ejercisio resueltos de programación en c++

1. 1++++++++++++++++++++++++++++++++++++++++++
// ConsoleApplication16.cpp: define el punto de entrada de la aplicación de
consola.
//
#include "stdafx.h"
#include<iostream>
using namespace std;
int main()
{
int A[10];
for (int i = 0; i <= 9; i++)
{
cout << "Digite el numero en la posicion" <<i<< endl;
cin >> A[i];
}
for (int i = 0; i <= 9; i++)
{
cout <<A[i]<< endl;
}
system("pause");
return 0;
}
2+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
// ConsoleApplication16.cpp: define el punto de entrada de la aplicación de
consola.
//
#include "stdafx.h"
#include<iostream>
using namespace std;
int main()
{
int M[10], N[10], Z[10];
for (int i = 0; i <= 9; i++)
{
M[i]= rand() % 100;
}
for (int i = 0; i <= 9; i++)
{
N[i] = rand() % 100;
}
for (int i = 0; i <= 9; i++)
{
Z[i] = M[i]+ N[i];
}
cout << "Vector M" << endl;
for (int i = 0; i <= 9; i++)
{
cout<<M[i]<<endl;
}
cout << "Vector N" << endl;
for (int i = 0; i <= 9; i++)
{

2. cout << N[i] << endl;
}
cout << "Vector Z" << endl;
for (int i = 0; i <= 9; i++)
{
cout << Z[i] << endl;
}
system("pause");
return 0;
}
3+++++++++++++++++++++++++++++++++++++++++++++++++++++++++++
// ConsoleApplication16.cpp: define el punto de entrada de la aplicación de
consola.
//
#include "stdafx.h"
#include<iostream>
using namespace std;
int main()
{
int M[15],Nu=0;
cout << "Digite el primer valor" << endl;
cin >> Nu;
for (int i = 0; i <= 14; i++)
{
M[i]= Nu+i;
}
for (int i = 0; i <= 14; i++)
{
cout << M[i] << endl;
}
system("pause");
return 0;
}
4+++++++++++++++++++++++++++++++++++++++++
// ConsoleApplication16.cpp: define el punto de entrada de la aplicación de
consola.
//
#include "stdafx.h"
#include<iostream>
using namespace std;
int main()
{
float A[10], B[10],SumaA[10],RestaA[10],MulA[10],DivA[10],SumaB[10],
RestaB[10], MulB[10], DivB[10],K;
for (int i = 0; i <= 9; i++)
{
A[i] = rand() % 100;
B[i] = rand() % 100;
}

3. K = rand() % 100;
for (int i = 0; i <= 9; i++)
{
SumaA[i] = A[i] + K;
SumaB[i] = B[i] + K;
RestaA[i] = A[i] - K;
RestaB[i] = B[i] - K;
MulA[i] = A[i] * K;
MulB[i] = B[i] * K;
DivA[i] = A[i] / K;
DivB[i] = B[i] / K;
}
cout << "Resultados de A" << endl;
for (int i = 0; i <= 9; i++)
{
cout <<K<<" "<<A[i] <<" "<<SumaA[i] <<" "<<RestaA[i] <<" "<<MulA[i]
<<" "<<DivA[i] <<" "<<endl;
}
cout << endl;
cout << "Resultados de B" << endl;
for (int i = 0; i <= 9; i++)
{
cout << K << " " << B[i] << " " << SumaB[i] << " " << RestaB[i] << "
" << MulB[i] << " " << DivB[i] << " " << endl;
}
system("pause");
return 0;
}
5+++++++++++++++++++++++++++++