  • 7. If P is not constant, the work done is given by www.physicsbeckons.wordpress.com Thermodynamics: At a glance The work done is area under the indicator (P-V) graph.
  • 8. Remember: An adiabatic P-V graph is steeper than an isotherm. Work done in an isothermal process: www.physicsbeckons.wordpress.com Thermodynamics: At a glance Work done in an adiabatic process:
  • 9. If the change in the internal energy is zero, the first law gives www.physicsbeckons.wordpress.com Thermodynamics: At a glance This means that whatever heat energy is supplied to the system, it is spent in doing work by the system. If heat is extracted from the system, then work must be done on the system.
  • 10. Efficiency of an ideal engine (Carnot Engine) is given by, www.physicsbeckons.wordpress.com Thermodynamics: At a glance η = 1 − 𝑊𝑜𝑟𝑘 𝑜𝑢𝑡𝑝𝑢𝑡 𝐻𝑒𝑎𝑡 𝑖𝑛𝑝𝑢𝑡 = 1 − 𝑄2 𝑄1 = 1 − 𝑇2 𝑇1
  • 11. 1. A Carnot engine whose sink is at 300 K has an efficiency of 40%. By how much should the temperature of the source be increased so as to increase its efficiency by 50% of original efficiency? 1) 380 K 2) 275 K 3) 325 K 4) 250 K www.physicsbeckons.wordpress.com
  • 12. 2. If Q, E and W denote respectively the heat added, change in internal energy and the work done in a closed cycle process, then: 1) Q = 0 2) W = 0 3) Q = W = 0 4) E = 0 www.physicsbeckons.wordpress.com
  • 13. Q3. In thermodynamic processes which of the following statements is not true? 1) In an adiabatic process PVγ = constant 2) In an adiabatic process the system is insulated from the surroundings 3) In an isochoric process pressure remains constant 4) In an isothermal process the temperature remains constant. www.physicsbeckons.wordpress.com
  • 14. Q4.The internal energy change in a system that has absorbed 2 Kcal of heat and done 500 J of work is: 1) 7900 J 2) 8900 J 3) 6400 J 4) 5400 J www.physicsbeckons.wordpress.com
  • 15. Q5. If ΔU and ΔV represent the increase in internal energy and work done by the system respectively in a thermodynamic process, which of the following is true? 1) ΔU = -ΔW, in an isothermal process 2) ΔU = -ΔW, in an adiabatic process 3) ΔU = ΔW, in an isothermal process 4) ΔU = ΔW, in an adiabatic process www.physicsbeckons.wordpress.com
  • 16. Q6. During an isothermal expansion, a confined gas does –150 J of work against its surroundings. This implies that 1) 150 J of heat has been added to the gas 2) 150 J of heat has been removed from the gas 3) 300 J has been added to the gas 4) no heat is transferred because the process is isothermal www.physicsbeckons.wordpress.com
  • 17. Q7. A thermodynamic system is taken through the cycle ABCD as shown in figure. Heat rejected by the gas during the cycle is: 1) PV 2) 2PV 3) 4PV 4)1/2 PV www.physicsbeckons.wordpress.com V A B
  • 18. Q8. A gas is taken through the cycle A B C A, as shown. What is the net work done by the gas? 1) Zero 2) –2000 J 3) 2000 J 4) 1000 J www.physicsbeckons.wordpress.com
  • 19. Q9. Pick the only reversible process among the following processes: 1) Movement of a particle on a frictionless track 2) Passage of current through a resistor 3) Passage of heat from water at 40 °C to water at 20 °C 4) Expansion of a gas coming out of a nozzle www.physicsbeckons.wordpress.com
  • 20. Q10. Pick the one that is not a state variable of a thermodynamic system: 1) Temperature 2) Heat 3) Volume 4) Internal energy www.physicsbeckons.wordpress.com
  • 21. Q11. The second law of thermodynamics is concerned essentially with 1) nature of heat flow 2) amount of heat flow 3) direction of heat flow 4) speed of heat flow www.physicsbeckons.wordpress.com
  • 22. Q12. Consider the following two statements: A: A system is in steady state if its properties are independent of space. B: A system is in steady state if its properties are independent of time. Which of the following statements is true? 1) Both A and B are true 2) A is false but B is true 3) A is true but B is false 4) Both A and B are false www.physicsbeckons.wordpress.com
  • 23. Q13. Consider a refrigerator in a kitchen. Take the refrigerator and everything in it to be our system. Which best describes the system's surroundings? 1) All of the air in the kitchen 2) Pans and gas stove in the kitchen 3) The air inside the refrigerator 4) Everything in the universe external to the system www.physicsbeckons.wordpress.com
  • 24. Q14: Two moles of a gas undergo expansion from volume V to 10V at a temperature of 27°C. The work done in the process in J is 1) 4.5 × 102 2) 1.0 × 103 3) 5.0 × 103 4) 1.1 × 104 www.physicsbeckons.wordpress.com
  • 25. Q15: Two moles of a monatomic gas are taken adiabatically from a state where its temperature is 27 °C to a state where its temperature is 127 °C. The work done in the process in J is 1) 2.5 × 103 2) 4.2 × 103 3) 6.8 × 105 4) 1.1 × 106 www.physicsbeckons.wordpress.com
  • 26. Q16: A system goes to state 1 one from state 2. It can take paths labelled A, B, C. The change in internal energy of the system is 1) smallest on A 2) smallest on B 3) smallest on C 4) same on all paths. www.physicsbeckons.wordpress.com A B C V P
  • 27. Q17: An ideal gas heat engine operates between 227 °C and 127 °C. It absorbs 6.0 × 104 cal of heat at higher temperature. Amount of heat converted into work is: 1) 4.8 × 104 cal 2) 6.0 × 104 cal 3) 2.4 × 104 cal 4) 1.2 × 104 cal www.physicsbeckons.wordpress.com
  • 28. www.physicsbeckons.wordpress.com Q18. An engine has efficiency of 1/6. When the temperature of sink is reduced by 62 °C, its efficiency is doubled. Temperature of the source is: 1) 99 °C 2) 124 °C 3) 37 °C 4) 62 °C
  • 29. Q19: Which of the following processes is reversible? 1) Transfer of heat by conduction 2) Transfer of heat by radiation 3) Isothermal compression 4) Electrical heating of a nichrome wire. www.physicsbeckons.wordpress.com
  • 30. www.physicsbeckons.wordpress.com KEY 1. (4) 2. (4) 3. (3) 4. (1) 5. (4) 6. (2) 7. (2) 8. (4) 9. (1) 10. (2) 11. (3) 12. (2) 13. (4) 14. (4) 15. (1) 16. (4) 17. (4) 18. (1) 19. (3)