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Association Between Variables :Nominal and
Ordinal
 One of the most useful and popular tools in social science
Research is cross tabulation or joint contingency analysis,using in
statitics known a chi-square.It is one of the most simpliest and
widely used non-parametric test in statistical work.It makes no
assumptions about the population being sampled.
 According to Anthony Walsh,
‘The chi-square is a test of significance that is used for discrete data
in the form of frequencies ,percentages or proportions known as
non-parametric statistics
 According to Spigel,
‘A measure of discrepancy existing between the observed and
expected frequency which is supplied by the X2 (chi square)
statistics.’
The formula says that chi-square or X is the sum we will get if we
1. Substract fr from fo for each other of the value.
2. Divide each squared difference by fe.
3.Square each of the differences
4. Sum all of answers.
[statistics for Management ,Richard I.Levin,David.S. Rubin, 7th edition, p-
572]
Assumptions For The Use of Chi-square:
1.We have independent random sample.
2.The data are nominal or ordinal level.
3. The data are no expected cell frequencies in less than 5.
4.Mutually exclusive
Significanceof chi-square
Chi-square test has some applications:
As a non-parametric statistical test chi square may be used-
1.As a test of goodness of fit and
2. As a test of independence
3. X-test is simply a technically judging the significance of
the measure of degree of relation between two attributes.
Condition of Chi-square Test:
 The experimental data (sample observation) must be
independent of each othar.
 The sample data must be drawn at random from the target
population.
 The data should be expressed i n original unit.
 There should not be less than five observations in any one
Limitations of chi-square test
 The data is from a random sample
 This test applied in a four fold table,will not give a
reliable result with one degree of freedom if the expected
value in any cell is less than 5
 This test tells the presence or absence of an Association
between the events but doesn’t measure the strength of
association.
 This test to be applicable when the individual
observation of sample are occurance of one individual
observation(event ) in the sample under considerations.
 This test doesn’t indicate the cause and effect ,it only
tells the probability of occurance of association by
characteristics
Chi
square
continuous
Non-
parametric
One tailed
test
Means of chi-
square is
given by
degrees of
freedom
Advantages
Easy to calculate
& evaluate
Used on nominal
data
Can be applied in
a broad area
Can test
association
between variables
Identifies
difference between
observed and
expected values.
Disadvantages
Can’t use
percentages
Data must be
numerical catagories
of l are not good to
compare
Test become invalid
if any of the
expected values are
5
Numbers of
observations must be
more than 20.
Quite complicated
Proportion reduction in error
The concept of PRE measures are derived by
comparing the errors, made in predicting the dependent
variables by using the independent variables with errors
made when making predictions that use information about
the independent variable.Not all measures of association
are PRE measures but whenever possible ,We use PRE
measures because they have a standerd interpretation as
indicated by the conceptual formula for pre measures.
 According to Franfort and Leon Guerrero, 2004:366
‘All pre measures are based on comparing predictive
error levels that results from each of two methos of
prediction’
Formula and Types
PRE= (E1 – E2) / E1
Where,
E1= Errors of prediction made when the
independent variable is ignored.
E2= Errors of prediction made when the prediction
is based on the independent variable
There are two kinds of most commonly used PRE
measures of association are,
1.Lamda ()
2.Gamma ()
 Lamda is defined as an asymmetrical measures of association that
is suitable for use with nominal variables.It may be range from 0.0
to 1.0 .Lamda provides us with an indication of the strength of the
relationship between independent and dependent variables.
As an assymetrical measure of association lamdas>>>> may
vary depending on which variable is considered the dependent
variables and which variables is considered the independent
variable. Lambda may range in value from 0.0 to 1.0. Zero
indicates that there is nothing to be gained by using the
independent variable to predict the dependent variable. In other
words, the independent variable does not, in any way, predict the
dependent variable. A lambda of 1.0 indicates that the
independent variable is a perfect predictor of the dependent
variable. That is, by using the independent variable as a predictor,
we can predict the dependent variable without any error.
Properties of Lamda
 It is an assymetrical statistics.
 The value of lamda varies which variable is
taken as dependent .
 It is appropriate for nominal variables
 It involves an unrestrictive minimizing of
errors.
 It has a cosiderably larger numerical value.
 It ranges from 0.0 to 1.00.
 It doesn’t give a direction of association
Formula
 There is no sample test of statistical
significance for lamda.
Lamda= E1-E2/E1
To calculate lamda, we need 2 numbers.
E1= Errors of prediction made when the
independent variable is ignored.
E2= Errors of prediction made when the
prediction is based on the independent
variable
 Gamma is defined as a symmetrical measure of
association suitable for use with ordinal variable
or with dichotomous nominal variables.
It can be vary from 0.0 to 1.0 and provides us
with an indication of the strength of the
relationship between two variables where as
lamba is an asymmetrical measure of associations
.Gamma is a symmetrical measure of association
.This means that the value of gamma will be the
same regardless of which variable is considered
the independent variable.
Properties of Gamma
Gamma
Two
parameter
femily of
probability
distribution
Appropriate
for ordinal
level
Ranges
between -1
and +1.
Origin:
This method of finding out co-variability or the lack of
it between two variables was developed by the British
psychologist Charles and Edward Spearman in 1904. This
measure is especially useful when quantitative measure of
certain factors can not be fixed but the individuals in the
group can be arranged in order there by obtaining for each
individual a number indicating his rank in the group.
In any event, the rank correlation coefficient is
applied to a set of ordinal rank numbers with 1 for the
individual ranked first in quantity or quality and so on. N for
the individual ranked last in a group of N individual.
Formula of rank correlation
coefficient:
R=1- σ Σ D2 / N (n2-1)
Where R donates rank coefficient of correlation and D refers to the
difference of ranks between paired items in two serious.The
value of this coefficient also lies between +1 and -1 .
When R is +1 there is complete agreement in the order of the ranks
and they are in opposite directions.
When R is -1 There is complete agreement in the order of the ranks
and they are in opposite directions.
This will be clear from the following:
R1 R2 D
(R1-R2
)
D2 R1 R2 D
(R1-R2
)
D2
1 1 0 0 1 3 -2 4
2 2 0 0 2 2 0 0
3 3 0 0 3 1 2 4
∑D2 = 0 ∑D2 = 8
 R= 1-6 ∑D2 ÷N (n2-1) R = 1-6 ∑D2 ÷N (n2-1)
= 1- 6 ÷3 (32 -1) = 1-6×8 3 (32 -1)
= 1- 0÷ 3 (9-1) =1- 6×8 ÷ 3 (9-1)
= 1-0 = 1- 48 ÷ 3 ×8
= 1- 48 ÷ 24
= 1-2
= -1.
To rank correlation we may have two types of problems
• Where the ranks are given
• Where ranks are not given
In rank correlation ,we may have two types of problems:
1.Where the actual ranks are given
2.Where ranks are not given
Calculation of rank correlation co-efficient:
Calculate the rank correlation co-efficient for the
following data of marks of 2 tests given to candidates
for a clerical job.
Preliminary Test: 92,89,87,86,83,77,71,63,53,50
Final Test: 86,83, 91,77,68,85,52,82,37,57
Calculation of rank correlation co-
efficient
Preliminar
y test (X)
Final test
(Y)
RX RY RX-RY (RX-RY)2
92 86 1 2 1 1
89 83 2 4 -2 4
87 91 3 1 2 4
86 77 4 6 2 4
83 68 5 7 -2 4
77 85 6 3 3 9
71 52 7 9 -2 4
63 82 8 5 3 9
53 37 9 10 1 1
50 57 10 8 2 4
N=10 Σ D2 = 44
Now,
R = 1-6 ∑D2 ÷N (n2-1)
= 1- 6× 44 ÷10{(10)2 -1}
= 1-6 × 44 ÷ 10 (1000-1)
= 1-0.267
= 0.733
Here, there is a high degree of positive co-rrelation between
preliminary and the final list.
Merits of the rank Method
 This method is simpler to understand and easier to apply
compared to the karl pearson’s method.
 Can use Where we are given the ranks and not the actual
data
 Can use where the data are of a qualitative nature like
honesty, efficiency, intelligence etc.
Limitations:
 Can not be used for finding out correlation in a group
frequency.
 Where the number of observations execd 30 , the
calculations become quite tedious an require a lot of time.
Difference Between rho and r
:
 Spearman’s rank co-rrelation is used to find the
correlation of coefficient for qualitative data,in
where pearson’s correlation cannot be applied
 spearman’s correlation cannot be used for
bivariate frequency distribution but pearson’s
correlation can be used in that case.
 Spearman’s coefficient of rank correlation is
slightly lower in quality than pearson’s
coefficient of correlation.
 [Business statistics, Md. Abdul Aziz]
A table that illustrates the relationship
between two variables by displaying the
distribution of one variable across the categories
of a second variable. Bivariate association can be
investigated by finding answers to three
question:
1.Existance of association.
2.Strength of association.
3. Pattern or direction of the association.
Bi-variate variables
relationship:
 Direct bivariate relationship:
When the variation in the dependent variable can
be attributed only to the independent variable, the
relationship is said to be direct.
 Spurious bivariate relationship:
When a third variable affects both the
independent and dependent variables (think of the
firefighter example) the relationship is said to be
spurious.
 Intervening bivariate relationship:
. When the independent variable affects the dependent
variable only by way of a mediating variable (sort of like
a chain reaction), it is said to be an intervening
relationship.
 Title.
 Categories of the IndependentVariable head the
tops of the columns.
 Categories of the DependentVariable label the
rows .
 Order categories of the two variables from lowest to
highest (from left to right across the columns; from
top to bottom along the rows).
 Show totals at the foot of the columns.
Productivity By Job Satisfaction
Low moderate high total
Low 30 21 07 56
Moderate 20 25 18 63
High 10 15 27 52
Total 60 61 52 173
Production
(Y)
Job satisfaction (x)
 When independent variable is the column
variable(as in this text and as is generally but
not always ,the case)
 calculate percentages within the column
(vertically).
 compare percentage across the column
(horizontally.
Association between-variables

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Association between-variables

  • 1. Association Between Variables :Nominal and Ordinal
  • 2.  One of the most useful and popular tools in social science Research is cross tabulation or joint contingency analysis,using in statitics known a chi-square.It is one of the most simpliest and widely used non-parametric test in statistical work.It makes no assumptions about the population being sampled.  According to Anthony Walsh, ‘The chi-square is a test of significance that is used for discrete data in the form of frequencies ,percentages or proportions known as non-parametric statistics  According to Spigel, ‘A measure of discrepancy existing between the observed and expected frequency which is supplied by the X2 (chi square) statistics.’
  • 3. The formula says that chi-square or X is the sum we will get if we 1. Substract fr from fo for each other of the value. 2. Divide each squared difference by fe. 3.Square each of the differences 4. Sum all of answers. [statistics for Management ,Richard I.Levin,David.S. Rubin, 7th edition, p- 572] Assumptions For The Use of Chi-square: 1.We have independent random sample. 2.The data are nominal or ordinal level. 3. The data are no expected cell frequencies in less than 5. 4.Mutually exclusive
  • 4. Significanceof chi-square Chi-square test has some applications: As a non-parametric statistical test chi square may be used- 1.As a test of goodness of fit and 2. As a test of independence 3. X-test is simply a technically judging the significance of the measure of degree of relation between two attributes. Condition of Chi-square Test:  The experimental data (sample observation) must be independent of each othar.  The sample data must be drawn at random from the target population.  The data should be expressed i n original unit.  There should not be less than five observations in any one
  • 5. Limitations of chi-square test  The data is from a random sample  This test applied in a four fold table,will not give a reliable result with one degree of freedom if the expected value in any cell is less than 5  This test tells the presence or absence of an Association between the events but doesn’t measure the strength of association.  This test to be applicable when the individual observation of sample are occurance of one individual observation(event ) in the sample under considerations.  This test doesn’t indicate the cause and effect ,it only tells the probability of occurance of association by
  • 7. Advantages Easy to calculate & evaluate Used on nominal data Can be applied in a broad area Can test association between variables Identifies difference between observed and expected values.
  • 8. Disadvantages Can’t use percentages Data must be numerical catagories of l are not good to compare Test become invalid if any of the expected values are 5 Numbers of observations must be more than 20. Quite complicated
  • 9. Proportion reduction in error The concept of PRE measures are derived by comparing the errors, made in predicting the dependent variables by using the independent variables with errors made when making predictions that use information about the independent variable.Not all measures of association are PRE measures but whenever possible ,We use PRE measures because they have a standerd interpretation as indicated by the conceptual formula for pre measures.  According to Franfort and Leon Guerrero, 2004:366 ‘All pre measures are based on comparing predictive error levels that results from each of two methos of prediction’
  • 10. Formula and Types PRE= (E1 – E2) / E1 Where, E1= Errors of prediction made when the independent variable is ignored. E2= Errors of prediction made when the prediction is based on the independent variable There are two kinds of most commonly used PRE measures of association are, 1.Lamda () 2.Gamma ()
  • 11.  Lamda is defined as an asymmetrical measures of association that is suitable for use with nominal variables.It may be range from 0.0 to 1.0 .Lamda provides us with an indication of the strength of the relationship between independent and dependent variables. As an assymetrical measure of association lamdas>>>> may vary depending on which variable is considered the dependent variables and which variables is considered the independent variable. Lambda may range in value from 0.0 to 1.0. Zero indicates that there is nothing to be gained by using the independent variable to predict the dependent variable. In other words, the independent variable does not, in any way, predict the dependent variable. A lambda of 1.0 indicates that the independent variable is a perfect predictor of the dependent variable. That is, by using the independent variable as a predictor, we can predict the dependent variable without any error.
  • 12. Properties of Lamda  It is an assymetrical statistics.  The value of lamda varies which variable is taken as dependent .  It is appropriate for nominal variables  It involves an unrestrictive minimizing of errors.  It has a cosiderably larger numerical value.  It ranges from 0.0 to 1.00.  It doesn’t give a direction of association
  • 13. Formula  There is no sample test of statistical significance for lamda. Lamda= E1-E2/E1 To calculate lamda, we need 2 numbers. E1= Errors of prediction made when the independent variable is ignored. E2= Errors of prediction made when the prediction is based on the independent variable
  • 14.  Gamma is defined as a symmetrical measure of association suitable for use with ordinal variable or with dichotomous nominal variables. It can be vary from 0.0 to 1.0 and provides us with an indication of the strength of the relationship between two variables where as lamba is an asymmetrical measure of associations .Gamma is a symmetrical measure of association .This means that the value of gamma will be the same regardless of which variable is considered the independent variable.
  • 15. Properties of Gamma Gamma Two parameter femily of probability distribution Appropriate for ordinal level Ranges between -1 and +1.
  • 16. Origin: This method of finding out co-variability or the lack of it between two variables was developed by the British psychologist Charles and Edward Spearman in 1904. This measure is especially useful when quantitative measure of certain factors can not be fixed but the individuals in the group can be arranged in order there by obtaining for each individual a number indicating his rank in the group. In any event, the rank correlation coefficient is applied to a set of ordinal rank numbers with 1 for the individual ranked first in quantity or quality and so on. N for the individual ranked last in a group of N individual.
  • 17. Formula of rank correlation coefficient: R=1- σ Σ D2 / N (n2-1) Where R donates rank coefficient of correlation and D refers to the difference of ranks between paired items in two serious.The value of this coefficient also lies between +1 and -1 . When R is +1 there is complete agreement in the order of the ranks and they are in opposite directions. When R is -1 There is complete agreement in the order of the ranks and they are in opposite directions. This will be clear from the following:
  • 18. R1 R2 D (R1-R2 ) D2 R1 R2 D (R1-R2 ) D2 1 1 0 0 1 3 -2 4 2 2 0 0 2 2 0 0 3 3 0 0 3 1 2 4 ∑D2 = 0 ∑D2 = 8
  • 19.  R= 1-6 ∑D2 ÷N (n2-1) R = 1-6 ∑D2 ÷N (n2-1) = 1- 6 ÷3 (32 -1) = 1-6×8 3 (32 -1) = 1- 0÷ 3 (9-1) =1- 6×8 ÷ 3 (9-1) = 1-0 = 1- 48 ÷ 3 ×8 = 1- 48 ÷ 24 = 1-2 = -1. To rank correlation we may have two types of problems • Where the ranks are given • Where ranks are not given
  • 20. In rank correlation ,we may have two types of problems: 1.Where the actual ranks are given 2.Where ranks are not given Calculation of rank correlation co-efficient: Calculate the rank correlation co-efficient for the following data of marks of 2 tests given to candidates for a clerical job. Preliminary Test: 92,89,87,86,83,77,71,63,53,50 Final Test: 86,83, 91,77,68,85,52,82,37,57
  • 21. Calculation of rank correlation co- efficient Preliminar y test (X) Final test (Y) RX RY RX-RY (RX-RY)2 92 86 1 2 1 1 89 83 2 4 -2 4 87 91 3 1 2 4 86 77 4 6 2 4 83 68 5 7 -2 4 77 85 6 3 3 9 71 52 7 9 -2 4 63 82 8 5 3 9 53 37 9 10 1 1 50 57 10 8 2 4 N=10 Σ D2 = 44
  • 22. Now, R = 1-6 ∑D2 ÷N (n2-1) = 1- 6× 44 ÷10{(10)2 -1} = 1-6 × 44 ÷ 10 (1000-1) = 1-0.267 = 0.733 Here, there is a high degree of positive co-rrelation between preliminary and the final list.
  • 23. Merits of the rank Method  This method is simpler to understand and easier to apply compared to the karl pearson’s method.  Can use Where we are given the ranks and not the actual data  Can use where the data are of a qualitative nature like honesty, efficiency, intelligence etc. Limitations:  Can not be used for finding out correlation in a group frequency.  Where the number of observations execd 30 , the calculations become quite tedious an require a lot of time.
  • 24. Difference Between rho and r :  Spearman’s rank co-rrelation is used to find the correlation of coefficient for qualitative data,in where pearson’s correlation cannot be applied  spearman’s correlation cannot be used for bivariate frequency distribution but pearson’s correlation can be used in that case.  Spearman’s coefficient of rank correlation is slightly lower in quality than pearson’s coefficient of correlation.  [Business statistics, Md. Abdul Aziz]
  • 25. A table that illustrates the relationship between two variables by displaying the distribution of one variable across the categories of a second variable. Bivariate association can be investigated by finding answers to three question: 1.Existance of association. 2.Strength of association. 3. Pattern or direction of the association.
  • 27.  Direct bivariate relationship: When the variation in the dependent variable can be attributed only to the independent variable, the relationship is said to be direct.  Spurious bivariate relationship: When a third variable affects both the independent and dependent variables (think of the firefighter example) the relationship is said to be spurious.  Intervening bivariate relationship: . When the independent variable affects the dependent variable only by way of a mediating variable (sort of like
  • 28. a chain reaction), it is said to be an intervening relationship.  Title.  Categories of the IndependentVariable head the tops of the columns.  Categories of the DependentVariable label the rows .  Order categories of the two variables from lowest to highest (from left to right across the columns; from top to bottom along the rows).  Show totals at the foot of the columns.
  • 29. Productivity By Job Satisfaction Low moderate high total Low 30 21 07 56 Moderate 20 25 18 63 High 10 15 27 52 Total 60 61 52 173 Production (Y) Job satisfaction (x)
  • 30.  When independent variable is the column variable(as in this text and as is generally but not always ,the case)  calculate percentages within the column (vertically).  compare percentage across the column (horizontally.