University Electromagnetism:
Electric field and potential of a capacitor that is partly filled (vertically or horizontally) with dielectric material (connected or not to a battery)
2. Partial filling a capacitor (1) Available: Flat capacitor : = surface area A , = distance of plates d , = no fill ( r . Question: What will happen with Q , E, D, V and C upon PARTIAL filling the capacitor with dielectric material (with r A d Assume: initially, plates are charged with +Q , -Q. +Q -Q
3. Partial filling a capacitor (2) A. Series B. Parallel I. Free II. Connected to battery Options:
4.
5. Relations Q f A d +Q -Q D E Material constants: D = r E V
6.
7. A.I. Horizontal fill, not connected d b , d t : bottom and top layer Fill: d b = d 0 /3 with r = 5 d t = 2 d 0 /3 with r = 1 Q f ’ D’ E’ d’ V’ V’ C’ Start Q f D E V d b d t Q f,t ’ -Q f,b ’ o = old t = top b = bottom } total
8. A.II. Horizontal fill, connected Fill: d b = d 0 /3 with r = 5 d t = 2 d 0 /3 with r = 1 Q f ’ D’ E’ d’ V’ V’ C’ V’ E’ D’ Q f ’ Consider ratios: Q f D E V d b d t Q f,t -Q f,b V 0 o = old t = top b = bottom } total <0
9. B.I. Vertical fill, not connected Fill: A r = A 0 /3 with r = 5 A l = 2 A 0 /3 with r = 1 Q f ’ D’ E’ Consider ratios: V’ A’ Q f D E V E’ C’ o = old l = left r = right } total Q f,l ’ -Q f,r ’ Q f,r ’ -Q f,l ’ A l A r Q f ’ Q f ’ D’ V’
10. B.II. Vertical fill, connected Fill: A r = A 0 /3 with r = 5 A l = 2 A 0 /3 with r = 1 Q f ’ D’ E’ C’ Consider ratios: V’ A’ Q f ’ Q f D E V o = old l = left r = right } total Q f,l ’ -Q f,r ’ Q f,r ’ -Q f,l ’ A l A r V 0
11. Options: overview C : 15/11 x Q f : unchanged V : 11/15 x V : unchanged Q f : 15/11 x C : 7/3 x Q f : unchanged V : 3/7 x V : unchanged Q f : 7/3 x B B.I and B.II : potentials parallel A A.I and A.II : potentials in series I II
12. With combination rules Filling with r =5 in 1/3 of volume B B.I and B.II : parallel A A.I and A.II : series I II
13. Finally... the end D = r E B B.I and B.II : parallel A A.I and A.II : series I II Q f D E V